Chapter 10 Molecular Structure Chapter 10 Molecular Structure 10.1 Covalent Bonds 10.2 Hybridization of Atomic Orbitals 10.3 Valence Shell Electron-Pair Repulsion Theory (VSEPR) 10.5 Intermolecular Forces Review of Chemical Bonds What is a chemical bond? the attractive force that holds atoms together in multi-atom elements or in compounds Why does it come about? Octet Rule: atoms combine to form bonds either by transferring electrons to form ionic bonds, or by sharing electrons in covalent bonds, until each atom is surrounded by eight valence electrons Problem How can an atom alter its electron configuration to obtain an octet (or duet) of electrons of a noble gas? Solution A metal e a cation e A nonmetal an anion ionic compounds Na + Cl + Na Sharing of electrons between nonmetals molecular compounds Cl - Types of Chemical Bonds: Ionic Bonds: transferring electrons Covalent Bonds: sharing electrons Metallic Bonds: Valence electrons are detached from atoms, and spread in an 'electron sea' that "glues" the ions together Ionic Bond is a strong electrostatic attraction between a positive ion and a negative ion electron is fully transferred from metal to nonmetal non-directional, magnitude of bond equal is all directions typically occur between a metal and a reactive non-metal n Na (3s1) -n e n Na+ (2s22p6) n Cl (3s23p5) +n e n Cl- (3s23p6) n NaCl(s) Covalent Bond Cooperative sharing of valence electrons Covalent bonds are HIGHLY directional typically occur between non-metal have a relatively low melting and boiling point 10.1 Covalent Bonds Key points: Why and how do two atoms bond together ? What’s the difference between them? σbond andπbond single bond, double bond and triple bond polar and nonpolar covalent bond 1. Describing Covalent Bonds Definition: A shared pair of electrons between two potential energy → atoms is known as a covalent bond. Example: H2 H + H HH repulsion Maximum attraction no overlap; no attraction 0 74pm Bond dissociation energy Bond length Distance between nuclei → Covalent Bond Theory : Bonds are formed by atom sharing two electrons in overlapping atomic orbitals. the number of bonds formed = the number of unpaired electrons usually NH3 Orbitals bond in the same axis to obtain maximum overlap. e.g.:HCl Cl 1s22s22p6 3s23p5 H 1s1 x z x 2. Bond Properties Bond Energy: the energy required to break one mole of bonds in a gaseous species. NH3(g)=NH2(g)+H(g) D1=435.3kJ·mol-1 NH2(g)=NH(g)+H(g) D2=397.5kJ·mol-1 NH(g)=N(g)+H(g) D3=338.9kJ·mol-1 NH3(g)=N (g)+3H(g) D=1171.5kJ·mol-1 EN-H=(D1+D2+D3)/3=390.5 kJ·mol-1→ The larger the bond energy, the stronger the chemical bond. Bond Length: distance between nuclears of two bonded atoms Bond lengths from x-ray analysis: 143 122 Bond Angle 104045‘ 113 3. Types of Bonds Ionic Bond: electrostatic attraction Chemical Bond Covalent Bond: sharing of electrons Coordinate Covalent Bond: both electrons from one atom (CO) C 1s22s22p2 Bond order one electron from each atom orbital overlap Coordinate Bond Polarity Covalent Bond σbond πbond Polar Covalent Bond Nonpolar Covalent Bond O 1s22s22p4 Single Bond Double Bond Triple Bond Covalent Bond: sigma bond and Pi bond Sigma (σ) bond = end-to-end overlap ☆ head-on overlap = end-to-end overlap ☆ s-s , s-px , px-px * s + s sigma overlap Sigma () bonds s + p sigma overlap p + p sigma overlap Pi (π) bond = side-by-side overlap ☆ sideways overlap Pi () bond ☆ pz-pz , py-py * + p orbital p orbital bond σ键 π键 Note here, that the extent of overlap between the orbitals is less in a pie bond as compared to a sigma bond. Thus, the force of attraction between the shared electron pair and the nuclei is comparatively less than that in a sigma bond. Therefore, a pie bond is always weaker than a sigma bond,and it can only coexist with sigma bond. A single covalent bond is a sigma bond. A double covalent bond is made up of one sigma and one pie bond. A triple covalent bond is made up of one sigma and two pie bonds. Bond Order and Multiple Bonds ☆ single bond => 1 pairs shared ☆ double bond => 2 pairs shared ☆ triple bond => 3 pairs shared N2 Relationship Between Order, Length, and Energy C—C C C C C Bond order = 1 2 3 length (pm) = 154 134 121 energy (kJ/mol) = 347 611 837 Conclusion: Bond lengths SHORTEN as bond order INCREASES. A double bond is STRONGER than a single bond. 10.1 Covalent Bonds • Polar Covalent Bonds and Nonpolar Covalent Bonds Problem • The electrons in the covalent bond are shared equally? Solution • The electronegativity (EN) differences of the elements are used to determine the extent of this unsharing. Nonpolar Bond diff. EN = 0 Electrons shared equally.(atoms with same electronegativity) H2: H H Polar Bond diff. EN > 0 Electrons shared unequally.(atoms with different electronegativity) HCl: + Ionic Bond diff. EN > 1.7 Electron transferred. - + ¦Ä Na¦Ä + ClNaCl: Na H Cl Notice: bond polarity≠molecular polarity Cl - 10.2 Hybridization of Atomic Orbitals Questions: Why can they hybrid? What kinds of orbitals are used for hybridization? Why do they need to hybrid? How to predict the shapes of molecules? Problem Experiment shows that the methane molecule (CH4) is tetrahedral, with four equivalent bonds. Solution 2 2 2 1s22s12p3 C 1s 2s 2p 2p 2p 2s 2s 1s ground state 1s excited state 2p 2s 1s excited state mutually perpendicular spherically symmetrical “atomic orbitals” vs. “hybrid orbitals” atomic orbitals ☆ on the same atom (central atom only ) ☆ in the same principal energy level or, occasionally, in adjacent energy level hybrid orbitals ☆ the shapes and directional properties of new hybrid orbitals ≠the orbitals used in constructing them ☆ the number of hybrid orbitals formed = number of atomic orbitals used 10.2 Hybridization of Atomic Orbitals [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] solution 2+ [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution [Cu(NH3) 4] 2+ solution After the paint is mixed, there are still the same numbers of cups of paint, but the color has changed. The mixing of orbitals is analogous. sp3 10.2 Hybridization of Atomic Orbitals The directional characteristics of the new hybrid orbitals will be decided by the type and number of atomic orbitals using in the mixing. Table 3 Three Types of s-p Hybrid Atomic orbitals one s, one p one s, two p one s, three p Hybrid Orbitals two sp three sp2 four sp3 Geometric Arrangement Linear* Trigonal planar* Tetrahedral 10.2 Hybridization of Atomic Orbitals sp 10.2 Hybridization of Atomic Orbitals 2 sp 10.2 Hybridization of Atomic Orbitals 3 sp 10.2 Hybridization of Atomic Orbitals Needed to form 4 sigma bonds The mutual repulsion among the electron pairs will orient them toward the apices of a tetrahedron. sp3 four sp3 hybrid orbitals 1s hybrided sp3 C-H sp3-s sigma bonds 1s in CH4 2 2 2 C 1s 2s 2p 1s22s12p3 2p 2p 2s 2s 1s ground state 1s excited state sp3 four sp3 hybrid orbitals 1s hybrided sp3 C-H sp3-s sigma bonds 1s in CH4 1. An Outline of Hybrid Orbital Theory I. Why can they hybrid? We can mathematically mix two or more of these wave functions that describe the electron, and produce an equal number of wave functions that have different shapes and orientation. However, the number of new hybrid orbitals will be the same as the number of orbitals used to form them. What kind of orbitals are used for hybridization? Hybrids are formed among orbitals lying in the same principal energy level or, occasionally, in adjacent energy levels. Example ns np ( n-1) d ns np or ns np nd II. 10.2 Hybridization of Atomic Orbitals III. Why do they need to hybrid? Each sp3 hybrid orbital has a large lobe pointing in one direction and a small lobe pointing in the opposite direction. The enlarged lobe of the resulting orbital can give more favorable overlap with the orbital of another atom and thus form a stronger bond than can either the p or s orbitals alone. + ++ + + _ _ + _ ++ Mix Mix _ ++ 10.2 Hybridization of Atomic Orbitals IV. Why do they form a geometry ? The mutual repulsion among the electron pairs will orient hybrid orbitals toward the apices of a geometry. Hybrid Number of Geometric Orbitals Orbitals Arrangement sp sp2 sp3 sp3d 2 3 4 5 Linear Trigonal Tetrahedral Trigonal bipyramidal sp3d2 6 Octahedral 10.2 Hybridization of Atomic 2. Application- Beryllium Chloride, BeCl2 : sp Orbitals 2 2 Be 1s 2s 2p 2p 2s 2s 1s ground state 1s excited state Use sp hybrid orbitals two unchanged and vacant p orbitals 2p 2p sp sp 1s hybridized Be-Cl bonds: sp-p sigma bond 1s in BeCl2 Two electron pairs produce a linear arrangement. Cl—Be—Cl 10.2 Hybridization of Atomic Orbitals 2 2 1 B 1s 2s 2p 2p 2p 2s 2s 1s ground state 1s excited state 2p BF3 : sp2 2p sp2 Use sp2 hybrid orbitals 1s hybridized sp2 B-F bonds F 1s B F F in BF3 Three electron pairs produce a triangular planar arrangement . 10.2 Hybridization of Atomic Orbitals 3 sp :CH4 NH3 H2O 2 2 2s 2p 2p C CH4 2p 2s 2s sp3 hybrid orbitals equivalent hybridization NH3 2 3 N 2s 2p 2p 2s H2O 2 4 O 2s 2p 2p 2s nonequivalent hybridization 104045‘ C2H6 C2H2 C2H4 What would be the name of the hybrid orbitals created by joining 1 s type, 3 p type and 2 d type orbitals? a. spd b. sp3d2 c. s3p2d 10.3 Valence Shell Electron-Pair (VSEPR) Repulsion Theory Key Points: What’s the difference between the arrangement of electron pairs and the molecular geometry ? How to predict the shapes of molecules? PbCl2 Pb: 5d106s26p2 Pb2+→ sp?linear? HgCl2 Hg: 5d106s2 Hg2+→ sp?linear? 10.3 Valence Shell Electron-Pair Repulsion Theory 1. VSEPR model The arrangement of electron pairs describes the arrangement of all electron pairs, shared or unshared, around a central atom. The molecular geometry of a molecule is the geometry described by the bonded atoms and does not include the unshared pairs of electrons. The minimum repulsion occurs when the electron pairs are as far apart as possible. 10.3 Valence Shell Electron-Pair Repulsion Theory Table 1 Arrangement of electron pairs about an atom Number of electron Pairs Arrangement of Electron Pairs 2 Linear 3 Trigonal planar 4 Tetrahedral 5 Trigonal bipyramidal 6 Octahedral 10.3 Valence Shell Electron-Pair Repulsion Theory If more than one structure is possible, the most stable structure can often be determined using the following rules: Bond angles: 90º>120º>180º Lone pairs (LP): LP-LP>LP-BP>BP-BP Bond order:triple >double >single bond Electronagetivity of the donor atom:Xsmall > Xlarge Select the stable structure which has the smallest number of lone pair-lone pair repulsions (usually 90o). 10.3 Valence Shell Electron-Pair Repulsion Theory 2. How to predict molecular structures? Determine the number of electron pairs (both bonded pairs and lone pairs) around the central atom. the number of electron-pairs=1/2 (the number of valence electrons on the central atom + the number of electrons furnished by donor atom) the number of valence electrons on the central atom =group number hydrogen and the halogens (Group VIIA) donate one electron each for sharing, 10.3 Valence Shell Electron-Pair Repulsion Theory Elements in the oxygen group (Group VIA) are considered to donate no electrons. Positive ion: subtract the positive charge on the ion. Negative ion: add the negative charge on the ion. In the case of an odd number of electrons, treat the extra electron (one-half of an electron-pair) as if it were an electron-pair (lone pair). Count a multiple bond as one pair. 10.3 Valence Shell Electron-Pair Repulsion Theory Identify the molecular geometry No. of Arrangement of e- pairs pairs 2(sp) Molecular geometry of ABn Linear 3(sp2) Trigonal planar AB2 AB3 4(sp3) Tetrahedral AB4 5 Trigonal 3 (sp d ) bipyramidal AB 5 AB4 AB6 AB5 6 (sp3d2) Octahedral AB2 AB3 AB2 AB3 AB4 AB2 10.3 Valence Shell Electron-Pair Repulsion Theory 3. Applying VSEPR Theory Using the VSEPR theory we could predict the geometry of an AXn molecule or ion . Using the VSEPR theory we could predict bond angles and molecular geometry. Using the VSEPR theory we could predict whether the molecule is polar or nonpolar. Using the VSEPR theory we could describe the hybrid orbitals used by the central atom. 10.3 Valence Shell Electron-Pair Repulsion Theory Using the VSEPR theory Central atom: Cl 3s23p5 we could predict the geometry of an AXn F F molecule or ion . Cl F F F Predict the geometry of the LP–LP 0 following molecules or LP–BP 4 ions. BP–BP 2 + BF3 PCl5 H2O H3O NH3 NH4+ NO2 NO2SF4 ClF3 XeF2 IF5 XeF4 SO42- O3 F F Cl Cl F 1 3 2 0 6 0 F 10.3 Valence Shell Electron-Pair Repulsion Theory Procedure ☆Determine the number of electron pairs. ※a multiple ≌ one pair ≌ an unpaired electron ☆ Arrange the electron pairs. ☆ Identify the molecular geometry. with lone pairs: the arrangement of electron pairs ≠ the molecular geometry 10.3 Valence Shell Electron-Pair Repulsion Theory Using the VSEPR theory we could predict bond angles and molecular geometry. H H N H O CH4 : H C H NH3 : H2O: H H H H No lone pair One lone pair Two lone pairs Tetrahedral Trigonal pyramidal Bent Notice: When lone pairs are present, the bond angles are smaller than the perfect angles. 10.3 Valence Shell Electron-Pair Repulsion Theory Using the VSEPR theory we could predict whether the molecule is polar or nonpolar. Problem How dose bond polarity relate to molecular polarity? Solution ☆ For diatomic molecules, if the bond is polar then the molecule is polar. ☆ For all other molecules, we need to know the molecular shape to be able to predict the polarity. 10.3 Valence Shell Electron-Pair Repulsion Theory If two people of exactly equal strength pull on the box in exactly opposite directions, their efforts cancel and there is no movement. Direction of movement 10.3 Valence Shell Electron-Pair Repulsion Theory nonpolar molecule 1. Polar or nonpolar covalent bond 2. has a perfect geometry (no lone pairs ) 3. dipole moments (μ) = 0 4. Example: O C O CO2 : Linear polar bonds nonpolar molecule polar molecule Polar covalent bond does not have a perfect geometry (with lone pairs ) μ≠0 SO2 : O S Bent polar bonds polar molecule O 10.3 Valence Shell Electron-Pair Repulsion Theory Conclusion ☆ For diatomic molecules, if the bond is polar then the molecule is polar. ☆ For all other molecules, we need to know the molecular shape to be able to predict the polarity. ※ Molecules with lone pairs of electrons on a central atom are generally polar molecules. ※ Nonpolar molecules that contain polar bonds are observed when there are no lone pairs on the central atom, and all of the atoms bonded to the central atom are identical. 10.3 Valence Shell Electron-Pair Repulsion Theory Use the VSEPR model to obtain the arrangement of electron pairs. From the arrangement of the electron pairs, deduce the type of hybrid orbitals. Arrangement of electron pairs Hybrid Orbitals Linear Sp(2) Trigonal planar Tetrahedral Trigonal bipyramidal Sp2(3) Sp3(4) Sp3d(5) Octahedral Sp3d2(6) 10.5 Types of Intermolecular Forces Key Points: What kinds of attractions exist between molecules? What’s the difference between the intermolecular forces and the intramolecular forces ? 10.5 Types of Intermolecular Forces Intramolecular forces hold atoms together in molecules. Ionic Covalent Metallic Cation-anion Nuclei-shared e- pair Cations-delocalized e- Intermolecular forces are those between Polar bond to H-dipole molecules. H bond Dipole-dipole Dipole-induced dipole Dispersion (London) charge (high EN of N, O, F) Dipole charges Dipole chargepolarizable e- cloud Polarizable e- clouds 10.5 Types of Intermolecular Forces 2. Explaining Liquid Properties Many of the physical properties of liquids (and certain solids) can be explained in terms of intermolecular forces. play a key role in determining the conditions under which a substance is a solid, a liquid, or a gas affect physical properties, such as the melting points of solids and the boiling points of liquids. 10.5 Types of Intermolecular Forces 3. Dipole Moment I. A polar molecule and dipole moment A polar molecule has permanent dipole Polar molecules are aligned in an electric field 10.5 Types of Intermolecular Forces I. Dipole moment = qx , dipole moment q, charge (or fractional charges) x, distance between charges a quantitative measure of the degree of charge separation in a molecule. expresses a molecule’s polarity. Molecules with large dipole moments are highly polar. Nonpolar molecules have a zero dipole moment. 10.5 Types of Intermolecular Forces II. Instantaneous And Induced Dipoles In describing electronic structures we speak of electron charge density or the probability that an electron is in a certain region at a given time. One probability is that at some particular instant―purely by chance―electrons are concentrated in one region of an atom or molecule. This displacement of electrons causes a normally nonpolar species to become momentarily polar. After this, electrons in a neighboring atom or molecule may be displaced to also produce a dipole, called an induced dipole. 10.5 Types of Intermolecular Forces 4. Types of Intermolecular Forces Dipole-Dipole Forces Dipole- Induced Dipole Forces London Forces Hydrogen Bonding Van Der Waals Forces 10.5 Types of Intermolecular Forces I. Dipole-Dipole Forces A polar molecule has two "poles". (Permanent Dipole ) Molecules with a permanent dipole can align themselves so that the negative end of one molecule is attracted to the positive end of another. These attractions are known as dipole-dipole attractions. 10.5 Types of Intermolecular Forces I. Dipole-Dipole Forces Notice only in permanence somewhat stronger than London forces because permanent occurs in all polar molecules 10.5 Types of Intermolecular Forces II. Dipole-Induced Dipole Interactions Dipole H2O and nonpolar O2: The dipole of H2O induces a dipole in O2 by be distorting the O2 electron cloud – Polarizability Interactions of polarizable molecules are called induced dipole interactions Notice occurs in polar and nonpolar molecules 10.5 Types of Intermolecular Forces III. Induced dipole - Induced dipole Interactions (London forces ) Two nonpolar atoms or molecules has no dipole moment . Momentary attractions and repulsions between nuclei and electrons in neighboring molecules lead to induced dipoles. The attraction between these induced dipoles then spreads from molecule to molecule, thus providing an attractive force between molecules. ± ± 10.5 Types of Intermolecular Forces Even nonpolar molecules and uncombined atoms have attractive forces between them. Notice all particles have London forces London forces increase with molecular weight. only force between noble gases and nonpolar compounds. about 1/1000 as strong as a covalent bond Notice All particles have London forces. London forces increase with molecular weight. about 1/1000 as strong as a covalent bond polar-polar polarnonpolar nonpolarnonpolar Dipole-Dipole Dipole- Induced Forces Dipole Forces √ √ √ London Forces √ √ √ 10.5 Types of Intermolecular Forces V. Hydrogen Bonding Problem Examination of the boiling points of the groups VA, VIA, and VIIA reveals that the first compound in each of these series has an unexpectedly high boiling point. A hydrogen atom bonded to an electronegative atom appears to be special. The electrons in the O-H bond are drawn to the O atom, leaving the dense positive charge of the hydrogen nucleus exposed. It’s the strong attraction of this exposed nucleus for the lone pair on an adjacent molecule that accounts for the strong attraction. A similar mechanism explains the attractions in HF and NH3. Condition X—H…Y(X,Y=F、O、N) X→ Xlarge、rsmall Y→ Xlarge、rsmall ,lone pair electron 10.5 Types of Intermolecular Forces Notice Rare, strong form of dipole-dipole interaction. Require H bonded to highly electronegative atom (N, O or Halogen): one of the following three structures must be present. H-N O-H F-H One molecule has a hydrogen atom attached by a covalent bond to an atom of nitrogen, oxygen, or fluorine. The other molecule has a nitrogen, oxygen, or fluorine atom present that possesses one or more lone pairs. strongest of four intermolecular forces are HIGHLY directional 10.5 Types of Intermolecular Forces Types of Hydrogen Bonds intermolecular hydrogen bonds Increase boiling points intramolecular hydrogen bonds Decrease boiling points 10.5 Types of Intermolecular Forces 5. The Double Helix of DNA is held together by hydrogen bonding In the three-dimensional Watson-Crick structure, two polynucleotide DNA strands wind around each other to form a double helix. Hydrogen bonds form between specific base pairs. Adenine is hydrogen bonded to thymine, and guanine is hydrogen bonded to cytosine to form complementary base pairs (A on one strand with T on the other strand, or C with G). adenine腺嘌呤 thymine胸腺嘧啶 guanine鸟嘌呤cytosine胞嘧啶 10.5 Types of Intermolecular Forces white = hydrogen blue = nitrogen black = carbon red = oxygen 10.5 Types of Intermolecular Forces Two hydrogen bonds occur between every adenine and thymine pair; three between each guanine and cytosine.