Chemical Nomenclature Part 111 Covalent Binary Compound (Two Nonmetals): Greek Prefix System Given Formula, Write the Name The Greek System A binary compound is one made of two different elements. There can be one of each element such as in CO or NO. There can also be several of each element such as BF3 or OCl2. This lesson shows you how to name binary compounds from the formula when two nonmetals are involved. The four formulas above are all examples of this type. Important point to remember: NO metals (which act as the cation) are involved. That means one of the nonmetals will be acting in the positive role while the other is negative. In fact, you do not even need to know the charges, since the formula comes right from the element names and their prefixes. Be aware that heavy use of Greek number prefixes are used in this lesson.Here are the first ten: one two three four five monoditritetrapenta- six seven eight nine ten hexaheptaoctanonadeca- Example #1 - write the name for N2O. Example #2 - write the name for NO2. Step #1 - part of the first name is the unchanged name of the first element in the formula. In the examples above, it would be nitrogen. If the subscript of the first element is 2 or more, you add a prefix to the name. In the first example above, you would write dinitrogen. If the subscript is one as in the second example above, you DO NOT use a prefix. You simply write the name, in this example it would be nitrogen. 1 Step #2 - the anion is named in the usual manner of stem plus "ide." In addition, a prefix is added. In the first example, the prefix is "mono-" since there is one oxygen. In the second example, use "di-" because of two oxygens. The correct names of the two examples are dinitrogen monoxide and nitrogen dioxide. Note that "monoxide" is written rather than "monooxide." It sounds better when spoken out loud. Example #3 - write the name for IF7. Step #1 - the first element is iodine and there is only one. This part of the name will be "iodine", NOT "monoiodine." Step #2 - the second element is fluorine, so "fluoride" is used. Since there are seven, the prefix "hepta" is used. The name of this compound is iodine heptafluoride. Example #4 - write the name for N2O5. Step #1 - the first element is nitrogen and there are two. This part of the name will be "dinitrogen." Step #2 - the second element is oxygen, so "oxide" is used. Since there are five, the prefix "penta" is used. The name of this compound is "dinitrogen pentaoxide." Many write is as "dinitrogen pentoxide." The Chemists believes that both are considered correct, but the second is to be prefered. Example #5 - write the name for XeF2. The first part of the name comes from the first element's name: xenon. Since there is only one atom present, no prefix is used. The second part of the name comes from the root of the second symbol plus 'ide' as well as the prefix "di-,"therefore di + fluor + ide = difluoride. This compound is named xenon difluoride. 2 Example #6 - write the name for N2O4. The first part of the name comes from the first element's name: nitrogen. Since there are two atoms, the prefix "di-" is used giving dinitrogen. The second part of the name comes from the root of the second symbol plus 'ide' as well as the prefix "tetra-,"therefore tetr + ox + ide = tetroxide. This compound is named dinitrogen tetroxide. Notice the dropping of the "a" in tetra. Just a reminder: this system of naming does not really have an offically accepted name, but is often called the Greek system (or method). It involves use of Greek prefixes when naming binary compounds of two nonmetals. Sometimes you will see the Stock system applied to these types of compounds. Here is what the IUPAC currently says about that practice: "The Stock notation can be applied to both cations and anions, but preferably should not be applied to compounds between nonmetals." Practice Problems Write the correct name for: 1) As4O10 2) BrO3 3) BN 4) N2O3 5) NI3 6) SF6 7) XeF4 8) PCl3 9) CO 10) PCl5 3 Answers to Set One 1) tetrarsenic decoxide 2) bromine trioxide 3) boron nitride 4) dinitrogen trioxide 5) nitrogen triiodide 6) sulfur hexafluoride 7) xenon tetrafluoride 8) phosphorous trichloride 9) carbon monoxide 10) phosphorous pentachloride Write the correct name for: 11) P2O5 12) S2Cl2 13) ICl2 14) SO2 15) P4O10 16) UF6 17) OF2 18) ClO2 19) SiO2 20) BF3 Answers to Set Two 4 11) diphosphorous pentoxide 12) disulfur dichloride 13) iodine dichloride 14) sulfur dioxide 15) tetraphosphorous decoxide 16) uranium hexafluoride 17) oxygen difluoride 18) chlorine dioxide 19) silicon dioxide 20) boron trifluoride Write the correct name for: 21) N2S5 22) CO2 23) SO3 24) XeF6 25) KrF2 26) BrCl5 27) SCl4 28) PF3 29) XeO3 30) OsO4 Answers 21) dinitrogen pentasulfide 5 22) carbon dioxide 23) sulfur trioxide 24) xenon hexafluoride 25) krypton difluoride 26) bromine pentachloride 27) sulfur tetrachloride 28) phosphorous trifluoride 29) xenon trioxide 30) osmium tetroxide Binary Compounds of Two Nonmetals Given Name, Write the Formula The Greek System A binary compound is one made of two different elements. There can be one of each element such as in CO or NO. There can also be several of each element such as BF<SUB3< SUB> or OCl2. This lesson shows you how to write the formula of a binary compound from its name when two nonmetals are involved. The four formulas above are all examples of this type. Important point to remember: NO metals (which act as the cation) are involved. That means one of the nonmetals will be acting in the positive role while the other is negative. In fact, you do not even need to know the charges, since the name comes right from the amounts of the two elements involved. Be aware that heavy uses of Greek number prefixes are used in this lesson. Here are the first ten: one two three four five monoditritetrapenta- six seven eight nine ten 6 hexaheptaoctanonadeca- Example #1 - write the formula for dinitrogen trioxide. Example #2 - write the name for carbon monoxide. Step #1 - the first name will tell you the first element in the formula. In the first example above, it would be N and in the second, C. If there is a prefix on the name, this gives the subscript on the element. In the first example above, the "di-" tells you there are two nitrogens. Absence of a prefix, as in the second example, says there is only one of that element involved. Step #2 - the anion name tells you the element; oxide means oxygen. Once again, the prefix will tell you how many of the element are involved. "Tri-" means three and "mono" means one. The correct formulas of the two examples are N2O3 and CO. Note that "monoxide' is written rather than "oxide" when there is one atom of the second element involved. Note also that when one element of the first atom is involved, no "mono-" is used. Monocarbon monoxide is just as wrong as carbon oxide. Example #3 - write the formula for bromine pentafluoride. Step #1 - the first symbol is Br and its subscript will be a one, which is understoo to be present. Step #2 - the second element is fluorine, so F is used. The prefix "penta-" indicates a subscript of 5. The formula of this compound is BrF5. Example #4 - write the formula for diphosphorous pentoxide. Step #1 - the first symbol is P and the subscript is 2. Step #2 - pentoxide says five oxygens are involved. The formula of this compound is P2O5. Example #5 - write the formula for iodine heptafluoride. 7 Step #1 - the first symbol is I and the subscript is 1. Again it is understood to be there. Step #2 - heptafluoride says 7 florides are involved. The formula of this compound is IF7. Practice Problems Write the correct formula for: 1) chlorine monoxide 2) oxygen difluoride 3) boron phosphide 4) dinitrogen monoxide 5) nitrogen trifluoride 6) sulfur tetrachloride 7) xenon trioxide 8) carbon dioxide 9) diphosphorous pentoxide 10) phosphorous trichloride Answers to Set One 1) ClO 2) OF2 3) BP 4) N2O 5) NF3 6) SCl4 7) XeO3 8 8) CO2 9) P2O5 10) PCl3 Write the correct formula for: 11) sulfur dioxide 12) bromine pentafluoride 13) disulfur dichloride 14) boron trifluoride 15) tetraarsenic decoxide 16) silicon tetrachloride 17) krypton difluoride 18) chlorine monoxide 19) silicon dioxide 20) boron trichloride Answers to Set Two 11) SO2 12) BrF5 13) S2Cl2 14) BF3 15) As4O10 16) SiCl4 17) KrF2 18) ClO 9 19) SiO2 20) BCl3 Write the correct formula for: 21) dinitrogen pentasulfide 22) carbon monoxide 23) sulfur trioxide 24) dinitrogen trioxide 25) dinitrogen monoxide 26) xenon hexafluoride 27) sulfur hexafluoride 28) phosphorous pentachloride 29) nitrogen monoxide 30) bismuth trichloride Answers 21) N2S5 22) CO 23) SO3 24) N2O3 25) N2O 26) XeF6 27) SF6 28) PCl5 29) NO 10 30) BiCl3 Polyatomics (Metal with fixed or variable charge/Polyatomic) Compounds Involving a Polyatomic Ion Given Formula, Write the Name These compounds to follow ARE NOT binary compounds. They contain three or more elements, as opposed to only two in a binary compound. The Greek method WILL NOT be used. That naming technique is used only for binary compounds of two nonmetals. That means, if you see a formula like BaSO4, the name is not barium monosulfur tetraoxide. Many unaware Chemists students over the years have made this error and suffered for it. Consequently, a warning: it is important that you learn to recognize the presence of a polyatomic ion in a formula. Many of Chemists’ students have made it their first priority to make a set of flashcards with the name on one side and the ion and its charge on the other. Then, carry them everywhere and use them. The cations used will be a mix of fixed charges AND variable charges. You must know which are which. Another warning: you must also know the charges associated with each polyatomic ion. For example, NO3¯ is called nitrate and it has a minus one charge. Once again, many unaware Chemists students have thought this means nitrate has a minus three charge. IT DOES NOT. Use of Parenthesis When more than one polyatomic ion is required, parenthesis are used to enclose the ion with the subscript going outside the parenthesis. For example, the very first formula used is Fe(NO3)2. This means that two NO3¯ are involved in the compound. Without the parenthesis, the formula would be FeNO32, a far cry from the correct formula. When you say a formula involving parenthesis out loud, you use the word "taken" as in the formula for ammonium sulfide, which is (NH4)2S. Out loud, you say "N H four taken twice S." OR with the formula for copper(II) chlorate, which is Cu(ClO3)2. You say " Cu Cl O three taken twice." 11 Example #1 - write the name for Fe(NO3)2 Step #1 - decide if the cation is one showing variable charge. If so, a Roman numeral will be needed. In this case, iron does show variable charge. If a variable charge cation is involved, you must determine the Roman numeral involved. You do this by computing the total charge contributed by the polyatomic ion. In this case, NO3¯ has a minus one charge and there are two of them, making a total of minus 2. Therefore, the iron must be a positive two, in order to keep the total charge of the formula at zero. Step #2 - determine the name of the polyatomic ion. Nitrate is the name of NO3¯. The correct name is iron(II) nitrate. The common name would be ferrous nitrate. Example #2 - write the name for NaOH Step #1 - the cation, Na+, does not show a variable charge, so no Roman numeral is needed. The name is sodium. Step#2 - OH¯ is recognized as the hydroxide ion. The name of this compound is sodium hydroxide. Usually, at this point, a cry is heard in the Chemist’s classroom. "But how do you know that OH¯ is hydroxide?" is the plaintive wail. The stock Chemists answer is "Well, how do you know anything? How do you know your phone number? How do you know your best friend's name? In fact, how do you know your name?" There are three things you must memorize: the name (hydroxide), the symbol (OH) and the charge (minus one). You must put in the time to learn this nomenclature stuff. It does not come easy and the Chemists realizes you'd rather be spending the time doing more important things: going cool places with friends, spending time with members of the opposite sex, spending your parents' money, sleeping, etc. Maybe some other time. Right now, let's move on. Example #3 - write the name for KMnO4 Step #1 - the cation, K+, does not show a variable charge, so no Roman numeral is needed. The name is potassium. 12 Step#2 - MnO4¯ is recognized as the permanganate ion. The name of this compound is potassium permanganate. Example #4 - write the name for Cu2SO4 Step #1 - decide if the cation is one showing variable charge. If so, a Roman numeral will be needed. In this case, copper does show variable charge. If a variable charge cation is involved, you must determine the Roman numeral involved. You do this by computing the total charge contributed by the polyatomic ion. In this case, SO42¯ has a minus two charge and there is only one, making a total of minus 2. Therefore, the copper must be a positive one. Why? Well, there must be a positive two to go with the negative two in order to make zero. Since the formula shows two copper atoms involved, each must be a plus one charge. Step #2 - determine the name of the polyatomic ion. Sulfate is the name of SO42¯. The correct name is copper(I) sulfate. The common name would be cuprous sulfate. Example #5 - write the name for Ca(ClO3)2 The first part of the name comes from the first element's name: calcium. You also determine that it is not a cation of variable charge. The second part of the name comes from the name of the polyatomic ion: chlorate. This compound is named calcium chlorate. Example #6 - write the name for Fe(OH)3 Iron is an element with two possible oxidation states. The iron is a +3 charge because (1) there are three hydroxides, (2) hydroxide is a minus one charge, (3) this gives a total charge of negative three and (40 there is only one iron, so it must be a +3. Therefore the first part of the name is iron(III). The second part of the name is hydroxide, the name of the polyatomic ion. 13 The name of this compound is iron(III) hydroxide (or ferric hydroxide when using the common method). Practice Problems The cations in this first set are all of fixed oxidation state, so no Roman numerals are needed. Write the correct name for: 1) AlPO4 2) KNO2 3) NaHCO3 4) CaCO3 5) Mg(OH)2 6) Na2CrO4 7) Ba(CN)2 8) K2SO4 9) NaH2PO4 10) NH4NO3 Answers to Set One 1) aluminum phosphate 2) potassium nitrite 3) sodium hydrogen carbonate [sodium bicarbonate] 4) calcium carbonate 5) magnesium hydroxide 6) sodium cromate 14 7) barium cyanide 8) potassium sulfate 9) sodium dihydrogen phosphate 10) ammonium nitrate These formulas involve the use of a polyatomic ion. The cations are all of variable oxidation state, so Roman numerals are needed. Write the correct name for: 11) Sn(NO3)2 12) FePO4 13) Cu2SO4 14) Ni(C2H3O2)2 15) HgCO3 16) Pb(OH)4 17) Cu2Cr2O7 18) Cu(ClO3)2 19) FeSO4 20) Hg2(ClO4)2 Answers to Set Two 11) tin(II) nitrate [stannous nitrate] 12) iron(III) phosphate [ferric phosphate] 13) copper(I) sulfate [cuprous sulfate] 14) nickel(II) acetate [nickelous acetate] 15) mercury(II) carbonate [mercuric carbonate] 16) lead(IV) hydroxide [plumbic hydroxide] 15 17) copper(I) dichromate [cuprous dichromate] 18) copper(II) chlorate [cupric chlorate] 19) iron(II) sulfate [ferrous sulfate] 20) mercury(I) perchlorate [mercurous perchlorate] These formulas mix the use of the two types of cations. Write the correct name for: 21) KClO3 22) SnSO4 23) Al(MnO4)3 24) Pb(NO3)2 25) Mg3(PO4)2 26) CuH2PO4 27) CaHPO4 28) Fe(HCO3)3 29) Na2CO3 30) MnSO4 Answers 21) potassium chlorate 22) tin(II) sulfate [stannous sulfate] 23) aluminum permanganate 24) lead(II) nitrate [plumbous nitrate] 25) magnesium phosphate 26) copper(I) dihydrogen phosphate [cuprous dihydrogen phosphate] 16 27) calcium hydrogen phosphate 28) iron(III) hydrogen carbonate [ferric hydrogen carbonate, iron(III) bicarbonate, ferric bicarbonate] Yep! Gotta know all four! 29) sodium carbonate 30) manganese(II) sulfate [manganous sulfate] Compounds Involving a Polyatomic Ion Given Name, Write the Formula These compounds to follow ARE NOT binary compounds. They contain three or more elements, as opposed to only two in a binary compound. The Greek method WILL NOT be used. That naming technique is used only for binary compounds of two nonmetals. That means, if you see a formula like BaSO4, the name is not barium monosulfur tetraoxide. Many unaware Chemists students over the years have made this error and suffered for it. Consequently, a warning: it is important that you learn to recognize the presence of a polyatomic ion in a name. Many Chemists students have made it their first priority to make a set of flashcards with the name on one side and the ion and its charge on the other. Then, carry them everywhere and use them. The cations used will be a mix of fixed charges AND variable charges. You must know which are which. Another warning: you must also know the formula and charge associated with each polyatomic ion' name. For example, NO3¯ is called nitrate and it has a minus one charge. The formula and charge are not inherent in the name. Use of Parenthesis When more than one polyatomic ion is required, parenthesis are used to enclose the ion with the subscript going outside the parenthesis. For example, the very first name used is copper(II) chlorate. The correct formula will require the use of parenthesis. When you say a formula involving parenthesis out loud, you use the word "taken" as in the formula for ammonium sulfide, which is (NH4)2S. Out loud, you say "N H four taken twice S." OR with the formula for copper(II) nitrate, which is Cu(NO3)2. You say " Cu N O three taken twice." 17 On writing the formula from the ions, you may want to review Charge-Crossing. or Least-Common-Multiple, for more information. Example #1 - write the formula for copper(II) chlorate Step #1 - the first word tells you the symbol of the cation. In this case it is Cu. Step #2 - the Roman numeral WILL tell you the charge on the cation. In this case it is a positive two. Step #3 - the polyatomic formula and charge comes from the second name. In this case, chlorate means ClO3¯. Step #4 - remembering the rule that a formula must have zero total charge, you write the formula Cu(ClO3)2. This graphic summarizes example #1: Example #2 - write the formula for silver cyanide Step #1 - the first word tells you the symbol of the cation. In this case it is Ag+. Step #2 - silver has a constant charge of +1, it is not a cation with variable charge. Step #3 - the polyatomic formula and charge comes from the second name. In this case, cyanide means CN¯. Step #4 - remembering the rule that a formula must have zero total charge, you write the formula AgCN. This graphic summarizes example #2: 18 Usually, at this point, a cry is heard in the Chemist’s classroom. "But how do you know that cyanide is CN¯?" is the plaintive wail. The stock Chemists answer is "Well, how do you know anything? How do you know your phone number? How do you know your best friend's name? In fact, how do you know your name?" There are three things you must memorize: the name (cyanide), the symbol (CN, not Cn, by the way) and the charge (minus one). You must put in the time to learn this nomenclature stuff. It does not come easy and the Chemists realizes you'd rather be spending the time doing more important things: going cool places with friends, spending time with members of the opposite sex, spending your parents' money, eating, etc. Maybe some other time. Right now, let's move on. Example #3 - write the formula for plumbic hydroxide Step #1 - the cation, Pb4+, does show a variable charge. The "-ic" ending means the higher of the two, for this cation that means +4. Step#2 - hydroxide is recognized as OH¯. The formula of this compound is Pb(OH)4. Notice that it is not PbOH4. This graphic summarizes example #3: You might want to read about a problem with hydroxide that many students suffer from. Example #4 - write the formula for sodium phosphate Step #1 - the cation, sodium, is Na+, and it does not show a variable charge. Step#2 - phosphate is PO43¯. The formula of this compound is Na3PO4. Notice that no parenthesis are required since only one polyatomis is used. This graphic summarizes example #4: 19 Example #5 - write the formula for mercurous nitrate Step #1 - the cation, mercurous, does show a variable charge and its formula is unusual. It is Hg22+. The "-ous" ending indicates the lower of the two charges mercury shows and that is the +1 charge. Remember that, in this particular case, Hg+ is wrong. Step#2 - nitrate is NO3¯. The formula of this compound is Hg2(NO3)2. This formula is not reduced. This graphic summarizes example #5: Example #6 - write the name for barium carbonate Step #1 - the cation, barium, does not show a variable charge and its symbol is Ba2+. Step#2 - carbonate is CO32¯. The formula of this compound is BaCO3. This graphic summarizes example #6: Example #6 - write the name for mercury(I) phosphate Step #1 - the cation, mercury(I), does show a variable charge and its symbol is Hg<SUB.2< sub>2+. Notice that there is a subscript of two and the charge is +2. Therefore, EACH Hg atom is +1, leading to the name mercury(I). Step#2 - phosphate is PO43¯. The formula of this compound is (Hg2)3(PO4)2. 20 Note the use of parenthesis around both parts (positive and negative) of the formula. It would be incorrect to write this formula: Hg6(PO4)2. We want the formula to show that mercury(I) comes in groups of two and that there are three of them. Practice Problems The cations in this first set are all of fixed oxidation state, so no Roman numerals are needed. Write the correct formula for: 1) silver carbonate 2) potassium hydrogen phosphate 3) aluminum hydroxide 4) sodium hydrogen carbonate 5) calcium acetate 6) potassium permanaganate 7) calcium perchlorate 8) lithium carbonate 9) magnesium hydrogen sulfite 10) sodium hypochlorite Answers to Set One 1) Ag2CO3 2) K2HPO4 3) Al(OH)3 4) NaHCO3 5) Ca(C2H3O2)2 6) KMnO4 21 7) Ca(ClO4)2 8) Li2CO3 9) Mg(HSO3)2 10) NaClO These formulas involve the use of a polyatomic ion. The cations are all of variable oxidation state, so Roman numerals are needed. Write the correct formula for: 11) tin(IV) chlorite 12) mercury(II) phosphate 13) tin(II) carbonate 14) mercurous acetate 15) lead(II) chromate 16) copper(I) sulfite 17) stannous dichromate 18) iron(III) nitrate 19) ferric sulfate 20) ferrous hydroxide Answers to Set Two 11) Sn(ClO2)4 12) Hg3(PO4)2 13) SnCO3 14) Hg2(C2H3O2)2 15) PbCrO4 16) Cu2SO3 22 17) SnCr2O7 18) Fe(NO3)3 19) Fe2(SO4)3 20) Fe(OH)2 These formulas mix the use of the two types of cations. Write the correct formula for: 21) potassium perchlorate 22) lead(IV) hydrogen phosphate 23) aluminum sulfate 24) iron(II) bicarbonate 25) barium iodate 26) tin(II) hydrogen sulfide 27) magnesium dihydrogen phosphate 28) plumbous cyanide 29) silver phosphate 30) cobalt(III) nitrite and two special additions: 31) ammonium sulfate 32) ammonium nitrate Answers 21) KClO4 22) Pb(HPO4)2 23) Al2(SO4)3 23 24) Fe(HCO3)2 25) Ba(IO3)2 26) Sn(HS)2 27) Mg(H2PO4)2 28) Pb(CN)2 29) Ag3PO4 30) Co(NO2)3 31) (NH4)2SO4 32) NH4NO3 Nomenclature of Inorganic Acids Recognizing an Acid At this very beginning level, you will recognize an acid by the fact that its formula starts with H, as in these examples: HCl HNO3 H2SO4 HClO3 H3BO3 As you become more sophisticated in your chemistry, you will realize that there are many acid formulas that do not start with H, but those will almost all be left for another time. There is one exception to this: the formula CH3COOH should be recognized as acetic acid. The particular way it is written is common in organic chemistry. An alternate way to write acetic acid is HC2H3O2. This is done in the inorganic style, which you are currently studying. One last comment before looking at how to name acids: the formula H2O should not be considered an acid. It is the formula for water. It is not an acid. When you study acid-base behavior later in the school year, you will learn more about water's role in acid-base chemistry, but not now. 24 Naming Acids In order to explain acid naming, the sequence of HCl, HClO, HClO2, HClO3, and HClO4 will be discussed in order. HCl is a binary acid. All binary acids are named the same way: 1. 2. 3. 4. the prefix "hydro" is used. the root of the anion is used. the suffix "ic" is used. the word "acid" is used as the second word in the name. The name for HCl is hydrochloric acid. Other binary acids you are responsible for are HF, HBr, HI, and H2S. 1) HClO is an acid involving a polyatomic ion. You MUST recognize the polyatomic ion in the formula. There is no other way to figure out the name. If you don't recognize the polyatomic, then you're sunk without a trace. The polyatomic ion is ClO¯ and its name is hypochlorite. Any time you see the "ite" suffix, you change it to "ous" and add the word acid. The name of HClO is hypochlorous acid. 2) HClO2 has the ClO2¯ polyatomic ion in it. The name of this ion is chlorite. Since the "ite" suffix is used, it gets changed to "ous." The name of HClO2 is chlorous acid. 3) HClO3 has the ClO3¯ polyatomic ion and its name is chlorate. Any time you know the "ate" ending is used on the polyatomic, you use "ic" when you write the corresponding acid formula. The name of HClO3 is chloric acid. 25 4) HClO4 has the ClO4¯ polyatomic ion and its name is perchlorate. Since the "ate" suffix is used, it gets changed to "ic." The name of HClO4 is perchloric acid. In the Chemists's estimation there are two keys. You have to: 1. recognize when a polyatomic is present and 2. know its name. Only then can you know to change the "ite" suffix to "ous" and the "ate" suffix to "ic" when it is an acid. Practice Problems Name the following acids: 1) H3PO4 2) H2CO3 3) H2SO4 4) HIO3 5) HF 6) HNO2 Write the formula for these acids: 7) hydrobromic acid 8) hydrocyanic acid [this has a twist in it] 9) nitric acid 10) sulfurous acid 11) phosphorous acid 26 12) acetic acid 1) phosphoric acid 2) carbonic acid 3) sulfuric acid 4) iodic acid 5) hydrofluoric acid 6) nitrous acid 7) HBr 8) HCN [even though CN¯ is polyatomic, it is named according to the binary rule] 9) HNO3 10) H2SO3 11) H3PO3 12) CH3COOH or HC2H3O2 Here are 10 more: Name the following acids: 1) H3PO3 2) HClO3 3) H2SO3 4) HBrO3 5) HI 6) CH3COOH Write the formula for these acids: 7) hydrochloric acid 27 8) hydrosulfic acid [this has a twist in it] 9) perchloric acid 10) hydrogen hydroxide Answers 1) phosphorous acid 2) chloric acid 3) sulfurous acid 4) bromic acid 5) hydroiodic acid (not hydroidiotic acid!) 6) acetic acid Write the formula for these acids: 7) HCl 8) H2S 9) HClO4 10) HOH (more usually know as H2O or water) The Nomeclature of Hydrates Hydrates are substances that include water into their formula. The water is not actually part of the chemical substance and this is reflected in the way the formula is written. Here is the example: CuSO4 . 5 H2O This formula means that for every one CuSO4 in the piece of this substance you are holding, there are also five water molecules. No, the substance is not wet, it appears dry. There are some hydrates that have a wet appearance, but most appear perfectly dry to the eye and to the touch. The dot IS NOT a multiplication sign. Remember, this is chemistry, not math. 28 Here is the name: copper(II) sulfate pentahydrate. Notice penta meaning five and hydrate meaning water. You would use this name both when writing the name or speaking it. That means that when you hear "pentahydrate," you have to know to write the dot and then the 5 H2O. Practice Problems 1) Suppose you heard "trihydrate." What would you write? 2) Suppose you heard "octahydrate." What would you write? 3) Name this substance: MgSO4 . 9 H2O 4) Write the formula for: barium chloride dihydrate Hydrate Problem Answers 1) trihydrate = . 3 H2O 2) octahydrate = . 8 H2O Now, I know you may have just said three and eight to yourself. That's OK. Just remember the business with the dot AND putting H2O. One really silly mistake I've seen is where the kid multiplies everything out. For example, with trihydrate, the person writes H6O3. So, what they did was take the three which should be out front and distributed it over the H2O. Nah! No! Nein! Non! You get the point. Right? 3) Name this substance: MgSO4 . 9 H2O 4) Write the formula for: barium chloride dihydrate Answers: 3) Magnesium sulfate nonahydrate 4) BaCl2 . 2 H2O 29 30