Microsoft Word Free Math Add-In Single Variable Calculus Differential The deriv function will yield the first derivative with respect to the variable indicated. The syntax is deriv(function, variable). The deriv function may be omitted. There is an alternate way to find the first derivative with respect to the particular variable, x. Enter the function as an expression in the variable x. Right-click and select Differentiate on x from the menu. The derivn function will yield a higher order derivative for a given function. The syntax is derivn(function, variable, n) where n ∈ {2, 3, 4, …..}, the order. Three arguments are required. There is an alternate way to find the nth derivative with respect to the particular variable, x. Enter the function as an expression in the variable x. Right-click and select Differentiate on x from the menu n times using the previous input lines. Example 1: Find the first derivative for a given function. Consider the input: πππππ£(arccos(π₯ − 3) , π₯) Right-click on the input line and select Simplify. ©2009 Nord Page 1 Microsoft Word Free Math Add-In The output is: − 1 √−(π₯ − 3)2 + 1 An easier way to get the same answer does not involve the deriv command. Type in the expression as follows: arccosβ‘(π₯ − 3) Right-click and select Differentiate on x. ©2009 Nord Page 2 Microsoft Word Free Math Add-In The output is: − 1 √−(π₯ − 3)2 + 1 Example 2: Find the third derivative with respect to x for a given function. Consider the input: sin−1 π₯ πππ β‘π₯ Right-click and select Differentiate on x. ©2009 Nord Page 3 Microsoft Word Free Math Add-In The answer for the first derivative is: sec(π₯)β‘tan(π₯)β‘sin−1(π₯) + sec(π₯) √−π₯ 2 + 1 Right click within the last output and select Differentiate on x . The answer is: π₯ sec(π₯) (−π₯ 2 + 3 1)2 + 2 sec(π₯)β‘sin−1(π₯) tan(π₯)2 + 2 sec(π₯) tan(π₯) √−π₯ 2 + 1 + sec(π₯)β‘sin−1(π₯) Right click within in the last output and select Differentiate on x a last time. The answer is: 3β‘π₯ 2 sec(π₯) 5+ (−π₯ 2 + 1)2 3β‘π₯ sec(π₯) tan(π₯) (−π₯ 2 + 3 1)2 + 6 sec(π₯)β‘sin−1(π₯) tan(π₯)3 + + 5 sec(π₯)β‘tan(π₯)β‘sin−1 (π₯) + 6 sec(π₯) tan(π₯)2 √−π₯ 2 + 1 + sec(π₯) 3 (−π₯ 2 + 1)2 3 sec(π₯) √−π₯ 2 + 1 The derivn command will allow the result to be displayed after one input line. Consider the input: sin−1 π₯ πππππ£π( , π₯, 3) πππ β‘π₯ Right click and select Simplify. ©2009 Nord Page 4 Microsoft Word Free Math Add-In The output is: 3β‘π₯ 2 sec(π₯) 5+ (−π₯ 2 + 1)2 3β‘π₯ sec(π₯) tan(π₯) (−π₯ 2 + 3 1)2 + 6 sec(π₯)β‘sin−1(π₯) tan(π₯)3 + + 5 sec(π₯)β‘tan(π₯)β‘sin−1 (π₯) + 6 sec(π₯) tan(π₯)2 √−π₯ 2 + 1 + sec(π₯) 3 (−π₯ 2 + 1)2 3 sec(π₯) √−π₯ 2 + 1 Example 3: Given a polynomial, find the 3rd derivative with respect to x. Consider the input: πππππ£π(2π₯ 5 − 2π₯, π₯, 3) The output is: 120β‘π₯ 2 The same output can be obtained with an initial input of an expression: 2π₯ 5 − 2π₯ Right click and select Differentiate on x. Repeat two more times with right-clicking on the previous outputs. The first and second and third derivatives are: 10β‘π₯ 4 − 2 40β‘π₯ 3 ©2009 Nord Page 5 Microsoft Word Free Math Add-In 120β‘π₯ 2 ©2009 Nord Page 6 Microsoft Word Free Math Add-In Single Variable Calculus Integrals There are three ways to evaluate an indefinite integral. ο· ο· ο· Type an expression and select Integrate on x. Use the integral symbol in the top ribbon and select Simplify. Use the command, integral, and input integral(input, variable) and select Simplify. I have seen that the third approach execute when involving a radical, here as the first two approaches may not evaluate and simply follow a return of the original input. The software appears to be cautious when working with a radical and requiring that the radical does not take on a value that is zero (or negative). The first approach is the easiest to input. There are two ways to evaluate a definite integral. ο· ο· Use the integral symbol in the top ribbon and select Simplify. Use the command, integral, and input integral(input, variable, lowervalue, uppervalue). Example 1: Type an expression. Select Integrate on x from the drop-down menu to integrate on x with the expression. Consider the example: √4 − π₯^2 Place the cursor in the middle and right click. Choose Integrate on x. ©2009 Nord Page 7 Microsoft Word Free Math Add-In The output is: π₯β‘√−π₯ 2 + 4 π₯ + 2 tan−1 ( )+Π‘ 2 √−π₯ 2 + 4 Example 2: Evaluate a definite integral. Use the integral symbol from the top ribbon. ©2009 Nord Page 8 Microsoft Word Free Math Add-In Consider the input: 5 ∫ √π₯ 2 − 4 ππ₯ 4 The right arrow button was used after the square root not place the dx underneath the square root. Right click and select Simplify from the menu. The output is: 2β‘ ln(2β‘√3 + 4) − 2 ln(√21 + 5) + 5β‘√21 − 4β‘√3 2 Right click within this output and select Calculate. ©2009 Nord Page 9 Microsoft Word Free Math Add-In The output is: 4.0285533270189 Example 3: Evaluate an indefinite integral that would involve a substitution. The input is: ∫ π₯ √π₯ − 1β‘ππ₯ Right click and select Simplify to yield the output: 3 2β‘π₯β‘(π₯−1)2 3 5 − 4β‘(π₯−1)2 15 The output does not include the integration constant. This will occur when evaluating some indefinite integrals. Consider another example where the input is only an expression: π₯√π₯ 2 − 9 Right click and select Integrate on x to give: 3 (π₯ 2 − 9)2 +Π‘ 3 The command integral would have yielded the same answer. The right arrow button should be used before inputting the comma. This will ensure that the comma and dx are not under the radical. The input is: ©2009 Nord Page 10 Microsoft Word Free Math Add-In 2 πππ‘πππππ(π₯ √π₯ 2 − 9, π₯) Select Simplify to give the answer: 3 (π₯ 2 − 9)2 +Π‘ 3 Example 4: Evaluate the definite integral: 1.5 ∫ √4 − π₯ 2 ππ₯ 1 Using the integral symbol in the top ribbon and selecting Simplify gives the output: 1.5 ∫ √−π₯ 2 + 4 ππ₯ 1 The definite integral is not evaluated. Consider trying this another way using the integral command and inputting: πππ‘πππππ(√−π₯ 2 + 4, π₯, 1,1.5) Again, the output is not simplified: 1.5 ∫ √−π₯ 2 + 4 ππ₯ 1 A work-around would be to consider an indefinite integral: ∫ √4 − π₯ 2 ππ₯ The output is simplified: π₯β‘√– π₯ 2 + 4 π₯ + 2 tan−1 ( )+Π‘ 2 √−π₯ 2 + 4 Apply the Fundamental Theorem by evaluating F(1.5) – F(1) and cut and paste from the previous output. Consider the new input: 1.5β‘√−1.52 + 4 1.5 1.0β‘√−1.02 + 4 1.0 ( + 2 tan−1 ( ) −β‘( + 2 tan−1 ( )) 2 2 2 √−1.5 + 4 √−1.0 + 4 Select Calculate. ©2009 Nord Page 11 Microsoft Word Free Math Add-In The output is: 2β‘ tan−1 ( 3β‘√7 3β‘√7 π √3 − − )+ 7 8 3 2 Select Calculate again to give: 0.7750579446311 Mathematica gives the same answer and evaluates the definite integral directly as shown below: Example 5: Evaluate a definite integral involving a trigonometric function. Consider the input: ©2009 Nord Page 12 Microsoft Word Free Math Add-In 5 ∫ sinx ππ₯ 0 The Math Preferences needs to be set. The angle measure should be in radian mode as shown below: The output from our example is: 1 − cos(5) Right-click and select Calculate from the menu to give: 0.7163378145368 Example 6: Evaluate an indefinite integral involving a trigonometric function. Consider the input: ©2009 Nord Page 13 Microsoft Word Free Math Add-In (cos π₯)2 Right-click and select Simplify to give: sin(2β‘π₯) π₯ + +Π‘ 4 2 Example 7: Take the derivative with respect to x for the following example involving an integral. π₯ ∫ 3π‘β‘ππ‘ 2 Right-click and select Simplify to give: 3β‘π₯ 2 −6 2 Right-click and select Differentiate on x. The Fundamental Theorem tells us the answer is: 3β‘π₯ Example 8: Evaluate the following definite integral by using the integral command. ©2009 Nord Page 14 Microsoft Word Free Math Add-In 6 ∫ π₯ √π₯ − 3β‘ππ₯ 4 The input is: πππ‘πππππ(π₯√π₯ − 3, π₯, 4,6) Select Simplify to give: 5 4 · 32 12 − + 12β‘√3 − 15 5 Select Calculate to give: 14.2276877526612 Example 9: Integrate using trigonometric functions and the superscript feature in the top ribbon. Consider the example: sinβ‘π₯β‘β‘cosβ‘(π₯)^5 Trigonometric functions are recognized. After typing one in, press enter to key in the argument. A blue box will appear as shown below: Parentheses are optional. As long as what is typed is within the blue box, the add-in will understand this as the argument. In the example below, typing cos (x) followed with a right arrow will ensure that the cos(x) is the base. sin π₯β‘ cos(π₯) ^5 Select Integrate on x to give: − ©2009 Nord cos(π₯)6 +Π‘ 6 Page 15 Microsoft Word Free Math Add-In Single Variable Calculus Graphing The table below describes some graphing commands. In most instances, the command may be absent. The exception is the plotparam command that is required. The commands are not case sensitive. That is, the use of capitalization is optional and will not change whether the line executes. Command Example Notation Requirements plot ππππ‘(3 ∗ π₯ 2 + 12 ∗ π₯) plotDataSet plotEq plotIneq ππππ‘π·ππ‘ππππ‘({{2, 3}, {5, −1}}) ππππ‘πΈπ(π₯ 2 + π¦ 2 = 9) ππππ‘πΌπππ(π₯ ≤ 3 + π¦) plotParam ππππ‘πππππ(sin π‘, π‘^2) plotPolar ππππ‘πππππ(3 × sin π) π π ππππ‘ππππππ·ππ‘ππππ‘({{2, } , {8, − }}) 3 2 Input function, f(x). Input point, {x, y}. Input f(x, y) = c. Input inequality in x and y. Input (f(t), g(t))where x=f(t) and y=g(t). Input π = π(π). plotPolarDataSet Input point {π, π}. DropDown Menu Option to Execute Simplify Calculate Simplify Simplify Simplify Simplify Calculate Graphing in two dimensions Here are a couple of options of how to input multiple equations. Method 1: Use the show command and this will allow the input of both equations with a single application of the Insert New Equation command. Insert New Equation can be found here: Input: ©2009 Nord Page 16 Microsoft Word Free Math Add-In π βππ€(ππππ‘(π ∗ π₯ 2 + π ∗ π₯), ππππ‘(2ππ₯ + π)) Select Simplify from the right-click menu. This will bring up the two graphs. The show command needs the following syntax: show(plot1example, plot2example) Method 2: Here are the equations. Each equation is inserted separately with Insert New Equation. π¦ = π ∗ π₯2 + π ∗ π₯ π¦ =2∗π∗π₯+π Use the mouse (left click and drag over the top of these equations with keeping the mouse pressed down) and highlight both simultaneously now. There cannot be any text between these equations. You only want the equations highlighted. You should see this image on your screen: After both are highlighted (in blue), right click to bring up the option, Plot in 2D. You need to right click and not left click. You are now working with both equations. ©2009 Nord Page 17 Microsoft Word Free Math Add-In Either method should return this graph: The animate option appears by default when a variable is introduced such as a. Example 1: Graph the following. Use the Trace command to find information about points on the curve. π = 1 − 2 cos 3π Input the following using Insert New Equation. π = 1 − 2 cos 3π Select Plot in 2D. ©2009 Nord Page 18 Microsoft Word Free Math Add-In The following will appear: Select Trace. ©2009 Nord Page 19 Microsoft Word Free Math Add-In Example 2: Give an example using the plotparam command. Consider the input: ππππ‘πππππ(2 sin(2π‘) , 3 sin(3π‘)) Select Simplify to get: Example 3: Give an example using the plotparam command and the Trace feature. Consider the input: ππππ‘πππππ(2 sin(2π‘) , 3 sin(π‘)) ©2009 Nord Page 20 Microsoft Word Free Math Add-In Select Simplify and then apply the Trace feature. Example 4: Plot the following equation. π₯ 2 − π₯π¦ − 5π¦ − 1 = 0 Input the equation, right-click, and select Plot in 2D. Use the Zoom out feature to capture the hyperbola. Zoom out using this button. ©2009 Nord Page 21