EDTA Titration of the Hardness of Water Purpose: In this experiment one is to design a procedure to find the amount of calcium in unknown samples. This should be a reproducible procedure. Procedure: An EDTA solution with a concentration of 0.1M should be standardized using calcium carbonate. This should take about 1.86g of EDTA in 500mL of distilled water. Make a buffer of 10 pH using NH4 and HCl. Using 20mL of calcium carbonate and 5mL of buffer and an indicator one will do the standardization. The determination of calcium in the water, use 25mL of tap water, 5mL of buffer and indicator titrate with EDTA. Then For the calcium determination for the antacid tablets, make a 100mL solution consisting of 7.5mL solution of HCl, 5mL of buffer and indicator titrate with EDTA. Determine the amount of calcium in tablets, and in the water using collected data. Data: EDTA: 1.8612g CaCO3: 0.2533g CaCO3: 0.00253mol In 250mL Water 0.01012 M CaCO3 Standardization Trial 1 2 3 Average Volume EDTA (mL) 27.70 23.31 26.72 25.91 Molarity of EDTA (M) 0.0091 0.0108 0.0095 0.0098 Hardness of Water Trial 1 2 3 Average Tablet # 1 2 3 Volume EDTA (mL) 6.21 5.00 5.00 5.40 Tablet Mass (g) 1.273 1.255 1.267 Ca2+ Concentration (M) 0.00243 0.00196 0.00196 0.00212 ppm in Water 97.38 78.55 78.55 84.82 Titration only used 0.5g Antacid Tablet Ca2+ in Antacid Tablet Trial Volume EDTA used (mL) 6.72 7.12 5.50 6.45 1 2 3 Average Ca2+ in Tablet (g) Mass % Ca2+ in Tablet 0.1677 0.1752 0.1366 0.1598 13.17 13.96 10.78 12.63 Calculations: Grams of EDTA needed πππππ πππ π πΈπ·ππ΄ ππππ ππππ × ππππππ ππππ × = 1 πππ πΈπ·ππ΄ π ππππππ Molarity of EDTA Grams of EDTA needed Example π πΆππΆπ3 ×πππ πΆππΆπ3 πππ πΈπ·ππ΄ 0.01012π πΆππΆπ3 ×0.025πΏ πΆππΆπ3 0.010012πΏ = π πΈπ·ππ΄ 292.14π πΈπ·ππ΄ 0.01π × 0.500πΏ × = 1.8612π ππππππ 1 πππ πΈπ·ππ΄ Molarity of EDTA for Trial 1 = 0.0091π πΈπ·ππ΄ Moles of CaCO3 1 πππ πΆππΆπ3 ππΆππΆπ3 × = πππ πΆππΆπ3 100.087π Molarity of CaCO3 πππππ πΆππΆπ3 =π πππ Moles of CaCO3 Example Ca2+ in Tap water Ca2+ in Tap water for Trial 1 1 πππ πΆπ2+ 1 πππ 0.2533π × 1 πππ πΆππΆπ3 = 0.00253πππ πΆππΆπ3 100.087π Molarity of CaCO3 Example 0.00253πππππ πΆππΆπ3 = 0.1012π πΆππΆπ3 0.250πΏ πππ πΈπ·ππ΄ × π πΈπ·ππ΄ × × = 1 πππ πΈπ·ππ΄ πππ π€ππ‘ππ πΆπ2+ ππππ 0.00621πΏ × 0.0098π × PPM of Ca2+ PPM of Ca2+ πππππ πππ π 1000ππ πΆπ2+ π × × = πππ 1 πππ 1π Mass % Ca2+ expected in tablet Mass of Ca+2 in Antacid πππππ πππ π 1 πππ 1 πππ 0.025πΏ = 0.00243π 40.078π 1000ππ × = 97.38 πππ 1 πππ 1π 0.5ππΆππΆπ3 × 1πππ 100.0869π × 1πππ πΆπ2+ 1πππ πΆππΆπ3 2+ × 40.078π 1πππ = 0.20023π πΆπ2+ 0.20023π πΆπ = 15.74% 1.273π π‘πππππ‘ Mass of Ca+2 in Antacid × ππππππ‘ πππ π .5π =π Percentage of Ca2+ πΆπ2+ πππππ’πππ‘ππ πππ π ππ πππ π ππ π‘πππππ‘ × Mass % Ca2+ expected in tablet example 1πππ 1πππ πΆπ2+ 40.078π ππΆππΆπ3 πππ π‘ππ × × × 100.0869π 1πππ πΆππΆπ3 1πππ π πΆπ2+ = = πππ π % π π‘πππππ‘ πππ πΈπ·ππ΄ × π πΈπ·ππ΄ × 0.00243π × 1 πππ πΆπ2+ 1 πππ πΈπ·ππ΄ 0.000672 × 0.0098π × 40.078π 1 πππ × 1.273π .5π = 0.1677π Percentage of Ca2+ for Trial 1 × 100 = % 0.1677π × 100 = 13.17% 1.273π Conclusion: This experiment was to determine the amount of calcium in antacid tablets. Overall this experiment went well, there was an error of about 19%. The calculated calcium percentage in the tablet was 15.7% and the average experimentally was 12.63%. The concentration determined for the tap water was high compared to the results from the York Water Company, which are about 20.30PPM, where we calculated an average of 84.82PPM. But this could be due to error in our experiment due to over titration. Many times the endpoint was not clear. There could have also been errors in the concentrations of solutions.