CHAPTER 8 Atomic Electron Configurations and Chemical Periodicity Outline -Collect homework -Review -Trends -Ions Kull Spring07 Lesson 23 Ch 8 1 Review Spdf notation Orbital box notation Kull Spring07 Lesson 23 Ch 8 2 Characteristics of Many-Electron Atoms: The Electron-Spin Quantum Number Name Symbol Permitted Values Property principal n positive integers(1,2,3,…) orbital energy (size) angular momentum l integers from 0 to n-1 orbital shape (The l values 0, 1, 2, and 3 correspond to s, p, d, and f orbitals, respectively.) magnetic ml integers from -l to 0 to +l orbital orientation spin ms +1/2 or -1/2 direction of e- spin Kull Spring07 Lesson 23 Ch 8 3 Kull Spring07 Lesson 23 Ch 8 4 Practice Problem 23-1 Consider this set of quantum numbers: n = 3, ℓ = 2, mℓ = -1, ms = +½ The maximum number of electrons in an atom which can share the above set of quantum numbers is A) 1 B) 14 C) 3 D) 10 E) none of the above Kull Spring07 Lesson 23 Ch 8 5 Practice Problem 23-1 Answer Consider this set of quantum numbers: n = 3, ℓ = 2, mℓ = -1, ms = +½ The maximum number of electrons in an atom which can share the above set of quantum numbers is A) 1 B) 14 C) 3 D) 10 E) none of the above Kull Spring07 Lesson 23 Ch 8 6 Practice Problem 23-2 An atom in its ground state contains 30 electrons. How many of these are in sublevels with ℓ = 2? A) 2 B) 4 C) 6 D) 8 E) 10 Kull Spring07 Lesson 23 Ch 8 7 Practice Problem 23-2 Answer An atom in its ground state contains 30 electrons. How many of these are in sublevels with ℓ = 2? A) 2 B) 4 C) 6 D) 8 E) 10 Kull Spring07 Lesson 23 Ch 8 8 Practice Problem 23-3 What are the possible values for the angular momentum quantum number ℓ ? A) integers from -ℓ to 0 to +ℓ B) 1, 2, 3, etc. C) 2, 4, 6, etc. D) +½ , -½ E) integers from 0 to n - 1 Kull Spring07 Lesson 23 Ch 8 9 Practice Problem 23-3 Answer What are the possible values for the angular momentum quantum number (ℓ )? A) integers from -ℓ to 0 to +ℓ B) 1, 2, 3, etc. C) 2, 4, 6, etc. D) +½ , -½ E) integers from 0 toLesson n -231Ch 8 Kull Spring07 10 Practice Problem 23-4 The electron configuration of the outermost electrons of atoms of the halogen group is: A) ns2np7 B) ns1 C) ns2np5 D) ns2np6(n-1)d7 E) ns2np6 Kull Spring07 Lesson 23 Ch 8 11 Practice Problem 23-4 Answer The electron configuration of the outermost electrons of atoms of the halogen group is: A) ns2np7 B) ns1 C) ns2np5 D) ns2np6(n-1)d7 E) ns2np6 Kull Spring07 Lesson 23 Ch 8 12 Practice Problem 23-5 The electronic configuration of the element whose atomic number is 26 is: A) 1s2 2s2 2p6 3s2 3p6 4s0 3d8 B) 1s2 2s2 2p6 3s2 3p6 3d6 4s2 C) 1s2 2s2 2p6 3s2 3p6 4s2 3d6 D) 1s2 2s2 2p6 3s2 3p6 4s2 3d4 4p2 E) none of the above Kull Spring07 Lesson 23 Ch 8 13 Practice Problem 23-5 Answer The electronic configuration of the element whose atomic number is 26 is: A) 1s2 2s2 2p6 3s2 3p6 4s0 3d8 B) 1s2 2s2 2p6 3s2 3p6 3d6 4s2 C) 1s2 2s2 2p6 3s2 3p6 4s2 3d6 D) 1s2 2s2 2p6 3s2 3p6 4s2 3d4 4p2 E) none of the above Kull Spring07 Lesson 23 Ch 8 14 Practice Problem 23-6 The set of quantum numbers that correctly describes an electron in a 3p orbital is A) n = 3; ℓ = 0; mℓ = 0; ms = 0 B) n = 3; ℓ = 2; mℓ = -2, -1, 0, 1, or 2; ms = +½ or -½ C) n = 3; ℓ = 1; mℓ = -1, 0, or 1; ms = +½ or -½ D) n = 4; ℓ = 0; mℓ = -1 ,0, or 1; ms = +½ or -½ E) none of the above Kull Spring07 Lesson 23 Ch 8 15 Practice Problem 23-6 Answer The set of quantum numbers that correctly describes an electron in a 3p orbital is A) n = 3; ℓ = 0; mℓ = 0; ms = 0 B) n = 3; ℓ = 2; mℓ = -2, -1, 0, 1, or 2; ms = +½ or -½ C) n = 3; ℓ = 1; mℓ = -1, 0, or 1; ms = +½ or -½ D) n = 4; ℓ = 0; mℓ = -1 ,0, or 1; ms = +½ or -½ E) none of the above Kull Spring07 Lesson 23 Ch 8 16 Practice Problem 23- 7 An atom in its ground state contains 18 electrons. How many of these are in orbitals with mℓ = 0? A) 2 B) 4 C) 6 D) 8 E) 10 Kull Spring07 Lesson 23 Ch 8 17 Practice Problem 23-7 Answer An atom in its ground state contains 18 electrons. How many of these are in orbitals with mℓ = 0? A) 2 B) 4 C) 6 D) 8 E) 10 Kull Spring07 Lesson 23 Ch 8 18 Practice Problem 23-8 The configuration for the six outer electrons in ground state oxygen atoms is A) 2s3 2p3-1 B) 2p6 C) 2s2 2p-12 2p02 D) 2s2 2p-12 2p01 2p11 E) 2s4 2p2-1 Kull Spring07 Lesson 23 Ch 8 19 Practice Problem 23-8 Answer The configuration for the six outer electrons in ground state oxygen atoms is A) 2s3 2p3-1 B) 2p6 C) 2s2 2p-12 2p02 D) 2s2 2p-12 2p01 2p11 E) 2s4 2p2-1 Kull Spring07 Lesson 23 Ch 8 20 Practice Problem 23-9 Which of the following is the electron configuration for chromium, element 24? A) 1s2 2s2 2p6 3s2 3p6 4s2 B) 1s2 2s2 2p6 3s2 3p6 4s2 3d4 C) 1s2 2s2 2p6 3s2 3p6 3d6 D) 1s2 2s2 2p6 3s2 3p6 4s1 3d5 E) 1s2 2s2 2p6 3s2 3p6 4s2 3d1 3d1 Kull Spring07 Lesson 23 Ch 8 21 Practice Problem 23-9 Answer Which of the following is the electron configuration for chromium, element 24? A) 1s2 2s2 2p6 3s2 3p6 4s2 B) 1s2 2s2 2p6 3s2 3p6 4s2 3d4 C) 1s2 2s2 2p6 3s2 3p6 3d6 D) 1s2 2s2 2p6 3s2 3p6 4s1 3d5 E) 1s2 2s2 2p6 3s2 3p6 4s2 3d1 3d1 Kull Spring07 Lesson 23 Ch 8 22 Kull Spring07 Lesson 23 Ch 8 23 Kull Spring07 Lesson 23 Ch 8 24 PERIODIC TRENDS Kull Spring07 Lesson 23 Ch 8 25 Trends in Some Key Periodic Atomic Properties: Trends in Electron Affinity Atomic and ionic size # electrons # shells – Larger orbitals, -electrons held less tightly Effective nuclear charge When higher: Electrons held more tightly Electron affinity: energy involved when an atom gains an electron to form an anion. Kull Spring07 Lesson 23 Ch 8 26 Trends in Some Key Periodic Atomic Properties: Trends in Atomic Size Atomic radii of the maingroup and transition elements. Kull Spring07 Lesson 23 Ch 8 27 Characteristics of Many-Electron Atoms: Electrostatic Effects and the Splitting of Energy Levels Factors Affecting Atomic Orbital Energies The Effect of Nuclear Charge (Zeffective) Higher nuclear charge lowers orbital energy (stabilizes the system) by increasing nucleus-electron attractions. The Effect of Electron Repulsions (Shielding) Additional electron in the same orbital An additional electron raises the orbital energy through electron-electron repulsions. Additional electrons in inner orbitals Inner electrons shield outer electrons more effectively than do electrons in the same sublevel. Kull Spring07 Lesson 23 Ch 8 28 Effective Nuclear Charge, Z* Z* is the nuclear charge experienced by the outermost electrons. Z* increases across a period owing to incomplete shielding by inner electrons. The 2s electron PENETRATES the region occupied by the 1s electron. 2s electron experiences a higher positive charge than expected. Estimate Z* by --> [ Z - (# inner electrons) ] Charge felt by 2s e- in Li Z* = 3 - 2 = 1 Be Z* = 4 - 2 = 2 B Z* = 5 - 2 = 3 and so on! Kull Spring07 Lesson 23 Ch 8 29 Ionization Energy IE = energy required to remove an electron from an atom in the gas phase. Mg (g) + 738 kJ ---> Mg+ (g) + e- Mg+ (g) + 1451 kJ ---> Mg2+ (g) + e- Mg+ has 12 protons and only 11 electrons. Therefore, IE for Mg+ > Mg Kull Spring07 Lesson 23 Ch 8 30 Trends in Some Key Periodic Atomic Properties: Trends in Ionization Energy Kull Spring07 Lesson 23 Ch 8 31 Ion Sizes + Li,152 pm 3e and 3p Li + , 78 pm 2e and 3 p Forming a cation. CATIONS are SMALLER than the atoms from which they come. The electron/proton attraction has gone UP and so size DECREASES. Kull Spring07 Lesson 23 Ch 8 32 Ion Sizes F, 71 pm 9e and 9p F- , 133 pm 10 e and 9 p Forming an anion. ANIONS are LARGER than the atoms from which they come. The electron/proton attraction has gone DOWN and so size INCREASES. Trends in ion sizes are the same as atom sizes. Kull Spring07 Lesson 23 Ch 8 33 Ion Configurations To form cations, always remove electrons of highest n value first! P [Ne] 3s2 3p3 - 3e- ---> P3+ [Ne] 3s2 3p0 3p 3p 3s 3s 2p 2p 2s 2s 1s 1s Kull Spring07 Lesson 23 Ch 8 34 Trends in Ion Sizes Active Figure 8.15 Kull Spring07 Lesson 23 Ch 8 35 Practice Problem 23-10 Which of the following has the largest radius? A) F B) N C) C D) O E) Ne Kull Spring07 Lesson 23 Ch 8 36 Practice Problem 23-10 Answer Which of the following has the largest radius? A) F B) N C) C D) O E) Ne Kull Spring07 Lesson 23 Ch 8 37 Practice Problem 23-11 Which of the following elements has the largest ionization energy? A) Na B) Ne C) F D) K E) Rb Kull Spring07 Lesson 23 Ch 8 38 Practice Problem 23-11 Answer Which of the following elements has the largest ionization energy? A) Na B) Ne C) F D) K E) Rb Kull Spring07 Lesson 23 Ch 8 39 Practice Problem 23-12 Which of the following has the greatest electron affinity (most negative value)? A) Cl B) K C) He D) Na E) Rb Kull Spring07 Lesson 23 Ch 8 40 Practice Problem 23-12 Answer Which of the following has the greatest electron affinity (most negative value)? A) Cl B) K C) He D) Na E) Rb Kull Spring07 Lesson 23 Ch 8 41 Practice Problem 23-13 In the periodic table, the most nonmetallic elements will be found A) at the top of Group 3A (13) B) at the top of Group 1A (1) C) at the top of Group 7A (17) D) at the bottom of Group 1A (1) E) at the bottom of Group 7A (17) Kull Spring07 Lesson 23 Ch 8 42 Practice Problem 23-13 Answer In the periodic table, the most nonmetallic elements will be found A) at the top of Group 3A (13) B) at the top of Group 1A (1) C) at the top of Group 7A (17) D) at the bottom of Group 1A (1) E) at the bottom of Group 7A (17) Kull Spring07 Lesson 23 Ch 8 43 Practice Problem 23-14 Which ion has the smallest radius? A) Li+ B) Na+ C) K+ D) Be2+ E) Mg2+ Kull Spring07 Lesson 23 Ch 8 44 Practice Problem 23-14 Answer Which ion has the smallest radius? A) Li+ B) Na+ C) K+ D) Be2+ E) Mg2+ Kull Spring07 Lesson 23 Ch 8 45 Practice Problem 23-15 Which of the following statements about periodic properties is incorrect? A) Both electron affinity and ionization energy decrease down a group. B) Atomic size increases to the right across a period. C) Ionization energy increases to the right across a period. D) Atomic size increases down a group. E) Electron affinity increases to the right across a period. Kull Spring07 Lesson 23 Ch 8 46 Practice Problem 23.15 Answer Which of the following statements about periodic properties is incorrect? A) Both electron affinity and ionization energy decrease down a group. B) Atomic size increases to the right across a period. C) Ionization energy increases to the right across a period. D) Atomic size increases down a group. E) Electron affinity increases to the right across a period. Kull Spring07 Lesson 23 Ch 8 47 Practice Problem 23.16 Which of the following elements has the greatest ionization energy? A) Ga B) As C) K D) Pb E) Na Kull Spring07 Lesson 23 Ch 8 48 Practice Problem 22.16 Answer Which of the following elements has the greatest ionization energy? A) Ga B) As C) K D) Pb E) Na Kull Spring07 Lesson 23 Ch 8 49 Practice Problem 23.17 Which of the following elements has the greatest electron affinity? A) Rb B) Ca C) Li D) Na E) I Kull Spring07 Lesson 23 Ch 8 50 Practice Problem 23.17 Answer Which of the following elements has the greatest electron affinity? A) Rb B) Ca C) Li D) Na E) I Kull Spring07 Lesson 23 Ch 8 51 Practice Problem 23.18 Which of the following ions and atoms has the largest radius? A) Mg B) Na C) Na+ D) Mg2+ E) Al Kull Spring07 Lesson 23 Ch 8 52 Practice Problem 23.18 Answer Which of the following ions and atoms has the largest radius? A) Mg B) Na C) Na+ D) Mg2+ E) Al Kull Spring07 Lesson 23 Ch 8 53 Practice Problem 23.19 Which of the following elements has the greatest metallic character? A) Mg B) Al C) Ca D) Ba E) Cs Kull Spring07 Lesson 23 Ch 8 54 Practice Problem 23.19 Answer Which of the following elements has the greatest metallic character? A) Mg B) Al C) Ca D) Ba E) Cs Kull Spring07 Lesson 23 Ch 8 55 Equations speed of light = wavelength x frequency c = λ X = 3.00 x 108 m/s E = nh = nh(c/) n= positive integer Planck’s constant(h) = 6.626 x 10–34 J s Eatom = Eemitted (or absorbed) radiation = nh Rydberg equation =R n2 > n1 R = 1.096776 x 107 m-1 ΔE = Efinal – Einitial = –2.18 x 10–18 J Ephoton = Estate A – Estate B = hν Kull Spring07 Lesson 23 Ch 8 56 Quantum mechanics Quantum number n– shell/level ℓ - subshell/ sublevel mℓ - orbital ms - spin Values Total number 1,2,3, …∞ 0, 1,… n-1 - ℓ, 0, + ℓ n=# subshells n-1 +½, n2 = # orbitals in a shell 2 ℓ +1 (orbitals in a subshell) -½ 2 possible Kull Spring07 Lesson 23 Ch 8 57 Practice Problem 23-20 When electrons in helium atoms fall from the 3s orbital down to the 1s orbital, how many different energies could be released if all possible pathways of decreasing energy are considered? A) 2 B) 4 C) 5 D) 6 E) 7 Kull Spring07 Lesson 23 Ch 8 58 Practice Problem 23-20 Answer When electrons in helium atoms fall from the 3s orbital down to the 1s orbital, how many different energies could be released if all possible pathways of decreasing energy are considered? A) 2 B) 4 C) 5 D) 6 E) 7 Kull Spring07 Lesson 23 Ch 8 59 Practice Problem 23-21 Of the following four electron configurations, which two represent elements that would have similar chemical properties? 1. 1s22s22p5 2. 1s22s22p6 3. [Ar]4s23d104p4 4. [Ar]4s23d104p5 A) 1 and 3 B) 1 and 4 C) 2 and 3 D) 1 and 2 E) 2 and 4 Kull Spring07 Lesson 23 Ch 8 60 Practice Problem 23-21 Answer Of the following four electron configurations, which two represent elements that would have similar chemical properties? 1. 1s22s22p5 2. 1s22s22p6 3. [Ar]4s23d104p4 4. [Ar]4s23d104p5 A) 1 and 3 B) 1 and 4 C) 2 and 3 D) 1 and 2 E) 2 and 4 Kull Spring07 Lesson 23 Ch 8 61 Practice Problem 23-22 The electron configuration for Fe2+ is 1s2 2s2 2p6 3s2 3p6 3d6. Therefore Fe2+ is A) paramagnetic with two unpaired electrons. B) paramagnetic with one unpaired electron. C) paramagnetic with three unpaired electrons. D) paramagnetic with four unpaired electrons. E) diamagnetic. Kull Spring07 Lesson 23 Ch 8 62 Practice Problem 23-22 Answer The electron configuration for Fe2+ is 1s2 2s2 2p6 3s2 3p6 3d6. Therefore Fe2+ is A) paramagnetic with two unpaired electrons. B) paramagnetic with one unpaired electron. C) paramagnetic with three unpaired electrons. D) paramagnetic with four unpaired electrons. E) diamagnetic. Kull Spring07 Lesson 23 Ch 8 63