Wiskunde gr 8 Kwartaal 1 Opdrag/ Mathematics gr 8 Term 1 Assignment
Graad 8 Wiskunde
Opdrag
Kwartaal 1 2020
Eksaminator:
Moderator:
Totaal : 50
Tyd: 1 uur
edwardsmaths
Grade 8 Mathematics
Assignment
Term 1 2020
Examiner:
Moderator:
Total: 50
Time: 1 hour
Hierdie opdrag bestaan uit 4 bladsye.
This assignment consists of 4 pages.
INSTRUKSIES EN INLIGTING
INSTRUCTIONS AND INFORMATION
1. Lees die volgende instruksies aandagtig
deur voordat die vrae beantwoord word.
2. Hierdie vraestel bestaan uit 5 vrae.
3. Beantwoord AL die vrae.
4. Dui ALLE berekeninge duidelik aan.
5. Sakrekenaars mag NIE gebruik word nie,
tensy anders vermeld.
6. Skryf netjies en leesbaar
7. Rond antwoorde af tot 2 des. syfers waar
nodig.
1. Read the following instructions carefully
before answering the questions.
2. This question paper consists of 5 questions.
3. Answer ALL the questions.
4. Clearly show ALL calculations.
5. Calculators may NOT be used in this
paper, unless stated otherwise.
6. Write neatly and legibly.
7. If necessary, answers should be rounded
off to two decimal places.
p. 1 of 4
Wiskunde gr 8 Kwartaal 1 Opdrag/ Mathematics gr 8 Term 1 Assignment
edwardsmaths
Vraag 1
Question 1
Beskou die volgende getalle:
Consider the following set of numbers:
{12; 13; 14; 15; 16; . . .28; 29; 30; 31}
{12; 13; 14; 15; 16; . . .28; 29; 30; 31}
Van hierdie stel getalle, kies die getalle wat
aan die volgende vereistes voldoen:
From this set of numbers, choose the number
that falls into the following categories:
1.1
Die faktore van 24
1.1
The factors of 24
1.2
Veelvoude van 4
1.2
Multiples of 4
1.3
Priemfaktore van 34
1.3
Prime factors of 34
1.4
Gemene faktore van 30 en 45
1.4
Common factors of 30 and 45
1.5
Gemene veelvoude van 6 en 8
1.5
Common multiples of 6 and 8
1.6
Volkome vierkante
1.6
Perfect squares
1.7
Saamgestelde getalle
1.7
Compound numbers
[7]
Vraag 2
Question 2
Skryf slegs waar of onwaar by elk van die
volgende stellings:
Write true or false for each of the following
statements:
2.1
1 is die kleinste onewe priemgetal
2.1
2.2
Die optellingsinverse van -12 is 12
2.2
2.3
Die identiteitselement van
vermenigvuldiging is 0
2.3
The identity element for
multiplication is 0
2.4
0÷5=0
2.4
0÷5=0
2.5
5÷0=0
2.5
5÷0=0
2.6
50 = 0
2.6
50 = 0
2.7
15 is ‘n faktor en ‘n veelvoud van 15
2.7
15 is a factor and multiple of 15
2.8
Die som van twee priemgetalle is
altyd ‘n priemgetal
2.8
The sum of two prime numbers is
always a prime number
1 is the smallest uneven prime
number
The additive inverse of -12 is 12
[8]
p. 2 of 4
Wiskunde gr 8 Kwartaal 1 Opdrag/ Mathematics gr 8 Term 1 Assignment
Vraag 3
edwardsmaths
Question 3
Beskou die volgende getalle. Skryf die getalle Consider the following numbers. Write down
neer wat:
the numbers that:
52 65 87 801 1024 1255 3624
52 65 87 801 1024 1255 3624
3.1
Deelbaar is deur 2
3.1
Is divisible by 2
3.2
Deelbaar is deur 3
3.2
Is divisible by 3
3.3
Deelbaar is deur 5
3.3
Is divisible by 5
[6]
Vraag 4
Question 4
Skryf 576 as ‘n produk van sy
priemfaktore.
4.1
4.2
As 420 = 2 × 2 × 3 × 5 × 7
4.2
If 420 = 2 × 2 × 3 × 5 × 7
4.2.1
Skryf die kleinste getal neer
waarmee 420 vermenigvuldig moet
word om dit ‘n volkome vierkant te
maak.
4.2.1
Write down the smallest natural
number that should be multiplied
by 420 to create a perfect square.
As verder gegee word dat
4.2.2
4.1
4.2.2
4.2.2.2
4.3
(2)
(2)
450 = 2 × 3 × 3 × 5 × 5
4.2.2.1
Write 576 as the product of its
prime factors.
If the following additional
information is given that
450 = 2 × 3 × 3 × 5 × 5
Bepaal die kleinste gemene
veelvoud (KGV) van 420 en 450.
4.2.2.1
Bepaal die grootste gemene faktor
(GGD) van 420 en 450.
4.2.2.2
Wat is die kortste tou wat ek kan
koop sodat ek dit in lengtes van
6m, 8m of 10m kan sny?
4.3
Determine the lowest common
multiple (LCM) of 420 and 450.
(2)
Determine the highest common
factor (HCF) of 420 and 450.
(2)
What is the shortest length of string
that I can buy so that I will be able
to cut it in lengths of 6m, 8m or
10m?
(2)
[10]
p. 3 of 4
Wiskunde gr 8 Kwartaal 1 Opdrag/ Mathematics gr 8 Term 1 Assignment
Vraag 5
Question 5
Vereenvoudig:
Simplify:
edwardsmaths
5.1
−3 + 7
5.1
−3 + 7
(1)
5.2
2 − (−6)
5.2
2 − (−6)
(1)
5.3
9 × (−2)
5.3
9 × (−2)
(1)
5.4
(−72) ÷ (−8)
5.4
(−72) ÷ (−8)
(1)
5.5
−2 + (−3) − (−4) + (−1)
5.5
−2 + (−3) − (−4) + (−1)
(2)
5.6
(−3)2 × (−4) ÷ (−6)
5.6
(−3)2 × (−4) ÷ (−6)
(2)
5.7
3 + (2 × −3) ÷ (−2)
5.7
3 + (2 × −3) ÷ (−2)
(3)
5.8
15 ÷ (−3) ÷ (−5)
5.8
15 ÷ (−3) ÷ (−5)
(2)
5.9
2 × (−4) + (−2) × 4
5.9
2 × (−4) + (−2) × 4
(3)
5.10
1 − √25 × (−2)2
5.10
1 − √25 × (−2)2
(3)
[19]
p. 4 of 4