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Chapter 9
Orbitals and Covalent Bond
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Atomic Orbitals Don’t Work
to explain molecular geometry.
In methane, CH
4 tetrahedral.
, the shape s
The valence electrons of carbon should be two in s, and two in p.
the p orbitals would have to be at right angles.
The atomic orbitals change when making a molecule
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Hybridization
We blend the s and p orbitals of the valence electrons and end up with the tetrahedral geometry.
We combine one s orbital and 3 p orbitals.
sp
3 hybridization has tetrahedral geometry.
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2s
In terms of energy
2p
Hybridization sp
3
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How we get to hybridization
We know the geometry from experiment.
We know the orbitals of the atom
hybridizing atomic orbitals can explain the geometry.
So if the geometry requires a tetrahedral shape, it is sp
3 hybridized
This includes bent and trigonal pyramidal molecules because one of the sp 3 lobes holds the lone pair.
6 sp 2 hybridization
C
2
H
4
Double bond acts as one pair.
trigonal planar
Have to end up with three blended orbitals.
Use one s and two p orbitals to make sp
2 orbitals.
Leaves one p orbital perpendicular.
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8
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2s
In terms of energy
2p
Hybridization
2p sp
2
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Where is the P orbital?
Perpendicular
The overlap of orbitals makes a sigma bond ( s bond)
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Two types of Bonds
Sigma bonds from overlap of orbitals.
Between the atoms.
Pi bond ( p bond) above and below atoms
Between adjacent p orbitals.
The two bonds of a double bond.
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H
H
C C
H
H
13 sp 2 hybridization
When three things come off atom.
trigonal planar
120º on s one p bond
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What about two
When two things come off.
One s and one p hybridize.
linear
15 sp hybridization
End up with two lobes 180º apart.
p orbitals are at right angles
Makes room for two p bonds and two sigma bonds.
A triple bond or two double bonds.
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2s
In terms of energy
2p
Hybridization
2p sp
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CO
2
C can make two s and two p
O can make one s and one p
O C O
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Breaking the octet
PCl
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The model predicts that we must use
the d orbitals.
dsp
3 hybridization
There is some controversy about how involved the d orbitals are.
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Trigonal
bipyrimidal can only s bond.
can’t p bond.
basic shape for five things.
dsp 3
PCl
5
Can’t tell the hybridization of Cl
Assume sp
3 to minimize repulsion of electron pairs.
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21 d 2 sp 3
gets us to six things around
octahedral
Molecular Orbital Model
Localized Model we have learned explains much about bonding.
It doesn’t deal well with the ideal of resonance, unpaired electrons, and bond energy.
The MO model is a parallel of the atomic orbital, using quantum mechanics.
Each MO can hold two electrons with
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opposite spins
Square of wave function tells probability
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What do you get?
Solve the equations for H
2
H
A
H
B
get two orbitals
MO
1
= 1s
A
- 1s
B
MO
2
= 1s
A
+ 1s
B
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The Molecular Orbital Model
The molecular orbitals are centered on a line through the nuclei
– MO
1 the greatest probability is between the nuclei
– MO
2 it is on either side of the nuclei
– this shape is called a sigma molecular orbital
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The Molecular Orbital Model
In the molecule only the molecular orbitals exist, the atomic orbitals are gone
MO
1 is lower in energy than the 1s orbitals they came from.
– This favors molecule formation
– Called an bonding orbital
MO
2 is higher in energy
– This goes against bonding
– antibonding orbital
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The Molecular Orbital Model
MO
2
1 s
1 s
MO
1
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The Molecular Orbital Model
We use labels to indicate shapes, and whether the MO’s are bonding or antibonding.
– MO
1
– MO
2
= s
1s
= s
1s
* (* indicates antibonding)
Can write them the same way as atomic orbitals
– H
2
= s
1s
2
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The Molecular Orbital Model
Each MO can hold two electrons, but they must have opposite spins
Orbitals are conserved. The number of molecular orbitals must equal the number atomic orbitals that are used to make them.
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1 s
H
2
s
1s
*
1 s s
1s
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Bond Order
The difference between the number of bonding electrons and the number of antibonding electrons divided by two
Bond Order =
# bonding-#antibonding
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