# Practice ten ```Practice 10 solution
Chapter 15
7
a. Maximum loss = 4.25 + 5.0 = 9.25
b. Profit / loss = 58 – 50 – 9.25 = -1.25
c. There are two break even prices: 59.25 (50+9.25) and 40.75(50-9.25).
8
c is the only correct statement.
13
a. Purchase a straddle, i.e., Long a put and a call on the stock. The total cost of the
straddle would be: \$10 + \$7 = \$17
b. Since the straddle costs \$17, this is the amount by which the stock would have to
move in either direction for the profit on either the call or the put to cover the
investment cost (not including time value of money considerations).
16
Position
S &lt; X1
0
Long call (X1)
0
Short 2 calls (X2)
0
Long call (X3)
Total
0
X1 &lt; S &lt; X2 X2 &lt; S &lt; X3
S – X1
S – X1
0
–2(S – X2)
0
0
S – X1
2X2 – X1 – S
X3 &lt; S
S – X1
–2(S – X2)
S – X3
(X2–X1 ) – (X3–X2) = 0
b. Vertical combination
1
Position
Long call (X2)
Long put (X1)
Total
S &lt; X1
0
X1 – S
X1 – S
X1 &lt; S &lt; X2
0
0
0
S &gt; X2
S – X2
0
S – X2
Position
Long call (X2)
Short call (X1)
Total
S &lt; X1
0
0
0
X1 &lt; S &lt; X2
0
–(S – X1)
X1 – S
S &gt; X2
S – X2
–(S – X1)
X1 – X2
17
In the bullish spread, the payoff either increases or is unaffected by stock price
increases. In the bearish spread, the payoff either increases or is unaffected by
stock price decreases.
2
22
a.
Position
Short call
Short put
Total
ST &lt; 165
0
– (165 – ST)
ST – 165
165 &lt; ST &lt; 170
0
0
0
ST &gt; 170
– (ST – 170)
0
170 – ST
Payoff
165
170
Write put
ST
Write call
b. Proceeds from writing options (from Figure 15.1):
Call = \$8.93
Put
= \$10.85
Total = \$19.78
If IBM is selling at \$167, both options expire out of the money, and profit equals
\$19.78. If IBM is selling at \$175, the call written results in a cash outflow of \$5 at
maturity, and an overall profit of: \$19.78 – \$5.00 = \$14.78
c. You will break even when either the short position in the put or the short position
in the call results in a cash outflow of \$19.78. For the put, this requires that:
\$19.78 = \$165 – ST  ST = \$145.22
For the call this requires that:
\$19.78 = ST – \$170  ST = \$189.78
d. The investor is betting that the IBM stock price will have low volatility.
23
Position
Short P1 (X = 90)
Long P2 (X = 95)
Total payoff
ST &lt; 90
-(90 – ST)
95– ST
5
90 &lt; ST &lt; 95
0
95-ST
95 – ST
95&lt;ST
0
0
0
3
The put with the higher exercise price must cost more. Therefore, the net outlay to
establish the portfolio is positive. Payoff line moves down by (P2-P1) and becomes Profit
line.
27
This strategy is a bear spread. The initial proceeds are: \$9 – \$3 = \$6
The payoff is either negative or zero:
Position
ST &lt; 50
50 &lt; ST &lt; 60
Long call (X = 60)
0
0
Short call (X = 50)
0
– (ST – 50)
Total
0
– (ST – 50)
ST &gt; 60
ST – 60
– (ST – 50)
–10
Breakeven occurs when the payoff offsets the initial proceeds of \$6, which occurs at a stock
price of ST = \$56.
C2-C1=6, Payoff moves up by 6 and becomes Profit line.
4
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