What’s coming up??? • • • • • • • • • • • • Oct 25 Oct 27 Oct 29 Nov 1 Nov 3,5 Nov 8,10 Nov 12 Nov 15 Nov 17 Nov 19 Nov 22 Nov 24 The atmosphere, part 1 Midterm … No lecture The atmosphere, part 2 Light, blackbodies, Bohr Postulates of QM, p-in-a-box Hydrogen and multi – e atoms Multi-electron atoms Periodic properties Periodic properties Valence-bond; Lewis structures VSEPR Hybrid orbitals; VSEPR Ch. 8 • Nov 26 Hybrid orbitals; MO theory Ch. 12 • • • MO theory bonding wrapup Review for exam Ch. 12 Ch. 11,12 Nov 29 Dec 1 Dec 2 Ch. 8 Ch. 9 Ch. 9 Ch. 9 Ch.9,10 Ch. 10 Ch. 10 Ch. 11 Ch. 11 Ch. 11, 12 Describing the bonding in more complicated molecules…... PROPYNE: CH3CCH 16 valence electrons Lewis Dot Structure….. H H C C C H H CENTRAL CARBON NEEDS OCTET PROPYNE: CH3CCH has the structure H H C C C H Tetrahedral Carbon: Hybridization? sp3 H Linear Carbons Hybridization? sp PROPYNE: CH3CCH has the bonding H H C sp3 overlaps with H 1s s bond C H C C H C p overlaps with C p p bonds C sp overlaps with C sp C sp3 overlaps with C sp s bond s bond H These four atoms are in a straight line C C C H H H FREE ROTATION of Methyl Group. LACTIC ACID The bonding frame work of lactic acid H H H C C H O H O C O H QUESTION H O H H C C C O THE BOND ANGLE SHOWN IS H H 1 120° 2 90° 3 4 180° 109° O H QUESTION H H H C C H O O C O THE BOND ANGLE SHOWN IS 1 H 2 3 4 120° 90° 180° 109° H QUESTION H H H C C H O C O THE BOND ANGLE SHOWN IS O 1 H 2 3 4 109° 90° 120° 180° H LACTIC ACID O O H H C H O C C H H H OK, so we have it all figured out! … or do we?? Let’s think about oxygen, O2 12 electrons … Lewis picture gives :O::O: .. .. 3 electron groups around each … sp2 and 1200 O s bond O p bond All electrons paired … diamagnetic BUT O2 is paramagnetic unpaired electrons!! MAGNETIC PROPERTIES Atoms, molecules or ions with at least one unpaired electron are paramagnetic. Paramagnetic materials are strongly attracted to magnetic fields. Nitrogen atom is PARAMAGNETIC 1s N 1s22s22p3 2s 2p Let’s try another approach … Combining the two 1S orbitals from two hydrogen atoms will give another way to think about bonding COMBINATION OF ORBITALS Remember, when we take linear combinations of orbitals we get out as many as we put in. Here, the sum of the 2 orbitals 1sA + 1sB = MO1 builds up electron density between nuclei. 90% probability COMBINATION OF ORBITALS 1sA – 1sB = MO2 results in low electron density between nuclei 1sA + 1sB = MO1 builds up electron density between nuclei. THE MO’s FORMED BY TWO 1s ORBITALS ANTI-BONDING s1s* 1sA – 1sB = MO2 BONDING Each orbital can hold up to two electrons. s1s 1sA + 1sB = MO1 COMBINING TWO 1s ORBITALS E Energy of a 1s orbital in a free atom A B Energy of a 1s orbital in a free atom COMBINING TWO 1s ORBITALS E Energy of a 1s orbital in a free atom A B s1s Energy of a 1s orbital in a free atom Energy of 1sA+1sB MO ADDITION gives an Energy more negative than average of original orbitals SUBTRACTION gives an…. Energy more positive than average of original orbitals E Energy of a 1s orbital in a free atom A s1s* s1s B Energy of a 1s orbital in a free atom ADDITION gives an…. Energy more negative than average of original orbitals COMBINING TWO 1s ORBITALS s1s* E 1sA A B s1s 1sB The bonding in H2 H H2 H s1s* E 1s 1s s1s H H2 H s1s* E 1s 1s s1s H2: (s1s)2 He2 Atomic configuration of He He He2 He s1s* E 1s 1s s1s One pair of electrons goes in s1s and the next pair in s1s* 1s2 He2: (s1s)2(s1s*)2 The He2 molecule is not a stable species. He He2 He s1s* E 1s 1s s1s The bonding effect of the (s1s)2 is cancelled by the antibonding effect of (s1s*)2 BOND ORDER Useful concept: The net number of bonds existing after the cancellation of bonds by antibonds. In He2 the electronic configuration is…. (s1s)2(s1s*)2 the two bonding electrons were cancelled out by the two antibonding electrons. There is no BOND! BOND ORDER = 0 BOND ORDER A measure of bond strength and molecular stability. If # of bonding electrons > # of antibonding electrons the molecule is predicted to be stable Bond order = 1/2 { = 1/2 (n # of bonding # of antibonding – electrons(nb) electrons (na) b - na) A high bond order indicates high bond energy and short bond length. Consider H2+,H2,He2+,He2………. } First row diatomic molecules and ions H2 H2+ He2+ He2 Magnetism Dia- Para- Para- — Bond order 1 ½ ½ 0 Bond energy (kJ/mol) 436 225 251 — Bond length (pm) 74 106 108 — s1s* E s1s