If you know solubility of silver chromate Ag2CrO4 in water, so you may calculate solubility
product with usage of equation:
A. Ksp = S5
B. Ksp = 27 ·S3
C. Ksp = 108 ·S5
D. Ksp = 4 ·S3
E. Ksp = S2
ANSWER: D
If you know solubility of magnesium arsenate Mg3(AsO4)2 in water, so you may calculate
solubility product with usage of equation:
A. Ksp = S5
B. Ksp = 27 ·S3
C. Ksp = 108 ·S5
D. Ksp = 4 ·S3
E. Ksp = S2
ANSWER: C
The solubility of precipitate markes out in … in analytical chemistry:
A. S
B. N
C. V
D. Cn
E. Na
ANSWER: A
The solubility of precipitate expresses in … in analytical chemistry:
A. g
B. mol
C. mol/L
D. m/L
E. L/mol
ANSWER: C
If you know solubility of lead iodide PbI2 in water, so you may calculate solubility product
with usage of equation:
A. Ksp = S5
B. Ksp = 27 ·S3
C. Ksp = 108 ·S5
D. Ksp = 4 ·S3
E. Ksp = S2
ANSWER: D
If you know solubility of bismuth iodide BiI3 in water, so you may calculate solubility product
with usage of equation:
A. Ksp = S5
B. Ksp = 27 ·S4
C. Ksp = 108 ·S5
D. Ksp = 4 ·S3
E. Ksp = S2
ANSWER: B
For calculation of magnesium arsenate solubility in presence of chloridic acid we use:
A. KspТ
B. 
C. Ка
D. KspR
E. KspC
ANSWER: E
Choose correct equation of solubility product of mercury (ІІ) iodide:
A. Ksp =[Нg2+]·[І-]2
B. Ksp =[Нg2+]·[І-]
C. Ksp =[Ме2+]+[І-]2
D. Ksp =[Нg2+] + [І-]2
E. Ksp =[Ме2+]·[І-]2
ANSWER: A
The precipitation of copper-ions is considered practically complete, if the concentration of the
precipitate’s ions in solution above sediment does not exceed a …:
A. 104 mol/L
B. 106 mol/L
C. 10-4 mol/L
D. 10-5 mol/L
E. 10-6 mol/
ANSWER: E
After action less quantity of an aqueous ammonia solution on a solution which contains
Mercury (ІІ) ions the … (colour) precipitate is formed.
A. The violet
B. The black
C. The green
D. The white
E. The red
ANSWER: D
Ions Cd2+ with sodium sulphide form a … (colour) precipitate.
A. Dark blue
B. The yellow
C. The black
D. The brown
E. The white
ANSWER: B
Ions Сu2+ with excess of the aqueous solution of ammonia form … (colour) a solution ...
(formula):
A. Red, [Cu(NH3)4]2+.
B. Black, [Cu(NH4)4]2+;
C. Dark blue, [Cu(NH4)3]2+;
D. Yellow, [Cu(NH3)3]2+;
E. Dark blue, [Cu(NH3)4]2+;
ANSWER: E
The red precipitate Mercury (ІІ) iodide ... (formula) is dissolved in excess of potassium iodide
with complex formation ... (formula):
A. Hg2I2, [HgІ3]2+.
B. HgІ2, [HgІ4]2+;
C. Hg3I2, [HgІ4]2-;
D. Hg2I2, [HgІ4]2-;
E. HgІ2, [HgІ4]2-;
ANSWER: E
In what solution it is possible to detect ion Сu2+ with sodium thiosulphate:
A. Cu2+ and Mn2+.
B. Cu2+ and Cd2+;
C. Cu2+ and Zn2+;
D. Cu2+ and Na+;
E. Cu2+ and Hg2+;
ANSWER: D
Ni2+ ions with Chugaiov reactant in ... medium form complex. What is name of reactant?
A. sulphatic, ditizone
B. acetic, aluminone
C. Ammoniac, dimethylglioxim
D. Basic, alizarine
E. Acidic, magnezone
ANSWER: C
Cu2+ ions with ammonium hydrogenphosphat form … (colour) precipitate of acidic salt …
(formula):
A. Black, Cu3(PO4)2
B. Blue, CuHPO4
C. Black, Cu2PO4
D. White, Cu3(PO4)2
E. Blue, Cu2PO4
ANSWER: B
Hg2+ ions with SnCl2 form … (colour) precipitate which then it will be .... colour
A. Yellow, green
B. Yellow, white
C. White, black
D. White, blue
E. White, yellow
ANSWER: C
Cd2+ ions with potassium tetraiodobismuthate … (formula) form ... (colour) precipitate.
A. K[BiІ3], white
B. K[BiІ4], black
C. K2[BiІ4], red
D. K2[BiІ4], red
E. K[BiІ4], white
ANSWER: B
The investigated solution has green colouring. Which cation is in the solution?
A. cation of sodium
B. cation of zinc
C. cation of copper
D. cation of nickel
E. cation of cobalt
ANSWER: D
The precipitate of mercury (ІІ) iodide has colour:
A. The red
B. The blue
C. The white
D. The black
E. The green
ANSWER: A
The precipitate of copper (ІІ) hydroxide has colour:
A. The red
B. The blue
C. The white
D. The black
E. The green
ANSWER: B
Ions Cd2+ with excess of ammonia solution form … (colour) solution … (formula):
A. Red, [Cd(NH3)4]2+.
B. Black, [Cd(NH4)4]2+;
C. Orange, [Cd(NH3)3]2+;
D. Yellow, [Cd(NH3)3]2+;
E. Colourless, [Cd(NH3)4]2+;
ANSWER: E
Ions Co2+ with Nitrozo-R-salt form … (colour) complex.
A. The violet
B. The black
C. The red
D. Dark blue
E. The yellow
ANSWER: C
Cu2+ ions with sodium thiosulphate forms … (colour) precipitate and it is dissolved in ... acid:
A. Black, acetic
B. Blue, nitric
C. White, chloric
D. Black, nitric
E. Yellow, nitric
ANSWER: D
Ni2+ ions with alkali forms … (colour) precipitate … (formula):
A. Green, Ni(OH)2
B. Black, Ni3(OH)2
C. Dark blue, Ni(OH)3
D. White, Ni2(OH)2
E. Blue, Ni(OH)2
ANSWER: A
Cadmium ions with solution of ammonium hydrogenphosphate forms ... (colour) crystal
precipitate … (formula):
A. Green, Cd3(PO4)2
B. Violet, Cd3(PO4)2
C. White, CdHPO4
D. Blue, CdHPO4
E. White, Cd2(PO4)3
ANSWER: E
In what solution it is impossible to detect ions Co2+ with ammonium thiocyanide?
A. Co2+ and Fe3+
B. Co2+ and Mn2+;
C. Co2+ and Cd2+;
D. Co2+ and Hg2+;
E. Co2+ and Cu2+;
ANSWER: A
Which hydroxide Cu(OH)2 or Fe(OH)3, Cr(OH)3, Sn(OH)3, Mn(OH)2 may form complex with
NH4OH:
A. Mn(OH)2
B. Sn(OH)3
C. Cr(OH)3
D. Fe(OH)3
E. Cu(OH)2
ANSWER: E
The investigated solution has blue colouring. Which cation is in the solution?
A. cation of sodium
B. cation of copper
C. cation of nickel
D. cation of cobalt
E. cation of zinc
ANSWER: B
Choose condition for formation of mercury (II) iodide precipitate.
A. [Mе2+][І-]2 = Ksp
B. [Нg2+][І-]2 < Ksp
C. [Нg2+][І-]2 > Ksp
D. [Нg2+][І-] < Ksp
E. [Mе2+][І-]2 > Ksp
ANSWER: C
A rule of solubility product for unsaturated solution of mercury (II) iodide has equation:
A. [Нg2+]2[І-] > Ksp
B. [Нg2+][І-]2 < Ksp
C. [Mе2+][І-] < Ksp
D. [Нg2+][І-] < Ksp
E. [Mе2+][І-]2 < Ksp
ANSWER: B
Choose condition for formation of magnesium phosphate precipitate.
A. [Mg2+]3[PO43-]2 > Ksp
B. [Mg2+][PO43-] > Ksp
C. [Mg2+]3[PO43-]2 < Ksp
D. [Mg2+]3 + [PO43-]2 < Ksp
E. [Mg2+][PO43-] < Ksp
ANSWER: A
Ions Mn (II) with sodium bismuthate … (formula) give ... (colour) solution.
A. NaBiО3, green
B. NaBiО3, crimson
C. NaBi2O3, red
D. Na2BiО3, dark blue
E. NaBiО3, dark blue
ANSWER: B
A rule of solubility product for supersaturated solution of mercury (II) iodide has equation:
A. [Mе2+][І-]2 = Ksp
B. [Нg2+][І-]2 < Ksp
C. [Mе2+][І-]2 > Ksp
D. [Нg2+][І-] < Ksp
E. [Нg2+][І-]2 > Ksp
ANSWER: E
A rule of solubility product for saturated solution of mercury (II) iodide has equation:
A. [Нg2+][І-]2 = Ksp
B. [Нg2+][І-]2 < Ksp
C. [Mе2+][І-] > Ksp
D. [Нg2+][І-] < Ksp
E. [Mе2+][І-]2 = Ksp
ANSWER: A
A rule of solubility product for supersaturated solution of magnesium phosphate has
equation:
A. [Mg2+]3 + [PO43-]2 < Ksp
B. [Mg2+][PO43-] > Ksp
C. [Mg2+]3[PO43-]2 < Ksp
D. [Mg2+]3[PO43-]2 > Ksp
E. [Mg2+][PO43-] < Ksp
ANSWER: D
A rule of solubility product for saturated solution of magnesium phosphate has equation:
A. [Mg2+]3 + [PO43-]2 = Ksp
B. [Mg2+][PO43-] > Ksp
C. [Mg2+]3[PO43-]2 = Ksp
D. [Mg2+]3[PO43-]2 < Ksp
E. [Mg2+][PO43-] < Ksp
ANSWER: C
A rule of solubility product for unsaturated solution of magnesium phosphate has equation:
A. [Mg2+]3 + [PO43-]2 < Ksp
B. [Mg2+][PO43-] > Ksp
C. [Mg2+]3[PO43-]2 > Ksp
D. [Mg2+]3[PO43-]2 < Ksp
E. [Mg2+][PO43-] < Ksp
ANSWER: D
Mg2 + ions with magnezone can be detect from a solution which contains:
A. Mg2+, Na+, Co2+.
B. Mg2+, Ba2+, K+;
C. Mg2+, Fe3+, Cd2+;
D. Mg2+, Sb3+, Ni2+;
E. Mg2+, Cr3+, Mn2+;
ANSWER: B
Bi3+ ions with ammonium hydrogenphosphate form a ... (colour) precipitate … (formula):
A. The white; Bi2PO4
B. Dark blue; Bi2(PO4)3
C. The black; BiPO4
D. The white; BiPO4
E. The yellow; Bi2PO4
ANSWER: D
In the acidic medium ions of V analytical group ... and ... form orange-red precipitates with
sulphides.
A. Bi3+ and Fe3+.
B. Sb3+ and Sb (V);
C. Bi3+ and Fe2+;
D. Mg2+ and Bi3+;
E. Mg2+ and Mn2+;
ANSWER: B
Bi3+ ions with sodium sulphide form ... (colour) precipitate, soluble in ... acid.
A. Orange, nitric
B. Brown, sulphatic
C. Black, chloric
D. Brown-black, sulphatic
E. Brown-black, nitric
ANSWER: E
Ions Fe3+ with Potassium hexacyanoferrate (…) form a …… (colour) precipitate:
A. (ІІ), dark brown
B. (ІІ), dark blue
C. (ІІІ), dark blue
D. (ІІІ), dark green
E. (ІІ), dark red
ANSWER: B
Ions Fe2+ with Potassium hexacyanoferrate (ІІІ) form … (colour) precipitate (formula):
A. Dark blue, Fe3[Fe(CN)6]2.
B. Black, Fe2[Fe(CN)6];
C. Red, Fe3[Fe(CN)6];
D. Green, Fe3[Fe(CN)6]2;
E. Dark blue, Fe3[Fe(CN)6];
ANSWER: A
A precipitate of magnesium hydroxide ... forms in the …. medium:
A. Mg(OH)Cl; basic at presence ammonium chloride
B. Mg(OH)2; the basic
C. Mg(OH)2; ammonium chloride
D. Mg(OH)Сl; hydrochloric
E. Mg(OH)2; the acidic
ANSWER: B
Ions of magnesium with sodium hydrogenphosphate at presence ammonium chloride form …
(colour) precipitate which has structure:
A. White, MgNH4PO46H2O
B. Black, MgNH4PO46H2O
C. Dark blue, Mg3(PO4)2
D. Yellow, Mg(NH3)2PO46H2O
E. White, Mg(NH4)2PO46H2O
ANSWER: A
After action of Potassium hydroxide on the solution of cations of V analytical group the white
precipitate forms. It will be brown by contact with air. What is this cation?
A.
Bi3+.
B.
Fe3+;
C.
Fe2+
D.
Mg2+;
E.
Mn2+;
ANSWER: C
Preliminary test on ions Mn2+ is reaction:
A. With ammonium persulphate in the basic medium
B. With chloric water in the acidic medium
C. With bromic water in the acidic medium
D. With sodium bismuthate in the acidic medium
E. Formation of a white precipitate of hydoxide
ANSWER: D
The investigated solution very dilute by water. The white precipitate forms. Which catons of
V analytical group may be in solution?
A. Bi3+, Sb3+, Sb (V).
B. Mg2+, Mn2+, Bi3+;
C. Fe2+, Fe3+, Sb3+;
D. Mg2+, Mn2+, Fe3+;
E. Mg2+, Mn2+, Fe2+;
ANSWER: A
After action of Bi3+ ions on hexahydroxostannite (ІІ) in ... medium, the … (colour) precipitate
forms.
A.
Basic, black
B.
Neutral, brown
C.
Basic, white
D.
Acidic, white
E.
Neutral, black
ANSWER: A
Adding to a solution which contains ions Sb3+, sodium thiosulphate … (its formula) observe
formation of ... (colour) precipitate.
A. Na2S2O8, black
B. Na2S2O4, violet
C. Na2S3O3, brown
D. Na3S2O3, white
E. Na2S2O3, red
ANSWER: E
One cation from V analytical group, react with ammonium thiocyanide and give us a red
solution. In an investigated solution there are ions:
A. Sb (V)
B. Sb (ІІІ)
C. Fe (ІІІ)
D. Fe (ІІ);
E. Mg (І)
ANSWER: C
Pharmacopeia’s reaction for detection of Fe2+ ions is reaction with .... (reagent). If in test tube
is Fe2+, the …. (colour) precipitate forms.
A. K2[Fe(CN)6]; Green
B. K4[Fe(CN)6]; Violet
C. K3[Fe(CN)6]; Green
D. K4[Fe(CN)6]; Dark blue
E. K3[Fe(CN)6]; Dark blue
ANSWER: E
Mn2+ ions are detected in .... medium with ammonium persulphate (it is formula….):
A. Neutral, (NH4)2S3O8
B. ammonium, (NH4)S2O3
C. nitric acid, (NH3)S2O8
D. Basic, (NH3)2S2O8
E. Acidic, (NH4)2S2O8
ANSWER: E
The ….... (colour) precipitate of magnesium hydoixide is dissolved in solutions of salts:
A. The yellow; ammonium carbonate
B. The white; ammonium chloride
C. The yellow; ammonium chloride
D. The white; ammonium hydogencarbonate
E. The white; ammonium carbonate
ANSWER: B
Which cation of V analytical group reacts with alkaline solution of magnezon І ?
A. Sb3+
B. Fe2+
C. Bi3+;
D. Mn2+;
E. Mg2+;
ANSWER: E
Which ions are ions of V analytical groups?
A. Mg2+, Mn2+, Bi3+, Fe2+, Fe3+, As3+, As (V);
B. Cd2+, Mn2+, Bi3+, Ca2+, Fe3+, Sb3+, Sb (V);
C. Mg2+, Mn2+, Bi3+, Fe2+, Fe3+, Sb3+, Sb (V);
D. Mg2 +, Na+, Bi3+, Ba2+, Sr2+, Sb3+, Sb (V);
E. Mg2+, Cr3+, Bi3+, Fe2+, Fe3+, Sn2+, Sn (IV);
ANSWER: C
For preparation of ammoniac buffer solution is necessary to use next substances:
A. CH3COOH and CH3COONa
B. NH3 and NH4ОН
C. NH3 and NH4Cl
D. NH2ОН and NH4Cl
E. HCOOH and HCOONa
ANSWER: C
For preparation of acetic buffer solution is necessary to use next substances:
A. CH3COOH and CH3CНO
B. CH3CН2OH and CH3COONa
C. CH3CHO and CH3COONa
D. CH3COOH and CH3COONa
E. HCOOH and HCOONa
ANSWER: D
Preliminary tests by specific reactions it is possible to detect such ions of IV analytical group:
A. AsO33-, AsО43-, Sn (II), Sn (IV), Al3+, Cr3+.
B. As (III), As (V), Sn (II), Sn (IV), Zn2+, Al3+, Cr3+;
C. Sn (II), Sn (IV), Al3+, Cr3+;
D. As (III), As (V);
E. As (III), Al3+, Cr3+;
ANSWER: A
Arsenit - and arsenat - ions can be distinguished by reaction with ammonium molybdat:
arsenat-ions form ... … precipitate (NH4)3[As(Mo3O10)4]H2O.
A. The dark blue crystal
B. The white crystal
C. The yellow crystal
D. The yellow amorphous
E. The brown amorphous
ANSWER: C
At interaction silver nitrate with arsenit-ions ... (formula) and arsenat-ions ... (formula) form
precipitates ... and ... colours accordingly.
A. AsО33-, AsО43-, yellow, orange
B. AsО33-, AsО43-, yellow, chocolate
C. AsО2-, AsО43-, orange, brown
D. AsО23-, AsО43-, yellow, brown
E. AsО33-, AsО43-, white, chocolate
ANSWER: B
In an acidic solution Sn2+ ions reducte HgCl2 to formation of …. precipitate …. (formula). If
to precipitate add excess of HgCl2 solution, … precipitate of metal mercury forms
A. White, HgCl2, yellow
B. White, Hg2Cl2, yellow
C. White, HgCl2, white
D. White, Hg2Cl2, black
E. White, Hg2Cl2, white
ANSWER: D
Cobalt nitrate with Zinc salts (by length heating) forms mixed оxide Zinc and Cobalt СоZnО2
…. colour.
A. The red
B. The blue
C. The green
D. The yellow
E. Dark blue
ANSWER: C
Coordination numbers in complex Na[Al(OH)4(H2O)2] is equal:
A. 6
B. 7
C. 3
D. 2
E. 4
ANSWER: A
Ligand in complex Na[Al(OH)4(H2O)2] is:
A. Na+
B. Only H2O
C. [Al(OH)4(H2O)2]D. Al3+
E. OH- і H2O
ANSWER: E
Ligand in complex K2[HgBr4] is:
A. K+
B. BC. Hg2+
D. BrE. [HgBr4]2ANSWER: D
Complexing atom in complex Na[Al(OH)4(H2O)2] is:
A. Na+
B. H2O
C. [Al(OH)4(H2O)2]D. Al3+
E. OHANSWER: D
Coordination sphere in complex Na[Al(OH)4(H2O)2] is:
A. Na+
B. H2O
C. [Al(OH)4(H2O)2]D. Al3+
E. OHANSWER: C
Coordination numbers in complex K2[HgBr4] is equal:
A. 7
B. 4
C. 5
D. 2
E. 6
ANSWER: B
Ionisation sphere in complex Na[Al(OH)4(H2O)2] is:
A. Na+
B. H2O
C. [Al(OH)4(H2O)2]D. Al3+
E. OHANSWER: A
Complexing atom in complex K2[HgBr4] is:
A. K+
B. It isn’t coordination compound
C. Hg2+
D. BrE. [HgBr4]2ANSWER: C
Coordination sphere in complex K2[HgBr4] is:
A. K+
B. Coordination sphere is absent
C. Hg2+
D. BrE. [HgBr4]2ANSWER: E
Ionisation sphere in complex K2[HgBr4] is:
A. K+
B. Ionisation sphere is absent
C. Hg2+
D. Br-
E. [HgBr4]2ANSWER: A
Central atom (ion) is named … in complex:
A. Coordination sphere
B. Ionisation sphere
C. Oxidizer
D. ligand
E. complexing (metal ion)
ANSWER: E
Which equation describes stepwise fashion of tetracyanoargenate (I) complexing?
A. Ag+ + 3CN-  Ag(CN)32B. Ag(CN)3- + CN-  Ag(CN)43C. Ag+ + CN-  AgCN
D. Ag+ + 4CN-  Ag(CN)43E. Ag+ + 2CN-  Ag(CN)2ANSWER: B
Which equation doesn’t describe common of tetracyanoargenate (I) complexing?
A. Ag+ + 2CN-  Ag(CN)2B. Ag+ + 4CN-  Ag(CN)43C. Ag(CN)3- + CN-  Ag(CN)43D. Ag+ + 3CN-  Ag(CN)32E. Ag+ + CN-  AgCN
ANSWER: C
Which equation doesn’t describe stepwise fashion of between ions (I) and cyanide?
A. Ag+ + 3CN-  Ag(CN)32B. Ag(CN)3- + CN-  Ag(CN)43C. Ag+ + CN-  AgCN
D. AgCN + CN-  Ag(CN)2E. Ag(CN)2- + CN-  Ag(CN)32ANSWER: A
Iron (ІІІ) salts with thiocyanide ions … (formula) form … :
A. CNO-; a solution of pink colour
B. SCN-; a solution of pink or red colour
C. CN-; a precipitate of red colour
D. S2-; a precipitate of black colour
E. NO2-; a solution of yellow colour
ANSWER: B
Sulphide ions with silver nitrate is impossible to detect in the presence of an ion:
A. S2O32-.
B. SO32-;
C. SO42-;
D. SCN-;
E. CN-;
ANSWER: C
At oxidation of iodide ions by potassium bichromate in … medium foms …
A. Sulphatic acid, free iodine
B. Nitric acid, potassium iodide
C. Acetic acid, iodine
D. Ammoniac, potassium and ammonium iodide
E. Basic, ammonium iodide
ANSWER: A
The concentrated sulphatic acid with dry salts of bromide, for example NaBr, gives …
(formula). It is oxidized by sulphatic acid to free bromine (it is … gas).
A. Br, red
B. Br2, brown
C. HBr2, black
D. H2Br, yellow
E. HBr, brown
ANSWER: E
Which analytical signal you see by iodine action on colourless anion reducers?
A. Decolouration of iodine solution
B. Precipitate forms
C. Precipitate dissolution
D. Formation of gas
E. Occurrence of iodine colouring
ANSWER: A
Silver iodate … (formula) is dissolved in aqueous ammonia solution with formation of
complex ions … :
A. AgJ, [Ag(NH3)2]+.
B. AgJO3, [Ag(NH3)2]+;
C. AgJO2, [Ag(NH3)2]+;
D. AgJ, [Ag(NH3)2]-;
E. AgJO, [Ag(NH3)2]+;
ANSWER: B
The group reagent on ІІ analytical group of anions with thiocyanide ions forms:
A. Pale yellow precipitate
B. Black precipitate
C. White precipitate
D. Red precipitate
E. Brown precipitate
ANSWER: C
At oxidation by chloric water of an investigated solution of ІІ analytical group anions the
chloroform layer was painted in orange colour. So, at a solution are present:
A. Bromide ions
B. Chloride ions
C. iodide ions
D. iodate ions
E. bromate ions
ANSWER: A
Chloride ions with silver nitrate form a … (colour) precipitate which is dissolved in ….
A. Red, KCN, NH4Cl
B. Yellow, (NH4)2CO3, HNO3
C. Light yellow, HNO3, NH3H2O, HJ
D. White, NH3H2O, (NH4)2CO3
E. Light, (NH4)2CO3, (NH4)2SO4
ANSWER: D
Which complex is one-nuclear complex?
A. heteropoly acids
B. acidocomplex
C. isopoly acids
D. cluster complex
E. bridging complex
ANSWER: B
Choose equation in which is ratio between common and stepwise fashion formation constant.
 5=k1·k2·k3·k4
B. 4=k1·k2+k3·k4
C. 4=k1·k2·k3
D. 4=k1·k2·k3·k4
E. 4=k1+k2+k3+k4
ANSWER: D
Which equation describes stepwise fashion of complexing?
A. Me + 2L ↔ MeL2
B. MeL4 + L ↔ MeL5
C. Me + 5L ↔ MeL5
D. Me + 3L ↔ MeL3
E. Me + 4L ↔ MeL4
ANSWER: B
Choose equation of common complexing.
A. MeL4 + L ↔ MeL5
B. MeL + L ↔ MeL2
C. Me + 3L ↔ MeL3
D. MeL2 + L ↔ MeL3
E. MeL3 + L ↔ MeL4
ANSWER: C
Which equation doesn’t common complexing?
A. MeL4 + L ↔ MeL5
B. Me + 2L ↔ MeL2
C. Me + 5L ↔ MeL5
D. Me + 3L ↔ MeL3
E. Me + 4L ↔ MeL4
ANSWER: A
Choose bidentate ligand:
A. Н2О
B. SCNC. ClD. NH3
E. C2O42ANSWER: E
Which ligand isn’t monodentate ligand:
A. C2O42B. SCNC. ClD. NH3
E. Н2О
ANSWER: A
Iodide in acidic medium are oxidised iodate ions to free iodine which paints water solutions in
… colour.
A. Dark blue
B. The green
C. The red
D. The black
E. Brown
ANSWER: E
Bromides in … medium are oxidised by bromate ions to ….
A. Acidic, free bromine
B. Neutral, free bromine
C. Acidic, gipobromite
D. Ammoniac, gipobromite
E. Basic, bromite
ANSWER: A
Which anions react with iron (II) salts in the presence of the concentrated sulphatic acid and
form a brown ring?
A. Thiocyanate ions
B. Nitrate ions
C. Bromate ions
D. Acetate ions
E. Citrate-ions
ANSWER: B
Inert complexes may be formed:
A. metals (s- and f-elements)
B. metals (s- and p-elements)
C. metals (d-elements)
D. metalloids (p-elements)
E. metals (s- and d-elements)
ANSWER: C
Labile complexes may be formed:
A. metals (s- and f-elements)
B. metals (s- and p-elements)
C. metals (d-elements)
D. metalloids (p-elements)
E. metals (s- and d-elements)
ANSWER: B
Complexes are divided on … (on kinetic stability):
A. stable and intact
B. kinetic and nonkinetic
C. inert and labile
D. Intact and labile
E. Labile and stable
ANSWER: C