Solubility and Concentration Review

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Name: _____________________________
Score: _____/21
Self-assessment: Solubility and Concentration
1. – 2. There are two parts to a solution. Name and describe each.
3. – 4. Draw a water molecule and explain why it is a polar molecule.
5. – 6. Draw and describe a hydrogen bond.
7. Describe how/why Like Dissolves Like.
8. – 9. How well something dissolves depends on what two forces?
How do the following affect the process of dissolving, at a molecular level?
10. Stirring/shaking?
11. Breaking it into smaller pieces?
12. Heating the solvent?
13. Describe how temperature affects solubility.
14. If a solution is holding the maximum amount it can it is called _________________________.
15. If it’s holding more than it usually can it is called _______________________________.
16. If it’s holding less than the maximum amount it is called _______________________________.
17. – 19. Describe how you could tell which one of the above three a solution is by adding
more solute to it. You should describe what would happen for each of the above three
situations.
Concentration = g (solute)/ ml (solvent)
20. ____________________ What is the concentration of 42.1 grams of silver nitrate that
dissolves in 1750 mL of water?
21. ____________________ How many grams of salt will dissolve in 350 mL of water is
the solubility of salt is 35.9 g / 100. mL of H2O?
22. ____________________ I want a solution with a concentration of 180 g / mL. If I
only have 400. g of solute, how many mL can I make?
Answer Key__
Score: _____/21
Self assessment: Solubility and Concentration
Name: __
1. – 2. There are two parts to a solution. Name and describe each.
Solute (what’s being dissolved)
Solvent (what’s doing the dissolving)
3. – 4. Draw a water molecule and explain why it is a polar molecule.
“Uneven distribution of
electrons”…electrons not shared
equally…hydrogen pulls on them a
little more than hydrogen, so one
side has a little positive charge
(+) and one side is a little negative (-)
5. – 6. Draw and describe a hydrogen bond.
Bond BETWEEN water molecules
(not within 1 molecule) from little
bit positive end of one to little bit
negative end of the other
7. Describe how/why Like Dissolves Like.
Polar things will dissolve in polar solvents,
nonpolar solutes will dissolve in nonpolar
solvents. Because the charges in a polar
molecule will pull apart the other if it also has
charges. (polar will pull apart polar, but not
nonpolar)
8. – 9. How well something dissolves depends on what two forces?
Between water and the solute molecules
Between the solute and the solute molecules
How do the following affect the process of dissolving, at a molecular level?
10. Stirring/shaking?
Moves molecules away, so more room for
interactions with solute.
11. Breaking it into smaller pieces?
More surface area for interactions
between water and solute molecules.
12. Heating the solvent?
Molecules of solute and solvent move
faster and interact more
13. If a solution is holding the maximum amount it can it is called _
14. If it’s holding more than it usually can it is called _
saturated_.
supersaturated _.
15. If it’s holding less than the maximum amount it is called _
unsaturated _.
16. – 18. Describe how you could tell which one of the above three a solution is by adding
more solute to it. You should describe what would happen for each of the above three
situations.
Add more powder:
If original is saturated, powder will not
dissolve, original amount will fall to bottom
If original is unsaturated, powder will not
dissolve
If original is supersaturated, powder will not
dissolve, more than original amount will fall to
the bottom
Concentration = g (solute)/ ml (solvent)
.024 g/mL__ What is the concentration of 42.1 grams of silver nitrate that
19. _
dissolves in 1750 mL of water?
42.1
1750
20. __
= .0240571
130 g___ How many grams of salt will dissolve in 350 mL of water is
the solubility of salt is 35.9 g / 100. mL of H2O?
35.9
100
=
x
350
(cross muliply)
35.9 x 350 = 100 x
x = 125.65
21. __
12565 = 100 x
2.2 mL __ I want a solution with a concentration of 180 g / mL. If I
only have 400. g of solute, how many mL can I make?
180 = 400/x
180x = 400
x = 400/180
(mult by x)
(div by 180)
x = 2.22222222
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