Name: _____________________________
Score: _____/21
Self-assessment: Solubility and Concentration
1. – 2. There are two parts to a solution. Name and describe each.
3. – 4. Draw a water molecule and explain why it is a polar molecule.
5. – 6. Draw and describe a hydrogen bond.
7. Describe how/why “Like Dissolves Like.”
How do the following affect the process of dissolving, at a molecular level?
8. Stirring/shaking?
9. Breaking it into smaller pieces?
10. Heating the solvent?
11. If a solution is holding the maximum amount it can it is called _________________________.
12. If it’s holding more than it usually can it is called _______________________________.
13. If it’s holding less than the maximum amount it is called _______________________________.
When I look at a solution, it will look the same no matter if it’s unsaturated, saturated or
super saturated.
14. What can I do to tell which one it is.
15. -17. What will happen if it is:
Unsaturated
Saturated
Supersaturated:
Concentration = g (solute)/ ml (solvent)
18. ____________________ What is the concentration of 42.1 grams of silver nitrate that
dissolves in 1750 mL of water?
19. ____________________ I have a solution of copper chloride with a concentration of
3.47 g/ml. How much copper chloride do I need to
evaporate to get 300.00 g out of it?
20. ____________________ How many grams of salt will dissolve in 350 mL of water is
the solubility of salt is 35.9 g / 100. mL of H2O?
21. ____________________ I want a solution with a concentration of 180 g / mL. If I
only have 400. g of solute, how many mL can I make?
Answer Key__
Score: _____/21
Self assessment: Solubility and Concentration
Name: __
1. – 2. There are two parts to a solution. Name and describe each.
Solute (what’s being dissolved)
Solvent (what’s doing the dissolving)
3. – 4. Draw a water molecule and explain why it is a polar molecule.
“Uneven distribution of
electrons”…electrons not shared
equally…oxygen pulls on them a
little more than hydrogen, so one
side has a little positive charge
(+) and one side is a little negative (-)
5. – 6. Draw and describe a hydrogen bond.
Bond BETWEEN water molecules
(not within 1 molecule) from little
bit positive end of one to little bit
negative end of the other
7. Describe how/why Like Dissolves Like.
Polar things will dissolve in polar solvents,
nonpolar solutes will dissolve in nonpolar
solvents. Because the charges in a polar
molecule will pull apart the other if it also has
charges. (polar will pull apart polar, but not
nonpolar)
How do the following affect the process of dissolving, at a molecular level?
8. Stirring/shaking?
Moves molecules away, so more room for
interactions with solute.
9. Breaking it into smaller pieces?
More surface area for interactions
between water and solute molecules.
10. Heating the solvent?
Molecules of solute and solvent move
faster and interact more
11. If a solution is holding the maximum amount it can it is called _
12. If it’s holding more than it usually can it is called _
saturated_.
supersaturated _.
13. If it’s holding less than the maximum amount it is called _
unsaturated _.
When I look at a solution, it will look the same no matter if it’s unsaturated, saturated or
super saturated.
14. What can I do to tell which one it is.
Add more powder:
15. - 17. What will happen if it is:
Unsaturated
Saturated
powder will dissolve
powder will not dissolve, original
amount will fall to bottom
powder will not dissolve, more
than original amount will fall to
the bottom
Supersaturated:
Concentration = g (solute)/ ml (solvent)
.0241 g/mL__ What is the concentration of 42.1 grams of silver nitrate that
18. _
dissolves in 1750 mL of water?
42.1
1750
= .0240571
86.5 ml_ I have a solution of copper chloride with a concentration of
19. __
3.47 g/ml. How much copper chloride do I need to
evaporate to get 300.00 g out of it?
3.47
= 300
x
(mult by x)
3.47(x) = 300
(div by 3.47)
x
(mult by x)
300
3.47
x = 86.45533141
20. __
=
130 g___ How many grams of salt will dissolve in 350 mL of water is
the solubility of salt is 35.9 g / 100. mL of H2O?
35.9
100
=
x
350
(cross muliply)
35.9 x 350 = 100 x
x = 125.65
21. __
12565 = 100 x
2.2 mL __ I want a solution with a concentration of 180 g / mL. If I
only have 400. g of solute, how many mL can I make?
180 = 400/x
180x = 400
x = 400/180
(mult by x)
(div by 180)
x = 2.22222222