107 chem Assement Q
Student Name :
student Number
1. The wavelength of electromagnetic energy multiplied by its frequency equals:
a. c, the speed of light
b. h, Planck’s constant
c. Avogadro’s number
d. 4.184
2. The energy of a photon of electromagnetic energy divided by its frequency equals:
a. c, the speed of light
b. h, Planck’s constant
c. Avogadro’s number
d. 4.184
3. Light that contains colors of all wavelengths is called:
a.
b.
c.
d.
a continuous spectrum.
monochromatic.
a line spectrum.
a Balmer series.
4. The lowest energy state of an atom is referred to as its:
a. bottom state.
b. ground state.
c. fundamental state.
d. original state.
5. The hydrogen emission spectrum includes light with a wavelength of 434
nanometers. This is caused by an electron moving from:
a. the n = 3 state to the n = 2 state.
b. the n = 4 state to the n = 2 state.
c. the n = 5 state to the n = 2 state.
d. the n = 6 state to the n = 2 state.
6. “It is impossible to know both the position and the momentum of an electron
simultaneously” is a statement of:
a. Hund’s Rule.
b. deBroglie’s Hypothesis.
c. the Pauli Exclusion Principle.
d. the Heisenberg Uncertainty Principle.
7. “No two electrons in the same atom may have the same values for all four
quantum numbers” is a statement of:
a. Hund’s Rule.
b. deBroglie’s Hypothesis.
c. the Pauli Exclusion Principle.
d. the Heisenberg Uncertainty Principle.
8. All s orbitals are:
a. shaped like four-leaf clovers.
b. dumbbell-shaped.
c. spherical.
d. triangular.
9. The way electrons are distributed among the various orbitals of an atom is referred
to as the atom’s:
a. orbital diagram.
b. electron configuration.
c. electron distribution.
d. electron spread
10. [He]2s22p2 is the electron configuration of which element?
a. beryllium
b. boron
c. carbon
a. nitrogen
107 chem Assesment Q-2
Student Name :
Student Number :
1. Considering only the n = 1 to n = 5 states in the hydrogen atom, which transition
will emit the longest wavelength?





n = 5 to n = 4
n = 5 to n = 2
n = 3 to n = 1
n = 3 to n = 2
n = 4 to n = 2
2. What are the valence electrons of vanadium
 4s2
 3d3
 4s23d3
 3d5
 4d5
3. What are the valence electrons of gallium?
 4s2
 4p1
 4s23d104p1
 4s23d10
 4s24p1

4. What is the maximum number of orbitals described by the quantum numbers:
n=3 l=2
 1
 3
 5
 8
 9
5. What is the maximum number of electrons described by the quantum numbers:
n=4
 7
 14
 16
 32
 48
6. How many nodal planes does a d
orbital have?
 0
 1
 2
 3
 4
7. How many unpaired electrons does selenium have?
 0
 2
 4
 6
 8
8. How many unpaired electrons does chromium have?
 0
 2
 4
 6
 8