[INTERMEDIATE 1]
© Learning and Teaching Scotland 2004
This publication may be reproduced in whole or in part for educational purposes by educational establishments in Scotland provided that no profit accrues at any stage. ii NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
Section 1 Working with Whole Numbers and Decimals
1.1 Whole number
1.2 Decimals1
1.3 The four rules
Section 2 Rounding
2.1 The rule of five
2.2 Extending the use of the rule of five
2.3 Rounding to two decimal places
2.4 Rounding in a money calculation
2.5 The problems of real life
2.6 Significant figures
4.2 Finding a percentage by using a calculator
4.3 Percentage profit and loss
4.4 Percentage errors, increases and decreases
Section 5 Earnings
5.1 Earning a wage
5.2 Pay increases
5.3 Dealing with income tax
5.4 Higher tax rate
1
3
Section 3 Fractions
3.1 Quick and easy fractions
3.2 Fractions to percentages
15
18
Section 4 Percentages
4.1 Finding a percentage without using a calculator 25
9
9
11
6
8
8
26
27
28
33
36
37
42
Section 6 Working with money
6.1 Working with VAT
6.2 Practical problems
6.3 Hire purchase
Section 7 Calculations with time
7.1 Lengths of time
7.2 Calculating speed
7.3 Calculating distance
7.4 Calculating time
47
49
50
53
58
59
60
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION iii
© Learning and Teaching Scotland 2004
CONTENTS
Section 8 Ratio
8.1 Ratio as comparison
8.2 Mixed units
8.3 Proportional division
8.4 Direct proportion
Section 9 Formulas
9.1 The four rules of formulas
9.2 Two- and three-step formulas
63
67
68
70
75
77 iv NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
WORKING WITH WHOLE NUMBERS AND DECIMALS
Count from 1 to 10 in your head. The numbers you just used are called whole numbers.
Whole numbers are just the numbers that we use for counting whole things – no halves or quarters or decimals.
But – there is another whole number that everyone forgets about.
Suppose that you have fifty vouchers to hand out to customers as they come in to a shop. How many do you have left after giving them all away?
None. The number of vouchers that you have left is zero . Zero is also a whole number.
Definition
Whole numbers are the counting numbers and the number zero:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, and so on.
When we use decimals we are almost always working with money or measurements.
£5.68 per hour 1.78 metres tall 6.4 square metres of carpet
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 1
© Learning and Teaching Scotland 2004
WORKING WITH WHOLE NUMBERS AND DECIMALS
Activity 1
Here are four simple questions. Work out the answer and then see if you can tell what made each question different from the other.
Q1
Day
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Sunday
Cars sold
2
2
5
4
1
8
6
How many cars were sold in total?
Q2 A car odometer reads 24 500 miles at the start of a journey. It reads 24 660 miles at the end of the journey. How far was the journey?
Q3 Shirley is paid £8 per hour. How much does she earn for a 6-hour day?
Q4 A £12 million lottery pay-out is shared between two winners. How much does each receive?
2 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
WORKING WITH WHOLE NUMBERS AND DECIMALS
Addition, subtraction, multiplication and division are known as the four rules of numeracy.
You need to know how to use all the four rules. However, it is more important that you know when to use them.
If you knew which rule to use in the four questions above then you are well on your way to success in numeracy.
Questions 1.3
For each of the following questions, say which of the four rules you would use. (You may calculate the answer if you wish, but you need to respond by saying which rule you used.)
1. Joyce earns £280 per week. Steve earns £246. How much more does Joyce earn than Steve?
2. There are six eggs in a box. How many eggs are in 20 boxes?
3. There are 284 pupils in one primary school and 311 in another.
How many pupils are there altogether?
4. There are 10 chairs in a row and 16 rows. How many chairs are there altogether?
5. If £12 is shared equally among three people, how much does each get?
6. Hilary is 148 centimetres tall. Joseph is 122 centimetres tall.
How much taller is Hilary than Joseph?
7. Norrie’s dog eats 180g of dog food each day. What weight of dog food does it eat in 4 days?
8. The distance driven by a rep one morning is 40 miles. The distance driven in the afternoon is 83 miles. What is the total distance driven that day?
Knowing what to do is as important as knowing how to do it.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 3
© Learning and Teaching Scotland 2004
WORKING WITH WHOLE NUMBERS AND DECIMALS
Activity 1 Answers
Q1 28 cars
Q2 160 miles
Q3 £48
Q4 £6 million
Answers 1.3
1. Subtraction
2. Multiplication
3. Addition
4. Multiplication
5. Division
6. Subtraction
7. Multiplication
8. Addition addition subtraction multiplication division
2 + 2 + 5 + 4 + 1 + 8 + 6
24660 – 24500
£8 x 6
£12 million ÷ 2
4 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
ROUNDING
You will need a calculator for most of this section.
Example 2.1a
Calculate 171 ÷ 25
171 ÷ 25 = 6.84
6.84 has two decimal places – two figures after the decimal point.
We can give an approximate answer by rounding 6.84 to only one decimal place.
Keep the 6 and the 8. Get rid of the 4.
171 ÷ 25 = 6.8 (to 1 decimal place) (1dp for short)
It is okay to throw away a small amount. This is a little like saying
£6.84 is close to £6.80 – we may lose the 4p without much worry.
Example 2.1b
Calculate 172 ÷ 25
172 ÷ 25 = 6.88
6.88 can also be rounded to one decimal place.
Keep the 6 and the 8. Get rid of the second 8.
Think money again. £6.88 is not like £6.84 – it is more like £6.90
Before we can get rid of the 8 we must compensate for its size. It is a large amount to throw away, so we change the 6.8 to 6.9
6 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
ROUNDING
The rule of five
To round to one decimal place, look at the second decimal place. If it is a 5 or more, then round up. Otherwise round down.
6.80 becomes 6.8
6.81 becomes 6.8
6.82 becomes 6.8
6.83 becomes 6.8
6.84 becomes 6.8
6.85 becomes 6.9
6.86 becomes 6.9
6.87 becomes 6.9
6.88 becomes 6.9
6.89 becomes 6.9
Questions 2.1
Round the following numbers to 1 decimal place.
(a) 8.37 (b) 5.91
(d)
(g)
3.64
24.17
(e) 4.75
(h) 63.89
(c) 2.36
(f) 5.55
(i) 12.15
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 7
© Learning and Teaching Scotland 2004
ROUNDING
When rounding to one decimal place, we always consider the second decimal place and use the rule of five.
Examples 2.2
14.372 = 14.4 to 1 dp
22.316 = 22.3 to 1 dp
57.853 = 57.9 to 1dp
(the 7 is bigger than 5)
(the 3 is smaller than 5)
(the second decimal place is a 5 and 5 or
Questions 2.2
more rounds up)
Round the following numbers to 1 decimal place.
(a) 23.146
(d) 47.352
(b) 42.484
(e) 86.159
(c) 37.168
(f) 77.552
(g) 126.118 (h) 204.301
(i) 222.888
When rounding to two decimal places, we always consider the third decimal place and use the rule of five.
Examples 2.3
14.372 = 14.38 to 1 dp (the 2 is smaller than 5)
22.316 = 22.32 to 1 dp (the 6 is larger than 5)
57.815 = 57.82 to 1dp (the third decimal place is a 5 and 5 or more rounds up)
Questions 2.3
Round the following numbers to 2 decimal places.
(a) 23.171 (b) 14.283
(d) 16.414
(g) 29.915
(e) 73.843
(h) 63.885
(c) 25.317
(f) 15.427
(i) 40.404
8 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
ROUNDING
Example 2.4
Share £1264 among 7 people.
£1264 ÷ 7 = £ 180.5714286 This rounds to £180.57 (the 1 is smaller than 5)
Questions 2.4
(a) Share £5647 among 7 people.
(b) Share £15661 among 13 people.
(c) Share £2568 among 11 people.
Example 2.5a
£100 is shared between five people. How much does each receive?
£100 ÷ 5 = £20
Example 2.5b
£100 is shared between seven people. How much does each receive?
£100 ÷ 7 = £14.28571429 which rounds to £14.29
Problem! If 7 people all get £14.29 then we need
7 x £14.29 = £100.03
But we only have £100.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 9
© Learning and Teaching Scotland 2004
ROUNDING
If a fixed sum of money is to be shared out then the answer must always be rounded down. This makes sure that there is enough money to go round. There may be a small amount left over.
Questions 2.5
(a) Share £2263 among 7 people.
(b) Share £6638 among 12 people.
(c) Share £4493 among 7 people.
(d)
Share £15800 among 12 people.
(e) Share £265390 among 13 people.
10 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
ROUNDING
Sources within United reported that 20,000 attended last Tuesday’s cup tie…
It is highly unlikely that exactly 20 000 spectators were in the crowd.
The headline tells us that close to 20 000 were there. Closer to 20 000 than 10 000 or 30 000.
The significant (important) figure is the 2 – it is in the tens of thousands column.
Suppose the exact figure was 18 638. This could be rounded to
20 000 showing 1 significant figure
19 000 showing 2 significant figures
18 600 showing 3 significant figures
18 640 showing 4 significant figures
18 638 has 5 significant figures
Significant figures are used to give an impression of the size of a large number by rounding. They are counted from the left. The rule of five still applies when rounding.
Examples 2.6
1 Round 8432 to 2 significant figures
We keep the thousands and hundreds. The 3 in the tens column tells us to round down (smaller than a 5).
Answer 8400
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 11
© Learning and Teaching Scotland 2004
ROUNDING
2 Round 7172 to 2 significant figures
We keep the thousands and the hundreds. The 7 in the tens column tells us to round up (larger than a 5).
Answer 7200
3 Round 6312 to 1 significant figure
We keep the thousands. The 3 in the hundreds column tells us to round down (smaller than a 5).
Answer 6000
4 Round 48 617 to 3 significant figures
We keep the tens of thousands, the thousands and the hundreds.
The 1 in the tens column tells us to round down (smaller than a
5).
Answer 48 600
Questions 2.6
Round each of the following numbers to the number of significant figures shown in the brackets.
(a) 732 (2) (b) 8196 (2) (c) 3481 (2)
(d)
(g)
(j)
593 (1)
7341 (3)
21839 (4)
(e) 211 (1)
(h) 15684 (3)
(k) 21839 (3)
(f) 7619 (1)
(i) 27215 (3)
(l) 21839 (2)
12 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 2.1
(a) 8.4
(d) 3.6
(g) 24.2
Answers 2.2
(a) 23.1
(d) 47.4
(g) 126.1
Answers 2.3
(a) 23.17
(d) 16.41
(g) 29.92
Answers 2.4
(a) £806.71 each
(b) £1204.69 each
(c) £233.45 each
(b) 5.9
(e) 4.8
(h) 63.9
(b) 42.5
(e) 86.2
(h) 204.3
(b) 14.28
(e) 73.84
(h) 63.89
(c) 2.4
(f) 5.6
(i) 12.1
(c) 37.2
(f) 77.6
(i) 222.9
(c) 25.32
(f) 15.43
(i) 40.40
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 13
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 2.5
(a) £323.28 each
(b) £553.16 each
(c) £641.85 each
(d) £1316.66 each
(e) 20414.61 each
Answers 2.6
(a) 730
(d) 600
(g) 7340
(j) 21840
(b) 8200
(e) 200
(h) 15700
(k) 21800
(c) 3500
(f) 8000
(i) 27200
(l) 22000
14 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
FRACTIONS
The title ‘quick and easy’ isn’t supposed to make you think of boil-inthebag rice. It’s just that in the world of fractions (which most people hate) there are some very quick and easy results. We can all understand them. And we should all be able to store them in our brains.
Understanding fractions
1. The symbol for division is just a picture of a fraction.
something
over
something
2. Think about one half. If you take one chocolate bar and divide it between two children then each gets a half. A half is the answer to ‘one divided by two’.
1
2
one
divided by
two
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 15
© Learning and Teaching Scotland 2004
FRACTIONS
Activity 2
1. Since
1 means one divided by two, what do these mean…?
2
(a)
(b)
(c)
1
3
1
4
1
5
(d)
(e)
1
10
1
100
2.
Try a harder activity.
What do you think
2
3
means?
16 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
FRACTIONS
Activity 2 - Answers
1. one divided by three one divided by four one divided by five one divided by ten one divided by a hundred
2. 2 divided by 3.
Look at these chocolate bars.
Divide the two chocolate bars equally between three people.
Each person got
2
3
of a chocolate bar.
Two bars were divided among three people.
2 ÷ 3 =
2
3
.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 17
© Learning and Teaching Scotland 2004
FRACTIONS
Fractions are the numbers we use to describe the results of sharing.
Questions 3.1
Give a fraction answer to each of the following
1. one divided by four
3. two divided by five
5. seven divided by eight
2. one divided by six
4. three divided by four
6. three divided by ten
18 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
FRACTIONS
So you’ve heard yourself say it many times before: ‘OK, you can each have half the chocolate bar’. That’s one bar divided between two.
I guess you could say (though it’s a bit unnatural): ‘You can have 50% of a chocolate bar each.’
Unnatural, but true. (Is that a definition of mathematics?)
1
= 50%
2
We also know that
75% =
3
4
1
4
= 25%
Do we know any others?
How about 75%
75% =
3
4
1
Similarly
10
= 10%
1
Also
100
= 1%
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 19
© Learning and Teaching Scotland 2004
FRACTIONS
Definition
‘per cent’ means per hundred
Results
1
100
= 1%
1
10
= 10%
1
4
= 25%
1
2
= 50%
3
4
= 75% one whole = 100%
More fractions
What about
3
10
? Since
1
10
= 10%, can test this by using a calculator.
3
We know that
3
10
should be 30%. We means 3 ÷ 10. So do 3 ÷ 10 on your calculator.
10
You should get 0.3 This is not exactly 30!
So what is the problem?
20 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
FRACTIONS
Slick trick
Multiplying by 1 doesn’t change things.
Check it out…
7
1 = 7
15
1 = 15
3
1 = 3
999
1 = 999
But we know that 1 (one whole) = 100%.
So… (this is the tricky bit)… multiplying by 100 % (that’s 100% and not
100 the number) is the same as multiplying by 1 and doesn’t change the answer.
Read that ag ain, if you’re not still with me.
3
Back to
10
then.
3 ÷ 10 = 0.3 (a decimal)
3 ÷ 10
100% must equal the same thing because we are only multiplying by one (whole).
On your calculator do
3 ÷ 10
100 =
You should get 30.
Important note
Your calculator doesn’t show you that it means 30%. You have to know that for yourself.
Activity
7
Check that
10
= 70% by doing 7 ÷ 10
100 = on your calculator.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 21
© Learning and Teaching Scotland 2004
FRACTIONS
Questions 3.2
Use your calculator to convert the following fractio ns to percentages.
Use the routine
TOP ÷ BOTTOM
100 = every time.
Some answers are whole numbers. Some are decimals, e.g.
3
16
= 18.75%
1.
4.
7.
10.
13.
16.
19.
3
5
7
10
1
5
11
20
1
40
5
16
14
25
2.
5.
8.
11.
14.
17.
20.
1
8
4
5
7
8
9
40
11
50
9
16
4
25
3.
6.
9.
12.
15.
18.
21.
3
10
5
8
9
20
17
40
41
50
33
50
9
25
22 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
Answers 3.1
1.
4.
1
4
3
4
Answers 3.2
1. 60%
4. 70%
7. 20%
10. 55%
13. 2.5%
16. 31.25%
19. 56%
2.
5.
1
6
7
8
2. 12.5%
5. 80%
8. 87.5%
11. 22.5%
14. 22%
17. 56.25%
20. 16%
3.
6.
2
5
3
10
3. 30%
6. 62.5%
9. 45%
12. 42.5%
15. 82%
18. 66%
21. 36%
FRACTIONS
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 23
© Learning and Teaching Scotland 2004
PERCENTAGES
1
Remember that: 10% =
10
(one whole divided by 10)
1
1% =
100
(one whole divided by 100)
Example 4.1a
10% of £60 = £6 (just £60 ÷ 10)
(0.4 = 4 ÷ 10) 10% of 4 = 0.4
Example 4.1b
1% of £6 = 1% of 600p
= 6p
1% of 1573 = 15.73
Tricks of the trade
(600 ÷ 100)
(15.73 ÷ 100)
1. To find 5%, find 10% and half it.
2. To find 3%, find 1% and treble it.
3. To find 15%, find 10% then half that answer to find 5%. Then add your two answers together.
4. To find 2½%, find 5% then half the answer to get 2½%.
Example 4.1c
Find 5% of 80
Example 4.1d
10% of 80 = 8
5% of 80 = 4
1
2
of 8 = 4
Find 15% of 80
Example 4.1e
Find 3% of 220
10% of 80 = 8
5% of 80 = 4
15% of 80 = 12
1% of 220 = 2.2
3% of 220 = 6.6
8 + 4 = 12
2.2
3
6.6
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 25
© Learning and Teaching Scotland 2004
PERCENTAGES
Example 4.1f
Find 40% of 160
Questions 4.1
10% of 160 = 16
40% of 160 = 64
16
4
64
Calculate the following percentages. (Do not use a calculator.)
1. 5% of 60 2. 15% of 64 3. 20% of 160
4. 25% of 800
7. 7% of 300
10. 40% of £400
13.
2½% of 36
16. 17½% of 80
5. 60% of 500
8. 9 0% of £20
11. 75% of £240
14.
7½% of 48
6. 80% of 540
9. 8% of 120
12. 70% of 620
15. 150% of 62
Trick of the trade
So long as we can find 1%, we can find any percentage. Fo r example,
17% is 17 times as much as 1%.
Example 4.2a
Find 17% of £300.
Solution
(First find 1% by dividing by 100. Then multiply by 17).
£300 ÷ 100 = £3
£3 17 = £51
26 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
PERCENTAGES
Questions 4.2
Using a calculator work out the following:
1. 24% of 200 2. 16% of 400
4. 30% of 180
7. 95% of 400
10. 16% of 4000
5.
8.
16% of 2000
6% of 360
11. 12.5% of 880
13. 99% of 2000
16. 125% of 600
14. 40% of 36
3. 55% of 750
6.
9.
80% of 1600
28% of 480
12. 15% of 96
15. 17.5% of 400
Percentage profit =
Profit
Cost price
100%
Loss
Percentage loss =
Cost price
100%
Note: the cost price is t he amount of money paid by the ‘shopkeeper’ for the item being sold. Sometimes it is called t he ‘Buying Price’.
Example 4.3a
An antique dealer buys a vase of £60 and sells it for £72. Calculate his percentage profit.
Profit = £72 – £60
= £12
Percentage profit =
Profit
Cost price
100%
12
= 100%
60
= 20%
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 27
© Learning and Teaching Scotland 2004
PERCENTAGES
Example 4.3b
A shop buys coke cans for 24p each and sells them for 27 p each.
Calculate the percentage profit on each can of coke sold.
Profit = 27p –24p = 3p
Percentage profit =
Profit
Cost price
100%
3
= 100%
24
= 12.5%
Questions 4.3
For each of the following, calculate the actual profit or loss and the percentage profit or loss.
Cost price Selling price
1. £2.50
2.
£20
3. £15
4. £4.30
5. £24.80
6. £6.30
7. £15
8. £5.20
9. £126
10. £9.40
£2.70
£23.60
£11.25
£3.44
£31
£8.19
£17.55
£4.42
£157.50
£12.69
28 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
PERCENTAGES
Error
Percentage error =
Actual amount
100%
Increase
Percentage increase =
Original amount
100%
Decrease
Percentage decrease =
Original amount
100%
Example 4.4
In an experiment Peter calculated the weight of carbon to be 15g instead of 12g. Calculate his percentage error.
Error = 15 – 12 = 3g
Percentage error =
Error
Actual amount
100%
=
3
100%
12
= 25%
Questions 4.4
1. When measuring up a room for the new carpet, Ross measured the length of the room as 3.78m instead of 3.6m.
(a) What was the actual error in his measurement?
(b) What was the percentage error in his measurement?
2. A box of matches should contain 48 matches.
One box is selected at random and found to contain only 45 matches.
(a) What is the actual error in the number of matches contained in the box?
(b) What is the percentage error in the number of matches contained in the box?
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 29
© Learning and Teaching Scotland 2004
PERCENTAGES
3.
Helen’s salary increases from £18000 to £19080.
Calculate:
(a) the actual increase in her salary.
(b) the percentage increase in her salary.
4. A newspaper’s readership increases from 64000 to 66000.
Calculate:
(a) the actual increase in readership.
(b) the percentage increase in readership.
5. In order to help support a military campaign, the Chancellor of th e
Exchequer reduced the spending of the education department from £800,000,000 to £720,000,000.
Calculate:
(a) the actual reduction in spending.
(b) the percentage reduction in spending.
6. In a sale, the price of a dress decreases by £12. If its original price was £80 then calculate the percentage reduction.
30 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 4.1
1. 3
4. 200
7. 21
10. £160
13. 0.9
16. 14
Answers 4.2
1. 48
4. 54
7. 380
10. 640
13. 1980
16. 750
Answers 4.3
Actual profit/loss
1. £0.20 profit
2. £3.60 profit
3.
£3.75 loss
4. £0.86 loss
5. £6.20 profit
6. £1.89 profit
7. £2.55 profit
8. £0.78 loss
9. £31.50 profit
10. £3.29 profit
2. 9.6
5. 300
8. £18
11. £180
14. 3.6
2. 64
5. 320
8. 21.6
11. 110
14. 14.4
Percentage
8%
18%
25%
20%
25%
30%
17%
15%
25%
35%
3. 32
6. 432
9. 9.6
12. 434
15. 93
3.
6.
412.5
1280
9. 134.4
12. 14.4
15. 70
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 31
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 4.4
1. (a) 0.18m
2. (a) 3 matches
3. (a) £1080
4. (a) 2000
5. (a) £80,000,000
6. 15%
(b) 5%
(b) 6.25%
(b) 6%
(b) 3.125%
(b) 10%
32 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
EARNINGS
This section applies all the skills of the previous sections to our earnings.
It is vital that we are able to do calculations relating to the money we earn. This is part of budgeting.
Here, we will look at many of the key calculations that are used in working out how much we should be paid. There are many specialist terms that we need to get to know. These will be defined as we go along.
Example 5.1a
Sukhjinder works 38 hours per week and is paid £6.30 per hour.
Calculate his gross pay.
Solution
38 x £6.30 = £239.40 per week.
Gross pay is money earned before deductions.
Deductions are amounts of money taken off before we receive our pay, e.g. income tax or company pension scheme payment.
Example 5.1b
Stephanie works 40 hours at £7 per hour and 3 hours overtime at time and a half . Calculate her pay for the week.
Solution
Overtime rate = 1.5 x £7 = £10.50 (time and a half = 1.5 x normal rate)
Basic pay: 40 x £7 = £280
Overtime: 3 x £10.50 = £ 31.50
Total pay £311.50
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 33
© Learning and Teaching Scotland 2004
EARNINGS
Overtime means you are paid more per hour for each extra hour you work.
Example 5.1c
Colin works 36 hours at £8.40 per hour and 9 hours overtime at time and a quarter . Calculate his earnings for the week.
Solution
Overtime rate = 1.25 x £8.40 = £10.50
36 x £8.40 = £302.40
9 x £10.50 = £ 94.50
Total pay = £396.90
£8.40 ÷ 4 = £2.10 £8.40 + £2.10 = £10.50
Example 5.1d
Janice is a sales assistant, selling fashion sweaters. She earns a basic wage of £120 per week plus £3 for every sweater she sells. One week she sells 23 sweaters. Calculate her earnings for that week.
Solution
23 x £3 = £69
Example 5.1e
£120 + £69 = £189
Alan has a job as a car salesman. The garage pays him no basic wage at all. He only earns money if he sells cars and he is paid 4% of the value of his sales. In one year he sells cars to a total value of £560 000.
Calculate his earnings for the year.
Solution
£560 000 ÷ 100 x 4 = £22 400
34 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
EARNINGS
Examples 5.1d and 5.1e involved commission .
Commission is the money a sales person earns from selling. It may be just part of your earnings – or all of it.
Example 5.1f
Shamshad has a part-time job in a factory. She earns a basic wage of
£63 per week. She also earns money for the components she assembles.
However this part of her wage is only paid for the number of components above 200 that she assembles. Calculate her wage in a week when she assembles 580 components.
Solution
Basic wage £63.00
380 x £0.03 £11.40
Total wage £74.40
Note:
Enter 3p as 0.03 on the calculator (otherwise the calculator reads it as
£3)
Being paid for each piece of work that you do is called piecework .
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 35
© Learning and Teaching Scotland 2004
EARNINGS
Questions 5.1
1. Kit earns £7.20 per hour. Calculate his gross pay for a 36-hour week plus 5 hours’ overtime at time and a quarter.
2. Laura earns £6.50 per hour for a 35-hour basic working week.
Calculate her gross pay in a week when she works 37 hours.
(Overtime is paid at time and a half.)
3. Brian earns £12 per hour. He normally works 36 hours per week.
The first two hours of any overtime is paid at normal rate. After that, any more hours are paid at double time. Calculate his gross pay for a 43-hour week.
4. Jimmy works on the assembly line of a factory. He is expected to assemble at least 800 components per week. He earns 4p for every component assembled above this number. He also earns a basic wage of £81 per week. Calculate his gross pay in a week when he assembles 2130 components.
5. Jenna sells weapons to the armed forces. She is paid 1.2% of the total value of her sales. Calculate her annual salary in a year when she sells £4,600,000 of weapons.
6. Andrew earns £1350 per month plus 3% of his sales. Calculate his gross pay in a month where his sales total £19000.
7. Kris earns £6.80 per hour for a 36-hour week. He receives a 5% bonus on his basic pay. He also w orks 7 hours’ overtime at time and a quarter. Calculate his gross pay for that week.
36 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
EARNINGS
Pay increases are often announced on the news as percentages. It is important that we are able to work out what that means for us.
Example 5.2a
Martin earns £23430 per year as a fire-fighter. He is awarded a 4.2% pay increase. Calculate his new annual salary.
Solution
£23430 ÷ 100 x 4.2 = £984.06 (this would be rounded to £984 for an annual salary)
£23430 + £984 = £24414
Example 5.2b
Work ou t what Martin’s old and new pay per month will be. Also work out the monthly increase in his wages.
Solution
£23430 ÷ 12 = £1952.50 per month
£24414 ÷ 12 = £2034.50 per month
Monthly increase = £2034.50 – £1952.50 = £82
Questions 5.2
1. Jonathon earns £21750 per year. Calculate his new annual salary after a 2.3% pay increase.
2. Ross earns £31320 per annum (per year). Calculate his monthly increase if he gets a pay rise of 3.4%.
3. Emma earns £5.60 per hour. She is also paid 20p for every component she assembles.
(a) Calculate her new hourly rate after an increase of 5%.
(b) What should she be paid for each component assembled if her piecework rate is also increased by 5%?.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 37
© Learning and Teaching Scotland 2004
EARNINGS
The whole area of income tax is very complex. Some accountants are specialists in income tax. We will study the basics of the system, but we will need to take account of many different situations.
For many people, calculating how much income tax they should pay can be quite straightforward. However, if someone has a few jobs, with different methods of payment, or perks (e.g. a company car) or is married then the system can be more complicated.
Some things you should know:
Superannuation
If you pay into a superannuated pension scheme then you do not pa y income tax on the contribution.
Tax allowance
Everyone is allowed to earn a certain amount of money that is not taxed – called your Personal allowance. The amount depends on your circumstances. For example, pensioners are entitled to a higher Personal allowance.
Tax code
Your tax code is shown on your pay slip and is usually made up of three figures and a letter, e.g. 379L or 401P. An L indicates the basic Personal allowance while P signifies the full Personal allowance for those aged 65 to 74. The 3 79 and 401 mean that the people may earn £3790 and £4010 respectively before tax, i.e. this is their tax allowance.
Up-to-date tax allowances can be found in Inland Revenue publications and at www.inlandrevenue.gov.uk/leaflets/p3.htm#e.
In 2004 the Per sonal allowance basic amount is £4745.
Tax allowances change every year in the budget. There are other types of allowances depending on people’s jobs and circumstances.
Tax rate
Percentage tax rates also change in the budget. The rates we will use are:
Starting rate
Basic rate
Higher rate
10%
22%
40%.
38 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
EARNINGS
Taxable income
This is equal to your gross pay less your tax allowances. It is this amount which the Inland Revenue taxes (not your whole salary).
Examples
£4745.
Example 5.3a
These examples use the basic Personal allowance of
Nicola earns £10 985 p.a.* and has an additional personal allowance of
£530. Calculate her taxable income.
*p.a. stands for per annum and means ‘in each year’
Solution
Allowances 4745
+530
5275
Taxable Income = £5710
Salary 10985
–5275
5710
Example 5.3b
Mairi works parttime and earns £6545 each year. Calculate the tax she pays.
Solution
Salary
Tax allowance
6545
–4745
Taxable income 1800
Her taxable income is less than £1960 so the Starting rate of 10% applies.
Tax paid = £1800 ÷ 100 x 10 = £180
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 39
© Learning and Teaching Scotland 2004
EARNINGS
Example 5.3c
Mark earns £14200 p.a. Calculate the tax he pays.
Solution
Salary
Tax allowance
14200
–4745
9455
Taxable income 9455
Threshold for Basic rate –1960
To be taxed at Basic rate 7495 Taxable income
Tax payable = 10% of £1960 + 22% of £7495
= £196 + £1649
= £1845
Example 5.3d
James earns £10833 p.a. Calculate the tax he must pay per month.
Solution
Annual salary
Tax allowance
10833
–4745
Taxable income (for whole year) 6088
Threshold for Basic rate
To be taxed at Basic rate
–1960
4128
£1960 ÷ 100 x 10 + £4128 ÷ 100 x 22 = £196 + £908 = £1104
Tax paid per month = £1104 ÷ 12 = £92
Example 5.3d
Rhona earns £15000 p.a. and pays 6% of her salary in superannuation
(superannuation is non-taxable).
Calculate:
(a) her taxable income
(b) her take-home pay.
Solution
(a) 6% of £15000 = £900, Tax allowance = £4745
900
+4745
15000
–5645
Total non-taxed income £5645 Taxable income = £9355
40 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
EARNINGS
(b)
Taxable income
Threshold for Basic rate
9355
–1960
£7395 To be taxed at Basic rate
£1960 ÷ 100 x 10 + £7395 ÷ 100 x 22 = £196 + £1627 = £1823
Takehome pay = £15000 – £900 – £1823 = £12277
Questions 5.3
Refer to the tax allowances mentioned in the notes.
1. Mo earns £18200 per annum. She has an additional personal tax allowance of £250.
Calculate:
(a) her taxable income
(b) her tax paid
(c) her take-home pay for the year.
2. Jennifer earns £27000 per annum. She pays 5% of this as superannuation (before tax).
Calculate:
(a) her taxable income
(b)
(c) her tax paid her take-home pay for the year.
3.
Scott earns £13410 per year. He pays £660 per year into a pension fund (before tax).
Calculate
(a) his taxable income
(b) his tax paid
(c) his annual take-home pay
(d) his weekly take-home pay.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 41
© Learning and Teaching Scotland 2004
EARNINGS
If your taxable income is above a certain amount (called the threshold ) then you move into a higher tax band. Only the difference is taxed at the higher rate. In 2004 the higher rate tax threshold was £30500 and the higher rate was 40%.
On this basis a person with a taxable income of £35000 would be taxed as follows:
10% of £1960
22% of £28540 (£30500 – £1960 = £28540)
40% of £4500 (£35000 – £30500 = £4500)
Example 5.4a
Calculate the takehome salary of someone earning £38000 p.a.
Solution
Salary
Tax allowance
38000
–4745
Taxable income
Higher threshold
33255
–30500
Taxable income 33255 To be taxed at higher rate 2755
Tax payable = 10% of £1960 + 22% of £28540 + 40% of £2755
= £196 + £6279 + £1102
= £7577
Takehome salary = £38000 – £7577 = £30423
Example 5.4b
A man earns an annual salary of £36705. He has an additional personal tax allowance of £210.
Calculate
(a) his taxable income
(b) his tax paid in one year
(c) his net monthly salary.
42 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
EARNINGS
Solution
(a) Personal allowance
Total tax allowance
4745
Additional personal allowance +210
36705
–4955
4955 Taxable income £31750
(b) Tax paid = 10% of £1960 + 22% of £28540 + 40% of £1250
= £196 + £6279 + £500
= £6975
(c) Net annual salary = Gross annual salary – Tax paid
= 36705 – 6975
= £29730
Net monthly salary
Questions 5.4
= £29730 ÷ 12
= £2477.50
1. Calculate the annual takehome salary of someone earning £37200 per annum.
2. Calculate the takehome salary of a man earning £43200 per annum.
3. A woman earns £38700 per annum. She pays 6% superannuation
(before tax).
Calculate
(a)
(b)
(c) her taxable income her tax paid her take-home pay per month.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 43
© Learning and Teaching Scotland 2004
EARNINGS
Answers 5.1
1. £304.20
4. £134.20
7. £316.54
2. £247
5. £55200
Answers 5.2
1. £22250 (to the nearest £)
2. £88.74
3. (a)
£5.88
(b) 21p
Answers 5.3
1. (a) £13205
2. (a) £20905
3. (a) £8005
(d) £215.85
(b) £2669.90
(b) £4363.90
(b) £1525.90
3. £576
6. £1920
(c) £15530.10
(c) £21286.10
(c) £11224.10
44 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
Answers 5.4
1. £37200 – £4745 = £34455 (taxable income)
£34455 – £30500 = £1955
10% of £1960 = £196
22% of £28540 = £6279
40% of £1955 = £782
Tax paid = £196 + £6279 + £782 = £7257
£37200 – £7257 = £29943
2. £43200 – £4745 = £38455
£38455 – £30500 = £7955
10% of £1960 = £196
22% of £28540 = £6279
40% of £7955 = £3182
Tax paid = £196 + £6279 + £3182 = £9657
£43200 – £9657 = £33543
3. (a) £31633
(b)
£6928 (to the nearest £)
(c) £2454.15
EARNINGS
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 45
© Learning and Teaching Scotland 2004
WORKING WITH MONEY
Working with money is one of the most important skills we can learn.
Very often we will have the use of a calculator, a computer or a checkout till to help us. However, knowing what calculations to do and how to do them is key to many jobs.
In this section we will be using multiplication and percentages mostly. We will often be adding value added tax (VAT) to amounts. When we do this, we will always use 17.5% for the VAT.
When adding VAT to a number of items it is always quicker to add up the total first. Then we need only calculate the VAT once, at the end.
It is important to remember that most prices displayed in shops already include VAT. However, some do not. This is often the case when ordering goods over the internet or by post.
Example 6.1a
A computer costs £980 + VAT. Calculate:
(a) the VAT to be paid
(b) the total price
Solution
VAT = £980 ÷ 100 x 17.5 = £171.50
Total price = £980 + £171.50 = £1151.50
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 47
© Learning and Teaching Scotland 2004
WORKING WITH MONEY
Example 6.1b
A stereo costs £350 + VAT. Post and packing is added at a cost of £8.95.
Calculate:
(a) the VAT to be paid
(b) the total price
Solution
(a) VAT = £350 ÷ 100 x 17.5 = £61.25
(b) Total price = £350 + £61.25 + £8.95 = £420.20
Note: VAT is not charged on the post and packing, only on the goods.
Questions 6.1
In questions 1 to 6, calculate (a) the VAT and (b) the total price.
1. £200
4. £26
2. £750
5. £102
3. £840
6. £12.40
7. Goods valued at £103, £88, £14 and £23 are bought.
Calculate the total bill after VAT has been added.
8. A scanner costs £98 + VAT + £3.50 post and packing.
Calculate the total cost to be paid when ordering the scanner.
48 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
WORKING WITH MONEY
Everyday life and work is full of practical problems involving four rules calculations. We need to look at problems involving lengths, areas and volumes, as well as weight and temperature. Of course, we will also come across money calculations in all this as well.
Example 6.2a
A room is 4m long by 3.6m broad. Calculate:
(a) the area of the floor
(b) the cost of carpeting the room with carpet priced at £8.65 per square metre.
Solution
(a) 4m x 3.6m = 14.4 m 2
(b) 14.4 x £8.65 = £124.56
Example 6.2b
A room is 4m long by 3.6m broad. It is 2.8m high. Calculate:
(a) the perimeter of the floor.
(b) the area of all the walls
(c) the number of litres of paint needed to cover all the walls if one litre covers 15m 2 . (Don’t worry about the windows and doors!)
(d) the number of tins to be bought if paint comes in 2 litre tins
(e) the cost of the paint if each tin costs £9.55
Solution
(a) 4m + 3.6m + 4m + 3.6m = 15.2m
(b) 15.2m x 2.8m = 42.56 m 2 (round this up to 43 m 2 )
(c) 43 ÷ 15 = 2.866 … round this up to 3 litres
(d) 2 tins
(e) £9.55 x 2 = £19.10
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 49
© Learning and Teaching Scotland 2004
WORKING WITH MONEY
Questions 6.2
1. A room is 3.4m long by 3.8m broad.
(a) Calculate the area of the floor.
(b) Calculate the cost of carpeting the room with carpet costing
£9.50 per m 2 .
(c) How much more would it cost to carpet the room with carpet costing £11.65 per m 2 ?
2. A classroom is 8m long by 7.2m broad. It is 2.9m high.
Calculate:
(a)
(b) the perimeter of the floor the total area of all the walls
(c) the number of litres of paint to be bought if four such classrooms are to be painted and one litre covers 22m 2 .
(d) the number of tins to be bought if paint comes in 5 litre tins
(e) the cost of the paint if each tin costs £18.50.
Hire purchase agreements are sometimes called:
paying it up
buying on the never-never!
Definitions
Deposit an initial payment of part of the price of the goods
Instalments weekly or monthly payments made to ‘pay up’ the rest of the price
Cost of credit how much more the HP payment method costs, above the cash price
50 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
WORKING WITH MONEY
Example 6.3a
A sound system costs £349 cash OR a deposit of £50 and 12 monthly instalments of £29.
Calculate:
(a) the total HP price
(b) the cost of credit
Solution
(a) Deposit £50.00
12 x £29 £348.00
Total HP price £398.00
Example 6.3b
(b) £398 – £349 = £49
A computer costs £995 cash OR a 10% deposit and 24 monthly instalments of £41.
Calculate:
(a) the total HP price
(b) the cost of credit
Solution
(a) Deposit
24 x £41
£99.50
£984.00
Total HP price £1083.50
(b) £1083.50 – £995 = £88.50
(£995 ÷ 100 x 10)
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 51
© Learning and Teaching Scotland 2004
WORKING WITH MONEY
Questions 6.3
1. Work out the HP costs of items bought under the following terms:
(a) Deposit £40, 12 instalments of £18.
(b) Deposit £250, 24 instalments of £40.
(c) Deposit £8, 52 instalments of £3.50.
(d) Cash price £260. Deposit 10% of cash price and 6 instalments of £45.
(e) Cash price £3250. Deposit 20% of cash price and 24 instalments of £120.
2. How much cheaper is the cash price than the HP price in questions
1(d) and 1(e)?
3. A dishwasher can be purchased for £390 cash. On HP a deposit of
10% is required followed by 12 monthly instalments of £29.25.
(a) Calculate the total HP price.
(b) Comment on your answer.
52 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 6.1
1. (a) £35
2. (a) £131.25
3. (a) £147
4. (a) £4.55
5. (a) 17.85
6. (a) £2.17
7. £267.90
8. £118.65
(b) £235
(b) £881.25
(b) £987
(b) £30.55
(b) £119.85
(b) £14.57
Answers 6.2
1. (a) 12.92 m 2
(b)
£122.74
(c) £27.78
2. (a) 30.4m
(b) 88.16 m 2
(c) 16.03 litres
(d) 4 tins
(e)
£74
Answers 6.3
1. (a) £256
(b) £1210
(c) £1.90
(d) £296
(e)
£3530
2. £36, £280
3. (a) £390
(b) HP price is the same as cash price. (This is sometimes called
0% interest.)
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 53
© Learning and Teaching Scotland 2004
CALCULATIONS WITH TIME
‘How long does the film last?’
‘How many hours have I worked?’
We all need to be able to calculate lengths of time. This s ection is concerned with making awkward calculations simpler. We won’t be dealing with questions like, ‘How long from 10 am to 1 pm?’ That’s too easy.
Example 7.1a
Dyce
Aberdeen
Portlethen
Stonehaven
Montrose
Arbroath
Carnoustie
Monifieth
Broughty Ferry
Dundee
Invergowrie
Perth
Gleneagles
Dunblane
Stirling
Larbert
Lenzie
Glasgow Queen St
0650
0707
…
0723
0745
0759
0806
…
…
0820
…
0842
…
…
…
…
…
0938
0908
0939
…
0955
1017
1031
1038
…
1044
1051
…
1113
1148
1201
1143
1158
1216
1215
How long is the 09.08 journey from Dyce to Glasgow Queen Street?
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 55
© Learning and Teaching Scotland 2004
CALCULATIONS WITH TIME
Solution
Method 1 (Count it out)
09.08 to 09.15 = 7 mins
09.15 to 12.15 = 3 hours
Total time = 3 hours 7 mins
Method 2 (Calculation)
Take the start time away from the finish time.
12.15
– 09.08
3.07 3 hours 7 mins
Note
Never give an answer to this kind of question as 03.07.
03.07 is a time of day
3 hours 7 minutes is a length of time
Example 7.1b (trickier)
How long is the 06.50 journey from Dyce to Glasgow Queen Street?
Solution
Method 1 (Count it out)
06.50 to 07.00 = 10 mins
07.00 to 09.00 = 2 hours
09.00 to 09.38 = 38 mins
Total time = 2 hours 48 minutes
56 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
CALCULATIONS WITH TIME
Method 2 (Calculation)
Take the start time away from the finish time.
09.38
– 06.50
Problem! You can’t take 50 from 38.
Here, we use a clever trick. We do the minutes ’ calculation off to one side, but first we ‘steal’ an hour.
Changes to 08 09.38 + 60 mins
– 06.50
98
– 50
48
08
– 06
02
Answer 2 hours 48 minutes
Questions 7.1
Calculate these lengths of time.
1. From 07.13 to 11.48
2. From 13.22 to 20.55
3. From 03.46 to 08.29
4. From 17.23 to 23.03
5. From 10.27 to 16.11
6. From 18.51 to 22.17
7. From 06.29 to 21.13
8. From 21.13 to 06.29 next day
Hint for question 8. pretend that 06.29 next day is 30.29 today (!), i.e. add 24 hours to the 6 hours.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 57
© Learning and Teaching Scotland 2004
CALCULATIONS WITH TIME
Speed = Distance ÷ Time
Example 7.2a
Sam drove 189 miles in 4½ hours. Calculate her average speed.
Solution
Speed = Distance ÷ Time
= 189 ÷ 4.5
= 42 mph
N otice that the ‘units’ all tie up.
DISTANCE
SPEED miles hours miles per hour
Example 7.2b
Geoff runs 100m in 12.5 seconds. Calculate his speed.
Solution
Speed = Distance ÷ Time
= 100 ÷ 12.5
= 8 m/sec
TIME
58 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
CALCULATIONS WITH TIME
Questions 7.2
Calculate the speed of each of these journeys.
1. 78 km in 6 h
4. 60 km in 1½ h
7. 1500 km in 1¼ h
2. 133 km in 2 h
5. 180 km in 2¼ h
8. 750 km in 1½ h
3. 187 km in 5 h
6. 280 km in 2h 30 min
9. 560 km in 1h 45 min
Distance = Speed
Time
Example 7.3
A train travels across the American prairies at a steady speed of 85 mph.
If it travels for 9 hours non-stop, how far will it get?
Solution
Distance = Speed
Time
= 85
9
= 765 miles
Questions 7.3
Calculate the distanced travelled.
1. 6 h at 80 km/h
2. 3 h at 100 km/h
3. 5 h 30 min at 60 km/h
4. 2½ h at 78 km/h
5. 3½ h at 112 km/h
6. 7 h 45 min at 42 km/h12.
7. 7 h at 30.2 km/h
8. 4 h at 71.6 km/h
9. 5½ h at 52.8 km/h
10. 160 km/h for 2¼ h
11. 220 km/h for 1½ h
12. 300 km/h for 3 h 45 min
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 59
© Learning and Teaching Scotland 2004
CALCULATIONS WITH TIME
Time = Distance ÷ Speed
Example 7.4
To test the endurance of a new car, it is run on a test track at a steady 80 mph until it has covered exactly 260 miles. How long does this time trial last?
Solution
Time = Distance ÷ Speed
= 260 ÷ 80
= 3.25 hours
= 3 hours 15 minutes
Note
0.25 of an hour = ¼ of an hour = 15 minutes
Questions 7.4
Find the time taken to do these journeys.
1.
2.
3.
98 km at 14 km/h
150 km at 7.5 km/h
750 km at 12.5 km/h
4. 292.5 km at 30 km/h
5. 270 km at 45 km/h
6. 370 km at 40 km/h
7. 600 km at 80 km/h
8. 750 km at 500 km/h
9. 325.5 at 62 km/h
60 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 7.1
1. 4 hours 35 minutes
2. 7 hours 33 minutes
3. 4 hours 43 minutes
4. 5 hours 40 minutes
5. 5 hours 44 minutes
6. 3 hours 26 minutes
7. 14 hours 44 minutes
8. 9 hours 16 minutes
Answers 7.2
1. 13 km/h
4. 40 km/h
7. 1200 km/h
Answers 7.3
1. 480 km
2. 300 km
3. 330 km
4. 195 km
5. 392 km
6. 325.5 km
Answers 7.4
1. 7 hours
2. 20 hours
3. 60 hours
4. 9 hours 45 mins
5. 6 hours
2. 66.5 km/h
5. 80 km/h
8. 500 km/h
7. 211.4 km
8. 286.4 km
9. 290.4 km
10. 360 km
11. 330 km
12. 1125 km
3. 37.4 km/h
6. 112 km/h
9. 320 km/h
6. 9 hours 15 mins
7. 7 hours 30 mins
8. 1 hour 30 mins
9. 5 hours 15 mins
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 61
© Learning and Teaching Scotland 2004
RATIO
The simplest use of ratios is when comparing things.
Johnny was paid £5 per hour, as compared to Sandra who was paid
£8 per hour.
Here the total wages bill was shared out in the ratio 5 : 8.
A bag of sweets is shared between Dave and Nancy. Dave is given two sweets for every one that Nancy is given.
Here the sweets are shared out in the ratio 2 : 1.
Ratios can be used to describe unequal division.
Activity
Consider the following situations. What do they have in common?
John gets 12 sweets when Elaine gets 6.
Allan gets 8 sweets when Joyce gets 4.
Tom gets 10 sweets when Jennifer gets 5.
Angus gets 2 sweets when Pauline gets 1.
Answer
Well, they’re all about handing out sweets. The boys always get more than the girls. But, did you notice the crucial similarity? The boys always get twice as many as the girls (or the girls got half as many as the boys).
This comparison is true in all four situations.
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 63
© Learning and Teaching Scotland 2004
RATIO
Boys
12
8
10
:
:
:
:
2 :
These ratios are all equal.
12 : 6 = 2 : 1 8 : 4 = 2 : 1
Girls
6
4
5
1
10 : 5 = 2 : 1
Ratios are used to make comparisons.
When we write a ratio such as 12 : 6 in the form 2 : 1, we are writing it in its simplest form .
12 : 6 becomes 2 : 1 by dividing both parts of the ratio by the largest number we can find which will work.
12 can be divided by 6
6 can be divided by 6
12
÷ 6
2
: 6
÷ 6
: 1
If you use a smaller number we get:
12
÷ 3
4
: 6
÷ 3
: 2
64 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
RATIO
But 4 : 2 is not in simplest form.
4
÷ 2
: 2
÷ 2
: 1 2
Questions 8.1
1. Write these ratios as simply as possible.
(a) black dots to white dots
(b) ticks to crosses
(c) a’s to z’s
(d) squares to circles
(e) m’s to n’s
(f) ticks to crosses
(g) £ signs to $ signs
(h) 6’s to 9’s
a a a a
z z z z z z z z z z z z z z z z z z z z m m m m m m m m m m m m
£ £ £ £ £ £ £ £
£ £ £ £ £ £ £ £
6 6 6 6 6
6 6 6 6 6 n n n n
9 9
$ $
$ $
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 65
© Learning and Teaching Scotland 2004
RATIO j g d a
2. For each diagram, write as simply as possible the ratio of shaded pieces to unshaded pieces. b c e h k i l f
3. Write these ratios in their simplest forms
(a) 2 : 8 (b) 4 : 6 (c) 7 : 21
(e) 9 : 12
(i) 15 : 5
(f) 6 : 18
(j) 36 : 6
(g) 3 : 12
(k) 35 : 10
(d) 10 : 15
(h) 8 : 4
(l) 18 : 12
66 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
RATIO
We know that 12 : 6 = 2 : 1
So in length, 12 cm : 6 cm in weight, 12 kg : 6 kg
in capacity, 12 litres : 6 litres
= 2 : 1
= 2 : 1
= 2 : 1
Each first quantity is twice the size of each sec ond quantity.
But what about 12 m : 6 cm?
12 m is not twice the length of 6 cm.
We must make the units the same before we can make a true comparison.
12 m : 6 cm
= 1200 cm : 6 cm
÷ 6 ÷ 6
= 200
Example 8.2a
: 1
Write 5p : £1 in its simplest form.
Solution
5p : £1
= 5p : 100p
÷ 5 ÷ 5
= 1 : 20
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 67
© Learning and Teaching Scotland 2004
RATIO
Example 8.2b
Write 1cm : 4mm in its simplest form.
Solution
1 cm : 4mm
= 10 mm : 4 mm
÷ 2 ÷ 2
= 5 : 2
Questions 8.2
Write these ratios in their simplest forms.
(a)
(d)
(g)
1 mm : 1 cm
2 mm : 1 cm
3 min : 1 hour
(b) 1 day : 1 week (c) 1p : £1
(e) 6 days : 2 weeks (f) 2p : £1
(h) 500 cm 3 : 1 litre
(k) 4 mm : 2 cm
(i) 100 g : 1 kg
(l) 50p : £3 (j) 250 m : 1 km
(m) 30 min : 2 hours (n) 6 days : 3 weeks (o) 100 cm 3 : 2 litres
(p) 20 min : 3 hours (q) 40p : £1.60 (r) 50p : £1.25
(s) 250 g : ½ kg (t) 8 mm : 3.6 cm (u) 64p : £2.40
68 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
RATIO
Here is a recipe for slimeade.
Take 3 litres of semi-skimmed milk and 2 litres of limeade.
Mix together. Chill. Enjoy.
Clearly 3 litres + 2 litres = 5 litres. This is a recipe for 5 litres of slimeade.
If you only want a taste first then use this recipe:
3 spoonfuls of semi-skimmed milk
2 spoonfuls of limeade
This makes 5 spoonfuls of slimeade.
Notice that the quantities have changed, but the proportions have not.
The ratio of semi-skimmed milk to limeade in both cases is 3 : 2.
Now we turn the problem round. Suppose we want to make 10 pints of slimeade. How much of each ingredient should we start with? This problem is addressed in the next example.
Example 8.3a
Share 10 pints in the ratio 3 : 2.
Solution
Step 1 count the ‘parts’
Step 2 divide total by number of parts
3 + 2 = 5 parts
10 pints ÷ 5 = 2 pints
Step 3 allocate the parts
3 parts semi-skimmed milk
2 parts limeade
Step 4 double check
6 pints + 4 pints = 10 pints
= 3
= 2
2 pints = 6 pints
2 pints = 4 pints
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 69
© Learning and Teaching Scotland 2004
RATIO
Example 8.3b
Share £84 in the ratio 3 : 4
Solution
3 + 4 = 7 parts
£84 ÷ 7 = 12
3
£12 = £36 4
£12 = £48
(check = £36 + £48 = £84)
£84 shared in the ratio 3 : 4 is £36 : £48
Questions 8.3
Share the following quantities in the ratio given:
1. £1200 in the ratio 2 : 1
2. £549 in the ratio 5 : 4
3. 775 kg in the ratio 2 : 3
4. 68 m in the ratio 3 : 1
5. 102 litres in the ratio 5 : 7
6.
£225.60 in the ratio 1 : 5
70 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
RATIO
Activity
Decide which is the better buy:
2 chocolate biscuits cost 24p
5 chocolate biscuits cost 60p
Answer
Did you find that neither was the better buy? Each deal was as good as the other.
If you did, you probably worked out the cost of one chocolate biscuit.
In direct proportion problems, finding the cost of one is very important.
Definition
Two quantities are in direct proportion to each other if a change in one gives the same change in the other.
[NB The ‘change’ must be multiplication or division]
Example 8.4a
If 7 CDs cost £63, find the cost of 3 CDs.
Solution
1 CD costs £63 ÷ 7 = £9
3 CDs cost £9 3 = £27
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 71
© Learning and Teaching Scotland 2004
RATIO
Example 8.4b
Anne walks 8 miles in 2 hours. How far should she walk in 3 hours?
Solution
1 hour = 8 miles ÷ 2 = 4 miles
3 hours = 4 miles
3 = 12 miles
Example 8.4c
Apples cost 84p for 7. How much do 4 cost?
Solution
1 costs = 84 ÷ 7 = 12p
4 cost = 12p
4 = 48p
Questions 8.4
1. 8 books cost £52.
2.
3 cars cost £36000.
3. 36 eggs cost £5.04.
4. 12 books cost £71.40.
5. 3 oranges cost £54p.
How much will 11 cost?
How much will 5 cost?
How much will 6 cost?
How much will 5 cost?
How much will 4 cost?
6. 6 sacks of potatoes cost £46.80. How much will 1½ sacks cost?
72 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
RATIO
Answers 8.1
1. (a) 1 : 2
(e) 3 : 1
2. (a) 3 : 1
(e) 3 : 1
(i) 1 : 3
3. (a) 1 : 4
(e) 3 : 4
(i) 3 : 1
Answers 8.2
(a) 1 : 10
(d) 1 : 5
(g) 1 : 20
(j) 1 : 4
(m) 1 : 4
(p) 1 : 9
(s) 1 : 2
(b) 1 : 3
(f) 2 : 1
(b) 2 : 1
(f) 5 : 1
(j) 1 : 2
(b) 2 : 3
(f) 1 : 3
(j) 6 : 1
(b) 1 : 7
(e) 3 : 7
(h) 1 : 2
(k) 1 : 5
(n) 2 : 7
(q) 1 : 4
(t) 2 : 9
Answers 8.3
1. £800 : £400
2. £305 : £244
3. 310 kg : 465 kg
4. 51 m : 17 m
5. 42.5 litres : 59.5 litres
6. £37.6 : £188
(c) 1 : 5
(g) 4 : 1
(c) 3 : 1
(g) 1 : 3
(k) 1 : 3
(c) 1 : 3
(g) 1 : 4
(k) 7 : 2
(d) 1 : 2
(h) 5 : 1
(d) 5 : 3
(h) 1 : 5
(l) 1 : 3
(d) 2 : 3
(h) 2 : 1
(l) 3 : 2
(c) 1 : 100
(f) 1 : 50
(i) 1 : 10
(l) 1 : 6
(o) 1 : 20
(r) 2 : 5
(u) 4 : 15
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 73
© Learning and Teaching Scotland 2004
RATIO
Answers 8.4
1. £71.50
2. £60000
3. £0.84
4. £29.75
5. 72p
6. £11.70
74 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
FORMULAS
Definition
A formula is a mathematical rule written using letters to stand (as code) for numbers.
We need to know the four rules.
Addition: use a ‘+’ sign
Subtraction: use a ‘–‘ sign
Multiplication: write letters next to each other
Division: write letters one over the other, just like in a fraction.
Example a a ab a b
+
– b b
(means a
b
(means a
b)
)
Example 9.1a
The cost of paying two people is a + b , where a is the wage of the first person and b is the wage of the second person. Calculate the cost of paying one person £100 and another person £120.
Solution a + b
= 100 + 120
= 220
Answer £220
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 75
© Learning and Teaching Scotland 2004
FORMULAS
You do realise, I hope, that I just made a formula up when all you had to do was add two numbers together in your head.
That’s how easy formulas can be!
But be careful. Strictly speaking we have to say what we are calculating
– in this case, the total wage bill. Let’s call it W . So that:
W = a + b
= 100 + 120
= 220
( W = 220 when a = 100 and b = 120)
Example 9.1b
Calculate e if e = f
– g and f = 75, g = 10.
Solution e = f – g
= 75 –10
= 65
Example 9.1c
Calculate p if p = qr and q = 3, r = 5.
Solution p = qr
= 3
5
= 15
(Remember that
(the answer is qr not
means q
r )
‘35’, a ‘3’ beside a ‘5’!!!)
Example 9.1d
Calculate m if m = 4 n and n = 11.
Solution m = 4 n
= 4
11
= 44
(here the 4 in front of the n means 4
n )
76 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
Example 9.1e
t
Calculate s if s = u
and t = 100, u = 4.
Solution s =
= t u
100
4
= 25 (100 ÷ 4 = 25)
Questions 9.1
Work out each formula for the values given.
Formula Values
1. c = m + n m = 7, n = 10
2. a = y – p y = 33, p = 3 b = 11 3. t = 4 b
4. e = w d
5. s = qv w = 16, d = 2 q = 3, v = 6
FORMULAS
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 77
© Learning and Teaching Scotland 2004
FORMULAS
OK, so that was quite easy. But sometimes we need to ‘manage’ more than one calculation.
Example 9.2a
Calculate a when a = 3b + 2c and b = 5, c = 6.
Solution a = 3b + 2c
= 15 + 12
= 27
Example 9.2b
Calculate t =
4 p r
when p = 9, r = 6 t
Solution
=
=
4 p r
36
6
= 6
Sort out each part of the fraction separately first.
4 p = 4
p = 4
9 = 36
Example 9.2c
This is like the last example, but trick ier. Remember to sort out each part of the fraction first, before dividing.
Calculate c = when m = 7, p = 4
2 p
Solution c =
2 p
=
32
8
= 4
(5m – 3 = 35 – 3 = 32)
5
m = 5
7
78 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004
Questions 9.2
Work our each formula for the values given.
Formula
1. 2 t + 5
Values t = 4
2. d = 4 m + 3 p m = 2, p = 7
3. e =
4. n =
4 a
3
5 – 1
2 gh
5. f = m
6. w = 8 p + 4 g – 7
7. h = 11 y – 3 k
8. t =
4 – 5 s
3 w a = 12 s = 3 g = 2, h = 16, m = 4 p = 2, g = 3 y = 4, k = 2 a = 15, s = 6, w = 2
FORMULAS
NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION 79
© Learning and Teaching Scotland 2004
SAQ ANSWERS
Answers 9.1
1. c = 17
2. a = 30
3. t = 44
4. e = 8
5. s = 18
Answers 9.2
1. c = 13
2. d = 29
3. e = 16
4. n = 7
5. f = 8
6. w = 21
7. h = 38
8. t = 5
80 NUMERACY: OUTCOME 4 (INTERMEDIATE 1) TEXT VERSION
© Learning and Teaching Scotland 2004