Name:
Colligative Properties Calculations
Equations:
m=molality
m
moles solute
kg solvent
Kb(H2O) = 0.52 oC/m
T f  K f m
Tb  K b m
Kf(H2O) = 1.86 oC/m
1. What is the molality of a solution of 1.25 moles of sugar dissolved in 0.750 kg of water? What is
the boiling point and freezing point of the resulting solution?
2. Calculate the freezing point of a solution made from 32.7 g of propane, C 3H8, dissolved in 137.0
g of benzene, C6H6. The freezing point of benzene is 5.50°C and its Kf is 5.12°C/m.
3. Calculate the boiling point of a solution made from 227 g of MgCl2 dissolved in 700. g of water.
4. An aqueous solution was found to have an initial freezing point of -2.15 oC. What was the
molality of the solution?
5. A solution of glucose (MM = 180.18 g/mol) in 500. g of water had a boiling point of 102.25 oC.
a. What is the molality of the solution?
b. How many moles of glucose were added?
c. How many grams of glucose were added?