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Jethwa Maths Paper A - solutions

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Ig IG
HI
b)
4
-
10
2B
-
455+6
GT3
-
2105
a)
1831=653
=
x
21
Coo
-
2x
ya
-
-
)
+7
)
t
+7
210C -112-2+7
21×-712
b)
min
c)
fi -71
-
a)
i
,
2×2-4×+1
2×2
je
x=
y
-
-
42
-
six
=3
2
-
o
-
-
I
so
3×2-14 xtk.de
=
of -12×2 tkoctc
=
Otc
23-12122 )
848
C
-
-
1
7- T2
7tT2 ,
J
-
x=
.
.
b) Thx
'
:
y
-
K2 -2=18
t
2K
-
2=78
Toc
-
foot -12×+1 )
If
xx
) Ix -17 )
x -0
,
,
k
-2
23 -12×2+2×-2
-12×2-12×-2=2-2
23-12×2
a
t
2
-
-1
-
o
o
-
Mb
M,
-
at
7
so
i
-
-
i
2
-0 :
at sci
o
-
3-4+2--7
n:
gradient equal
taught
y
-
-
-
y
-
f-
z
7
=-3
-
,
when
s
)
sci
-
7
4)
3ft
sink )
-
t
3sin3c
sink
sink
T
-
sine
b)
3T I
-
"
+7
C
+13
"
"
,
(
-
,
-3
)
3/2
C
xx
7
X
,
1
=
-
17
-
7=0
42
=
4×3
=
x
"
X
6×2
=
724
=
OC
It 4×+6×2 -140C
bi )
9
40C
=
'
X
,
=
-
1
=
2×72×05
C
Ko 330
4
co
"
l
-
4
"
a)
"
(y
+
10,3 )
-
ly
+
(x -1012
r
'
toc
"
-1405+12+852*4
77 -112K
H
-
-
ra )
'T
4ha +12
117-12521
289
3=0
2
-1012
Coc
-
o
t 288
-
8oz
'
-
+4/2
408oz
577 -408ha
,
+
→
-
-
sci
a)
tssinoc
bsinx-02sinx-5s.mx
12×+7 ) fsc
3
-
,
270
-
3)
a)
f-
13 )
33
=
4132 )
-
x
-
-118--0
27-3G-9t18h
thus
bi
313 )
-
s
+3
sa
( Oc -3 )
4×2
-
-
-
a
factor
3×+18
t
Ie
¥2
is
-
33C
-
.
-
Ect -18
-
T O
O
foc 3) foe x G )
(
3) Ioc 3) foe -12 )
-
x
c)
-
-
y
d) ÷
-
-
=
-
i
O
-
>
(
-
3)
&
fsc -121
because
( 3,0 )
.
x
3×2-8×-3=0
( x 3) I 3×+1 )
repeated
-
x
=3
-
,
f
-
-
3
oc
=
Iz
-4
n
.
b)
2graspoalsutoioff.ae
cross
twice
two
in this
equations
interval
(
o
root
a)
27
b)
=
27
=
'
YT
3/8
=
=
"
log 12) t 310g 12 )
log 2
log 6
"
-
"
let
)
=3
52
.
3
sock
3
x
=
TE
-
Toc
-
3g
-
y
-
'
log 16 )
-
oc
Ip
2
-
-
-
z
let
a-
's
-
0
o
( 1,01
( 4,0 )
4
-
x
slog 2
to
7,2
Ioi
'
log 6
-
=
2
-
ya
22
-
)
-
log 6
-
P=oc=1
b) d÷=
2
=
-
÷6
G
log f6k÷G
=
oology
÷
6
=
'
a)
8
x
a
29×23
OC
a
×
a
log 1272 )
x
toga 8
>
27
a
8
+
as toga
=
-1×-3=0
sik
( si 's )
+
'
to
-
key
-
Ly
'
t
ly
y
y
-
'
-
O
SEA
=
y
I)
O
IT'S
,
,
-
O
2
bye
3-
£
's
212
-
-
(2
,
0.17157
"
)
↳
s
)
=
calc
0.17157
does not
.
answer
g
day
-
Tsi
's
¥123 )
-
-
give
form
Isis's
3-2/2-5 )
-
-
0.1768--0
Aof
in surd
1210.17151-1
14,01
.
.
i
.
maximum
I
a)
0.745326L
( 052
7
i
so
-
sink
IF
I
b)
(
b2
#
2abCosk )
=
2×7×3 tf
-
=
-
'
'
cos
121
-
#
-72-145
=
c)
1-
a
94-7X
III
x
41.8
-
3.
-
y
7
-
toy 712 -1213g 7) ly )
-
-
9
'
-149
y
14 ya
-
-
42g
+
y
a)
f÷
b)
J
1
=
-
Gsi
'
.
0=-1+2
-
n
t
-
y
-
=
X
X
7
-
f
+
y
-
2)
2 + c
sa
-
-
-
-
3×3
3×7
4×-3
to
-
-
O
7
2-12/2-21
2.
y
=
7
'
14g
c
-
-
c =
y
-
dsc
-12×-2
x
,
Ibi -41
,
6y2
'
-
-
y
-
7
442--0
56
g- 3
=
x
256
i
'
t
z
-
-
e
7--32
-
-
7
7
=
=
2
-4
-
-
o
a)
bl
Soc
(
x
-
C)
15
>
-
E
¥
8
V8
-
3×-12=4%7--4
'
(
3
OCT 8
a) TF
b)
>
8) Ix -121--0
2C Oct
3
x
,
ex
-
f
.
=
2
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