Lab 21 – IONIC REACTIONS(I will accept this by Monday... the review)! 1) FOR EACH REACTION THAT HAD A VISABLE RESULT:

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Lab 21 – IONIC REACTIONS(I will accept this by Monday after
the review)!
1) FOR EACH REACTION THAT HAD A VISABLE RESULT:
A. WRITE THE FORMULAS OF THE REACTANTS.
B. PREDICT THE PRODUCTS WITH CORRECT
FORMULAS.
C. CLASSIFY THE REACTANTS AND REACTIONS.
a) Classify reactants using the acid and base tables (K,L).
Salts have a metal and non metal (or non-metal
polyatomic ion).
b) Use this PowerPoint to get formulas.
c) Do NOT write an intro or discussion.
d) Write each reaction you saw.
e) Predict solubility using table F.(PowerPoint 267)
LAB 21 – TYPES OF REACTIONS,IONIC REACTIONS AND
SOLUBILITY
DIRECTIONS: THIS LAB IS DUE ON FRIDAY JUNE 15 (BY E
MAIL AS A WORD ATTACH), OR AT WEEKEND REVIEW ON
THE 16 OR 17, IF YOU ATTEND MONDAYS LAB REVIEW AT
1:00, THE LAB IS DUE ON REGENTS DAY.
PROCEDURE: FORMULA OF A SALT (CRISS-CROSS).
1)
2)
3)
4)
LOOK UP EACH WORD ON TABLS “S” FOR ELEMENTS AND TABLE “E” FOR
POLYATOMIC IONS. YOU MAY HAVE TO USE BOTH IF YOU DO NOT RECOGNISE THE
SUBSTANCE.
PUT POLYATOMIC IONS IN PARENTHESIS, GET THE CHARGE FROM TABLE “E”.
GET THE CHARGE OF ELEMENTS FROM THE REDOX RULES OR GROUP IT IS IN.
USE THE CRISS –CROSS METHOD TO GET SUBSCRIPTS.
Table “E”
Ca2+
3
( PO4)32
Ca3(PO4)2
USE
ABSOLUTE
VALUE
WRITING THE DISSOCIATION OF A SALT
Ca3( PO4) 2
NEUTRAL,
NO CHARGE
WRITTEN
0
=
2(3-)
1)WRITE THE FORMULA.
2)USING TABLE “E” AND “
WRITE THE PRODUCT
POLYATOMIC ION AS AN
ION.
3) USE THE REDOX RULES
TO GET THE CHARGE OF
THE = ION (MOSTLY A A
METAL)
+ (X) ; X=2+
32+
(
)
Ca3 PO4 2 2 ( PO4) + 3 Ca
Ca IS IN GROUP TWO,
ANOTHER WAY TO
GET THE CHARGE OF
2+
WRITING THE DISSOCIATION OF A SALT
Ca (NO3)2
NEUTRAL,
NO CHARGE
WRITTEN
0
=
2(1-)
1)WRITE THE FORMULA.
2)USING TABLE “E” AND “
WRITE THE PRODUCT
POLYATOMIC ION AS AN
ION.
3) USE THE REDOX RULES
TO GET THE CHARGE OF
THE = ION (MOSTLY A A
METAL)
+ (X) ; X=2
1(
)
Cu NO3 2 2 ( NO3) +
2+
Cu
Cu HAS MULTIPLE
STATES SO YOU HAVE
TO SOLVE IT THIS
WAY
TYPES OF REACTIONS:
1) SYNTESIS: A + B  C ; A PRODUCT LARGER THAN EITHER
REACTANT IS PRODUCED, 2 OR MORE REACTANTS AND ONE
PRODUCT.
A. N2 + 3H2  3 NH3 (ELEMENTAL FORMATION REACTION(SYSNTESIS TYPE)
B. 2 CO + O2  2 CO2
2) DECOMPOSITION (CHEMICAL, NOT NUCLEAR) C  A + B ONE
REACTANT AND TWO OR MORE PRODUCTS.
A. 2 NaHCO3  Na2CO3 + CO2(g) + H2O
3) NEUTRALIZATION: ACID + BASE  SALT + WATER,
A. HCl + NaOH  NaCl + H2O
B. H3PO4 + KOH  K3PO4 + 3 H2O
4) DOUBLE REPLACEMENT (DISPLACEMENT); MUST HAVE A
PRECIPITATION AB + CD  AD + CB.
A. Pb(NO3)2 + K2CrO4  PbCrO4 + 2 KNO3
5) SINGLE REPLACMENT ( DISPLACEMENT); A TYPE OF REDOX.
A. Fe + Cu(NO3)2  Fe (NO3)2 + Cu
0
oxidation
2+
2+
0
reduction
TYPES OF REACTIONS:
6) COMBUSTION; A HYDROCARBON REACTANT REACTS WITH O2
RELEASING ENERGY.
A. C8H18 + 25 O2  16CO2 + 18 H2O
7) OXIDATION: A SUBSTANCE REACTS WITH OXYGEN.
A. 4Al + 3 O2  2 Al2O3
LOOK AT POWER-POINT 281 – TABLE I, THIS IS IMP.
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