Monohybrid and Dihybrid Honors Biology-Ms. Kim What is a genotype? • • • • A. Brown Hair B. Freckles C.Tt D. All of the above Homozygous Dominant • • • • A. aa B. Aa C. AA D. Blue Eyes If I crossed a 2 True Breeding Plants with different traits, their offspring would be… • • • • A. All Heterozygous B. Hybrids C. AA, Aa, aa D. Both A and B What is a carrier? • The heterozygous genotype that does not express the phenotype when disorders are caused by recessive alleles What is the probability that 2 carriers for Cystic Fibrosis will have a child with Cystic Fibrosis/ A. B. C. D. 100% 75% 50% 25% What is Probability? –The chance that a specific event will occur • Probability = number of ways a specific event can occur number of total possible outcomes How is Probability used in Genetics? • Used to explain the chance of an offspring inheriting a specific trait • Each box represents ¼ or 25 % What is a Punnett Square? • Way to predict ALL possible outcomes of a cross How do you read a Punnett square? • Axes represent possible gametes from each parent • Boxes represent possible genotypes for offspring Genetics Vocab (pt 2) • Monohybrid cross cross where parents differ in only one trait (Rr x rr) • Dihybrid cross cross where parents differ in two traits (RrHh x rrHH) • Punnett square – a diagram that shows the gene combinations that might result from a genetic cross of two parents 11 Monohybrid Cross • a cross between 2 individuals that looks at 1 trait – Ex: Just looking at the possibility of getting freckles Dihybrid Cross • a cross between 2 individuals that looks at the possibilities of inheriting 2 DIFFERENT traits at one time – Ex: looking at the possibility of getting freckles AND dimples in the SAME offspring Monohybrid Punnett Square Mom’s genotype (Hh) x Dad’s genotype (hh) Tall Short Mom’s allele #1 Dad’s Allele #1 h Dad’s Allele #2 h Mom’s allele #2 H h Hh hh Hh hh Genotype Outcome (Ratio) vs. Phenotype Outcome (Ratio) • Genotype Possibilities = the GENOTYPE probabilities (expected results) of offspring »Ex: 50% Hh and 50% hh (0:2:2) • Phenotype Possibilities= the PHENOTYPE probabilities (expected results) of offspring »Ex: 50% Tall 50% Short (2:2) Genetics Vocab (pt 3) • Dominant – allele that appears more frequently. It masks the recessive. – Represented by a capitol letter (R=red) • Recessive – allele that appears less frequently (b/c it is repressed when paired with a dominant allele) – Represented by a lower case letter (r=white) • Genotype – a description of the genetic make-up of an individual (TT, Rr) • Phenotype – a description of what an individual LOOKS like (tall, red) 15 Genetics Vocab (pt 4) • Homozygous – two identical alleles for a trait – AA – HOMOZYGOUS dominant – aa – homozygous recessive • Heterozygous – two different alleles for a trait – Aa – HETEROZYGOUS one of each allele 16 Solving Punnett Squares H Biology 17 Punnett squares Step 1 STEP 1 Define the alleles If a homozygous round pea plant is crossed with a heterozygous round pea plant, what will their offspring look like? R = round r = wrinkled Why are we using the same letter? Why not use “R” for round and “W” for wrinkled? 18 Step 2 • Define the parents If a homozygous round pea plant is crossed with a heterozygous round pea plant, what will their offspring look like? RR x Rr 19 Step 3 Draw the Punnett square R R R r 20 Step 4 Cross the parents to find the probability of offspring 1. Bring the top letter down and the side letter over… R RR R RR R r Rr Rr 21 Step 5 Find the genotype and phenotype of the offspring R R R RR RR r Rr Rr Genotype: genetic make-up (letters) Phenotype: physical characteristics 22 Finished Product Key: R=round r=wrinkled R R r RR Rr R RR Rr Genotype: genetic make-up (letters) 2 RR: 2Rr 50% RR 50% Rr Phenotype: physical characteristics 4 (round): 0 (wrinkled) 100% Round 23 Practice #2 • In pea plants, round seeds are dominant over wrinkled. A plant that is homozygous dominant for round seeds is crossed with a heterozygous plant. Key: R = round r = wrinkled Cross: RR x Rr Genotype: Phenotype: Example: Heterozygous x Heterozygous Do the following cross: Mom’s genotype (Hh) x Dad’s genotype (Hh) Tall Tall Draw a Punnett Square and determine the offspring’s genotype and phenotype. Give the probabilities and ratios for each Example: Heterozygous x Heterozygous Mom’s genotype (Hh) x Dad’s genotype (Hh) Tall Tall H h H HH Hh h Hh hh Genotype ratio = 25% HH, 50% Hh, 25% hh (1:2:1) Phenotype ratio = 75% Tall, 25% short (3:1) Working Backwards…The Testcross • Allows us to determine the genotype of an organism with the dominant phenotype, but unknown genotype – Genotype is not obvious…could be HH or Hh • Cross an individual with the dominant phenotype with individual that is recessive for the same trait • Conduct a test cross, where the unknown dominant individual is crossed with the known recessive . • H _ ?_ x hh Test Cross Mom’s genotype (H?) x Dad’s genotype (hh) Tall Short H ? h Hh ?h h Hh ?h If all the offspring are ALWAYS tall…Mom has to be HH If some offspring are short…Mom has to be Hh DIHYBRID CROSSES: Assuming genes follow Mendelian Genetics (complete dominance) Dihybrid Crosses • crosses involving crossing 2 DIFFERENT traits at one time – Example: Mate 2 parents and look at the probability of seeing 2 traits, such as: • eye color AND hair color • freckles AND dimples How do You Do Dihybrid Crosses? • Setting up a complex Punnett Square OR • 2 separate monohybrid • 1 square for EACH trait • use PROBABILITY RULES and MULTIPLY What is a dihybrid cross? • Cross that shows inheritance of two different traits – For example: homozygous round & yellow crossed with a homozygous wrinkled & green seed – RRYY x rryy Setting up a Dihybrid • #1- read the problem & list all 4 alleles – For example: R=round, r=wrinkled, Y=yellow, y=green • #2 – Create the parental genotypes (4 letters each) – Example: RRYY (Round, yellow) x rryy (wrinkled, green) • #3 – Using the “foil” method, determine the sets of gametes (up to 4 possibilities) – Example: 1. RRYY 2. RrYy RY RY, Ry, rY, ry 34 Setting up a Dihybrid • #4 – Fill in the tops and sides of punnett square with gamete combinations RY – Example: Ry rY ry RY 1. RRYY 2. RrYy RY RY, Ry, rY, ry • #5 - Genotype and Phenotype as usual RY RY RRYY Ry RRYy rY ry ry RrYY RrYy 35 Dihybrid Final Product • R=round, r=wrinkled, Y=yellow, y=green RY RY • • • • RRYY = RRYy = RrYY = RrYy = RRYY Ry RRYy rY RrYY ry RrYy Round and Yellow Round and Yellow Round and Yellow Round and Yellow • So…we can say that all of our offspring (100%) will be round and yellow! 36 Dihybrid Example Problem #1 • Round is dominant over wrinkled • Yellow is dominant over green • Two pea plants produce offspring. One is round and heterozygous for yellow seed color. The other is wrinkled and heterozygous for yellow seed color. STEP 1: • Parental genotypes = RRYy x rrYy Possible gametes RY, Ry rY, ry 37 Dihybrid Example Problem #1 STEP 2: • Set up the dihybrid cross using the gametes from before… RY rY ry RrYY RrYy Ry RrYy Rryy 38 Dihybrid Example Problem #1 STEP 3: Determine the genotype and phenotype! RY rY RY RrYY ry RrYy Genotype: Ry Ry RrYy Rryy Phenotype: 1 RrYY: 2 RrYy : 1 Rryy 3 Round, yellow 1 Round, green 39 Dihybrid Example Problem #2 • Black fur is dominant to white fur • Long hair is dominant to short hair • Two guinea pigs mate. The dad is homozygous for black fur and long hair. The mom is also homozygous, but for white fur and short hair. – 1) Determine the dominant & recessive traits – 2) Determine the possible gametes of each parent – 3) What is the only gamete possibility for their offspring? 40 Dihybrid Example Problem #2 1) Key: Black fur is dominant (B) to white fur (b) Long hair is dominant (L) to short hair (l) Two guinea pigs mate. The dad is homozygous for black fur and long hair. The mom is also homozygous, but for white fur and short hair. 2) 3) Determine the possible gametes of each Dad ALL BL Mom ALL bl What is the only gamete possibility for their offspring? GENOTYPE: 100% BbLl PHENOTYPE: Black, long-haired 41 Ggbb x ggBb FOIL (FIRST, OUTER, INNER, LAST) Ggbb X ggBb G= Grey hair g = white hair B = Black eyes b = red eyes Ggbb x ggBb Gb gb gB GgBb ggBb gb Ggbb ggbb Ggbb x ggBb Gb gb Gb gb gB 1/16 GgBb 1/16 ggBb 1/16 GgBb 1/16 ggBb gb 1/16 Ggbb 1/16 ggbb 1/16 Ggbb 1/16 ggbb gB 1/16 GgBb 1/16 ggBb 1/16 GgBb 1/16 ggBb 1/16 Ggbb 1/16 ggbb 1/16 Ggbb 1/16 ggbb gb GGbb x ggBb GENOTYPE POSSIBILITIES: GgBb = 4/16 or ¼ = 25% Ggbb= 4/16 or ¼ = 25% ggBb= 4/16 or ¼ = 25% ggbb= 4/16 or ¼ = 25% Genotypic ratio: 1 GgBb : 1 Ggbb : ggBb : 1 ggbb PHENOTYPE POSSIBILITES: Grey Hair Black Eyes: 25% Grey Hair Red Eyes: 25% White Hair Black Eyes: 25% White Hair Red Eyes: 25% Phenotypic ratio: 1: 1: 1: 1 Practice • In pea plants, yellow seeds are dominant to green seeds in peas. Round seeds are dominant over wrinkled. Cross two plants that are heterozygous for both traits. – Write the genotypes for the parents. – Then use “FOIL” to determine your possible allele combinations from each parent – Then set up Punnett Square and fill in the boxes – Then figure out the genotypic and phenotypic ratios YyRr x YyRr YR Yr yR yr YR 1/16 YYRR 1/16 YYRr 1/16 YyRR 1/16 YyRr Yr 1/16 YYRr 1/16 YYrr 1/16 YyRr 1/16 Yyrr yR 1/16 YyRR 1/16 YyRr 1/16 yyRR 1/16 yyRr yr 1/16 YyRr 1/16 Yyrr 1/16 yyRr 1/16 yyrr YyRr x YyRr YR Yr yR yr YR 1/16 YYRR 1/16 YYRr 1/16 YyRR 1/16 YyRr Yr 1/16 YYRr 1/16 YYrr 1/16 YyRr 1/16 Yyrr yR 1/16 YyRR 1/16 YyRr 1/16 yyRR 1/16 yyRr yr 1/16 YyRr 1/16 Yyrr 1/16 yyRr 1/16 yyrr YyRr x YrRr GENOTYPE POSSIBILITIES: YyRr = 4/16 or 1/4 = 25% YYRr=2/16 or 1/8 =12.5% YyRR=2/16 or 1/8 =12.5% Yyrr=2/16 or 1/8 =12.5% yyRr=2/16 or 1/8 =12.5% YYrr= 1/16 = 6.25% YYRR= 1/16 = 6.25% yyRR=1/16 = 6.25% yyrr =1/16 = 6.25% PHENOTYPE POSSIBILITES: 9 yellow, round 3 yellow, wrinkled 3 green, round 1 green, wrinled Would you like to know a few SHORT CUTS? Short Cuts for MONOHYBRID CROSSES • Every parent “donates” only 1 allele to each offspring – Law of Segregation • When crossing 2 heterozygous individuals in complete dominance, you will ALWAYS get – 1:2:1 GENOTYPE ratio • 1 homozygous dominant: 2 heterozygous: 1 recessive – 3:1 PHENOTYPE ratio • 3 dominant phenotype: 1 recessive Short Cuts for DIHYBRID CROSSES • When crossing 2 heterozygous individuals in complete dominance, you will ALWAYS get – 9:3:3:1 PHENOTYPE ratio • • • • 9 dominant, dominant phenotype 3 dominant, recessive phenotype 3 recessive, dominant phenotype 1 recessive, recessive phenotype NOTE: The genotypes have to be ALL heterozygous •Ex: HhFf x HhFf Now…Let’s do Multicharter Problems • What is the probability of producing an offspring with the genotype AaBBCcDDeeFf in a cross between 2 parents with the following genotypes? – AABbCcDDeeFf X – AaBbCcDdeeFf • ½ x ¼ x ½ x ½ x 4/4 x ½ • = 4/256 = 1/64 or 1.5% chance Practice 1) In humans, curly hair is dominant over straight hair. A woman heterozygous for hair curl marries a man with straight hair and they have four children. a) Show the parental cross and the possible gametes produced. b) Use a Punnett square to find the possible genotypes for the F1 generation. c) What are the phenotypic and genotypic ratios of the F1? d) What is the probability that the first child will have curly hair? What is the probability that the third child will have curly hair? Practice 2) The ability to taste the drug phenyl-thio carbamide (P.T.C.) is due to a dominant gene. A non-taster man marries a taster woman whose father was a non-taster. a) What will be the expected genotypes of their four children? b) What would be the expected phenotypes for ten children? c) What is the probability that their first child has the heterozygous genotype? d) Give the phenotypic and genotypic ratios of the possible offspring produced More Practice? • The dark wizard, Lord Voldemort, is able to speak parseltongue (pp), which is a recessive trait. Not only can he speak parseltongue, he can also do dark magic (dd). Him and his followers, the Death Eaters, spend a lot of time together practicing dark magic. Over the years, Voldemort and Bellatrix Lestrange fell in love. In order to continue their dream of taking over the wizarding world, they decided to have children. Bellatrix, who can do dark magic, cannot speak parseltongue. However, they only want children if they can speak pareseltongue as well. – What is Voldemort’s genotype? – What does Bellatrix’s genotype have to be in order to have a child who can do black magic and speak parseltongue? – Create a dihybrid cross using Bellatrix’s genotype of part B, include genotypic and phenotypic ratios. – What is the percent chance that they have a child who can speak parseltongue and do black magic? Practice • Determine the results of a cross between two dolphins. Female is heterozygous dominant for skin color and has a short tail land the male is heterozygous for both traits. Grey skin (G) is dominant to white skin (g) and long tails (T) are dominant over short tails (t). List all phenotype ratios and % for the F1 generation. Practice In humans, right-handedness (R) is dominant to lefthandedness and hitchhiker thumb (H) is dominant to straight thumb. Chuck is homozygous right-handed and has a hitchkiker’s thumb. His father has a straight thumb. Emily is left-handed and can’t bend her thumb back. – What are the phenotype possibilities if Chuck and Emily have children? – What is the probability that their baby’s genotype will be like: • Chuck? • Emily?