Calculations involving moles, masses, and volumes of both reactants and products in a chemical equation. The balanced chemical equation indicates the MOLE RATIOS of the reactants and products Example: 2 CuO 1 O2 2 Cu + Coefficents indicate the number of moles. (in blue) i.e. 2 mol Cu : 1 mol O2 : 2 mol CuO How many moles of copper (II) oxide can be produced from 0.50 moles of oxygen gas? ? Mol CuO = 0.50 mol O2 x 2 mol CuO = 1.0 mol CuO 1 mol O2 How many moles of copper would be required to produce 2.10x10-2 moles of copper (II) oxide? ? Mol Cu = 2.10x10-2 mol CuO x 2 mol Cu 2 mol CuO = 2.1x10-2 mol CuO A. Mole to Mole Calculations Example: 3 H2(g) + N2(g) 2 NH3(g) How many moles of NH3 are formed when 6.5 mol N2 are reacted with a large excess of H? ? Mol NH3 = 6.5 mol N2 x 2 mol NH3 1 mol N2 = 13 mol NH3 Note: The proportions from the balanced equation are NOT for masses Reaction Calculations Worksheet. In-class Assignment. P.154 #1-6. Homework. 2 AgNO3(aq) + Cu(s) Cu(NO3)2(aq) + 2 Ag(s) How many moles of AgNO3 would be required to produce 3.2x10-2 mol of Cu(NO3)2? 3.2x10-2 mol Cu(NO3)2 x 2 mol AgNO3 = 6.4x10-2 mol AgNO3 1 mol Cu(NO3)2 What mass of AgNO3 would be required to produce 0.020 mol of Cu(NO3)2? 1) Determine the moles of AgNO3 required. 0.020 mol Cu(NO3)2 x 2 mol AgNO3 1 mol Cu(NO3)2 = 0.040 mol AgNO3 2) Convert moles of AgNO3 to mass. 0.040 mol AgNO3 x 169.9 g 1 mol = 6.8g AgNO3 Or you can put both steps together. 0.020 mol Cu(NO3)2 x 2 mol AgNO3 x 169.9 g 1 mol Cu(NO3)2 1 mol = 6.8g AgNO3 If we need to produce 5.0g of silver, what mass of copper would be needed? mass Ag mol Ag Use molar mass of Ag 5.0g Ag mol Ag 107.9g Ag mol Cu Use balanced equation 1 mol Cu 2 mol Ag 63.5g Cu mol Cu mass Cu Use molar mass of Cu = 1.5g Cu Classwork: – Chem 11 Worksheet Homework: – Read Lab 6B – There will be a Pre-lab Quiz