Sample calculations for molar volume of H2 lab
Reaction:
Mg + 2HCl  H2 + MgCl2
Theoretical Yield of H2
Sample length of Mg = 4.5 cm (use your length)
Grams of Mg = 4.5 cm x 0.04g/1 cm = 0.18 g
Moles of Mg = 0.18 x 1 mol/24.30 g = 0.0074 mol
Since molar ratio of Mg to H2 is a 1:1 they are equivalent
Moles of H2 = 0.0074 mol
Liters of H2 = 0.0074 mol x 22.4 L/ 1 mol = 0.166 L or 166 ml
Experimental yield
This is the amount of milliliters you actually got in the lab
% yield = experimental / theoretical X 100