ECE369A: Fundamentals of Computer Architecture ECE 369A MWF 10:00 AM - 10:50 AM in CHVZ 405 Instructor Teaching Assistant Name: Ali Akoglu Nirmal Kumbhare Office: ECE 356-B ECE232 Phone: (520) 626-5149 Email: akoglu@ece.arizona.edu nirmalk@email.arizona.edu Office Mondays 1:00-2:00PM, Hours: Fridays 2:00-4:00pm or by appointment TBD ECE369 1 General Policies, Tips • • • • • • • D. A. Patterson and J.L. Hennessy, Computer Organization and Design: The Hardware/Software Interface, Fifth Edition, Morgan Kaufmann Publishers. Prerequisite: ECE274 & Programming in C & Programming in Veriolg/VHDL Course involves class (3 credits) and laboratory (1 credit) activities. Class activities will involve 3 to 4 assignments, quizzes, reading assignments, 5 examinations, and a semester long project. Laboratory activities will accompany the topics covered in the lectures with hands on programming based assignments. A coordinated sequence of lab assignments will help students design, program, debug, and evaluate specific components of a datapath using the Xilinx ISE and a FPGA board. Laboratory activities (programming and debugging) and assignments (15) will help students build the foundation for the semester long datapath-design based project. Final project will require students implement a synthesizable datapath based on a given instruction set architecture and evaluate its performance on a specific FPGA platform. ECE369 2 General Policies, Tips • NO LATE ASSIGNMENTS • Make-ups may be arranged prior to the scheduled activity. • Inquiries about graded material => within 3 days of receiving a grade. • You are encouraged to discuss the assignment specifications with your instructor, your teaching assistant, and your fellow students. However, anything you submit for grading must be unique and should NOT be a duplicate of another source. • Read before the class • Participate and ask questions • Manage your time • Start working on assignments early ECE369 3 Grading Distribution of Components Component Percentage Class Participation 10 Laboratory 10 Exam-I 8 Exam-II 10 Exam-III 10 Exam-IV 12 Exam-V 15 Project 25 Grades Scale Percentage Grade 90-100% A 80-89% B 70-79% C 60-69% D Below 60% E Class Participation: Piazza participation (3%), Quizzes (7%) (in-class) ECE369 4 Labs and Project • Laboratory: – Labs1-17: 2000pts • Project – Labs18-28: 2500pts – Competition: !!!! ECE369 5 Announcements • ECE232 LAB (Starts Aug 31) – TA • Assignments & Project – Pairs only !!! – Who is my partner? (Aug 31) • Lecture notes on the web – http://ece.arizona.edu/~ece369/ ECE369 6 Objective • Understand “how computer works” • Appreciate the design tradeoffs ECE369 7 Chapter 1 ECE369 8 Introduction • This course is all about how computers work • But what do we mean by a computer? – Different types: desktop, servers, embedded devices – Different uses: automobiles, graphics, finance, genomics… – Different manufacturers: Intel, Apple, IBM, Microsoft, Sun… – Different underlying technologies and different costs! ECE369 9 First Microprocessor Intel 4004, 1971 • 4-bit accumulator architecture • 8mm pMOS • 2,300 transistors • 3 x 4 mm2 • 750kHz clock • 8-16 cycles/inst. ECE369 10 Hardware • Team from IBM building PC prototypes in 1979 • Motorola 68000 chosen initially, but 68000 was late • 8088 is 8-bit bus version of 8086 => allows cheaper system • Estimated sales of 250,000 • 100,000,000s sold [ Personal Computing Ad, 11/81] ECE369 11 11 DYSEAC, first mobile computer! • Carried in two tractor trailers, 12 tons + 8 tons • Built for US Army Signal Corps ECE369 12 End of Uniprocessors Intel cancelled high performance uniprocessor, joined IBM and Sun for multiple processors ECE369 13 Processor Technology Trends • Shrinking of transistor sizes: 250nm (1997) 130nm (2002) 65nm (2007) 32nm (2010) 28nm(2011, AMD GPU, Xilinx FPGA) 22nm(2011, Intel Ivy Bridge, die shrink of the Sandy Bridge architecture) 14nm (2014, Intel Core M, Core I7) • Transistor density increases by 35% per year and die size increases by 10-20% per year… more cores! ECE369 14 Power Consumption Trends • Dyn power a activity x capacitance x voltage2 x frequency • Capacitance per transistor and voltage are decreasing, but number of transistors is increasing at a faster rate; hence clock frequency must be kept steady • Leakage power is also rising • Power consumption is already between 100-150W in high-performance processors today 3.3GHz Intel core i7: 130 watts ECE369 15 Recent Microprocessor Trends Transistors: 1.43x / year Cores: 1.2 - 1.4x Performance: 1.15x Frequency: 1.05x Power: 1.04x 2004 2010 Source: Micron University Symp. ECE369 16 What you will learn • How programs are translated into the machine language – And how the hardware executes them • Hardware and Software Interface • Both Hardware and Software affect performance: – Algorithm determines number of source-level statements – Language/Compiler/Architecture determine machine instructions – Processor/Memory determine how fast instructions are executed • What is parallel processing ECE369 17 Below Your Program • • Application software – Written in high-level language System software – Compiler: translates HLL code to machine code – Operating System: service code • Handling input/output • Managing memory and storage • Scheduling tasks & sharing resources • Hardware – Processor, memory, I/O controllers ECE369 18 Inside the Processor (CPU) • • • Datapath: performs operations on data Control: sequences datapath, memory, ... Cache memory – Small fast SRAM memory for immediate access to data ECE369 19 Abstraction • Delving into the depths reveals more information • An abstraction omits unneeded detail, helps us cope with complexity ECE369 20 Instruction Set Architecture • A very important abstraction – interface between hardware and low-level software – standardizes instructions, machine language bit patterns, etc. – advantage: different implementations of the same architecture – disadvantage: sometimes prevents using new innovations • Modern instruction set architectures: – IA-32, PowerPC, MIPS, SPARC, ARM, and others ECE369 21 Sneak Peak (Lecture 18) ECE369 22 Performance • • • • Measure, Report, and Summarize Make intelligent choices See through the marketing hype Key to understanding underlying organizational motivation Why is some hardware better than others for different programs? What factors of system performance are hardware related? (e.g., Do we need a new machine, or a new operating system?) How does the machine's instruction set affect performance? ECE369 23 Defining Performance • Which airplane has the best performance? Boeing 777 Boeing 777 Boeing 747 Boeing 747 BAC/Sud Concorde BAC/Sud Concorde Douglas DC-8-50 Douglas DC8-50 0 100 200 300 400 0 500 Boeing 777 Boeing 777 Boeing 747 Boeing 747 BAC/Sud Concorde BAC/Sud Concorde Douglas DC-8-50 Douglas DC8-50 500 1000 4000 6000 8000 10000 Cruising Range (miles) Passenger Capacity 0 2000 0 1500 Cruising Speed (mph) 100000 200000 300000 400000 Passengers x mph ECE369 24 Computer Performance: TIME, TIME, TIME • Response Time (latency) — How long does it take for my job to run? — How long does it take to execute a job? — How long must I wait for the database query? • Throughput — How many jobs can the machine run at once? — What is the average execution rate? — How much work is getting done? • If we upgrade a machine with a new processor what do we increase? • If we add a new machine to the lab what do we increase? ECE369 25 Execution Time • • • Elapsed Time – counts everything (disk and memory accesses, I/O , etc.) – a useful number, but often not good for comparison purposes CPU time – doesn't count I/O or time spent running other programs – can be broken up into system time, and user time Our focus: user CPU time – time spent executing the lines of code that are "in" our program ECE369 26 Book's Definition of Performance • For some program running on machine X, PerformanceX = 1 / Execution timeX • "X is n times faster than Y" PerformanceX / PerformanceY = n • Problem: – machine A runs a program in 20 seconds – machine B runs the same program in 25 seconds ECE369 27 Clock Cycles • Instead of reporting execution time in seconds, we often use cycles seconds cycles seconds program program cycle Clock period Clock (cycles) Data transfer and computation Update state • clock rate (frequency) = cycles per second (1 Hz. = 1 cycle/sec) ECE369 28 How to Improve Performance seconds cycles seconds program program cycle So, to improve performance (everything else being equal) you can either (increase or decrease?) ________ the # of required cycles for a program, or ________ the clock cycle time or, said another way, ________ the clock rate. ECE369 29 How many cycles are required for a program? ... 6th 5th 4th 3rd instruction 2nd instruction Could assume that number of cycles equals number of instructions 1st instruction • time This assumption is incorrect, different instructions take different amounts of time on different machines. Why? hint: remember that these are machine instructions, not lines of C code ECE369 30 Different numbers of cycles for different instructions time • Multiplication takes more time than addition • Floating point operations take longer than integer ones • Accessing memory takes more time than accessing registers • Important point: changing the cycle time often changes the number of cycles required for various instructions (more later) ECE369 31 Example • Our favorite program runs in 10 seconds on computer A, which has a 4 GHz. clock. We are trying to help a computer designer build a new machine B, that will run this program in 6 seconds. The designer can use new (or perhaps more expensive) technology to substantially increase the clock rate, but has informed us that this increase will affect the rest of the CPU design, causing machine B to require 1.2 times as many clock cycles as machine A for the same program. What clock rate should we tell the designer to target?" • Don't Panic, can easily work this out from basic principles ECE369 32 Example • Our favorite program runs in 10 seconds on computer A, which has a 4 GHz. clock. We are trying to help a computer designer build a new machine B, that will run this program in 6 seconds. The designer can use new (or perhaps more expensive) technology to substantially increase the clock rate, but has informed us that this increase will affect the rest of the CPU design, causing machine B to require 1.2 times as many clock cycles as machine A for the same program. What clock rate should we tell the designer to target?" seconds cycles seconds program program cycle ECE369 33 Now we understand cycles • A given program will require – some number of instructions (machine instructions) – some number of cycles – some number of seconds • We have a vocabulary that relates these quantities: – cycle time (seconds per cycle) – clock rate (cycles per second) – CPI (cycles per instruction) a floating point intensive application might have a higher CPI – MIPS (millions of instructions per second) this would be higher for a program using simple instructions ECE369 34 Back to the Same Formula, CPI (Cycles/Instruction) seconds cycles seconds program program cycle ECE369 35 CPI Example • Suppose we have two implementations of the same instruction set architecture (ISA). seconds cycles seconds program program cycle For some program, Machine A has a clock cycle time of 250 ps and a CPI of 2.0 Machine B has a clock cycle time of 500 ps and a CPI of 1.2 What machine is faster for this program, and by how much? ECE369 36 Let’s Complicate Things A Little bit… A compiler designer is trying to decide between two code sequences for a particular machine. Based on the hardware implementation, there are three different classes of instructions: Class A, Class B, and Class C, and they require one, two, and three cycles (respectively). Which sequence will be faster? How much? seconds cycles seconds program program cycle What is the CPI for each sequence? The first code sequence has 5 instructions: 2 of A, 1 of B, and 2 of C The second sequence has 6 instructions: 4 of A, 1 of B, and 1 of C. ECE369 37 Component Analysis ECE369 38 What is MIPS? • • Instruction execution rate => higher is better Issues: – Can not compare processors with different instruction sets – Varies between programs on the same processor – Can vary inversely with the performance… ? ECE369 39 MIPS Example ECE369 40 Amdahl's Law • The performance enhancement of an improvement is limited by how much the improved feature is used. In other words: Don’t expect an enhancement proportional to how much you enhanced something. • Example: "Suppose a program runs in 100 seconds on a machine, with multiply operations responsible for 80 seconds of this time. How much do we have to improve the speed of multiplication if we want the program to run 4 times faster?" How about making it 5 times faster? ECE369 41 Amdahl’s Law 1. Speed up = 4 2. Old execution time = 100 3. New execution time = 100/4 = 25 4. If 80 seconds is used by the affected part => 5. Unaffected part = 100-80 = 20 sec 6. Execution time new = Execution time unaffected + Execution time affected / Improvement 7. 25= 20 + 80/Improvement 8. Improvement = 16 ECE369 42 Example: Speed up using parallel processors Suppose an application is “almost all” parallel: 90%. What is the speedup using 10, 100, and 1000 processors? new time = old time * 10% + ( old time * 90% ) / 10 Speed up (P=10) = old time / new time Speedup (P=10) = 5.3 Speedup (P = 100 ) = 9.1 Speedup ( P = 1000 ) = 9.9 ECE369 43 Amdahl’s Law Overview ECE369 44 Example • Suppose we are considering an enhancement that runs 10times faster than the original machine but is only usable 40% of the time. What is the overall speedup gained by incorporating the enhancement? Speedup 1 0.4 0.6 10 ECE369 1.56 45 Example • Implementations of floating point square root vary significantly in performance. Suppose FP square root (FPSQR) is responsible for 20% of the execution time of a critical benchmark on am machine, One proposal is to add FPSQR hardware that will speed up this operation by a factor of 10. The other alternative is just to try to make all FP instructions run faster; FP instructions are responsible for a total of 50% of the execution time. The design team believes that they can make all FP instructions run two times faster with the same effort as required for the fast square root. Compare those two design alternatives. Speedup FPSQR SpeedupFP 1 0.2 (1 0.2) 10 1 0.5 (1 0.5) 2 ECE369 1.22 1.33 46 Benchmarks • • • Performance best determined by running a real application – Use programs typical of expected workload – Or, typical of expected class of applications e.g., compilers/editors, scientific applications, graphics, etc. Small benchmarks – nice for architects and designers – easy to standardize – can be abused SPEC (System Performance Evaluation Cooperative) – companies have agreed on a set of real program and inputs – valuable indicator of performance (and compiler technology) – can still be abused ECE369 47 Benchmark Games • An embarrassed Intel Corp. acknowledged Friday that a bug in a software program known as a compiler had led the company to overstate the speed of its microprocessor chips on an industry benchmark by 10 percent. However, industry analysts said the coding error…was a sad commentary on a common industry practice of “cheating” on standardized performance tests…The error was pointed out to Intel two days ago by a competitor, Motorola …came in a test known as SPECint92…Intel acknowledged that it had “optimized” its compiler to improve its test scores. The company had also said that it did not like the practice but felt to compelled to make the optimizations because its competitors were doing the same thing…At the heart of Intel’s problem is the practice of “tuning” compiler programs to recognize certain computing problems in the test and then substituting special handwritten pieces of code… Saturday, January 6, 1996 New York Times ECE369 48 SPEC CPU2000 ECE369 49 Problems with Benchmarking • Hard to evaluate real benchmarks: – Machine not built yet, simulators too slow – Benchmarks not ported – Compilers not ready Benchmark performance is composition of hardware and software (program, input, compiler, OS) performance, which must all be specified ECE369 50 IR optimization example C source code compile unoptimized IR ECE369 51 Constant folding cfold ECE369 52 Constant propagation constprop ECE369 53 Dead code elimination dce ECE369 54 ECE369 Xe on 3G Hz 5 12 K B( o ) d) pt im iz e B( -x W -O 3xW xB (-O 0) -O 3- B 12 K 3G Hz 5 MB , .6G Hz /1 MB , 12 K 3G Hz 5 .6G Hz /1 Xe on B1 B1 Xe on Compiler and Performance Application Set 500 450 400 350 300 250 200 150 100 50 0 55 Scary Stuff Op ALU Load Store Branch Frequency 43% 21% 12% 24% Cycle Count 1 1 2 2 Let’s say we were able to reduce the cycle count for “Store” operations to 1 with a cost of slowing our clock by15%. Is this new design feasible? n CPI i IC i n IC i i 1 CPI original CPI i Instruction _ Count i 1 Instruction _ Count ECE369 56 Example(Contd.) Old CPI = 0.43 + 0.21 + 0.12x2 + 0.24x2 = 1.38 New CPI = 0.43 + 0.21 + 0.12 + 0.24x2 = 1.24 Speed up = old time/new time = (ICx oldCPI x T)/(IC x newCPI x 1.15T) =0.97 so, don't make this change. ECE369 57 Performance Measurement Overview CPUtime CPUclock _ cycles _ for _ the _ pogram Clock _ Cycle _ Time CPUtime CPI CPUclock _ cycles _ for _ the _ pogram Clock _ Rate CPUclock _ cycles _ for _ the _ pogram IC CPUtime IC CPI Clock _ Cycle _ Time CPUtime CPUtime IC CPI Clock _ Rate Seconds Instructions ClcokCycles Seconds Pr ogram Pr ogram Instruction ClockCycle ECE369 58 Performance Measurement Overview n CPU clock _ cycles _ for _ the _ program CPIi ICi i 1 n CPUtime CPI i IC i Clock _ Cycle _ Time i 1 n CPI i IC i n IC i i 1 overall _ CPI CPI i Instruction _ Count i 1 Instruction _ Count ECE369 59 Exercise Suppose we have made the following measurements: • Frequency of FP operations = 25% • Average CPI of FP operations = 4.0 • Average CPI of other instructions = 1.33 • Frequency of FPSQR = 2% • CPI of FPSQR = 20 Assume that the two design alternatives are: a) to reduce the CPI of FPSQR to 2 or b) to reduce the average CPI of all FP operations to 2. Compare these alternatives. ECE369 60 Solution n CPI i IC i n IC i i 1 CPI original CPI i Instruction _ Count i 1 Instruction _ Count 4 25% 1.33 75% 2.0 CPI Saved _ on _ FPSQR 2% (CPI oldFPSQR CPI newFPSQR ) 2% (20 2) 0.36 CPI overall _ for _ new _ FPSQR CPI original CPI Saved _ on _ FPSQR 2 0.36 1.64 CPI overall _ for _ new _ FP 75% 1.33 25% 2.0 1.5 SpeedupFP CPUTimeoriginal CPUTimenew IC ClockCycle CPI original IC ClockCycle CPI new ECE369 CPI original CPI new 2.00 1.33 1.5 61 Multiprocessors • • Multicore microprocessors – More than one processor per chip Requires explicitly parallel programming – Compare with instruction level parallelism • Hardware executes multiple instructions at once • Hidden from the programmer – Hard to do • Programming for performance • Load balancing • Optimizing communication and synchronization ECE369 62 Hardware/Software Tradeoffs • Which operations are directly supported in “hardware” and which are synthesized in software? • How much hardware should you employ to speed up certain functions? Advantages Disadvantages Hardware Speed, Consistency Cost No flexibility Software Flexibility, easier/faster design lower cost of errors Slowness ECE369 63 Remember • Performance is specific to a particular program – Total execution time is a consistent summary of performance • For a given architecture performance increases come from: – – – – • increases in clock rate (without adverse CPI affects) improvements in processor organization that lower CPI compiler enhancements that lower CPI and/or instruction count Algorithm/Language choices that affect instruction count Pitfall: expecting improvement in one aspect of a machine’s performance to affect the total performance ECE369 64