Lesson 6-7 Pages 298-302
Using Percent
Equations
Lesson Check 6-6
What you will learn!
1. How to solve percent
problems using percent
equations.
2. How to solve real-life
problems involving discount
and interest.
Percent equation
Discount
Simple interest
What you really need to know!
In a percent equation,
the percent is written
as a decimal.
What you really need to know!
% of BASE = PART
The word “ of ”
means multiply!
What you really need to know!
The number after the
word “of” is the base!
The number near the
word “is” is the part!
Example 1:
Find 38% of 22.
% x BASE = PART
38% x 22 = PART
0.38 x 22 = PART
8.36 = PART
Example 2:
19 is what percent of 25?
% x BASE = PART
% x 25 = 19
% = 19 ÷ 25
% = 0.76
76%
Example 3:
84 is 16% of what number?
% x BASE = PART
16% x BASE = 84
0.16 x BASE = 84
BASE = 525
84 ÷ 0.16
Example 4:
The regular price of a ring is
$495. It is on sale at a 20%
discount. What is the sale
price of the ring?
20% x $495 = $99
$495 - $99 = $396
Example 5:
Suppose you invest $2,000 at
an annual interest rate of
4.5%. How long will it take
to earn $495?
I = prt
I = prt
I is interest
p is principal
r is annual interest rate
t is time in years
Example 5:
Suppose you invest $2,000 at
an annual interest rate of
4.5%. How long will it take
to earn $495?
495 = 2,000 • 0.045 • t
5.5 years = t
Page 300
Guided Practice
#’s 4-11
Read:
Pages 298-300 with
someone at home and
study examples!
Homework: Pages 301-302
#’s 12-40 even
#’s 44-61
Lesson Check 6-7
Page
738
Lesson 6-7
Lesson Check 6-7