Chemical Nomenclature Chapter 7 Basic Chemistry Daub and Seese

Naming Binary

Compounds

Containing a Metal and a Nonmetal

Pisgah High School

M. Jones

The Stock System

Named for Alfred Stock, a

German chemist and teacher who published the system in 1919.

Add a Roman numeral after the name of the metal to indicate the oxidation number.

Using the Stock System:

1. Write the name of the metal

2. Add a Roman numeral corresponding to the oxidation number of the metal (if necessary)

3. Write the name of the negative element, modified to end in ide

When is the Roman Numeral

Necessary?

When the metal has more than one oxidation number.

Metals in groups IA, IIA, and III B do not need Roman numerals.

In addition, omit the Roman numeral for Al, Ga, In, Zn, Cd and Ag.

What is an oxidation number?

The oxidation number is a number that tells us how an element combines with other elements.

For ions, the oxidation number is the ionic charge.

What does the Roman Numeral do?

The Roman numeral indicates the oxidation number on a single metal atom, and differentiates between several possible compounds.

Consider: FeO and Fe

2

O

3

Both contain iron and oxygen

But, both cannot be iron oxide

What does the Roman Numeral do?

Therefore…

FeO is called iron(II) oxide and

Fe

2

O

3 is called iron(III) oxide.

Consider: FeO and Fe

2

O

3

Both contain iron and oxygen

But, both cannot be iron oxide

First, determine the oxidation number of iron in FeO …

… by starting with the negative element, find the oxidation number of the positive element.

Since iron has an oxidation number of +2, FeO is named iron(II) oxide.

Then for Fe

2

O

3

First, determine the oxidation number of iron in Fe

2

O

3

… by starting with the negative element, find the oxidation number of the positive element.

Since iron’s oxidation number is +3,

Fe

2

O

3 is named iron(III) oxide.

Remember …

The Roman numeral indicates the oxidation number of the metal.

You need not use a Roman numeral for metals in groups

IA, IIA and IIIA, or for Al, Ga, In, Zn, Cd or Ag

Name these compounds:

SrO

CrCl

3

ZnS

Srontium oxide

Chromium(III) chloride

Zinc sulfide

Mn

2

O

3

SnF

4

TiS

2

Manganese(III) oxide

Sin(IV) fluoride

Titanium(IV) sulfide

Writing formulas for binary compounds of a metal and a nonmetal

The sum of the oxidation numbers on all the atoms in a compound must equal zero.

+2 –2 = 0

FeO

Consider iron(II) oxide.

Oxygen is –2 and iron is +2.

The sum is 0.

Now consider iron(III) oxide

+3 -2

Fe

2

O

3

In iron(III) oxide, the iron is +3 and the oxygen is –2.

These don’t add up to zero.

Now consider iron(III) oxide

+6 -6 = 0

+3 -2

Fe

2

O

3

But, since there are two Fe atoms and three O atoms, we can multiply to

2 x 3 = 6 get the totals.

3 x –2 = -6 Now the sum is zero.

Look at it another way:

+6

–6

= 0

+6 -6

+3 +3 -2 -2 -2

Fe

2

O

3

=

Fe Fe

O O O

Now you are ready to write formulas

The Crisscross Method

Simple but effective…

…most of the time.

Be aware of the potential problems with this method.

Suppose you are writing the formula for copper(II) chloride

First, write down the symbols

:

Cu Cl

Then write the oxidation numbers in copper(II) chloride

The oxidation number of copper comes from the

+2 name.

-1

Cu Cl

Get the oxidation number of chlorine from the periodic table.

Crisscross the numbers for the formula of copper(II) chloride

When you crisscross, ignore the signs.

+2 -1

Cu Cl

1 2

Clean up the subscripts in the formula of copper(II) chloride

Subscripts of 1 are invisible.

(don’t even put the 1)

+2 -1

Cu Cl

1 2

Clean up the subscripts in the formula of copper(II) chloride

Subscripts of 1 are invisible.

(don’t even put the 1)

+2 -1

Cu Cl

2

Now you have the formula of copper(II) chloride

Cu Cl

2

When is the “crisscross method” a problem?

When all the subscripts are divisible by a number other than 1.

Look at chromium(VI) oxide

The oxidation number of Cr is

+6

+6 -2

Cr O

Oxygen is always -2

Look at chromium(VI) oxide

Now, crisscross the oxidation numbers.

+6 -2

Cr O

2 6

When you crisscross, both subscripts are divisible by 2.

Look at chromium(VI) oxide

Divide each subscript by 2.

+6 -2

Cr O

2 2

Look at chromium(VI) oxide

This is the correct formula

Cr O

3

Remember, 1’s are invisible.

Remember: reduce the subscripts to their smallest whole-number values.

Unless there’s a really good reason not to.

N

2

Some Exceptions:

O

4

C

2

H

6

P

4

O

10

C

6

H

6

Hg

2

Cl

2

H

2

O

2

The “ic/ous” System

The “ic/ous” method …

… is an archaic method, but still in use today by the chemical industry

… uses the –ic or – ous suffixes on the name of the metal.

… may use the Latin name

… uses prefixes like hypo& per-

Higher oxidation number

Use “ic” for the higher oxidation number, like ferric.

IC

OUS

Use “ous” for the lower oxidation number, like ferrous.

Lower oxidation number

Name and

Latin Root iron

Lower Ox.

Number ferrum copper ferrous

Fe 2+ cuprous cuprum Cu + mercury mercurous

Hg

2

2+

Higher Ox.

Number ferric

Fe 3+ cupric

Cu 2+ mercuric

Hg 2+

Examples

FeCl

2

CuO

FeN

Cu

3

P

HgS

Hg

2

Cl

2

Ferrous chloride

Cupric oxide

Ferric nitride

Cuprous phosphide

Mercuric sulfide

Mercurous chloride

Write the formula …

Ferric bromide

Cupric nitride

Ferrous chloride

Mercuric oxide

Mercurous iodide

Stannous fluoride

FeBr

3

Cu

3

N

2

FeCl

2

HgO

Hg

2

I

2

SnF

2

Mike Jones

Pisgah High School

Canton NC mjones@haywood.k12.nc.us

Copyright 2012

All rights reserved.