Atomic Structure II

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Atomic Structure II

Electron Configurations

Barbara A. Gage PGCC CHM 1010

Atomic Orbitals

• Each electron is assigned to:

Primary energy level (shell), n

Orbital type in the shell (s,p,d,f)

Specific orbital of the type

Because of repulsion considerations only 2 electrons can occupy any orbital

(spinning in opposite directions)

Barbara A. Gage PGCC CHM 1010

Atomic Shells and Orbitals

Shell

(n)

# s orbitals

# p orbitals

# d orbitals

# f orbitals

Total e -

1

2

3

4

5

1

1

1

1

1

3

3

3

3

5

5

5

7

7

2

8

18

32

50

Barbara A. Gage PGCC CHM 1010

Barbara A. Gage PGCC CHM 1010

This diagram shows the energy levels of the atomic orbitals.

Electrons fill orbitals from bottom to top of the diagram.

A vertical orbital diagram for the Li ground state.

no color-empty light - half-filled

The electron configuration is written as:

1s 2 2s 1 # electrons in orbital dark - filled, spin-paired shell orbital

Barbara A. Gage PGCC CHM 1010

Barbara A. Gage PGCC CHM 1010

Barbara A. Gage PGCC CHM 1010

You can use a chart like this to determine the electron configuration.

(But there is an easier way.)

Barbara A. Gage PGCC CHM 1010

A periodic table of partial ground-state electron configurations.

Barbara A. Gage PGCC CHM 1010

Determining Electron Configuration

PROBLEM: Using the periodic table on the inside cover of the text (not

Figure 8.12 or Table 8.4), give the full and condensed electrons configurations, partial orbital diagrams showing valence electrons, and number of inner electrons for the following elements:

(a) potassium (K: Z = 19) (b) molybdenum (Mo: Z = 42) (c) lead (Pb: Z = 82)

SOLUTION:

Use the atomic number for the number of electrons and the periodic table for the order of filling for electron orbitals.

Condensed configurations consist of the preceding noble gas and outer electrons.

(a) for K (Z = 19) full configuration partial orbital diagram

1s 2 2s 2 2p 6 3s 2 3p 6 4s 1 condensed configuration [Ar] 4s 1

There are 18 inner electrons.

4s 1 3d

Barbara A. Gage PGCC CHM 1010

4p

(b) for Mo (Z = 42) full configuration 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 1 4d 5 condensed configuration partial orbital diagram

[Kr] 5s 1 4d 5

There are 36 inner electrons and 6 valence electrons.

5s 1 4d 5 5p

(c) for Pb (Z = 82) full configuration 1s

2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 2 4d 10 5p 6 6s 2 4f 14 5d 10 6p 2 condensed configuration partial orbital diagram

[Xe] 6s 2 4f 14 5d 10 6p 2

There are 78 inner electrons and 4 valence electrons.

6s 2 6p 2

Barbara A. Gage PGCC CHM 1010

Configuration for Ions

• What is the electron configuration for

Na + ?

Na = 1s 2 2s 2 2p 6 3s 1

Na + = 1s 2 2s 2 2p 6 3s 1

• What is the electron configuration for

Se 2?

Se = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 4

Se 2= 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6

Barbara A. Gage PGCC CHM 1010

Configuration for Ions

• Transitions metals have a twist…

Fe = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 6

Fe 2+ = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 6

Fe 3+ = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 5

Barbara A. Gage PGCC CHM 1010

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