Changing the pH of salt solutions by an electric current Juernene Tholel & Patrick Hack Cygnus Gymnasium, Amsterdam, The Netherlands Received June 2011 ------------------------------------------------------------------------------------------------------------------------------ Summary pH is a measure of the acidity or basicity of an aqueous solution. A solution with a pH lower than 7 is acidic and a solution with a pH greater than 7 is basic. The question answered in this article is how the pH of two the same salt solutions, connected by a salt bridge, change as a current is passed through them. Two solutions of magnesium sulfate-7H2O in water showed that when a power supply supplied 9 volt to the circuit redox reactions took place. These redox reactions ensured that the pH of both solutions changed. The solution on the anode side of the circuit became acidic and the solution at the cathode side became basic. Introduction The presence of hydrogen ions(H+) and hydroxide ions(OH-) in solutions determine if a solution is acidic or basic. Acids have a higher concentration of hydrogen ions than hydroxide ions(pH below 7). Bases have a higher concentration of hydroxide ions than hydrogen ions(pH higher than 7). The pH in solutions can change because of redox reactions (reduction and oxidation reactions). Redox reactions are processes where electrons move from one molecule to another. Water can be electrolyzed by passing an electric current through it in an electrochemical cell. Electrons from the power supply are added to the water molecules at the negative electrode. A question relevant to this is: How does the pH of two the same salt solutions, connected by a salt bridge, change as a current is passed through them? The electrode connected to the negative terminal of the power supply is called the cathode. Adding electrons results in the following reduction reaction: 2H2O + 2 e- → H2 (gas) + 2OHThe water will react with electrodes supplied by the negative terminal of the power supply. Forming hydrogen gas and 2 hydroxide ions. The other electrode is attached to the other, positive, terminal of the power supply. At this electrode, the anode, electrons are removed from the solution by the electrode. So at the cathode electrons are added and at the anode they are removed. Because of this the circuit is completed and the current can flow. At the anode the water is oxidized by the following reaction: : H2O → 1/2 O2 (gas) + 2H+ + 2eSo at the anode the water will react and form oxygen gas, hydrogen ions, and electrons. The oxidation reaction and the reduction reaction can’t happen if one of both doesn’t happen. So both reactions always happen at the same time. It is essential that a current can flow from the anode to the cathode, because else the electrolysis isn’t possible. Because of this dissolving magnesium sulfate in purified water is a smart choice. Purified water itself is a poor conductor, but because the dissolved magnesium sulfate become positive magnesium ions(Mg 2+) and negative sulfate ions(SO42-, which allow the current to from the anode to the cathode. Magnesium sulfate-7H2O is a good choice for this experiment because it doesn’t react with the carbon electrodes, so only water will react. Essential is that the solutions stay separated, but the current must be able to pass. For this the a salt bridge is needed. Our hypothesis is that there will be a difference in pH at the end of the two solutions because of the electrolysis of water that will take place. The pH of the solution on the cathode side will get higher and the pH of the solution on the anode side lower, because on the anode side the oxidation of water will take place and on the cathode side the reduction of water. So in the solution on the anode side hydrogen ions will be formed and solution on the cathode side hydroxide ions will be formed. ----------------------------------------------------------------------------------------------------- Experimental procedure Two cleaned measuring cups were filled with 75mL of purified water. 20 grams of magnesium sulfate-7 H2O were put into one of the filled measuring cups and another 20 grams into the other measuring cup. After both mixtures had been stirred, the magnesium sulfate-7H2O dissolved in the water and it became a colorless solution. Six drops of bromothymol blue were added to both solutions. This gave the solutions a green/blue color. Bromothymol blue gives colorless solutions a blue color when the pH of the solution is higher than 7.6 and a yellow color when the solution has a pH lower than 6.0. Because both solutions were neutral(pH = 7.0) the bromothymol blue gave the solutions a green/blue color. A power supply was connected to two carbon electrodes with insulated wires and an alligator clip. One carbon electrode was connected to the supply’s positive side, so this electrode became the anode. The other carbon electrode was connected to the supply’s negative terminal, making it the cathode. At last a salt bridge connected the solutions of magnesium sulfate-7H2O. A pH-meter was used to measure the pH of both solutions every five minutes for a total time of 35 minutes. To make sure that the solutions didn’t mix while changing the pH meter from one solution to the other. The pH meter had been cleaned in purified water every time it would be switched. Figure 1: Schematic draw of the experimental setup. Both solutions in the picture consist of: Mg2+(aq) ions, SO42-(aq) ions, the bromothymol blue drops, which made the solutions turn blue/green and of course H2O. Results The results obtained are shown in the table and figures below: Table 1: the change in pH of both magnesium sulfate-7 H2O solutions at the anode and cathode side of the circuit. Time (minutes) pH pH Anode + Cathode- 0 7.21 7.21 5 6.66 7.60 10 6.21 8 15 5.81 8.61 20 5.63 9.41 25 5.40 9.73 30 5.22 10.01 35 4.86 10.52 Figure 2: Graph of the change of pH of the magnesium sulfate-7 H2O solutions at the cathode and anode side of the circuit. Figure 3: Picture showing the change in color of both magnesiumsulfate-7H2O solutions Another thing that became visible was that bubbles got produced at the electrodes. At the cathode side H2(gas) got produced(as seen in the equations in the introduction). And at the Anode side the oxidation of water took place so O2(gas) got produced. Discussion and Conclusion It became visible and was measured that the pH got lower at the anode side and pH rose at the cathode side. This became visible, because of the change of color of the solutions. First both solutions were green/blue but at the end the anode side had a yellow color. The cathode side got a blue color. The anode side turned acidic and the cathode side basic. So our hypothesis on the inquiry question has been proved to be correct. The pH did change on both sides. The anode side has become acidic and the cathode side basic because of the forming of hydroxide ions and hydrogen ions. At the cathode the reduction of water took place: 2H2O + 2 e- → H2 (gas) + 2OHBecause of the hydroxide ions(OH-) that got produced at the cathode side the solution became basic, so the pH rose. At the same time bubbles became visible, because of the H2(gas) that got produced. At the anode side the oxidation of water took place producing hydrogen ions(H+): H2O → 1/2 O2 (gas) + 2H+ + 2eBecause of the Hydrogen ions that got produced the pH lowered, so the solution became acidic. At the same time also on this side bubbles became visible because of the O2(gas) that got produced. Evaluation We believe, when evaluating our experiment, that our results are valid. The measuring cups we used were cleaned thoroughly before we used it, making sure that there weren’t any other substances still in the cups. Also while measuring we had to switch from one solution to the other, because we only had one pH-meter. Because we didn’t want the solutions to mix we cleaned the pH-meter every time in purified water when we switched the pHmeter from one solution to the other. By this we made sure the solutions didn’t mix. Something that could have been improved was the duration of the experiment. We did not have any time left at the time we did the experiment and we had to stop after 35 minutes. It would have been interesting to see if something different would have happened after a longer time. Our school didn’t have a lot of magnesium sulfate-7H2O and therefore we weren’t able to repeat the experiment, which would ensure even more that our results were valid. Repeating the experiment is something that we actually should have done, although we couldn’t. -------------------------------------------------------------------------------------------------Bibliography: 1. http://www.chemistryrules.me.uk /tandp/optiontransitionelements.htm 2.http://en.wikipedia.org/wiki/Magnesium _sulfate 3. http://en.wikipedia.org/wiki/PH 4. “BINAS”, NVON fifth edition, 2004, Wolters-Noordhoff bv Groningen, The Netherlands 5. Icy – road salt, January 2011, Vrije Universiteit Amsterdam, The Netherlands 6. http://en.wikipedia.org/wiki/Electrolysis _of_water