Business Mathematics and Statistics A general set (population) – objects or phenomenon whose attributes are interested in totality. Target - a representative chosen by the General set (population) proportion. Mathematical statistics - that presents the science of data analysis techniques that assist the available data to assess the different part of all relevant population (general population) characteristics. AVM 2 Feature The population and sample unifying characteristic phenomenon or event can take on different meanings. Variable • Size, measured on the character and changing along with the sample members. • Quantitative: discrete (revenue expenditure), continuous (temperature, height). • Qualitative:-rank (busy place, condition assessments) nominal (sex, place of residence). AVM 3 Population Size N Average m Target Data n n x = 1 ∑ xi n i =1 x gr = Quantitative Dispersion σ2 s2 = 1 k ∑x * i ⋅ fi Quantitative Qualitative n i=1 Qualitative 1 n (x − x )2 ∑ i n −1 i=1 Quantitative Qualitative 2 * 1 k h 2 s = f i (xi − x gr ) − n −1 ∑ 12 i=1 2 gr Standard deviation Probability/compar ative rate Correliation rate σ p (tikimybė) ρ s = s2 Comparative rate υ= f n r (formulas will be provided later) AVM Qualitative Quantitative, nominal 4 Numerical characteristics calculation with MS Excel program AVM 5 Histogram Quantifying the distribution of attribute values describe the population density function, which graphically depicts the density function graph. Quantitative variable graphically depict the distribution of the sample histogram. AVM 6 Histogram AVM 7 Y "J· ®Eel . ; Home lnsert Bookl . Microsoft beei Page Layout Q} JWConnectrons !:J' Propertres External Data ... 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Solver f[JSubtotal Outline Data Tools Sort & Filter Connections Chart Data ( , Clear A Sort r 1 Chcrt Tools s Įt !$A$1:$A$20I 345 Bin 614 3 4 5 6 7 8 9 10 11 946 1596 209 423 250 1002 1611 539 1627 12 13 14 15 16 17 18 100 387.1 674.2 961.3 1248.4 1535.5 1822.6 Frequency 387.1 8 674.2 961.3 5 3 1 1248.4 1535.5 1822.6 9 Histogram o 3 • Freque11cy H1stogram Input Įnput Range: ii OK .El! 387.1 t:Įelp ==.;;-r iJ 674.2 961.3 1248.4 1535.5 1822.6 Bin 19 20 21 22 23 8 Normal (Gauss) distribution One of the ways to "roughly" to check whether the quantitative attribute values distributed according to population normal (Gauss) distribution is the asymmetry coefficient g1 and g2 divide the excesses of the following mean square error. g1 6 n ≤ z 1 + P ir 2 g2 24 n ≤ z 1+ P 2 z (1 + P) / 2 - a normal distribution (1 + P) / 2 rows quintile, which is taken from the 1st quintile table, P-probability (confidence level), the basis of which conclusions are drawn about the population characteristics. So, if P = 0.95, a = 1.96 z0.975. AVM 9 p Zp 0,50 0,51 o -) , _ 0,53 0,5-1 0,55 0,56 o-7 , . 0,58 0,59 0,60 0,6 1 0,62 0,63 0,6-1 0,65 0,66 0,67 0,68 0,69 0,70 0,71 0,72 0,73 0,7-1 0,0000 0,02 51 0,0502 0,0753 0,100-1 0,1257 0,1510 O,176-1 0,2019 o1 1r) O, _ ) j -1 0,2793 0,3055 0,3319 0,3585 0,3853 0,-1125 0,-1399 0,-1677 0,4959 0,52-1-1 0,553-1 0,5828 0,6128 0,6-13-1 ·-- p Zp 0,75 0,76 0,77 0,78 0,79 0,80 0,81 0,82 0,83 0,8-1 0,85 0,86 0,87 0,88 0,89 0,900 0,905 0,910 0,915 0,920 o' 9_1 0,930 0,935 0,9-10 0,9-15 0,67-15 0,7063 0,7389 0,7721 0,806-1 0,8-116 0,8779 0,915-1 0,95-12 0,99-15 1,036-1 1,0803 1,126-1 1,1750 1 116-) 1,2816 1,3106 1,3-108 1, .Jn . -1 l,.Į051 1,-1395 1,-1758 1,51-11 1,55-18 1,5982 ·-- AVM p 0,950 0,955 0,960 0,965 0,970 0.975 0,980 0,985 0,990 0,991 0,992 0,993 0,99-1 0,995 0,996 0,997 0,998 0,999 Zp 1"6-1-19 1"695-1 1"7507 1"8119 1"SSOS 1 .9600 ' o- s - :; _l 2"170 1 2,,326-1 ) 6 -6 _ ";t -:o 2"-1089 ) -1--, J 2"5121 _' " --I -8 2"6521 2"7.Ji S 2"8782 3"0902 10 Quintile zp finding in MS Excel For example: quintile row, when P=0,95: p=(1+P)/2=(1+0,95)/2=0,975 Write quintile row AVM 11 Checking Excel program, or a quantitative attribute values d istributed according to Gauss's law AVM 12 General population characteristics Evaluation of characteristics of the sample Attribute values of the numerical characteristics of the sample based on variable values, measured in two main ways: • Written in numeric attribute values ccharacteristics confidence intervals; • Examinated hypothesis. AVM 13 Confidence intervals Quantitative trait values o f average population of confidence range s x− t 1+ P 2 n s < m < x + t 1+ P n 2 x - variable values mean, standard deviation, s, t-Student distribution is with n-1 degrees of freedom (1 + P) / 2 successive quintile Interest characteristic values o f the likelihood confidence interval for the population ν − z 1+P 2 ν (1 − ν ) n < p < ν + z 1+P 2 ν (1 − ν ) n z – a normal distribution N (0,1) (1 + P) / 2 successive quintile, P-confidence level; - are interested in the relative values of the variable target rate AVM 14 The size of the sample When you are interested in a quantitative character values m ean: z2 s2 n= (1+ P ) / 2 ∆2 z - a normal distribution N (0,1) (1 + P) / 2 successive quintile, P-confidence level; s - a quantitative variable standard deviation ∆- the desired accuracy assessment When we are interested in the qualitative character of the distribution of values: z (1+ P) / 2 ν ⋅ (1 − ν ) n= 2 ∆2 ν– interested in the relative values of a qualitative variable frequency ∆ -the desired accuracy assessment AVM 15 Testing hypotheses • Any assumption about the observed random variable or several sizes refer to the statistical distribution hypothesis. • The main hypothesis of the observed law of distribution and its parameters are called main hypothesis H0. The opposite argument is called by Alternative hypothesis H1. • The rule, according to which hypothesis is examined rejected (accepted), called the criterion. • Criteria for the award is based on the idea of low expectations the principle is very little chance that the main hypothesis is false. AVM 16 Testing hypotheses • Usually, the hypothesis tested in accordance with 0.95 probability, the probability of failure 0.05. This possibility is also called the significance level and bears. • The most basic hypothesis states that there is no difference between the groups compared parameters. • If the alternative hypothesis states that there is a difference (eg. H1 m1 m2) means the criteria that we use to check the hypothesis is two-sided. • If the alternative claim that a population parameter is greater than or less than the other population parameter (eg H1 m1> m2), then the criteria - one-sided. AVM 17 Type I and type II errors of testing hypothesis • Hypotheses are tested based on a random sample of the data, thus making it possible mistakes or rejection. We are accepting Is for real H0 H1 H0 + β H1 α + -the first type of error. These are likely to reject the hypothesis correct. -the second type of error. This is likely to P H0 H1 = β accept a false hypothesis. P{H1 H0}= α { } AVM 18 General hypothesis testing scheme. 1. Formulated the main and alternative hypotheses (H0 and H1). 2. According to the chosen criterion is calculated from the sample data random - the criterion of statistical significance of T. 3. According to the chosen level of confidence and sample degrees of freedom the critical value tables, which are formed on each of the criteria selected by the criterion of critical importance. 4. Compare the obtained with t-test statistics with a critical criterion value. Generally, if the test statistics module is less or equal to the critical value, then accept H0. If test statistics module is greater than the critical value reject H0 and H1 take (the only difference hypothesis H0 2 = C, H1 C check) 5. We conclude based on the received hypothesis testing results. AVM 19 Criterion critical value-a test of the statistical distribution row quintile, quintile of the distribution is found in the table or MS Excel program. If the hypothesis (i.e. H0 m = m0) used to check the one-sided criteria (eg. H1 m> m0), then turn tailed and a confidence level of P (Fig. b); If the hypothesis (i.e. H0 m = m0) used to check the two-sided test (ie. H0 m m0), then tailed a number calculated: (1 + P) / 2 (sometimes tailed series) (Fig. a). necessary and (1-P) / 2 AVM 20 Testing hypothesis: H0 m = m0 Let P = 0.95, n = 26 one-sided test H1 m> m0: The column P row n-1 The column is 0.95, and line 25, then the quintile tp = 1.7081 (blue) Two-sided test of H0 m0 Column (1 + P) / 2 row n-1 So column 0.975, line 25, then the quintile t (1 + P) / 2 = 2.0595 (red) AVM 21 Tailed Student's distribution with MS Excel 1. Click fx and find TINV: Assume P = 0.95, n = 26 Duplex criteria: The Probability write 1-P to write Deg_freedom n-1 Kvantilio t eikšmė Assume P = 0.95, n = 26 one-sided criteria: The Probability write 2 * (1-P) the Deg_freedom write n-1 Quantile ratio AVM 22 The first and second kind of error, if verified hypothesis H0 m = 10, m = m0 H1> 10 tP tP – Student distribution P = P consecutive quintile, P-confidence level. tP - found in the second quintile table or MS Excel program. AVM 23 p-meaning The probability that the criterion of statistical significance (when H0 is true) will be not less than the observed realization (counted) is called p-value: • p-value = P (t ≥ t), where H0 is correct. • p-value - observed significance level. If p< α, tai H0 rejected; If p≥ α, tai H0 accepted. AVM 24 Literature • V. Čekanavičius, G. Murauskas. Statistics and its aapplications: Part I. Vilnius 2000; • G. Kasnauskienė. Statistics on business decisions. Vilnius 2010. AVM 25