1/30/2013
Mole Map
Mass Mountain
Stoichiometry
Liter Lake
Mole Island
Particle
Peninsula
Using the Mole Map with
Chemical Equations
• We can convert between Moles, Liters,
Particles and Grams, but…
• This only gives us information about one
substance!
• How do we determine how much reactants
to use in a chemical reaction? Or how
much product we will create?
STOICHIOMETRY
Mole Ratio
• A conversion factor that converts moles of
one compound in a balanced chemical
equation into moles of another compound.
2 H2 + 1 O2  2 H2O
• Coefficients tell how many particles (or
MOLES of particles) of each chemical is
needed in the reaction.
• Remember, if there is no coefficient, it
means “1”.
Stoichiometry Sea
Mole Ratios
How many moles of water will be formed if I
react 14.0 moles of oxygen with excess H2?
2 H2 + O2  2 H2O
2 moles H2O
14.0 moles O2 x ___________=
28.0 moles H2O
Known
Unknown
Substance A
Substance B
Mass Mountain
Mass Mountain
Liter Lake
1 mole O2
MOLE RATIO
From the balanced equation.
Coefficients tell moles of each substance.
Mole Island
Particle Peninsula
Mole Ratio Mole Island
Raft
Liter Lake
Particle Peninsula
1
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1/30/2013
Stoichiometry
2 TiO2 + 4 Cl2 + 3 C
Mass
Known
Unknown
Substance A
Substance B
115
x gg
x mol
CO2 + 2 CO + 2 TiCl4
4.55 mol
x molecules
How many moles of chlorine will react with 4.55 moles of carbon?
Mass
4.55 mol C
C
Volume
1 mole = 22.4 L @ STP
= 6.07 mol Cl2
How many grams of titanium (IV) oxide will react with 4.55 moles of carbon?
Use coefficients
from balanced
chemical equation
Mole
4 mol Cl2
3 mol C
Cl2
Mole
1 mole = 22.4 L @ STP
Volume
(gases)
4.55 mol C
(gases)
C
2 mol TiO2
3 mol C
79.9 g TiO2
= 242 g TiO2
1 mol TiO2
TiO2
How many molecules of TiCl4 will react with 115 g TiO2?
115 g TiO2
Particles
1 mol TiO2 2 mol TiCl4 6.02x1023 molecules TiCl4
79.9 g TiO2 2 mol TiO2
1 mol TiCl4
Particles
= 8.66x1023 molecules TiCl4
TiO2
Your Turn
• How many grams of H2O will be created
when 9.16 grams of H2 is reacted
according to the equation:
2 H2 + O2  2 H2O
1 mole H 2   2 moles H 2 O   18.0 g H 2O 
9.16 g H 2 


 = 82.4 g H 2O
 2.0 g H 2   2 moles H 2  1 mole H 2 O 
TiCl4
Your Turn
4 NH3 + 3 O2  2 N2 + 6 H2O. If you need
to create 35.6 grams of H2O, how many
moles of NH3 will you need to react?
1 mole H 2 O   4 moles NH3 
35.6 g H 2 O 

 = 1.32 moles NH 3
 18.0 g H 2O   6 moles H 2 O 
2
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