제3장: 결정질 고체의 구조 ISSUES TO ADDRESS... • How do atoms assemble into solid structures? • How does the density of a material depend on its structure? • When do material properties vary with the sample (i.e., part) orientation? Chapter 3 - 1 학습목표... • 원자/분자 구조에서 결정질과 비결정질 재료의 차이점 분석 • 면심입방격자, 체심입방격자, 육방조밀격자의 제도 • 면심입방격자와 체심입방격자 구조에서 단위정 모서리 길이와 원자 반지름 사이의 관계식 유도 • 주어진 단위정 차원에서 면심입방격자와 체심입방격자 구조를 갖는 금속의 밀도 계산 • 세 방향 지수가 주어질 때, 단위정 내에 이 지수와 일치하는 방향 제도 • 단위정 내에 그려진 면의 Miller 지수 표기 • 원자의 조밀 충진면으 적층에 의해 면심입방격자와 육방조밀격자가 생기는 과정을 설명 • 단결정과 다결정 재료의 구분 • 재료 성질에서 등방성과 이방성의 차이 Chapter 3 - 2 Energy and Packing • 치밀않음, 불규칙배열(random packing) Energy typical neighbor bond length typical neighbor bond energy • 치밀, 규칙배열(ordered packing) r Energy typical neighbor bond length typical neighbor bond energy r 치밀하고 규칙적인 배열의 구조는 낮은 에너지상태를 갖는 경향이 있다. Chapter 3 - 3 Materials and Packing 결정질 재료(Crystalline materials...) • 장범위 규칙적 원자배열, 3차원적 패턴 • 예: -모든 금속 -대부분의 세라믹 -일부의 폴리머 crystalline SiO2 Adapted from Fig. 3.23(a), Callister & Rethwisch 8e. Si 비결정질 재료(Noncrystalline materials...) • 장범위 원자의 규칙성 없음 • 예: -복잡한 구조 -급냉(rapid cooling) “Amorphous" = Noncrystalline Oxygen noncrystalline SiO2 Adapted from Fig. 3.23(b), Callister & Rethwisch 8e. Chapter 3 - 4 금속의 결정 구조 • How can we stack metal atoms to minimize empty space? 2-dimensions vs. Now stack these 2-D layers to make 3-D structures Chapter 3 - 5 금속의 결정 구조 • 조밀한 원자 충진 • 이유: - 일반적으로 오직 한 성분만이 존재, 같은 크기의 원자 - 금속결합: 방향성 무 - 작은 최인접 원자간 거리: 낮은 결합에너지 - 개개의 전자 구름은 중심부를 보호하고 있음(Electron cloud shields cores from each other) • 가장 간단한 결정구조 We will examine three such structures... Chapter 3 - 6 단순입방정(Simple Cubic Structure (SC)) • 낮은 충진밀도: 흔하지 않음 (only Polonium(Po) has this structure) • 입방정의 모서리: 조밀방향 (Close-packed directions) • 배위수(Coordination #) = 6 [최인접원자수(# nearest neighbors)] (Courtesy P.M. Anderson) http://bcs.wiley.com/hebcs/Books?action=mininav&bcsId=5242&itemId=0470419970&assetId=19905 3&resourceId=19134 Chapter 3 - 7 원자충진율(Atomic Packing Factor (APF)) APF = Volume of atoms in unit cell* Volume of unit cell *assume hard spheres • 단순입방정의 APF = 0.52 atoms unit cell a R=0.5a APF = volume atom 4 p (0.5a) 3 1 3 a3 close-packed directions contains 8 x 1/8 = 1 atom/unit cell Adapted from Fig. 3.24, Callister & Rethwisch 8e. volume unit cell Chapter 3 - 8 체심입방정[Body Centered Cubic Structure (BCC)] • 체심과 모서리 원자는 입방의 대각선상에 서로 접촉 --Note: 모든 원자는 동일; 중심부의 다른 색깔의 원자는 쉽게 구별하기 위함 ex: Cr, W, Fe (), Tantalum, Molybdenum • 배위수(Coordination #) = 8 Adapted from Fig. 3.2, Callister & Rethwisch 8e. (Courtesy P.M. Anderson) 2 atoms/unit cell: 1 center + 8 corners x 1/8 Chapter 3 - 9 원자충진율(Atomic Packing Factor: BCC) • APF for a body-centered cubic structure = 0.68 3a a 2a Adapted from Fig. 3.2(a), Callister & Rethwisch 8e. R a Close-packed directions: length = 4R = 3 a atoms volume 4 p ( 3a/4 ) 3 2 unit cell atom 3 APF = volume 3 a unit cell Chapter 3 - 10 면심입방정[Face Centered Cubic Structure (FCC)] • 원자는 입방의 모서리와 면의 중심에 위치 --Note: All atoms are identical; the face-centered atoms are shaded differently only for ease of viewing. ex: Al, Cu, Au, Pb, Ni, Pt, Ag • Coordination # = 12 Adapted from Fig. 3.1, Callister & Rethwisch 8e. (Courtesy P.M. Anderson) 4 atoms/unit cell: 6 face x 1/2 + 8 corners x 1/8 Chapter 3 - 11 원자충진율(Atomic Packing Factor: FCC) • APF for a face-centered cubic structure = 0.74 최대의 APF Close-packed directions: length = 4R = 2 a 2a a Adapted from Fig. 3.1(a), Callister & Rethwisch 8e. Unit cell contains: 6 x 1/2 + 8 x 1/8 = 4 atoms/unit cell atoms volume 4 3 p ( 2a/4 ) 4 unit cell atom 3 APF = volume 3 a unit cell Chapter 3 - 12 FCC 적층 배열 • ABCABC... Stacking Sequence • 2D Projection B B C A B B B A sites C C B sites B B C sites • FCC Unit Cell A B C Chapter 3 - 13 조밀육방정[Hexagonal Close-Packed Structure (HCP)] • ABAB... Stacking Sequence • 3D Projection c a • 2D Projection A sites Top layer B sites Middle layer A sites Bottom layer Adapted from Fig. 3.3(a), Callister & Rethwisch 8e. • Coordination # = 12 • APF = 0.74 • c/a = 1.633 6 atoms/unit cell ex: Cd, Mg, Ti, Zn Chapter 3 - 14 이론밀도(Theoretical Density, r) Density = r = r = where Mass of Atoms in Unit Cell Total Volume of Unit Cell nA VC NA n = number of atoms/unit cell A = atomic weight VC = Volume of unit cell = a3 for cubic NA = Avogadro’s number = 6.022 x 1023 atoms/mol Chapter 3 - 15 Theoretical Density, r r = • Ex: Cr (BCC) A = 52.00 g/mol R = 0.125 nm n = 2 atoms/unit cell Adapted from Fig. 3.2(a), Callister & Rethwisch 8e. atoms unit cell r= volume unit cell R a 2 52.00 a3 6.022 x 1023 nA VC NA a = 4R/ 3 = 0.2887 nm g mol rtheoretical = 7.18 g/cm3 ractual atoms mol = 7.19 g/cm3 Chapter 3 - 16 재료의 밀도 일반적으로 rmetals > rceramics > rpolymers 30 왜? 금속(Metals have...) Ceramics have... • less dense packing • often lighter elements Polymers have... r (g/cm3 ) • 조밀충진(close-packing) (metallic bonding) • 대부분 큰 원자질량 • low packing density (often amorphous) • lighter elements (C,H,O) Composites have... • intermediate values Metals/ Alloys 20 Platinum Gold, W Tantalum 10 Silver, Mo Cu,Ni Steels Tin, Zinc 5 4 3 2 1 0.5 0.4 0.3 Titanium Aluminum Magnesium Graphite/ Ceramics/ Semicond Composites/ fibers Polymers B ased on data in Table B1, Callister *GFRE, CFRE, & AFRE are Glass, Carbon, & Aramid Fiber-Reinforced Epoxy composites (values based on 60% volume fraction of aligned fibers in an epoxy matrix). Zirconia Al oxide Diamond Si nitride Glass -soda Concrete Silicon G raphite PTFE Silicone PVC PET PC HDPE, PS PP, LDPE Glass fibers GFRE* Carbon fibers CFRE * A ramid fibers AFRE * Wood Data from Table B.1, Callister & Rethwisch, 8e. Chapter 3 - 17 Crystals as Building Blocks • Some engineering applications require single crystals: -- diamond single crystals for abrasives (Courtesy Martin Deakins, GE Superabrasives, Worthington, OH. Used with permission.) -- turbine blades Fig. 8.33(c), Callister & Rethwisch 8e. (Fig. 8.33(c) courtesy of Pratt and Whitney). • Properties of crystalline materials often related to crystal structure. -- Ex: Quartz fractures more easily along some crystal planes than others. (Courtesy P.M. Anderson) Chapter 3 - 18 Polycrystals 이방성(Anisotropic) • Most engineering materials are polycrystals. Adapted from Fig. K, color inset pages of Callister 5e. (Fig. K is courtesy of Paul E. Danielson, Teledyne Wah Chang Albany) 1 mm <Nb-Hf-W plate with an electron beam weld> 등방성(Isotropic) • Each "grain" is a single crystal. • If grains are randomly oriented, overall component properties are not directional. • Grain sizes typically range from 1 nm to 2 cm (i.e., from a few to millions of atomic layers). Chapter 3 - 19 단결정(Single) vs 다결정(Polycrystals) • Single Crystals E (diagonal) = 273 GPa Data from Table 3.3, Callister & Rethwisch 8e. (Source of data is R.W. Hertzberg, Deformation and Fracture Mechanics of Engineering Materials, 3rd ed., John Wiley and Sons, 1989.) -Properties vary with direction: anisotropic. -Example: the modulus of elasticity (E) in BCC iron: • Polycrystals -Properties may/may not vary with direction. -If grains are randomly oriented: isotropic. (Epoly iron = 210 GPa) -If grains are textured, anisotropic. E (edge) = 125 GPa 200 mm Adapted from Fig. 4.14(b), Callister & Rethwisch 8e. (Fig. 4.14(b) is courtesy of L.C. Smith and C. Brady, the National Bureau of Standards, Washington, DC [now the National Institute of Standards and Technology, Gaithersburg, MD].) Chapter 3 - 20 동질이상(Polymorphism) • 하나 이상의 결정구조를 갖는 재료[Two or more distinct crystal structures for the same material (allotropy/polymorphism)] titanium , -Ti carbon diamond, graphite iron system liquid BCC 1538ºC -Fe FCC 1394ºC -Fe 912ºC BCC -Fe Chapter 3 - 21 결정계(Crystal Systems) 단위정(Unit cell): 결정의 완벽한 격자 형태를 포함하는 가장 작은 반복 체적(smallest repetitive volume which contains the complete lattice pattern of a crystal) 7 crystal systems 14 crystal lattices a, b, and c are the lattice constants Fig. 3.4, Callister & Rethwisch 8e. Chapter 3 - 22 입방 육방 정방 삼방 사방 단사 삼사 Chapter 3 - 23 점 좌표(Point Coordinates) z 단위정 중심에 대한 점 좌표(Point coordinates for unit cell center are) 111 c a/2, b/2, c/2 y 000 a x ½ ½ ½ b 단위정 꼭지점에 대한 점 좌표(Point coordinates for unit cell corner are) 111 z 2c b b y 평행이동(Translation): 격자상수를 곱하여 정수로 표시(integer multiple of lattice constants) 결정격자 내에서는 동일한 위치(identical position in another unit cell) Chapter 3 - 24 결정 방향(Crystallographic Directions) z 방법(Algorithm) 1. 적절한 크기의 벡터를 좌표축의 중심을 지나도록 한다. 2. 벡터가 각 축에 투영되는 길이를 결정하여 단위정의 크기인 a, b, c로 나타낸다. y 3. 최소의 정수로 표기한다. 4. 콤마로 분리하지 않고, 모난 괄호 안에 표시한다. x [uvw] ex: 1, 0, ½ => 2, 0, 1 => [ 201 ] -1, 1, 1 => [ 111 ] 위의 바(overbar)는 음의 지수(음의 좌표)를 나타냄 동등한 방향들을 묶어 족으로 표시(families of directions) <uvw> Chapter 3 - 25 선밀도(Linear Density) • Linear Density of Atoms LD = Number of atoms Unit length of direction vector [110] ex: linear density of Al in [110] direction a = 0.405 nm # atoms a Adapted from Fig. 3.1(a), Callister & Rethwisch 8e. LD = length 2 = 3.5 nm-1 2a Chapter 3 - 26 육방 결정의 방향(HCP Crystallographic Directions) z 방법 a2 - a3 a1 1. Vector repositioned (if necessary) to pass through origin. 2. Read off projections in terms of unit cell dimensions a1, a2, a3, or c 3. Adjust to smallest integer values 4. Enclose in square brackets, no commas [uvtw] a 2 Adapted from Fig. 3.8(a), Callister & Rethwisch 8e. ex: ½ , ½ , -1, 0 -a3 a2 2 => [ 1120 ] a3 dashed red lines indicate projections onto a1 and a2 axes a1 2 a1 Chapter 3 - 27 HCP Crystallographic Directions • Hexagonal Crystals – 4개의 축 Miller-Bravais 좌표계에서 방향은 다음과 같은 관계를 갖는다(i.e., u'v'w'). z [ u 'v 'w ' ] [ uvtw ] a2 - a3 a1 1 u = (2 u ' - v ') 3 1 v = (2 v ' - u ') 3 t = - (u +v ) w = w' Fig. 3.8(a), Callister & Rethwisch 8e. Chapter 3 - 28 결정면(Crystallographic Planes) Adapted from Fig. 3.10, Callister & Rethwisch 8e. Chapter 3 - 29 결정면(Crystallographic Planes) • 밀리지수(Miller Indices): 면과 만나는 3좌표축의 역수, 최소의 정수값. 모든 평행한 면은 동일한 밀러지수(reciprocals of the (three) axial intercepts for a plane, cleared of fractions & common multiples. All parallel planes have same Miller indices.) • Algorithm 1. Read off intercepts of plane with axes in terms of a, b, c 2. Take reciprocals of intercepts 3. Reduce to smallest integer values 4. Enclose in parentheses, no commas i.e., (hkl) Chapter 3 - 30 결정면(Crystallographic Planes) z example 1. Intercepts 2. Reciprocals 3. Reduction a 1 1/1 1 1 4. Miller Indices (110) example 1. Intercepts 2. Reciprocals 3. Reduction a 1/2 1/½ 2 2 4. Miller Indices (100) b 1 1/1 1 1 c 1/ 0 0 c y b a x b 1/ 0 0 c 1/ 0 0 z c y a b x Chapter 3 - 31 결정면(Crystallographic Planes) z example 1. Intercepts 2. Reciprocals 3. Reduction 4. Miller Indices a 1/2 1/½ 2 6 b 1 1/1 1 3 (634) c c 3/4 1/¾ 4/3 4 a x y b Family of Planes {hkl} Ex: {100} = (100), (010), (001), (100), (010), (001) Chapter 3 - 32 결정면[Crystallographic Planes (HCP)] • In hexagonal unit cells the same idea is used z example 1. Intercepts 2. Reciprocals 3. Reduction a1 1 1 1 1 a2 1/ 0 0 a3 -1 -1 -1 -1 c 1 1 1 1 a2 a3 4. Miller-Bravais Indices (1011) a1 Adapted from Fig. 3.8(b), Callister & Rethwisch 8e. Chapter 3 - 33 결정면(Crystallographic Planes) • • 결정면의 원자충진 철 포일도 촉매제로 사용이 가능. 노출면의 원자충진이 중요. a) Fe의 (100)과 (111) 결정 면을 그리시오. b) 각각의 결정 면에 대한 면밀도를 계산하시오. Chapter 3 - 34 Virtual Materials Science & Engineering (VMSE) • VMSE is a tool to visualize materials science topics such as crystallography and polymer structures in three dimensions • Available in Student Companion Site at www.wiley.com/college/callister and in WileyPLUS Chapter 3 - 35 VMSE: Metallic Crystal Structures & Crystallography Module • VMSE allows you to view crystal structures, directions, planes, etc. and manipulate them in three dimensions Chapter 3 - 36 Unit Cells for Metals • VMSE allows you to view the unit cells and manipulate them in three dimensions • Below are examples of actual VMSE screen shots FCC Structure HCP Structure Chapter 3 - 37 VMSE: Crystallographic Planes Exercises Additional practice on indexing crystallographic planes Chapter 3 - 38 면밀도(Planar Density) of (100) Iron Solution: At T < 912ºC iron has the BCC structure. 2D repeat unit (100) Planar Density = area 2D repeat unit 1 a2 = 4 3 R 3 Radius of iron R = 0.1241 nm Adapted from Fig. 3.2(c), Callister & Rethwisch 8e. atoms 2D repeat unit a= 1 4 3 R 3 atoms atoms 19 = 1.2 x 10 2 = 12.1 2 nm m2 Chapter 3 - 39 Planar Density of (111) Iron Solution (cont): (111) plane 1 atom in plane/ unit surface cell 2a atoms in plane atoms above plane atoms below plane h= 3 a 2 2 atoms 2D repeat unit 4 3 16 3 2 2 area = 2 ah = 3 a = 3 R = R 3 3 1 atoms = = 7.0 2 Planar Density = area 2D repeat unit 16 3 3 R 2 nm 0.70 x 1019 atoms m2 Chapter 3 - 40 VMSE Planar Atomic Arrangements http://bcs.wiley.com/he-bcs/Books?action=mininav&bcsId=5242&itemId=0470419970&assetId=199053&resourceId=19134 • VMSE allows you to view planar arrangements and rotate them in 3 dimensions BCC (110) Plane Chapter 3 - 41 X-선 회절(X-Ray Diffraction) • Diffraction gratings must have spacings comparable to the wavelength of diffracted radiation. • Can’t resolve spacings • Spacing is the distance between parallel planes of atoms. Chapter 3 - 42 X-Rays to Determine Crystal Structure • 결정면에 대한 입사 X-선의 회절(Incoming X-rays diffract from crystal planes). extra distance travelled by wave “2” q q d Measurement of critical angle, qc, allows computation of planar spacing, d. reflections must be in phase for a detectable signal Adapted from Fig. 3.20, Callister & Rethwisch 8e. spacing between planes X-ray intensity (from detector) n d= 2 sin qc q qc Chapter 3 - 43 회절의 조건; Bragg의 법칙 여기서 면간 거리, Chapter 3 - 44 Chapter 3 - 45 X-Ray Diffraction Pattern z z Intensity (relative) c a x z c b y (110) a x c b y a x (211) b (200) Diffraction angle 2q Diffraction pattern for polycrystalline -iron (BCC) Adapted from Fig. 3.22, Callister 8e. Chapter 3 - 46 y SUMMARY • Atoms may assemble into crystalline or amorphous structures. • Common metallic crystal structures are FCC, BCC, and HCP. Coordination number and atomic packing factor are the same for both FCC and HCP crystal structures. • We can predict the density of a material, provided we know the atomic weight, atomic radius, and crystal geometry (e.g., FCC, BCC, HCP). • Crystallographic points, directions and planes are specified in terms of indexing schemes. Crystallographic directions and planes are related to atomic linear densities and planar densities. Chapter 3 - 47 SUMMARY • Materials can be single crystals or polycrystalline. Material properties generally vary with single crystal orientation (i.e., they are anisotropic), but are generally non-directional (i.e., they are isotropic) in polycrystals with randomly oriented grains. • Some materials can have more than one crystal structure. This is referred to as polymorphism (or allotropy). • X-ray diffraction is used for crystal structure and interplanar spacing determinations. Chapter 3 - 48 ANNOUNCEMENTS Reading: Core Problems: Self-help Problems: Chapter 3 - 49