Power Factor and Reactive Power Ward Jewell Wichita State University Power Systems Engineering Research Center (pserc.org) PSERC Energy to lift a 5 pound weight 2 feet high: 2 ft x 5 lb = 10 ft-lb = 0.0000038 kWh = 0.0033 “calories” (which are actually kcal) Value at 10.3 cents per kWh: (average residential US price, summer 2006) 0.000039 cents PSERC Page 1 As dragline bucket lowers, motors generate, return electricity to source PSERC Induction motor with no load 800 energy to motor 735.249 power (watts) 600 400 200 p ( t) 0 energy from motor 0 200 400 − 465.196 600 0 0 0.002 0.004 0.006 0.008 0.01 0.012 t 0.014 time (seconds) PSERC Page 2 0.016 0.018 0.017 Induction motor 800 735.249 power (watts) 600 average power: 130 watts 400 200 p ( t) 0 200 400 − 465.196 600 0 0.002 0 0.004 0.006 0.008 0.01 0.012 0.014 0.016 t 0.018 0.017 time (seconds) PSERC Incandescent lights 350 306.8 power (watts) 300 250 average power: 150 watts 200 p ( t) 150 100 50 0 0 0 0 0.002 0.004 0.006 0.008 0.01 0.012 t 0.014 time (seconds) PSERC Page 3 0.016 0.018 0.017 0 Incandescent Lights PSERC Induction motor with no load PSERC Page 4 Lights and Motor Power Current Voltage Incandescent lights 0.15 kW 1.3 A 118.0 V Induction motor with no load 0.13 kW 5.1 A 117.7 V PSERC Why do the Volts and Amps matter? PSERC Page 5 Motors and Resistance Heat: 100 MW Customer voltage Power lost in wires Resistance Heat 12.3 kV 1.0 MW Motors 11.7 kV 2.3 MW PSERC Incandescent Lights PSERC Page 6 Incandescent lights power: Power = 118 V x 1.3 A = 153 W = 0.15 kW = power measured by meter PSERC Incandescent Lights PSERC Page 7 Induction motor with no load PSERC Induction motor power: 117.7 V x 5.1 A = 600 W? = 0.6 kW? NOT the power measured by meter PSERC Page 8 Induction motor with no load PSERC Define some new values: Apparent power = volts x amps For the motor: 117.7 V x 5.1 A = 600 VA = 0.6 kVA VA: volt-ampere PSERC Page 9 Define some new values: Power Factor = Average (“real”) (kW) power Apparent (kVA) power For the motor: pf = 0.13 kW / 0.60 kVA pf = 0.22 VI2 – average power2 2 2 ( 0.60kVA) − ( 0.13kW) = 0.59 kVAR 0.58 kVAR reactive power = 0.58 kVAR reactive power = Appa rent p ower = Define some new values: the power triangle for the motor: 0.60 kVA PSERC VAR: volt-ampere reactive real power = 0.13 kW PSERC Page 10 Induction motor with no load PSERC Lights and Motor Real Reactive Apparent Power Current Voltage power factor power Power Incandescent lights 0.15 kW 0 kVAR 0.15 kVA 1.0 1.3 A 118.0 V Induction motor with no load 0.13 kW 0.58 kVAR 0.60 kVA 0.22 5.1 A 117.7 V Note: the motor’s reactive power will stay near its no-load value of 0.58 kVAR as its load and real power (and thus apparent power and power factor) vary from no load to full load. PSERC Page 11 Power factor and reactive power are indicators of power losses in wires voltage drop between supply and load PSERC Typical Power Factors Induction motor 0.7-0.8 Resistance heat 1.0 Incandescent lights 1.0 Fluorescent lights 0.6-1.0 Battery Chargers 0.6-1.0 Computers 0.5-1.0 Variable Speed Motor Drives 0.5-1.0 PSERC Page 12 Power factor: lagging or leading? Most loads with lower power factor are inductive. Current lags voltage. Power factor is “lagging.” PSERC Induction motor with no load voltage current 3.6 ms Current lags voltage by about 3.6 milliseconds PSERC Page 13 Another way to calculate power factor 16.7 ms 3.6 ms One 60 Hz cycle = 1/60 seconds = 16.7 ms PSERC Another way to calculate power factor: “displacement” power factor (3.6 ms / 16.7 ms) x 360 degrees = 77 degrees current lags voltage by 77 degrees cosine (77 degrees) = 0.22 power factor is 0.22 lagging pf = cos θ θ = angle between voltage and current PSERC Page 14 Incandescent lights PSERC Current and voltage are “in phase.” Incandescent lights: displacement power factor: angle between voltage and current = 0 degrees pf = cos(0 degrees) = 1.0 PSERC true power factor: pf = 0.15 kW / 0.15 kVA pf = 1.0 Page 15 If voltage and current are sinusoidal displacement pf (DPF) = true pf (PF) lights motor PSERC Correcting (increasing) power factor PSERC Page 16 Capacitors to improve power factor: capacitors release energy when inductors consume 1.2 1 Capacitor current 0.5 iL( t) 0 ic ( t) Inductor current 0.5 1 − 1.2 0 0.002 0.004 0.006 0.008 0 0.01 t 0.012 0.014 0.016 0.018 0.017 PSERC Induction motor with power factor correction capacitor PSERC Page 17 Induction motor with power factor correction capacitor Real Reactive Apparent power power power Power factor Current Voltage Induction motor 0.13 kW 0.58 kVAR 0.60 kVA 0.22 5.1 A 117.7 V Induction motor with capacitors 0.13 kW 0.11 kVAR 0.18 kVA 0.96 1.5 A 118.4 V PSERC Wire losses: motors with capacitors Customer voltage Power lost in wires Motors 11.7 kV 2.3 MW Motors with power factor correction capacitor 12.3 kV 1.0 MW PSERC Page 18 Incandescent lights with power factor correction capacitor PSERC Incandescent lights with power factor correction capacitor Incandescent lights Lights with capacitors Real Reactive Apparent power power power 0.15 0 kVAR 0.15 kVA kW 0.15 kW 0.64 kVAR 0.66 kVA PSERC Page 19 Power factor 1.0 0.23 leading Current Voltage 1.3 A 118.0 V 5.5 A 119.9 V Wire losses: lights with capacitors Customer voltage Power lost in wires Resistance heat 12.3 kV 1.0 MW Resistance heat with power factor correction capacitors 13.0 kV 2.0 MW PSERC Leading power factor Current leads voltage in a capacitor. Too much capacitance causes low leading power factor. (just as bad as low lagging power factor) Leading power factor causes high voltage and increased wire losses. Use the correct amount of capacitance. (more is not better) Switch capacitors off when motors are off (just put capacitor on same switch as motor) PSERC Page 20 If voltage and current are sinusoidal displacement pf = true pf lights motor PSERC If waveform is not sinusoidal: PC voltage and current PSERC Page 21 If waveform is not sinusoidal: PC voltage and current PSERC Harmonic distortion PSERC Page 22 Low power factor caused by harmonic distortion cannot be corrected by capacitors Harmonic currents are not accompanied by harmonic voltage, so average (real) power in harmonics is almost zero. pf = average power / apparent power decreases PSERC Common harmonic loads computers motor drives battery chargers rectifiers induction heaters arc furnaces To correct low power factor caused by distorted current waveforms, the harmonic currents must be filtered. PSERC Page 23 Capacitors can make harmonic distortion worse: Lights with power factor correction capacitor This is rare, but should be considered in the presence of harmonic loads PSERC Summary Induction motors and other inductive equipment load the electric power system differently than incandescent lights and resistive heaters Power Factor and Reactive Power are indicators of power lost in wires and reduced customer voltage Low displacement power factor caused by induction motors (and other inductive loads) can be corrected with power factor correction capacitors Power factor correction capacitors must be sized properly Power factor correction capacitors cost much less than utility power factor charges and will eliminate those charges Power factor correction capacitors should be disconnected when motors are disconnected Low harmonic power factor is corrected with filters, not capacitors. Capacitors may make it worse. PSERC Page 24 Ward Jewell 316.978.6340 ward.jewell@wichita.edu pserc.org (slides are posted under “presentations”) PSERC Page 25