RooneyMWLab Molecular Weight Experiment Mary Anne Rooney November 11, 2006 MISE - Physical Basis of Chemistry Third Experiment Molecular Weight of a Volatile Liquid Lab Report – Submit electronically (digital drop box) by Sunday, November 18, 6:01PM Note: When submitting to digital Drop Box label you files with your name first and then a brief description of what the document is. Purpose: The Purpose of this experiment is to determine the molecular weight of a compound that is a volatile liquid. DATA/CALCULATIONS Note: Data and Calculations may be completed on an Excel spreadsheet. Unknown Letter: B Molecular Weight of a Volatile Liquid (If you performed more than one trial, adjust your data table accordingly.) 1. Determination of mass of vapor: Weight of flask + foil cap + rubber band Temperature of water bath when (excess) vapor ceased to escape Weight of flask + foil cap + rubber band + condensed vapor Weight of condensed vapor Trial 1 Trial 2 91.8751 g 93.7 oC 91.8751 g 93.8 oC 92.4380 g 92.3002 g .5629 g .5629 g 233.14 g 91.42 g 141.72 g 23.1 oC 0.142 L 233.14 g 91.42 g 141.72 g 23.1 oC 0.142 L Barometric pressure : 760 mmHg = 1 atmHg 770.9 mm 1.01 atm therefore, 770.9Hg = 1.01 atmHg Temperature (Kelvin): oC + 273 = oK therefore, 23.1 oC + 273 = 296.1 oK 23.1 oC 296.1 oK 2. Determination of full volume of flask: Weight of Erlenmeyer flask filled with water Weight of clean, dry, and empty Erlenmeyer flask Weight of water that completely filled Erlenmeyer flask Temperature of water in the filled Erlenmeyer flask Calculated volume of Erlenmeyer flask (in liters) Show work here: 1.0 gH2O = 1.0 mLH2O 1000 mL = 1 L; so 141.72 mL ÷ 1000 = 0.142 L RooneyMWLab Molecular Weight Experiment Mary Anne Rooney November 11, 2006 Determination of molecular weight of the volatile liquid: (Assuming ideal gas behavior, use the pressure of the vapor (P), its volume (V), and its temperature (T) to determine the moles of vapor in the Erlenmeyer flask. Then, using the mass of vapor which occupied the Erlenmeyer flask, determine the molecular weight (MW in g/mole) of the volatile liquid. If you performed more than one trial, show all work for each trial and then compute the average molecular weight.) Show work below. T = 93.7 OC + 273 = 366.7 OK MW = gRT MW = 0.5629 g x 0.0821 atm*L x 366.7 K 16.95 118.2 PV 1.01 atm x n * K x .142 L .14342 g/n (Average) Molecular Weight g/mole 118.2 Determination of Empirical and Molecular Formula of volatile liquid: The table below lists the pure volatile liquids that were distributed in lab. The first column gives the letter designation of the compound and the remaining columns give the appropriate elemental mass percents. Using the data for your particular volatile liquid, please determine the empirical formula and the molecular formula for your particular sample. Show all work. Sample Letter mass % carbon (C) mass % hydrogen (H) mass % oxygen (O) “A” (cyclohexane) 85.60 % 14.40 % None “B” (ethyl acetate) 54.52 % 9.17 % 36.31 % “C” (2-propanol) 59.94 % 13.44 % 26.62 % moles C = (54.52 g C) x ( 1 mole C ) = 54.52 g (12.01 g C) 12.01 g moles H = (9.17 g H) x (1 mole H ) = 1.01 g H 9.17 g 1.01 g = 4.54 moles C = 9.08 moles H moles O = (36.31 g O) x (1 mole O ) = 36.31 g = 2.27 moles O 16.00 g O 16.00 g moles C = 4.54 moles = 1 = CH2 moles H 9.08 moles 2 moles C = 4.54 moles = 2 = C2O moles O 2.27 moles 1 moles H = 9.08 moles = 4 = H4O moles O 2.27 moles 1 Empirical Formula C2H4O Volume vapor = Volume water = mass water densitywater T = 93.7 OC Volume = 0.142 L + 273 = 366.7 OK 141.72 g 142.1 mL x 1L = 0.9975 g/mL 1000 mL RooneyMWLab Molecular Weight Experiment MW = gRT PV Mary Anne Rooney November 11, 2006 MW = 0.5629 g x 0.0821 atm*L x 366.7 K 16.95 118.2 1.01 atm x n * K x .142 L .14342 g/n Molecular Weight = 118.2 g/mole EWF = (2 x 12.01g/mole C) + (4 x 1.01 g/mole H) + 16.00 g/mole O = 44.06 g/mole N = MW = EWF 118.2 g/mole 44.06 g/mole = 2.650 2 Molecular Formula = C4H8O2 CONCLUSION QUESTIONS 1. Why is the barometric (i.e., atmospheric) pressure considered to be the pressure of the vapor, i.e., how does the experimental procedure ensure this? Explain carefully. The barometric pressure of a substance in a non-porous container that has a pin hole in the “lid” will balance out to be the same inside the container as is the barometric pressure outside the container. 2. Why isn't it necessary to weigh the amount of liquid initially put into the flask? Explain. It isn’t necessary to weigh the amount of liquid initially put into the flask because we were concerned with the molecular weight of the vapor, not the liquid. By heating the liquid until vaporized, we were permitting the container to fill completely with vapor – vapor (gas) will expand to fill the available space. Extra Credit– It is sometimes stated that the above method (Dumas method) relies on the presumption that the investigated gas follows the ideal gas law (PV = nRT). This allows one to determine the moles of the contained vapor via: PV n = moles of contained vapor = RT , i.e., its measured pressure (P), volume (V), and temperature (T). Of course, the gas constant (R) is tabulated and equals 0.0821 L•atm•mol-1•K-1. Then, the molecular weight of the gas (MW in g/mol) can be determined from the measured mass of the contained vapor (g in grams) divided by the calculated number of moles. g g gRT MW = n = PV = . In other words, if the gas did not behave ideally, then the PV RT calculated molecular weight would be a crude approximation at best. Please explain why this is commonly not a big problem, i.e., why an approximate value of the molecular weight is often sufficient when determining the actual chemical formula of a volatile compound. What other information is commonly obtained for a compound in the process of determining its chemical formula such that an approximate molecular weight is often “good enough”? An approximate value of the molecular weight is often sufficient when determining the actual chemical formula of a volatile compound because the law of multiple proportions allows us to obtain the empirical formula equal to the sums of the atomic weights of the constituent elements.