Name: ____________________________ Genetics 314 – Spring 2004 Second Exam – 100 points 1. Neighbors of a chemical plant that produces fluorocarbons believe that emissions from the plant have resulted in a localized hole in the ozone allowing for an increase in UV light exposure leading to an increase incidence of mutations that have lead to an increase in skin cancer. a) The company claims that the mutations are not due to the U.V. light. Is it possible to have mutations without an external cause such as U.V. light? Briefly explain your answer. Yes it is possible to have mutations without an external cause. Spontaneous or natural mutations can occur from errors in proof reading by DNA polymerase to changes in base form (ex. keto to enol) that result in mispairing. b) You decide to test the theory on increased U.V. light by exposing several strains of bacteria to the light around the chemical plant. In two strains you find a low level of mutation (lower than you expected for the level of U.V. light exposure) but in one strain you observe a high level of mutation. 1. What could keep the mutation rate lower than expected in the first two bacterial strains? Briefly explain your answer. Bacteria possess two forms of thymine dimer repair systems, light activated and dark (excision – repair), that could minimize the damage caused by U.V. light. In the case of the first two bacterial strains the repair systems are working properly reducing the number of mutations induced by the U.V. light. 2. What is different about the third strain to make it show such a high rate of mutation? In the case of the third strain it appears that it does not have functional repair systems so the damage caused by the U.V. light is not repaired leading to base pairing errors resulting in a high mutation rate. 2. You are asked to make modifications in plants using a chemical mutagen. You want to make mutations that modify the function of enzymes but not make them non-functional. You have a choice between a chemical that causes base deletions and a chemical that causes base changes. Which chemical would you pick and why? 1 Name: ____________________________ I would choose the chemical that causes base changes over the chemical that causes base deletions. A base change may lead to the changing of a single amino acid that may or may not have a major affect on the functionality of the protein. A base deletion on the other hand would lead to a frameshift mutation changing all codons and resulting amino acids downstream of the deletion. This would have a high probability of producing a non-functional protein product. 3. Your neighbor is afraid of getting bacterial infections but also is afraid of contributing to the problem of creating antibiotic resistant bacteria by using antibiotic soaps so he buys a new cleaning solution that claims it kills bacteria from the inside out by soaking the bacteria in a base analog of adenine. a) Could this cleaning solution kill bacteria? Briefly explain your reasoning. In theory yes, a chemical that is a base analog could induce base change mutations by replacing a base but at the next replication pair with a different base leading to a base change mutation. If the chemical induces a high enough level of mutation, critical protein products will be affected leading to the death of the bacteria. b) You ask your neighbor if he wears gloves when he uses the cleaning solution, why? The base analog could cause mutations in his DNA as easily as it could cause mutations in the bacterial DNA. 4. You are asked to create a regulatory system for a three gene/enzyme biochemical pathway in bacteria that you can turn on and off by adding an ingredient to the media that that you use to grow the bacteria. You have learned about two pathways in bacteria for lactose utilization and tryptophan synthesis. a) What are the differences between the two gene/enzyme systems in terms of regulation of gene expression? Lactose utilization is an inducible system where a repressor protein will bind to the operator site preventing transcription unless lactose is present. Lactose will act as an inducer and bind to the repressor making it unable to bind to the operator site and transcription can occur. Tryptophan is a repressible system where the repressor protein can not bind to the operator site allowing transcription unless the end-product tryptophan is present. Tryptophan will act as a co-repressor and when it binds to the repressor it becomes active and can bind to the operator site preventing transcription. 2 Name: ____________________________ b) Which of the regulatory systems would you use for your three gene/enzyme system? Briefly explain your answer. I would use the inducible system since I could then control when transcription would start by adding the inducer. The inducer would then bind with the repressor protein preventing it from blocking the operator site allowing transcription to begin. As long as I keep adding the inducer transcription of my gene would be occurring. 5. You are asked to move your three gene/enzyme system into a eukaryotic organism. a) How would you change your system to allow for simultaneous expression of the three genes in the eukaryote? Since operons do not exist in eukaryotes I would use a combination of enhancer sequences and activator proteins to turn on the genes at the same time. By having the same enhancer sequences upstream from the promoter regions for all three genes I could ‘turn on’ all three genes simultaneously by adding the transcription activator proteins that correspond to the enhancer sequences. b) You want to add a second level of regulation on to your system. What could you regulate in eukaryotes that can not be regulated in prokaryotes and how could it affect expression of your gene? Eukaryotes require an mRNA processing step before translation can occur. Regulation of the processing such as intron removal, addition of the poly A tail, or movement of the mRNA out of the nucleus would affect the rate of protein synthesis by affecting when translation could start and in the case of the poly A tail, how long translation could occur. The length of the poly A tail appears to affect how long the mRNA will be available for translation. The greater the number of adenines the longer the life of the mRNA and the longer it can be translated. 6. Viruses are a challenge to control but it is proposed that RNA viruses could possibly be controlled. What makes them different and how could you limit their ability to replicate? RNA virus requires special ‘non-host’ enzymes for replication. In the case of an RNA to RNA virus this enzyme is replicase and for retrovirus (RNA to DNA to RNA) virus the enzyme is reverse transcriptase. Since these enzymes are not essential for normal functioning of the host cell, elimination or deactivation of these enzymes would not hurt the host cell but would effectively prevent the RNA virus from replicate. 3 Name: ____________________________ 7. There was talk recently about the flu virus and how an avian flu virus could recombine with another virus to create a virulent flu virus that could attack people. How could genetic recombination between two viruses occur? Key for recombination of two viruses is the simultaneous infection of the host cell by two viruses. After infection there could be recombination between the genetic material of the two viruses, copy-choice errors during replication and/or errors in packaging that could lead to genetic material from both viruses being packaged into one viral capsule. 8. Virus and prokaryotic DNA can replicate by two methods. What are the two methods and why are two methods needed for replication of circular DNA? The two methods are bi-directional ((Theta) replication and rolling circle replication. Bi-directional replication will produce two circular pieces of DNA. Rolling circle replication has the potential to produce single or double stranded linear pieces of DNA. Linear DNA is needed by virus when it is packaged into the viral capsule and by bacteria for conjugation to occur. 9. You are asked to put a piece of DNA into bacteria. a) What are the three ways for recombination to occur in bacteria? Transformation Conjugation Transduction b) Which would be the easiest to use and how would it work? Transformation, all that would be needed is competent cells, and pieces of DNA. The competent bacterial cells will take up the DNA from the environment and some of the DNA will recombine with the bacteria’s chromosome. In the case of plasmid DNA the bacteria will take up the plasmid and it will be functional without recombination with the bacterial chromosome. 10. You are given the following data on recombination using conjugation and Hfr strains for gene mapping in bacteria Strain A34 B22 D15 F55 -------------gene order-------------trp ala cys pro met ala trp bio gal lac pro met glu leu lac bio gal lac leu glu 4 Name: ____________________________ Diagram a gene map showing gene order, F factor insertion site and F factor orientation. F55 trp bio ala gal A34 B22 cys lac pro D15 leu glu met 11. You discover bacteria recombination is occurring whenever you infect bacteria with a bacterial phage. In some cases it is only recombination involving two genes, bio and gal, and in other cases a low level of recombination involving many bacterial genes. What form of recombination is occurring and how do the two types of cases differ? Transduction is occurring where a virus is serving as a vector to move the DNA from one bacterium to other bacteria. In the first case specialized or specific transduction is occurring where a temperate phage disassociates from the bacteria chromosome improperly taking a gene adjacent to the insertion site with it. In the case of the temperate lambda phage this insertion site is in between the bio and gal genes so one or the other of these genes would be transferred. In the second case generalized transduction is occurring where pieces of bacterial chromosome are accidentally packaged into the viral capsule. This is a random event so any genes could be transferred. 5 Name: ____________________________ 6