3) Data Interpretation:
When eqm is reached, we have a constant concentration for each of the 3
species during 3 consecutive trials.
Summary Questions:
1) Strategy used to obtain eqm.
Stop competing and synchronize the rates so that we get constant [ ]s
Agree to break the same # of bonded as to make the same # of bonded.
2) At eqm: rate (synthesis) = rate (decomposition)
When [large atom],[small atom],[molecule]: have a constant value.
3) When rates are equal, amounts of small/large atoms and
molecules aren't equal.
However, the amount of each substance is constant.
# small atoms  # large atoms  #molecules
4) When more paper clips (stress) are added:
small atom + large atom  molecule
**T** 3 possibilities: Le Châtelier’s Principle
Def: An eqm system will counteract any imposed stress
Stress
Outcome
i) If [small atom], then [large atom] and [molecule]
ii) If [large atom], then [small atom] and [molecule]
iii) If [molecules], then [large atom]  and [small atom]
The above results should’ve taken place, however some experimental
results were different.
**T**5) At eqm, rates for forward and reverse rxns are equal
The number of effective collisions to form molecule is the same as
the number of molecules breaking down into small/large atoms
forward rate =
reverse rate
# m/c formed
=
# m/c breaking down
Conclusion:
If paperclips collide at the correct speed and alignment, a bonded paperclip
will form.
If the speed of bonded p.c. is fast enough, they will decompose into
small and large p.c.