Rocket City Math League 2012-2013 Round 1 Apollo Test Solutions n x2 1. 1 n(n 1)( 2n 1) , so 6 10 x 2 1 10 11 21 385 6 385 2. [ln(1000)][log(𝑒 2 )] = [log(1000)][ln(𝑒 2 )] = 3 * 2 = 6. 6 3. Where a+bi corresponds to a point a in the real direction and b in the imaginary direction, the reflection of this point over the imaginary axis would correspond to a point –a in the real direction but still b in the imaginary direction. This reflected point corresponds to the complex number –a+bi. 4. Hyun Su had a 120 mile (3hr*40mph) head start. After that, both rockets went forward—Hyun Su’s at 40 mph and Raisa’s at 60 mph. Raisa’s rocket gained 20 miles for every hour traveled. That means for it to catch up to Hyun Su, it would take 120/20, or 6 hours. Alternatively, let x be the number of hours it would take for both rockets to be at the same location. Then, -a+bi 6 x 40 ( x 3) 60 40 x 60 x 180 20 x 180 x 6 5. x 6x y - 10y 22 0 (x 6x 9) ( y - 10y 25) -22 9 25 12 , so r2=12 and r= 2 2 2 2 12 = 2√3 using the equation of a circle in the coordinate plane. √3 6. A = (.5)(a)(b)(sin(C)) = (.5)(6√6)(12)(sin(60)) = (.5)(6√6)(12)( ) = 54√2 2 𝟓𝟒√𝟐 7. The expansion is found using Pascal’s triangle. The fourth line is 1, 4, 6, 4, 1. Thus, the equation is 1(81x4) – 4(27x3y) + 6(9x2y2) – 4(3xy3) + 1(y4), or 81x4 – 108x3y + 54x2y2 – 12xy3 + y4. The sum of the coefficients is then 81 – 108 + 54 – 12 + 1=16. Alternatively, the sum of the coefficients is also the value of (3x-y)4 when x=y=1. (3(1)-(1))4=(2)4=16. 8. Using the formula for the sum of an infinite geometric series 𝑆 1 𝑥−1 2𝑥 𝑥 = 𝑎1 1−𝑟 ,𝑆 2√𝟑 = 1 𝑥 1 1− 2 𝑥 = 𝑥 . 1 𝑥 2 −1 𝑥+1 + 16 110 = 𝑥 2 −1 = 2 (𝑥 2 −1) = 2(55) = 110. 9. The Galaxy goes 330 miles forward for every 8 gallons. That means it goes a total of 1650 miles. The Starchild just goes 1080 miles. The Moondust goes 210 miles for every 5 gallons. That means it goes 2240 miles total. The Rumble goes 125 miles for every 3.5 gallons, or 1425 miles. The Moondust is the only rocket ship that can go the 2000 miles. 10. 5𝑥 3 − 11𝑥 2 + 9𝑥 = −6 5𝑥 3 − 11𝑥 2 + 9𝑥 + 6 = 0. 𝑚2 + 𝑛2 + 𝑝2 = −11 (𝑚 + 𝑛 + 𝑝)(𝑚 + 𝑛 + 𝑝) − 2(𝑚𝑛 + 𝑛𝑝 + 𝑚𝑝). By Vieta’s formulas, 𝑚 + 𝑛 + 𝑝 = − = 9 11 5 5 𝑚𝑛 + 𝑛𝑝 + 𝑚𝑝 = , so 𝑚2 + 𝑛2 + 𝑝2 = ∗ 11 5 9 31 5 25 −2( ) = 5 11 5 and . The Moondust 𝟑𝟏 𝟐𝟓 The material on this page is the property of the Rocket City Math League. Reproduction other than for non-profit educational purposes is strictly prohibited without the expressed written consent of the RCML. Rocket City Math League www.rocketcitymath.org Sponsored by Mu Alpha Theta - National Math Honor Society www.mualphatheta.org