Supplemental Information Thermal Conductivity of Er+3:Y2O3 films grown by Atomic Layer Deposition Hafez Raeisi Fard1, Nicholas Becker2, Andrew Hess1, Kamyar Pashayi1, Thomas Proslier2, Michael Pellin2 and Theodorian Borca-Tasciuc1,* 1 Mechanical, Aerospace and Nuclear Engineering Department, Rensselaer Polytechnic Institute, Troy, New York 12180, USA 2 Material Sciences Division, Argonne National Laboratory 9700 S. Cass Avenue, Lemont, Illinois 60439, USA Calibration of the temperature coefficient of resistance The calibration of the temperature coefficient of resistance (TCR) was carried out using a 4-probe method to obtain heater electrical resistance at different ambient temperatures. The electrical current passing through the heater was kept low to avoid self-heating. Equation (1) shows how TCR links the sample electrical resistance to temperature rise: π = π 0 × (1 + ππΆπ × βπ) (1) where R is electrical resistance at any temperature and R0 is the initial resistance, TCR is the temperature coefficient of resistance and βπ is temperature difference. Figure S1 shows an example of the linear relationship between the experimentally measured resistances as a function of temperature for a 0.98 mm long and 20 οm wide heaters deposited on an as-deposited sample. The uncertainty in TCR was found to be ~ 10%. *Corresponding author, borcat@rpi.edu 1 40.7 not-annealed sample TCR=0.00161 (1/K) 40.6 Resistance ο¨οο© 40.5 40.4 40.3 40.2 y = 39.867 + 0.064841x R= 0.99706 40.1 4 6 8 10 o Temperature ( C) 12 14 Fig. S1. Temperature coefficient of resistance calibration plot showing the linear dependence of the electrical resistance as a function of temperature for a 0.98 mm long and 20 οm wide heater made of 25 nm Ni and 35 nm Au. Fitting the substrate and film thermal conductivities and the interface thermal resistance In this work a two-dimensional (2D) heat conduction model was used initially to fit the frequency dependent temperature amplitude of the 3ο· heaters. Results are presented in Fig. S2. 0.4 0.35 DT (K) 0.3 ΔTfilm 0.25 0.2 0.15 0.1 10 100 4 1000 10 Frequency (Hz) 5 10 Fig. S2. Experimental temperature amplitude as a function of frequency for an as-deposited 458 nm film on substrate sample (circular dots) and predicted temperature rise using the 2D heat conduction model for substrate only (line). The difference is the film temperature rise. 2 In Fig S2 the circular dots depict the measured ac temperature amplitude which corresponds to the film plus substrate temperature rise. The solid line shows the substrate temperature rise calculated from our2 2D multilayer heat conduction code by modeling the case with no film on the substrate. The calculated substrate ac temperature rise is parallel with the experimental data. The difference between the total temperature rise from the experiment and substrate temperature rise from the model is the film temperature rise, which is used to calculate thin film conductivity. We used a 2D heat conduction model to fit the film temperature rise. However, for large heaters width (vs. the film thickness) and films on large thermal conductivity substrates the heat conduction across the film could be close to one-dimensional (1D).2 When using a one-dimensional (1D) heat conduction model across the film and same ITR the film thermal conductivity from Fig. S2 was found to be 22% higher than the value determined from the 2D fitting. For the substrate temperature rise a simple analytical expression was proposed by Cahill et al using a linear function of ln(π): π ππ = π×π×πΎ × πππππππ (ln(π)) (2) π where l is the heater length, P is the rms power and the linear function is shown in more detail in the first term in Eq. 3. Based on the above expression the substrate thermal conductivity can be found by fitting the slope of the real part of the temperature profile as a function of frequency. The heater temperature amplitude can be then approximated as: π 1 πΌ 1 ππ π×π π π = π΄ππ {(π×π×πΎ [2 ln (π2 ) + π − 2 ln(2π) − 4 ]} + 2×π×π×πΎ + πΌππ × 2×π×π π π (3) where b and d are heater half width and thickness of the specimen respectively, α is thermal diffusivity of the heater and π is a constant. The main unknowns in Eq. (3) are substrate and film 3 thermal conductivities as well as the overall interface thermal resistivity (ITR) of substrateEr+3:Y2O3-metal heater system. Determining ITR requires two film samples with similar thermal conductivities and with different thicknesses. For this purpose we employed the as-deposited samples with 110nm and 458nm thicknesses. The procedure to determine the ITR and thermal conductivity simultaneously is shown in the Fig. S3. In this method a solution set of ITR vs. thermal conductivity that fits the sample temperature rise is generated for each sample, and then the solution curves are intersected to find the common values. It should be noted that the values of thermal conductivities that provide an accurate temperature rise for each sample and different ITR are at least an order of magnitude smaller than the thermal conductivity of the annealed sample. Using this method the film thermal conductivity for the as-deposited samples was found to be 0.49 W/m-1K-1 and substrate thermal conductivity is 36 W/m-1K-1 and ITR is 2.5x10-8 Km2/W. The value of the substrate thermal conductivity is in a good agreement with the reported value for sapphire thermal conductivity in text books3, which is in the range of 30-46 W/m-1K-1. Data reduction was repeated for each sample at different powers and the results were consistent. 10 -5 10 -6 10 -7 10 -8 2 ITR (m K/W) 110 nm 458 nm 0.3 0.4 0.5 K layer 0.6 0.7 -1 -1 (Wm K ) 0.8 0.9 Fig. S3. Solution sets of ITR vs. film thermal conductivity that fit the experimental temperature rise for the two heaters on the two as-deposited samples. The intersections of the curves provide the determined values of ITR and thermal conductivity. 4 Reduction in Oxygen content after post deposition annealing Figure S4 shows the RBS result of oxygen content for the samples. The oxygen content for pure Y2O3 is 60%. In yttria deposited by ALD oxygen atoms above stoichiometric values are carried by OH/H2O. The oxygen content was ~67% for the as grown sample and the excess oxygen was removed after annealing at 700°C. Fig. S4. RBS results. Error analysis In this work the uncertainty in thermal conductivity of the substrate and film were estimated using uncertainty propagation analysis. If film thermal conductivity can be written as an analytical function of n independent variables xi, each with an absolute uncertainty wi, then the absolute uncertainty of the thermal conductivity is, ππΎ π€πΎ = √∑ππ=1(ππ₯ × π€π )2 (4) π 5 The auto cancellation4 3ο· setup was used for the measurement and the experimental heater temperature amplitude is related to the experimental signals as: 2×π 3π π = ππΆπ ×π (5) 1π The experimental temperature rise has two contributions, film and substrate as shown in Fig. S2. If we consider the expression of the substrate temperature rise from Eq. 3 and consider m its derivative with respect to ln (π) then the substrate thermal conductivity can be determined as: −π πΎπ = 2π×π×π (6) The uncertainty in m was determined based on the experimental uncertainty of the heater temperatures at opposite ends of the frequency range. The derivatives with respect to each variable are, ππΎπ ππ ππΎπ ππ ππΎπ ππ 1 = − 2π×π×π π 1 π 1 (7a) = 2π×π × π2 (7b) = 2π×π × π2 (7c) 6 After substitution of Eqs. 7(a-c) into Eq. 4 it was found that the total relative error in substrate thermal conductivity is ~50%. This is mainly due to the uncertainties of the slope m and heater length. Next step is to calculate the uncertainty of the film thermal conductivity. Neglecting the ITR, the film thermal conductivity can be extracted after substitution of Eq. 5 and Eq. 6 in Eq. 3, π×π −1 2×π 3π πΎπ = 2×π×π (ππΆπ ×π − ππ ) (8a) 1π π×π −1 2×π 3π πΎπ = 2×π×π (ππΆπ ×π + 2 × π × πππππππ (ln(π))) 1π π×π = 2×π×π × π΄ (8b) The derivatives with respect to P, d, b, l, V3w, TCR, and m are: ππΎπ ππ ππΎπ ππ ππΎπ ππ ππΎπ ππ π΄×π = 2×π×π (9a) π×π΄ = 2×π×π = = ππΎπ ππ3π (9b) π×π×π΄ −1 2×π ( π2 ) (9c) π×π×π΄ −1 2×π ( π2 ) −2 ππΆπ ×π1π π×π = 2×π×π . (9d) ( (9e) 2 2×π3π +2×π×πππππππ (ln(π)) ππΆπ ×π1π 7 ππΎπ ππ ππΎπ π×π = 2×π×π . −2×πππ (9f) 2 2×π3π ( +2×π×πππππππ (ln(π)) ππΆπ ×π1π 2×π3π /(ππΆπ 2 ×π1π ) π×π = 2×π×π . πππΆπ ( 2×π3π +2×π×πππππππ (ln(π)) ππΆπ ×π1π (9g) 2 After substitution of Eqs. 11(a-g) into Eq. 6, the error for the film conductivity was found to be ~27%, 17% and 27% respectively for the 110nm and 458nm as-deposited samples and the 80nm annealed sample. The smaller error in film thermal conductivity vs. substrate thermal conductivity is because the film temperature rise is larger than the substrate temperature rise. Furthermore, the effect of the change in heater physical properties was investigated. It was found that an order of magnitude change in heater density or heater heat capacity does not affect the results significantly (the change in the film conductivity and substrate conductivity was by ~3% and ~4% respectively) References: 1 D. G. Cahill, H. E. Fischer, T. Klitsner, E. T. Swartz, and R. O. Pohl, J. Vac. Sci. Technol. A 7, 1259 (1989). 2 T. Borca-Tasciuc, A. R. Kumar, and G. Chen, Rev. Sci. Instrum. 72, 2139 (2001). 3 D. A. Kaminski, M. K. Jensen, Introduction to Thermal and Fluids Engineering, John Wiley & Sons, New York (2005). 4 P. B. Kaul, K. A. Day, and A. R. Abramson, J. Appl. Phys. 101, 083507 (2007). 8