Sheet (6) - Engineering Sciences

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Faculty of engineering sciences
communication and electronics department
communication theory (1)
Sheet (6)
1. The figure bellow (Fig.1)shows a scheme for coherent demodulation. Show that
this scheme can demodulate the AM signal [A+ m(t)] cos 𝑀𝑐 t regardless of the
value of A
Fig.1
2. Sketch the AM signal [𝐴 + π‘š(𝑑)]π‘π‘œπ‘ π‘€π‘ 𝑑 for the periodic triangle signal π‘š(𝑑)
shown in the Fig.2 corresponding to the modulation index: (a)πœ‡ = 0.5; (b) πœ‡ = 1;
(c) πœ‡ = 2; (d) πœ‡ = ∞. How do you interpret the case πœ‡ = ∞?
Fig.2
3. For the AM signal in prob 2 with πœ‡ = 0.8:
(a) Find the amplitude and power of the carrier.
(b) Find the sideband power and the power efficiency πœ‚.
4.
(a) Sketch the DSB_SC signal corresponding to π‘š(𝑑) = π‘π‘œπ‘ 2πœ‹π‘‘.
(b)This DSB_SC signal π‘š(𝑑) cos 𝑀𝑐 𝑑 is applied at the input of an envelop
detector. Show that output of the envelop detector is not π‘š(𝑑), but |π‘š(𝑑)|. Show
that ,in general, if an AM signal [𝐴 + π‘š(𝑑)]π‘π‘œπ‘ π‘€π‘ 𝑑 is envelop-detected, the
output is |𝐴 + π‘š(𝑑)|. Hence ,show that the condition for recovering π‘š(𝑑)from
the envelop detector is 𝐴 + π‘š(𝑑) > 0 for all t.
Faculty of engineering sciences
communication and electronics department
communication theory (1)
5. Show that any scheme that can be used to generate DSB-SC can also generate
AM . Is the converse true? Explain.
6. Show that any scheme that can be used to demodulate DSB_SC can also
demodulate AM. Is the converse true? Explain.
7. In thee textbook, mentioned in the syllabus, the power efficiency of AM for a
sinusoidal m(t) was derived. Carry out a similar analysis when m(t) is a random
binary signal as shown in the figure(Fig.3) and πœ‡ = 1. Sketch the AM signal with
πœ‡ = 1, find the sideband’s power and the total power (power of the AM signal)
as well as their ratio (the power efficiency πœ‚.
Fig.3
8. A modulated signal π‘š(𝑑) is given by:
(a) π‘š(𝑑) = π‘π‘œπ‘ 100𝑑.
(b) π‘š(𝑑) = π‘π‘œπ‘ 100𝑑 + 2π‘π‘œπ‘ 300𝑑.
(c) π‘š(𝑑) = π‘π‘œπ‘ 100𝑑 π‘π‘œπ‘ 500𝑑.
Determine πœ™πΏπ‘†π΅ (𝑑) and πœ™π‘ˆπ‘†π΅ (𝑑) if the carrier frequency 𝑀𝑐 = 1000. Hint: if
π‘š(𝑑) is sinusoidal , its Hilbert transform π‘šβ„Ž (𝑑) is the sinusoidal π‘š(𝑑) phase
πœ‹
delayed by 2 π‘Ÿπ‘Žπ‘‘.
9. Find πœ™πΏπ‘†π΅ (𝑑) and πœ™π‘ˆπ‘†π΅ (𝑑) for the modulated signal π‘š(𝑑) = 𝑠𝑖𝑛𝑐 (2πœ‹π΅π‘‘) with
𝐡 = 1000 and carrier frequency 𝑀𝑐 = 10,000πœ‹ follow these do it yourself steps:
(a) Sketch spectra of m(t) and the corresponding DSB_SC signal 2π‘š(𝑑)π‘π‘œπ‘ π‘€π‘ 𝑑.
(b) To find the LSB spectrum , suppress the USB. in the DSB_SC spectrum
found in (a).
(c) Find the LSB signal πœ™πΏπ‘†π΅ (𝑑), which is the inverse Fourier transform of the
LSB spectrum found in part (b). follow a similar procedure to find πœ™π‘ˆπ‘†π΅ (𝑑).
10. An USB signal is generated by using the phase-shift method .if the input is
π‘šβ„Ž (𝑑) instead of π‘š(𝑑), what will be the output? Is this signal still an SSB signal
with equal to that of π‘š(𝑑)? Can this signal be demodulated [to get back π‘š(𝑑)]? If
so, how?
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