8a Multiplying Integers
Part 2
When we multiply integers, we can use a graphic organizer to help us Study the Problem,
and figure out what is this problem asking me to find.
The sign of the first number tells us whether we’re going to gain or lose some number of
groups of positive or negative items. Using the graphic organizer in our first example:
Positive 3 times Positive 2. We can do the S step of the SOLVE process to figure out
what is this question asking me to find. Because the sign of the first number is positive,
we will gain 3 groups of positive 2 items.
Because in multiplication we begin with a value of zero, we can look back at our S
statement and follow the instructions.
Our S statement says Gain 3 groups of positive 2 items. Here’s one group of positive 2,
two groups of positive 2, three groups of positive 2.
Because they’re the same color, I can push together and say that positive 3 times positive
2 is 1,2,3,4,5,6 yellow chips or positive 6.
In our second example we have positive three times negative two.
Using the graphic organizer, we can S this problem to find out what this problem is
asking me to find.
Because the sign of this first number is positive, we’re going to gain 3 groups of negative
2 items.
Because in multiplication we begin with a value of zero, we can look back at our S
statement and follow the instructions.
Our S statement says to gain 3 groups of negative 2 items.
Here’s one group of negative 2, 2 groups of negative two, 3 groups of negative 2.
I can push them together because they’re all one color and count.
Positive 3 times negative 2 is 1, 2, 3, 4, 5, 6 red chips or negative 6.
8b Multiplying Integers
Part 2
Our next example is negative 3 times positive 2. We’ll use the graphic organizer to S our
problem and find out what is this problem asking us to find.
Because our first number is negative, we will lose 3 groups of positive 2 items.
Because in multiplication we begin with a value of zero, we simply look to our S
statement and follow the instructions.
Our S statement says lose 3 groups of positive two items.
I can not lose what I don’t have so I must create the possibility with zero pairs.
This is one group of 2 zero pairs. So right now I am able to lose one group of positive 2
items, but I need 3 groups.
I’ve created the possibility to lose two groups of positive 2 items but my S statement says
I need to lose 3 groups of positive items.
Now I am able to lose 3 groups of positive 2 items.
Now that my answer is all in one color I can push together and count.
Negative 3 times positive 2 is 1, 2, 3, 4, 5, 6 red chips or negative 6.
The next example, we have negative 3 times negative 2.
We’ll use this graphic organizer to S this problem and figure out what is this problem
asking me to find.
Because the sign of the first number is negative, we will lose 3 groups of negative 2
items.
Because in multiplication we begin with a value of zero, we simply look to our S
statement and follow the instructions.
Our S statement says lose 3 groups of negative 2 items.
Because I can not lose what I do not have I must create the possibility with zero pairs.
I will need 3 groups of 2 zero pairs.
Now I can lose 3 groups of negative items.
1 group, 2 groups, 3 groups.
Because my chips are all one color I can push together and count.
Negative 3 times negative 2 is 1, 2, 3, 4, 5, 6 yellow chips or positive 6.