Periodic Relationships Among the Elements Chapter 8 Chapter 8 Topics Periodic Relationships •History of periodic table and periodic trends •Periodic Classification of element •Periodic trend of Physical properties (Atomic size, Ionization energy, Electron Affinity, and Electronegativity ) Ions electron configuration •Ions Sizes (isoelectronic ions) •Group elements and its oxides Dr. Ali Bumajdad History of periodic table and periodic trends •Lother Meyer (German, 1830-1895) and Ivanonich Mendeleev (Russian, 1834-1907) put the form of periodic table • Mendeleev given most credit because he predict the existence and properties of unknown elements and he corrected several values for atomic masses Atomic mass Not atomic number Mendeleev’s periodic Table Corrected (they thought its atomic mass is 76) When the Elements Were Discovered The current periodic table is different than Mendeleev by: 1) Element order by atomic number not by atomic mass 2) Contain many more elements discovered after Mendeleev. Classification of the Elements •Atomic radius •Ionization energy •Electron affinity •Electronegativity •Atomic radius •Ionization energy •Electron affinity •Electronegativity -Electron is added on different principle quantum number Effective nuclear +ve charge not much change due to the shielding effect Size increase -Electron is added on same principle quantum number Effective nuclear +ve charge increase due to no shielding effect Size decrease •Effective nuclear charge (Zeff): the “positive charge” felt by an electron (1) Atomic size (2) Ionization energy (3) Electron affinity •Atomic radius is half the •Energy required to remove e •Energy released or absorbed distance between two from an isolated gaseous atom, when an electron is added to neighboring atoms in their ion or molecules (kJ/mol) an isolated gaseous atom, solid state ion (kJ/mol) Na(g) + E Na+ + 1e Cl(g) + 1e Cl- + E •As you go down a group Release =exothermic the atom size increase • Endothermic process (+ve E) (Zeff is approx. constant because e is attracted to nucleus Cl-(g) + 1e + E Cl2or even decrease and e • As size increase it is easier to Absorbed = endothermic placed in a new energy remove e level) (1) Atomic size •As you go left to right across a period atom get (2) Ionization energy (3) Electron affinity • All element (except H) have • All element have more than more than 1 ionization energy 1 Electron Afffinity smaller (Zeff increase and e placed in the same energy •1st Eionization < 2ed Eionization <… • 1st Eaffinity usually exothermic Level. because e placed into (removing e from neutral atom •For transition elements and is easier than from +ve ion) environment where it experience attraction to nucleu inner transition elements, the last e,s are added onto an inner shell (3d) not the valence shell. This cause the Zeff to increase but not much (there is a slight shielding effect) atomic size decrease but slowly. Q) Why the 2nd Eionization for • 2st E affinity endothermic alkali metal is much more because the second e added than the first one? to a negatively charge ion It has a noble gas electron configuration (1) Atomic size Q) Why Zr have similar size as Hf? (2) Ionization energy (3) Electron affinity Q) Why the 3ed Eionization for • Some Irregularities a cross earth alkali metal is the a period highest change? A raw of Lanthanide elements It has a noble gas electron configuration •For ions: 1 P Eaffinity < As affinity O Eaffinity < S Eaffinity +ve ion < -ve ion Why? •Because e are crowding in shell 2 more than in shell 3 more repulsion in shell2 less energy evolve less Eaffinity 2 C has -ve Eaffinity while N has +ve Eaffinity (1) Atomic size (2) Ionization energy (3) Electron affinity • Some Irregularities a cross a •Because the e in c inter a vacant 2p orbital while for N e period must be placed in an already Be Eionization > B Eionization occupied orbital N Eionization > O Eionization P Eionization > S Eionization Why? •For Be and B, it is easier to remove e from 2p1 than from 2s2 because it is further apart from nucleus •For N and O, it is easier to remove e when there is e-e repulsion in an orbital Effective Nuclear Charge (Zeff) increasing Zeff increasing Zeff Adding electron to the same principal quantum number Adding electron on different principal quantum number Sa Ex. : Eionization of P = 1060kJ/mol and for S = 1005 kJ/mol, explain this irregularity. The valence electron configuration for S contains one filled orbital and hence there is e-e repulsion and hence easier to be removed Sa Ex. : Among the following elements (Ne, Na, Mg) (a) Which atom has the largest 1st ionization (b) Which atom has the smallest 2nd ionization energy (a) Ne (b) Mg (the first and second e’s are valence electrons) Be2+ < Mg2+ < Ca2+ < Sr2+ The Alkali Metals Li Cs •More reactive (why) Easier to loss electron (less effective nuclear charge) • In aqueous system less reducing ability (why) Difficult to be solubilized in water due to its large size (less effective nuclear charge), less polar Ions electron configuration •When two nonmetals react they share electrons, so that the valence electron configuration completes for both atoms •When nonmetal react with metal, the ions form so that the valence electron configuration of the nonmetal achieves the electron configuration of the next noble gas atom and the valence orbital of the metal are emptied Na [Ne]3s1 Na+ [Ne] Ca [Ar]4s2 Ca2+ [Ar] Al [Ne]3s23p1 Al3+ [Ne] Atoms gain electrons so that anion has a noble-gas outer electron configuration. Atoms lose electrons so that cation has a noble-gas outer electron configuration. H 1s1 H- 1s2 or [He] F 1s22s22p5 F- 1s22s22p6 or [Ne] O 1s22s22p4 O2- 1s22s22p6 or [Ne] N 1s22s22p3 N3- 1s22s22p6 or [Ne] -1 -2 -3 +3 +2 +1 Cations and Anions Of Representative Elements Electron Configurations of Cations of Transition Metals When a cation is formed from an atom of a transition metal, electrons are always removed first from the ns orbital and then from the (n – 1)d orbitals. Fe: [Ar]4s23d6 Fe2+: [Ar]4s03d6 or [Ar]3d6 Fe3+: [Ar]4s03d5 or [Ar]3d5 Mn: [Ar]4s23d5 Mn2+: [Ar]4s03d5 or [Ar]3d5 Ions Sizes (isoelectronic ions) •Isoelectronic ions: ions contain the same number of electrons Na+: [Ne] Al3+: [Ne] O2-: 1s22s22p6 or [Ne] F-: 1s22s22p6 or [Ne] N3-: 1s22s22p6 or [Ne] Na+, Al3+, F-, O2-, and N3- are all isoelectronic with Ne No. proton 11 13 9 8 7 10 The ion with less protons is bigger N3- > O2- > F- > Ne > Na+ > Al3+ Dr. Ali Bumajdad Q) What neutral atom is isoelectronic with H- ? H-: 1s2 same electron configuration as He Sa. Ex. : Arrange the ions in order of decreasing size ? Se2-, Br-, Rb+, Sr2+ Se2- > Br- > Rb+ > Sr2+ Sa. Ex. : Choose the largest ion in each of the following Groups: a) Li+, Na+, K+, Rb+, Cs+ b) Ba2+, Cs+, I-, Te2- Cation is always smaller than atom from which it is formed. Anion is always larger than atom from which it is formed. Dr. Ali Bumajdad The Radii (in pm) of Ions of Familiar Elements Sa Ex. : Predict the trend in radius for : Be2+ ,Mg2+ ,Ca2+ ,Sr2+ Group 1A Elements (ns1, n 2) Group 2A Elements (ns2, n 2) Group 3A Elements (ns2np1, n 2) Group 4A Elements (ns2np2, n 2) Group 5A Elements (ns2np3, n 2) Group 6A Elements (ns2np4, n 2) Group 7A Elements (ns2np5, n 2) Group 8A Elements (ns2np6, n 2) Completely filled ns and np subshells. Highest ionization energy of all elements. No tendency to accept extra electrons. 8.6 Properties of Oxides Across a Period basic acidic