1 Introduction •Material transport by atomic motion •Diffusion couple: eg., Cu-Ni in close contact; hold at elevated temperature for extended period and cool to room temperature. Chapter 5: Diffusion 2 Introduction continue… Before After •Interdiffusion or impurity diffusion •Self diffusion: same type of atoms; no composition change Chapter 5: Diffusion 3 Diffusion mechanisms Vacancy diffusion Interstitial diffusion 1.Vacancy Diffusion Atom from normal lattice position changes position with an adjacent vacancy (vacancy lattice site). So, the atoms and vacancies travel in opposite directions. Both selfdiffusion and inter (impurity)-diffusion can occur thus Chapter 5: Diffusion 4 Diffusion mechanisms continue … Source: William Callister 7th edition, chapter 5, page 112, figure 5.3(a) Chapter 5: Diffusion 5 Diffusion mechanisms continue … 2) Interstitial Diffusion Atoms move from one interstitial site to another (vacant) interstitial site . Source: William Callister 7th edition, chapter 5, page 112, figure 5.3(b) Chapter 5: Diffusion 6 Steady state Diffusion J=M/At If J is constant, steady-state diffusion exists. Where, J= rate of mass transfer with time, kg/m2-sec or atoms/m2sec A= Area across which diffusion is occurring t= elapsed time, sec Chapter 5: Diffusion 7 Steady state Diffusion continue…. Steady-state diffusion Concentration profile Source: William Callister 7th edition, chapter 5, page 113, figure 5.4 Chapter 5: Diffusion 8 Steady state Diffusion continue…. C: Concentration of diffusing species, kg/m3 or gm/cm3 x: Position Hydrogen gas across palladium plate Concentration Gradient: Slope at a particular point on the curve =dC/dx ΔC/ΔX CA C B XA X B Chapter 5: Diffusion 9 Steady state Diffusion continue…. Fick’s first law of diffusion J D d c dx D = Diffusion coefficient, m2/sec dc/dx = Concentration gradient is the main driving force for diffusion (-) = Concentration gradient decrease Chapter 5: Diffusion 10 Steady state Diffusion continue…. =- Problem Carbon diffusing through a plate of iron Carbon rich Carbon deficient 5mm 10mm Concentration: 1.2 kg/m3 0.8 kg/m3 Chapter 5: Diffusion 11 - = Steady state Diffusion continue…. Problem continue Diffusion coefficient: 3 x 10-11 m2/sec CA CB J D XA X B 11 (3 10 (1.2 0.8) m /sec) (5 103 ) - (10 103 ) 2 = 2.4 x 10-9 kg/m2-sec Chapter 5: Diffusion 12 Non-steady state Diffusion •Diffusion flux and concentration gradient vary with time; net accumulation or depletion of diffusing species results ………… Fick’ second law ……… Modified Fick’s second law Chapter 5: Diffusion 13 Semi-Infinite solid Surface concentration at the other end is constant. eg, Bar of length, l > 10Dt , i.e., none of the diffusing atoms reach the bar end during the time-period of diffusion Assumptions: 1. Co = Concentration before diffusion 2. x = Distance; at surface it is 0. It increases into the solid 3. t = Time; zero(0) at the instant diffusion starts Chapter 5: Diffusion 14 Semi-Infinite solid continue…. We have, for t=0, C=Co at 0≤x≤ For t>0, C=CS (Constant surface concentration) at x = 0 Also, C= CO at x= Error function Chapter 5: Diffusion This equation shows relationship between concentration, position and time 15 Semi-Infinite solid continue…. erf Where, CX=Concentration at depth x after time t. erf =erf2 •Concentration at distance x, CX is a function of •If time (t) and position (x) are known and CO, CS and D are given, CX can be determined Chapter 5: Diffusion 16 Semi-Infinite solid continue…. If CX=C1 at a specific concentration of solute, =constant Therefore =constant =constant Chapter 5: Diffusion 17 Semi-Infinite solid continue…. Surface concentration Concentration C at distance x Concentration before diffusion Chapter 5: Diffusion 18 Problem Carburization of steel using methane (CH4) at 950°C (1750°F) Steel: 0.25 wt% Carbon. Using CH4, carbon at surface is suddenly brought to and maintained at 1.2 wt% carbon. How long will it take to achieve a carbon content of 0.80% carbon at a position 0.5 mm below the surface? Chapter 5: Diffusion 19 Problem continue… D= 1.6 x 10-11 m2/sec Chapter 5: Diffusion 20 Problem continue… Chapter 5: Diffusion 21 Problem The diffusion coefficients for copper in aluminum at 500 and 600 C are 4.8x10-14 and 5.3x10-13 m2/s, respectively. Determine the approximate time at 500 C that will produce the same diffusion result (in terms of concentration of Cu at some specific point in Al) as a 10-h heat treatment at 600°C. To produce the same effect at 500°C, how long will it take? Chapter 5: Diffusion 22 Problem continue… Dt= constant Chapter 5: Diffusion 23 Factors in diffusion •Temperature •Time D increases 5 orders of magnitude with temperature Chapter 5: Diffusion 24 Factors in diffusion continue… Q D Do exp( d ) RT Do = temperature independent pre-exponential (m2/sec) Qd = the activation energy for diffusion (J/mol,cal/mol and ev/atom) R = gas constant, 8.31 J/mol-K or 8.62 eV/atom-K T = absolute temperature (K) Chapter 5: Diffusion 25 Factors in diffusion continue… Chapter 5: Diffusion 26 Summary •Self Diffusion •Inter-Diffusion •Steady state J=M/At Fick’s First law •Non-steady state Fick’s second law •Temperature effect •Activation energy Chapter 5: Diffusion 27