SAVE PAPER AND INK!!! When you print out the notes on PowerPoint, print "Handouts" instead of "Slides" in the print setup. Also, get rid of background shading by selecting “Pure Black & White” instead of “Grayscale.” Unit 1 The Atom, Atomic Theory & the Nucleus Chapters 3 & 21 Atoms: The Building Blocks of Matter CHAPTER 3 Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory The Particle Theory of Matter • In 400 B.C. Democritus, a Greek philosopher, first proposed the idea of a basic particle of matter that could not be divided any further. • He called this particle the atom, based on the Greek word atomos meaning indivisible. • This early theory was not backed up by experimental evidence and was ignored by the scientific community for nearly 2000 years. Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory Foundations of Atomic Theory • By the late 1700s, experiments with chemical reactions led to the discovery of 3 basic laws: 1. The Law of Conservation of Mass – Mass is neither created nor destroyed during ordinary chemical reactions or physical changes. Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory Foundations of Atomic Theory The Law of Conservation of Mass Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory Foundations of Atomic Theory 2. The Law of Definite Proportions – A chemical compound contains the same elements in exactly the same proportions by mass regardless of the size of the sample or source of the compound. Visual Concept Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory Foundations of Atomic Theory 3. The Law of Multiple Proportions – If different compounds are composed of the same two elements, then the ratio of the masses of the elements is always a ratio of small whole numbers. Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory Dalton’s Atomic Theory • In 1808, John Dalton proposed an explanation for the three laws. His atomic theory states: 1. All matter is composed of atoms. 2. Atoms of the same element are identical; atoms of different elements are different. 3. Atoms cannot be subdivided, created, or destroyed. 4. Atoms of different elements combine in simple wholenumber ratios to form chemical compounds. 5. In chemical reactions, atoms are combined, separated, or rearranged. Chapter 3 – Section 1: The Atom: From Philosophical Idea to Scientific Theory Corrections to Dalton’s Theory • Dalton turned Democritus’s idea into a scientific theory that could be tested by experiment. • But not all aspects of Dalton’s theory have proven to be correct. We now know that: – Atoms are divisible into even smaller particles. – A given element can have atoms with different masses. Chapter 3 – Section 2: The Structure of the Atom Dalton’s Atomic Model • An atom is the smallest particle of an element that has all the properties of that element. • Atoms are too small to see…even through the most powerful microscope!! • Dalton thought atoms were solid balls of matter and were indivisible. Chapter 3 – Section 2: The Structure of the Atom Discovery of the Electron • In 1897, Joseph John (JJ) Thomson showed that cathode rays are composed of identical negatively charged particles, which were named electrons. • The electron was the first subatomic particle to be discovered. Chapter 3 – Section 2: The Structure of the Atom Thomson’s Cathode Ray Tube Experiment Visual Concept Chapter 3 – Section 2: The Structure of the Atom Charge and Mass of the Electron • In 1909, Robert Millikan measured the charge on the electron during his oil drop experiment. • Using the charge-to-mass ratio, scientists were able to figure out the mass of the electron: about 1/2000 the mass of a hydrogen atom. Chapter 3 – Section 2: The Structure of the Atom Millikan’s Oil Drop Experiment Visual Concept Chapter 3 – Section 2: The Structure of the Atom Thomson’s Plum Pudding Model • After the work of Thomson and Millikan, the accepted model of the atom was called the plum pudding model. • The atom was viewed as a ball of positivelycharged material with tiny negatively-charged electrons spread evenly throughout. Chapter 3 – Section 2: The Structure of the Atom Discovery of the Atomic Nucleus • More detail of the atom’s structure was provided in 1911 by Ernest Rutherford and his associates Hans Geiger and Ernest Marsden. •The results of their gold foil experiment led to the discovery of a very densely packed bundle of matter with a positive electric charge. •Rutherford called this positive bundle of matter the nucleus. Chapter 3 – Section 2: The Structure of the Atom The Gold Foil Experiment Visual Concept Chapter 3 – Section 2: The Structure of the Atom Rutherford’s Atomic Model • After Rutherford’s gold foil experiment, the accepted model of the atom looked like this: • A small, positively-charged nucleus with negative electrons surrounding it at some distance away. Most of the atom is empty space. Chapter 3 – Section 2: The Structure of the Atom Subatomic Particles • The nucleus is made up of at least one positively charged particle called a proton and usually one or more neutral particles called neutrons. • Protons, neutrons, and electrons are often referred to as subatomic particles. Chapter 3 – Section 3: Counting Atoms Atomic Number • The atomic number (Z) of an element is the number of protons of each atom of that element. • Atoms of the same element all have the same number of protons. Chapter 3 – Section 3: Counting Atoms Mass Number • The mass number is the total number of protons and neutrons in the nucleus of an atom. • Atoms of the same element can have different mass numbers. Chapter 3 – Section 3: Counting Atoms Isotopes •Isotopes are atoms of the same element that have different masses. •Isotopes have the same number of protons and electrons but different numbers of neutrons. •Most of the elements consist of mixtures of isotopes. Chapter 3 – Section 3: Counting Atoms Designating Isotopes •Hyphen notation: The mass number is written with a hyphen after the name of the element. uranium-235 •Nuclear symbol: The superscript indicates the mass number and the subscript indicates the atomic number. Mass number Atomic number 235 92 U Chapter 3 – Section 3: Counting Atoms Calculating Neutrons • The number of neutrons is found by subtracting the atomic number from the mass number. mass number − atomic number = number of neutrons • Nuclide is a general term for a specific isotope of an element. Chapter 3 – Section 3: Counting Atoms Calculating Subatomic Particles Sample Problem How many protons, electrons, and neutrons are there in an atom of chlorine-37? Solution: Number of protons = atomic number (on periodic table) 17 Number of electrons = number of protons 17 Number of neutrons = mass number - protons 20 Significant Figures • the non-place-holding digits in a reported measurement are called significant figures. • All non-zero numbers are significant, but some zeros in a written number are only there to help you locate the decimal point. • How do you remember which zeros are significant and which are not? Significant Figures • The Atlantic – Pacific Rule: Pacific (Present): If decimal point is present, start with the first nonzero number on the left. Atlantic (Absent): If decimal point is absent, start with the first non-zero number on the right. Significant Figures • Examples: How many significant figures? 99,000 2 sig figs 99,000. 0.0099 5 sig figs 2 sig figs 0.0990 3 sig figs Calculating with Significant Figures • When you use your measurements in calculations, your answer may only be as exact as your least exact measurement. • For addition and subtraction, round to the fewest decimal places. Example: (3 decimals) (1 decimal) (unrounded) (rounded) 50.259 + 17.4 = 67.659 67.7 • For multiplication and division, round to the fewest significant figures. Example: (3 sigfigs) (1 sigfig) (unrounded) (rounded) 0.135 x 20 = 2.7 3 Chapter 3 – Section 3: Counting Atoms The Atomic Mass Unit • The standard used by scientists to compare units of atomic mass is the carbon-12 atom. •One atomic mass unit, or 1 amu, is exactly 1/12 the mass of a carbon-12 atom. •The atomic mass of any atom is determined by comparing it with the mass of the carbon-12 atom. Chapter 3 – Section 3: Counting Atoms Average Atomic Mass •Average atomic mass is the weighted average of the atomic masses of the naturally occurring isotopes of an element. •The average atomic mass of an element depends on both the mass and the relative abundance of each of the element’s isotopes. Percent • To convert a decimal to a percent, multiply by 100 (move the decimal point 2 places to the right.) .205 .090 20.5% 9.0% • To convert a percent to a decimal, divide by 100 (move the decimal point 2 places to the left.) 65% .03% 0.65 .0003 Multiplying by a Percent • First, convert the percent to a decimal, then multiply. Example: How many grams of carbon are in a 50.0 gram sample of a substance that is 17.5% carbon? 17.5% 0.175 50.0 g x 0.175 = 8.75 g Chapter 3 – Section 3: Counting Atoms Calculating a Weighted Average If you have the following grades, what would your marking period average be? Category Percent of Grade Grade Tests 45 ÷ 100 = 0.45 x 72 = 32.4 Quizzes 10 ÷ 100 = 0.10 x 78 = 7.8 Labs 25 ÷ 100 = 0.25 x 84 = 21.0 HW/CW 10 ÷ 100 = 0.10 x 98 = 9.8 Project 10 ÷ 100 = 0.10 x 94 = + 9.4 80.4 • First, change percents to decimals. • Next, multiply each grade by its decimal percent. • Finally, add up all the products. Chapter 3 – Section 3: Counting Atoms Calculating Average Atomic Mass Sample Problem 1 Copper consists of 69.15% copper-63, which has an atomic mass of 62.929 601 amu, and 30.85% copper-65, which has an atomic mass of 64.927 794 amu. What is the Average Atomic Mass of Copper? Solution • Change percents to decimals. • Multiply the atomic mass of each isotope by its relative abundance. • Add up all of the products. Relative Abundance Mass Cu-63 0.6915 x 62.93 = 43.52 Cu-65 0.3085 x 64.93 = 20.03 + 63.55 Chapter 3 – Section 3: Counting Atoms Calculating Average Atomic Mass Sample Problem 2 A student believed that she had discovered a new element and named it mythium. Analysis found it contained two isotopes. The composition of the isotopes was 19.9% of atomic mass 10.013 and 80.1% of atomic mass 11.009. What is the average atomic mass, and do you think mythium was a new element? Solution: Round off to: • Average Atomic Mass: 10.8 (.199 x 10.013) + (.801 x 11.009) = 10.811 • Because the atomic mass is the same as the atomic mass of boron, mythium was not a new element. Scientific Notation • A shorthand system of writing very large or very small numbers. • The power of 10 (called the exponent), is the number of times the decimal point is moved. • The number in front of the times sign(called the coefficient) must be greater than 1 and less than 10. Scientific Notation • Examples: What would each of these numbers be in scientific notation? 3000 3 x 103 32,000 0.05 3.2 x 104 5 x 10-2 0.0058 5.8 x 10-3 Multiplying in Scientific Notation • First, multiply the coefficients. • Then, add the exponents together. • Rewrite your answer in correct scientific notation (coefficient less than 10), and remember to round to the correct number of significant figures. Example: 5.5 x 103 x 3.7 x 104 = 20.35x 107 = 2.0 x 108 Dividing in Scientific Notation • First, divide the coefficients. • Then, subtract the exponents. • Rewrite your answer in correct scientific notation (coefficient less than 10), and remember to round to the correct number of significant figures. Example: 1.8 x 10-2 ÷ 3.2 x 10-6 = 0.5625 x 104 = 5.6 x 103 Chapter 3 – Section 3: Counting Atoms The Mole • A mole (mol) is the amount of a substance that contains as many particles as there are atoms in exactly 12 g of carbon-12. • It is a counting unit, similar to a dozen. In a dozen, there are 12 things. In a mole, there are 6.02 x 1023 things. Visual Concept Chapter 3 – Section 3: Counting Atoms Avogadro’s Number • Avogadro’s number: 6.022 1415 × 1023— the number of particles in exactly one mole of a pure substance. • Named for nineteenth-century Italian scientist Amedeo Avogadro. Visual Concept Chapter 3 – Section 3: Counting Atoms Molar Mass • Molar Mass is the mass of one mole of a pure substance. • Molar mass units are g/mol. • The molar mass of an element is the same number as its atomic mass, only the units are different. Try some - What is the molar mass of: • Magnesium? 24.3 g/mol • Carbon? 12.0 g/mol Chapter 3 – Section 3: Counting Atoms Gram/Mole Conversions • Chemists use molar mass as a conversion factor in chemical calculations. • Remember, molar mass means grams per mole. Example: • What is the mass of 2.5 moles of Helium gas? This is what we’re given: Use molar mass as a conversion factor 2.5 mol He x 4.0 g He = 10. g He 1 mol He Chapter 3 – Section 3: Counting Atoms Gram/Mole Conversions Sample Problem 1 What is the mass in grams of 3.50 mol of the element copper, Cu? Solution: Given Conversion factor 3.5 mol Cu x 63.5 g Cu = 220 g Cu 1 mol Cu Chapter 3 – Section 3: Counting Atoms Gram/Mole Conversions Sample Problem 2 A chemist produced 11.9 g of aluminum, Al. How many moles of aluminum were produced? Solution: Given 11.9 g Al Conversion factor x 1 mol Al = 0.441 mol Al 27.0 g Al Chapter 3 – Section 3: Counting Atoms Conversions with Avogadro’s Number • Avogadro’s number can be used as a conversion factor between atoms and moles. • Avogadro’s number units are atoms per mole. Example: •How many moles of silver, Ag, are in 3.01 1023 atoms of silver? Given 3.01 x 1023 atoms Ag x Conversion factor 1 mol Ag = 0.500 mol Ag 6.02 x 1023 atoms Ag Chapter 3 – Section 3: Counting Atoms Conversions with Avogadro’s Number Sample Problem 1 What is the mass in grams of 1.20 108 atoms of copper, Cu? nd 2 Solution: st Given 1.20 x 108 atoms Cu x 1 Conversion factor Conversion factor 1 mol Cu x 63.5 g Cu 6.02 x 1023atoms Cu 1 mol Cu = 1.27 x 10-14 g Cu Nuclear Chemistry CHAPTER 21 Chapter 3 – Section 2: The Structure of the Atom Forces in the Atom • Electrons and protons attract because of opposite electrical charges, but protons and protons repel since they have the same charge. • The nucleus is held together by a mysterious force called the strong nuclear force which only exists between nucleons (protons and neutrons) which are very close together. Chapter 21 – Section 2: Radioactive Decay Naturally Radioactive Elements • All of the elements beyond atomic number 83 are unstable and thus radioactive. Chapter 21 – Section 1: The Nucleus Nuclear Reactions • Large, unstable nuclei spontaneously break apart to form smaller, more stable nuclei. • A nuclear reaction is a reaction that affects the nucleus of an atom. Example: 92238 U 42 He 90234 Th • A transmutation is a change in the identity of a nucleus as a result of a change in the number of its protons. Chapter 21 – Section 1: The Nucleus Nuclear Reactions Sample Problem Identify the products that balance the following nuclear reactions: 212 4 Po a. 84 2 He ____ b. 1122 Na ____ 1022 Ne Solution: 208 a. Atomic Mass: 212 = 4 + _____ 82 Atomic Number: 84 = 2 + _____ 0 = 22 b. Atomic Mass: 22 + ____ -1 = 10 Atomic Number: 11 + ____ 208 82 Pb 0 1 e Chapter 21 – Section 2: Radioactive Decay Radioactive Decay • Radioactive decay is the spontaneous disintegration of a nucleus into a lighter nucleus, accompanied by nuclear radiation. • Nuclear radiation is particles and/or electromagnetic radiation emitted from the nucleus during radioactive decay. Chapter 21 – Section 2: Radioactive Decay Types of Radioactive Decay Alpha Emission • An alpha particle (α) is two protons and two neutrons bound together and is emitted from the nucleus during some kinds of radioactive decay. 4 • 2 He • The atomic number decreases by two and the mass number decreases by 4. Chapter 21 – Section 2: Radioactive Decay Types of Radioactive Decay (continued) Beta Emission • A beta particle (β) is an electron emitted from the nucleus during some kinds of radioactive decay (a neutron can be converted into a proton and an electron.) • 01 β • The atomic number increases by one and the mass number stays the same. Chapter 21 – Section 2: Radioactive Decay Types of Radioactive Decay (continued) Positron Emission • A positron (β+) is a particle that has the same mass as an electron, but has a positive charge (to decrease the number of protons, a proton can be converted into a neutron by emitting a positron.) 0 • 1 β • The atomic number decreases by one and the mass number stays the same. Chapter 21 – Section 2: Radioactive Decay Types of Radioactive Decay (continued) Electron Capture • In electron capture, an inner orbital electron is captured by the nucleus of its own atom. (An inner orbital electron combines with a proton to form a neutron.) 0 • 1 e • The atomic number decreases by one and the mass number stays the same. Chapter 21 – Section 2: Radioactive Decay Types of Radioactive Decay (continued) Gamma Emission • Gamma rays () are high-energy electromagnetic waves emitted from an unstable nucleus. • Atomic number and mass number both stay the same because gamma rays have no charge and no mass. • They are pure energy, and very dangerous to living things. Chapter 21 – Section 2: Radioactive Decay Comparing Alpha, Beta and Gamma • Alpha particles - big and slow, can’t penetrate skin or paper. • Beta particles - about 100 x the penetrating power of alpha, can be stopped by clothing, wood, or aluminum foil. • Gamma rays - the greatest penetrating ability, only stopped by a thick layer of lead or concrete. They will go right through a person and damage living cells. Visual Concept Chapter 21 – Section 2: Radioactive Decay Half-Life • Half-life is the time required for half the atoms of a radioactive nuclide to decay. • Each radioactive nuclide has its own half-life. • More-stable nuclides decay slowly and have longer half-lives. Chapter 21 – Section 2: Radioactive Decay Half-Life Sample Problem 1 The half-life of radon-222 is 4 days. After what time will ¼ of a given amount of radon remain? Solution: Determine the number of half-lives that it takes to cut a sample to ¼ of the original amount. Then multiply that number by the half-life. 2 x 4 days = 8 days Chapter 21 – Section 2: Radioactive Decay Half-Life Sample Problem 2 Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 57.2 days if you start with 4.0 mg of the isotope? Solution: Determine the number of half-lives in 57.2 days. 57.2 days ÷ 14.3 days = 4 half-lives For each half-life, multiply the original amount by ½: 4.0 mg x ½ x ½ x ½ x ½ = 0.25 mg Chapter 21 – Section 3: Nuclear Radiation Whole-Body Radiation Exposure • Rem – The unit used to measure the biological effects of absorbed radiation in humans. Chapter 21 – Section 3: Nuclear Radiation Radiation Detection • Film badges - use exposure of film to measure the approximate exposure of people working with radiation. • Geiger-Müller counters - instruments that detect radiation by counting electric pulses carried by gas ionized by radiation. • Scintillation counters - instruments that convert scintillating light to an electric signal for detecting radiation. Chapter 21 – Section 3: Nuclear Radiation Uses of Radiation • Radioactive dating – scientists can determine the approximate age of an object based on the amount of certain radioactive nuclides present. Chapter 21 – Section 3: Nuclear Radiation Uses of Radiation (continued) •Radioactive tracers are radioactive atoms that are incorporated into substances so that movement of the substances can be followed by radiation detectors. –Radioactive tracers can be used by doctors to diagnose diseases. –Radioactive tracers are also used in agriculture to determine the effectiveness of fertilizers. Chapter 21 – Section 3: Nuclear Radiation Uses of Radiation (continued) •Irradiated Food – nuclear radiation is used to prolong the shelf life of food. Chapter 21 – Section 3: Nuclear Radiation Uses of Radiation (continued) • Nuclear Power Plants – use energy as heat from nuclear reactors to produce electrical energy. They have five main components: 1. Shielding – radiation-absorbing material used to decrease exposure to radiation from nuclear reactors. 2. Fuel – usually Uranium-235. 3. Coolant – usually water, it absorbs excess heat energy. 4. Control rods – neutron-absorbing rods that limit the number of free neutrons 5. Moderator – used to slow down the fast neutrons produced by fission. Chapter 21 – Section 3: Nuclear Radiation Nuclear Power Plant Chapter 21 – Section 3: Nuclear Radiation Fission vs. Fusion • Nuclear Fission – very heavy nuclei split into smaller, more stable nuclei. –Can occur spontaneously or when nuclei are bombarded by particles. –Controlled fission chain reactions are used in nuclear power plants. Uncontrolled fission chain reactions are used in nuclear bombs. Chapter 21 – Section 3: Nuclear Radiation Fission vs. Fusion (continued) • Nuclear Fusion – low-mass nuclei combine to form a heavier, more stable nucleus. –Fusion releases even more energy per gram of fuel than fission. –Scientists are not yet able to control fusion reactions, so we can’t use them in power plants. –Fusion is the primary process that fuels our sun and the stars. Chapter 21 – Section 3: Nuclear Radiation Nuclear Waste • Radioactive waste produced in nuclear reactors can take hundreds of thousands of years to decay. • Disposal of nuclear waste is done with the intention of never retrieving it. • There are 77 disposal sites around the country. A new one (Yucca Mountain) is being developed for the permanent disposal of much of our nuclear waste beginning in 2017. Visual Concept