OXIDATION-REDUCTION REACTIONS 1 DEFINITIONS • Oxidation – loss of electrons, usually done by metals. • Reduction – gain of electrons, usually done by nonmetals. • Oxidizing Agent – gains electrons causing oxidation. • Reducing Agent – loses electrons causing reduction. 2 RULES BEFORE BALANCING • Check Oxidation Numbers. • Oxygen is always -2 except in peroxides where the O- is -1 and as OF2 where O is +2. • All compounds have a zero net charge. • In ternary compounds, add the known oxidation numbers to determine the transition metal’s oxidation number. 3 PAY ATTENTION! 4 BALANCING RULES • Assign oxidation numbers to elements undergoing oxidation and reduction. • Balance electrons. • Follow balancing rules from your chemical reactions’ notes. 5 DISPROPORTIONATION • A chemical reaction in which a single compound serves as both oxidizing and reducing agent and is thereby converted into a more oxidized and a more reduced derivative. • Example: The decomposition of hydrogen peroxide. 2H2O2 2H2O + O2 6 HALF-REACTION METHOD • Write down the unbalanced equation. • Assign oxidation numbers to all of the elements in the equation. • Decide which atoms change in oxidation number from the reactant to the product side. 7 Half-Reactions Continued • Write half-reactions for the oxidation (electron loss) and reduction(electron gain). This is ONLY done for the elements changing in oxidation number from the reactant to the product side of the original equation. 8 Half-Reactions Continued • If an element has a subscript in the unbalanced equation, carry this into the half-reaction. – When the element is free, carry the subscript as a subscript. – When the element is part of a compound or polyatomic ion, carry the subscript as a coefficient. 9 Half-Reactions Continued • Balance the electron gain and loss in the half-reactions (multiply through the equations by the appropriate whole numbers). • Add the oxidation and reduction half-reactions. Since the electron gain and loss should be equal, the electrons won’t appear in the sum of the equations. 10 Half-Reaction Continued •Use the coefficients in the sum of the half-reactions to determine the coefficients of the unbalanced equation. •This procedure will only balance the elements changing in oxidation number. INSPECTION BALANCING will always be the last step. 11 Practice: oxidation numbers in HCO3– _ H O C O O 12 Practice: oxidation numbers in HCO3– 6 – (4 + 4) = –2 4 – (0 + 0) = +4 6 – (4 + 4) = –2 _ 1 – (0 + 0) = +1 H O C O O # valence e– in neutral atom # nonbonding e– # bonding e– assigned oxidation number 6 – (6 + 2) = –2 They add up to charge of ion: (–2) + 4 + (–2) + 1 + (–2) = –1 13 Practice: oxidation numbers in K2Cr2O7 (+1) ( ?) (-2 ) K2Cr2O7 (+2) + 2(+6) + (-14) = 0 14 Balancing Redox Equations • To balance the charge, add electrons to the side of the equation with the higher charge. 15 Balancing Redox Equations • Multiply the half-reactions by appropriate numbers to balance electron gain and loss. 16 Balancing Redox Equations • Add the half-reaction equations, subtracting any duplications on the left and right sides. 17 Half-Reaction in Acidic Solution • Again, write the two half-reactions. • Balance each half-reaction, keeping in mind to do hydrogen and then oxygen as the last two steps, respectively. O’s must be balanced with H2O. H atoms must be balanced with H+ ions. • Balance the number of electrons in each halfreaction. • Add the two half-reactions to form a net balanced ionic equation. • Check to make sure everything is balanced. 18 What if the solution is Basic? • If the reaction occurs in basic solution, the final equation must not contain H+. • If your equation has H+ ions, add an equal number of OH- ions to both sides of the equation. • Combine the H+ and OH- into H2O and cancel any replications of H2O. 19 EXAMPLES 1. Al˚ + CuCl2 → AlCl3 + Cu˚ • Each Al loses 3 e• Each Cu gains 2e- ( 2 X 3 ) = 6 • 2Al˚ + 3CuCl2 → 2AlCl3 + 3Cu˚ 2. FeCl3 + H2S → FeCl2 + S˚ + HCl • Each Fe gains 1 e• Each S loses 2 e- ( 2 X 1 ) = 2 • 2FeCl3 + H2S → 2FeCl2 + S˚ + HCl • Balance non-redox species + 2HCl 20 Gram-Equivalent Weights 21 Gram-Equivalent Weight • Also known as a gram-equivalent or equivalent. • Used to indicate the amount of a chemical used in a reaction. • Can be used instead of moles for redox reactions. 22 Gram-Equivalent • A gram-equivalent weight of a substance is the amount of this substance which releases or acquires one mole of electrons during a redox reaction. 23 Gram-Equivalent • The chief advantage of working with gram- equivalents is that you don’t have to write a balanced equation to solve a stoichiometry problem involving a redox reaction. 24 Gram-Equivalent • A gram-equivalent of oxidizing agent is the amount of the chemical which accepts one mole of electrons during a redox reaction. 25 Gram-Equivalent • A gram-equivalent of reducing agent is the amount of the chemical which releases one mole of electrons during a redox reaction. 26 Gram-Equivalent • In a redox reaction the total electron gain by the oxidizing agent must equal the total electron loss by the reducing agent. 27 Gram-Equivalent • In a redox reaction the number of gram- equivalents of oxidizing agent must equal the number of gram-equivalents of reducing agent. 28 Gram-Equivalent • The change in the oxidation number of an element during a redox reaction is used to determine the number of gram-equivalents of that substance per mole. 29 NORMALITY OF SOLUTIONS (NORMALITY AS APPLIED TO REDOX REACTIONS) 30 NORMALITY • The normality of a solution, like its molarity, indicates the concentration of a solution. 31 NORMALITY Normality is expressed in terms of the number of gram-equivalents of solute per liter of solution. gram - equivalents of solute Normality = liter of solution 32 Normality • The number of gram-equivalents per mole of a solute may change depending on the redox reaction that it undergoes. 33 Normality • During a redox titration involving solutions of oxidizing agent and reducing agent, the gramequivalents of oxidizing agent must equal the gramequivalents of reducing agent. 34 Normality Since, Volume (in liters) x Normality = G-Equiv. VOA x NOA = VRA x NRA Where OA = Oxidizing Agent and RA = Reducing Agent 35