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Combined Gas Law The combined gas law combines Boyle’s Law and Charles’ Law Combined Gas Law Boyle’s Law P1V1 = P2V2 Charles’ Law V1 V2 = T1 T2 Combined Gas Law P1V1 P2V2 = T1 T2 Combined Gas Law For example: If I initially have a gas at a pressure of 12 atm, a volume of 23 L and a temperature of 200 K, then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas? Combined Gas Law Begin by converting to Kelvin. It is not necessary in this problem. Combined Gas Law Next, write down the information you know and want to know. P1 = V1 = T1 = P2 = V2 = T2 = Combined Gas Laws Next, write down the information you know and want to know. P1 = 12 atm V1 = T1 = P2 = V2 = T2 = Combined Gas Law Next, write down the information you know and want to know. P1 = 12 atm V1 = 23 L T1 = P2 = V2 = T2 = Combined Gas Law Next, write down the information you know and want to know. P1 = 12 atm V1 = 23 L T1 = 200K P2 = V2 = T2 = Combined Gas Law Next, write down the information you know and want to know. P1 = 12 atm V1 = 23 L T1 = 200K P2 = 14 atm V2 = T2 = Combined Gas Law Next, write down the information you know and want to know. P1 = 12 atm V1 = 23 L T1 = 200K P2 = 14 atm V2 = x T2 = Combined Gas Law Next, write down the information you know and want to know. P1 = 12 atm V1 = 23 L T1 = 200 K P2 = 14 atm V2 = x T2 = 300 K Combined Gas Law Now plug in the information you have . . . P1V1 P2V2 = T1 T2 12atm(23L) 14 atm (x) = 200K 300K Combined Gas Law Cross multiply to solve for x 12atm(23 L)(300K) = 200 K (14L)(x) 82800 = 2800x x = 29.57 Liters