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ESTERS OrgChemGroup3

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ESTERS
STRUCTURE OF ESTERS
PREPARATION OF ESTERS
CYCLIC ESTERS
Escamillan | Estember | Gabinete | Gabunal | Guevarra | Juesna
STRUCTURE OF ESTERS
Ester is a carboxylic acid derivative in which the -OH portion of the
carboxyl group has been replaced with an -OR group.
The ester functional group is thus:
In linear form, the ester functional group can be represented as
-COOR or -COR
2
General formula of Ester
RCOOR′
NOTE:
R may be a hydrogen atom, an alkyl group, or an aryl group, and R′ may
be an alkyl group or an aryl group but not a hydrogen atom
The Simplest Ester has a hydrogen atom attached to the ester
functional group
The structure of the simplest aromatic ester is derived from the
structure of the simplest aromatic carboxylic acid
Benzoic Acid
NOTE:
The difference between a carboxylic acid and an ester is a “H versus R”
relationship
Example of carboxylic acid:
- Acetic acid
Example of Ester :
-Methyl Acetate
Structures of carboxylic acids to Esters
PREPARATION OF ESTERS
Ester is produced through esterification.
An esterification reaction is the reaction of a carboxylic acid with
an alchohol (or phenol) to produce an ester. A strong acid catalyst
(generally H2SO4) is needed for esterification.
In the esterification process, a -OH group is lost from the
carboxylic acid, a -H atom is lost from the alcohol, and water is
formed as a by-product. The net effect of this reaction is
substitution of the -OR group of the alcohol for the -OH group
of the acid.
An example of esterification is the reaction of acetic acid
with methyl alcohol.
Esterification reactions are equilibrium processes,
Usually favoring products only slightly. That is, at equilibrium, substantial
amount of both reactants and products are present. The amount of ester
formed can be increased by using an excess of alcohol or by constantly
removing one of the products.
According to Le Chatelier’s principle, either of these techniques will shift the
position of equilibrium to the right (the product side of the equation). This
equilibrium problem explains the use of the “double-arrow” in all the
esterification equations in this section.
It is often useful to think of
the structure of an ester in
terms of its “parent”
alcohol and acid
molecules; the ester has an
acid part and an alcohol
part.
In this context, it is easy to identify the acid and alcohol from
which a given ester can be produced; just add a -OH group to the
acid part of an ester and a -H atom to the alcohol part to
generate the parent molecules.
CYCLIC ESTERS
Cyclic Esters (Lactones)
Hydroxy acids—compounds which contain both a hydroxyl and a
carboxyl group have the capacity to undergo intermolecular esterifi
cation to form cyclic esters. Such internal esterifi cation easily takes
place in situations where a five- or six-membered ring can be formed.
Lactones are formed by intramolecular esterification of the corresponding
hydroxycarboxylic acids, which takes place spontaneously when the ring that
is formed is five- or six-membered
Cyclic esters are formally called lactones. A lactone is a cyclic ester.
Like cyclic ethers, cyclic esters are also heterocyclic organic compounds.
The oxygen atom that remains after a molecule of water is formed becomes
part of the ring structure.
Lactones are generally named after the carboxylic acid by using the suffix lactone.
A Greek letter is used to indicate the ring size.
A lactone with a five-membered ring is a y-lactone because the g-carbon
from the carbonyl carbon atom is bonded to the heteroatom (O) of the ring.
Similarly, a six-membered lactone ring system is a d-lactone because the
d-carbon is bonded to the heteroatom (O) of the ring system.
Thank you!
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