Percent Yield Instructions: Complete all sections of this report and answer all questions in complete sentences for full credit. Title: Objective(s): Hypothesis: None Materials: What scientific equipment and tools were used to collect data in the simulation? (Record the materials as you work through the simulation.) Materials lots Variables: Remember the three variables: controlled (what is kept the same), independent (what is tested or changed), and dependent (what is the outcome or observed). List variables below as you work through the simulation. Type Variables Controlled Time to heat; Mass of crucible and lid Independent Amount of magnesium Dependent Mass of magnesium oxide Procedure: Clear steps are in the simulation. No written procedure is needed for this virtual experience. However, it is important that you understand the experimental design of this lab for the conclusion section. Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School. Data Type the data in the data table below. Don't forget to record measurements with the correct number of significant figures and units. Data Mass of empty crucible with lid Length of ribbon cut Mass of Mg metal, crucible, and lid Mass of MgO, crucible, and lid Trial 1 26.679 g 2 in 26.996 g 27.192 g Trial 2 26.688 g 2 in 26.982 g 27.112 g Calculations Show your calculations for each of the following. Remember, calculations should follow rules for significant figures. Remember to use the balanced chemical reaction: 2Mg(s) + O2(g) → 2MgO(s). 1. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of Mg, crucible, and lid (row 2 in the chart) to find the mass of magnesium for each trial. Trial 1: 26.996 - 26.687 = 0.309 Trial 2: 26.982 - 26.688 = 0.294 2. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 3 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yield of magnesium oxide for each trial. Trial 1: 27.192 - 26.687 = 0.505 Trial 2: 27.112 - 26.688 = 0.424 3. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial using stoichiometry. Trial 1: 0.512 g MgO Trial 2: 0.488g MgO 4. Determine the percent yield of MgO for your experiment for each trial. Trial 1: 86.9% Trial 2: 92.8% 5. Determine the average percent yield of MgO for the two trials. Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School. Conclusion Using complete sentences, write a conclusion that addresses the following: The purpose of the lab, what you explored, what you learned An explanation of how percent yield can be affected during experimentation A description of the sources of errors that impacted your data measurements This lab was to determine the precent yield of magnesium oxide with a specific mass of magnesium. The product, MgO, has a higher mass than the reactant, Mg, because oxygen was added. This demonstrates conservation of mass because mass is not created or destroyed in chemical reactions, but the mass of both reactants was not measured before the reaction. Percent yield can be affected by the amount of each reactant and experimental conditions. Sources of error that could impact the data are incorrect measurements, impurities in the reactants and the combustion reaction not going to completion. I could further investigate this by trying with a different amount of magnesium or heating the reaction multiple times. Post-Lab Connection Questions Answer questions in complete sentences. 1. In physical labs, when conducting this experiment, sometimes the metal is heated and cooled for several rounds. After each round, the mass is recorded. This continues until the mass measurements remain the same. Explain the purpose of this process and how it might reduce errors. The purpose of doing this with an is because it will help reduce the errors during the experiment, so then the metal will be in its pure state so that when the data is recorded it will be accurate. Once the metal reaches a state of no change, scientists will know that the data is done 2. Imagine a company producing MgO with the same cost of materials as in this lab. The company averages a 92 percent yield for MgO. Would you recommend the company to continue their process or update? Support your recommendation using your calculations and understanding of stoichiometry from this lab. Yes I would recommend, but I would suggest that they try to slightly raise the yield closer to the theoretical yield.Calculations: 0.92*13.12=12.06 grams of MgO Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School. Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.