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stat hw 2

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2
Homework
1) ⑥
G
Gin Gan 63
=
61
true ,
represents
G
The event
Gz
,
intersection
and
,
6,
of
the
event
63
must
Gz , and
,
that
Gs
all
The
.
country
no
has
simultaneously
occur
Gc represents
event
next
recession
a
the
.
G
Therefore,
that
event
year
be
can
least
at
order for
In
.
expressed
that
to
the
as
has
one
country
the
relationship
of
multiple
be
recession
a
G,
next
year
.
62
G
⑤ PCG)
PCG ,)
≤
61,62 , and 63
be
⑥
most
at
be
PCG ,)
0
=
,
order
the
.
false
that
year
.
The
G
PCG , )
When
of
of
false
is
is
,
we
a
recession and
events
recession
can
be
country
no
.
2
intersection
the
because
events
PCGD , PCGZ) PC 63)
of
,
between
can
cannot
,
In
0.01
D- 84
0-16
that
that
Since
.
as
atleast
0.16
is
I
country
the
bound
lower
a
112 ,
country
61
or
62
,
and
,
has
3
has
one
maximum
PC G)
for
63
Since
.
recession
a
making
,
6
probability
So
.
,
lower
a
.
:O
PIG} )
-99
country
2
has
PC country
other words
one
probability
of
complements
the
probability
the
=
use
can
we
complement
its
use
,
the
represents
recession ,
having
0.01
=
represents
union
PC 6216 ,)
has
assuming
Without
.
PCG) → intersection
thus
PCG)
for
0.1+0.05-1
6 would
1
bound
their
,
true
always
is
PC 634
0.05
lower
0.9
=
=
those
union
country
having
a
respectively
,
bound for
④
'
find
to
PC 6316216 , )
-
PCG 3) = 0.99
0.95
=
PC 62 )
I
)
.
PCG 2)
complements
next
PCGD
PCG 216 ,
.
smallest event ,
of the
size
0.9
=
PCG c)
In
the
PCG ,)
=
statement
this
we know
,
than
larger
PC G)
because
63
is
PCGI)
*
2
a
99%
recession
P( country
:
2
/
0-99
chance
G1)
=
recession
of
0.01
/
.
G1)
having
The
=
no
recession ,
probability
0.9 ✗
0.01
=
of
or
country
0
.
1-1
a
009
1
.
chance
having
Or
-
9 't
no
.
2) ⑥
É
⑥
¥
②
¥2 ¥ ÷ f-
Because
If the
first
④ ¥2 ¥
3
Begins
¥2
Again
to
due
g.
no
cancer
Lii)
symmetry
0.04
134
,
PC not
Pcno
getting
)
=
test )
I
Pccancer)
-
=
CO
test)
pcnegative
test)
=
( 0.01)
D. 8
②
0.1
cancer
-9
us
.
the
chocolates
1st
is
the
same
.
.
.
8)
152
=
go.qgg.co
.
so
,
you
begin
°
-
168 ≈ 17
04 ,
-1
( 0.2×0.0 , ,
=
>
04)
°
99>9
-
I
+ (O.gg ,
° -831
99.8-1
≈
≈
83 I -1
.
.
.
go,]
(0-2) -10.99 ) (0-96)
)
+
cancer
-
0.96
99 't
=
( d. 1) ( 0.8
0.2
no
as
.
0.952 ≈
=
95.2-1
+
-
0-04
°
,
( 0.99 )ca04)
=
(0-99) CO
Civ)
dark
5 dark
3111 etc
then
same
-99360.96)
) 60.96)
/ positive
,
the
is
( 0.01 ) CO
( 0.99
Ciii) Pcno cancer
being
-
cancer
negative
cancer
of 12
out
CO -01) (0.8) +
+
0.96
ci)
chocolate
9 slots left and
are
4 milk
/
_
e. a
0.99
⑥
in
cancer
01
4th
of the
1-
0.8
3) ⑨
odds
the
,
not dark, there
are
11880
.
=
symmetry
24
=
.
.
-
of
(0.1×0.8)+(0-9310.04)
=
.
6896
≈
69 /
'
'
.
-
1
.
with
¥É
,
then
FᵈÉ÷
4)
{ 0.1.2
3,
a
Event
3. 4,5 , 6,7
,
possibilities
possibilities :
Total
Event
be
can
⑤
{
5
,
2.3
i.
/
②
I
3
3
{ Red 48)
Is
person
20
same
logic
has
a
No
a
to
,
¥8
these
much
as
=
( above)
out
total
to
of
1000
.
}
10
E
&
choose
any
,
8- >
=
g-
'
6.5
56-30
=
94
94
every subsequent
and
Green
C2)
there
are
person
has
1
less
option
out
the
of
total
9
}
383
before ,
events
smaller
"
no
that
just
chance
ensure
321
203
5g
'
,
Black CIS) ,
20
58
-
,
312 ,
1000
=
4
can
213,
,
combinations
78,9
2
first
,
6.
,
231
,
¥0
6
&
The
20
④
4,5
,
132
,
=
wl
made
}
10×10×10
¥
=
total
123
123
:
8,9
,
of
are
not
"
.
is
This
is
red b black
black ,
in
independent
probability
black
landing
not
18
PC.no
.
.
2
the
prob
black) is
¥8?
"
because
still true
boxes,
Thus
,
so
no
red
since
"
.
green
is
rather
,
3%3
as
severely
since
shown
,
the
above ,
limits
PCA) ≠ PCAIB)
than
these
the
1
of
events
but
#
events
color
each
are
.
Each ball
independent
.
Pcno black / no red] falls to
of
slots
are
not
the
balls
independent
could
.
3%-3
land
,
in
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