2 Homework 1) ⑥ G Gin Gan 63 = 61 true , represents G The event Gz , intersection and , 6, of the event 63 must Gz , and , that Gs all The . country no has simultaneously occur Gc represents event next recession a the . G Therefore, that event year be can least at order for In . expressed that to the as has one country the relationship of multiple be recession a G, next year . 62 G ⑤ PCG) PCG ,) ≤ 61,62 , and 63 be ⑥ most at be PCG ,) 0 = , order the . false that year . The G PCG , ) When of of false is is , we a recession and events recession can be country no . 2 intersection the because events PCGD , PCGZ) PC 63) of , between can cannot , In 0.01 D- 84 0-16 that that Since . as atleast 0.16 is I country the bound lower a 112 , country 61 or 62 , and , has 3 has one maximum PC G) for 63 Since . recession a making , 6 probability So . , lower a . :O PIG} ) -99 country 2 has PC country other words one probability of complements the probability the = use can we complement its use , the represents recession , having 0.01 = represents union PC 6216 ,) has assuming Without . PCG) → intersection thus PCG) for 0.1+0.05-1 6 would 1 bound their , true always is PC 634 0.05 lower 0.9 = = those union country having a respectively , bound for ④ ' find to PC 6316216 , ) - PCG 3) = 0.99 0.95 = PC 62 ) I ) . PCG 2) complements next PCGD PCG 216 , . smallest event , of the size 0.9 = PCG c) In the PCG ,) = statement this we know , than larger PC G) because 63 is PCGI) * 2 a 99% recession P( country : 2 / 0-99 chance G1) = recession of 0.01 / . G1) having The = no recession , probability 0.9 ✗ 0.01 = of or country 0 . 1-1 a 009 1 . chance having Or - 9 't no . 2) ⑥ É ⑥ ¥ ② ¥2 ¥ ÷ f- Because If the first ④ ¥2 ¥ 3 Begins ¥2 Again to due g. no cancer Lii) symmetry 0.04 134 , PC not Pcno getting ) = test ) I Pccancer) - = CO test) pcnegative test) = ( 0.01) D. 8 ② 0.1 cancer -9 us . the chocolates 1st is the same . . . 8) 152 = go.qgg.co . so , you begin ° - 168 ≈ 17 04 , -1 ( 0.2×0.0 , , = > 04) ° 99>9 - I + (O.gg , ° -831 99.8-1 ≈ ≈ 83 I -1 . . . go,] (0-2) -10.99 ) (0-96) ) + cancer - 0.96 99 't = ( d. 1) ( 0.8 0.2 no as . 0.952 ≈ = 95.2-1 + - 0-04 ° , ( 0.99 )ca04) = (0-99) CO Civ) dark 5 dark 3111 etc then same -99360.96) ) 60.96) / positive , the is ( 0.01 ) CO ( 0.99 Ciii) Pcno cancer being - cancer negative cancer of 12 out CO -01) (0.8) + + 0.96 ci) chocolate 9 slots left and are 4 milk / _ e. a 0.99 ⑥ in cancer 01 4th of the 1- 0.8 3) ⑨ odds the , not dark, there are 11880 . = symmetry 24 = . . - of (0.1×0.8)+(0-9310.04) = . 6896 ≈ 69 / ' ' . - 1 . with ¥É , then FᵈÉ÷ 4) { 0.1.2 3, a Event 3. 4,5 , 6,7 , possibilities possibilities : Total Event be can ⑤ { 5 , 2.3 i. / ② I 3 3 { Red 48) Is person 20 same logic has a No a to , ¥8 these much as = ( above) out total to of 1000 . } 10 E & choose any , 8- > = g- ' 6.5 56-30 = 94 94 every subsequent and Green C2) there are person has 1 less option out the of total 9 } 383 before , events smaller " no that just chance ensure 321 203 5g ' , Black CIS) , 20 58 - , 312 , 1000 = 4 can 213, , combinations 78,9 2 first , 6. , 231 , ¥0 6 & The 20 ④ 4,5 , 132 , = wl made } 10×10×10 ¥ = total 123 123 : 8,9 , of are not " . is This is red b black black , in independent probability black landing not 18 PC.no . . 2 the prob black) is ¥8? " because still true boxes, Thus , so no red since " . green is rather , 3%3 as severely since shown , the above , limits PCA) ≠ PCAIB) than these the 1 of events but # events color each are . Each ball independent . Pcno black / no red] falls to of slots are not the balls independent could . 3%-3 land , in