Unit 1 Lecture 7: Percent Composition, Empirical and Molecular Formulas The student can justify the observation that the ratio of the masses of the constituent elements in any pure sample of that compound is always identical on the basis of the atomic molecular theory. Mass Percent/ Percent Composition • Found by dividing the mass of the element by the mass of the compound and multiplying by 100. 𝒑𝒂𝒓𝒕𝒆𝒍𝒆𝒎𝒆𝒏𝒕 𝒎𝒂𝒔𝒔 𝒑𝒆𝒓𝒄𝒆𝒏𝒕 = 𝒙 𝟏𝟎𝟎% 𝒘𝒉𝒐𝒍𝒆𝒄𝒐𝒎𝒑𝒐𝒖𝒏𝒅 • Can be determined from molecular formula. • NOTE: Subscripts indicate the mole ratio of elements present in a compound. • For iron in iron(III) oxide, (Fe2O3): (2 𝑚𝑜𝑙 )( 𝑚𝑎𝑠𝑠 % 𝑜𝑓 𝐹𝑒 = 2 𝑚𝑜𝑙 55.85 𝑔 ) 𝑚𝑜𝑙 55.85 𝑔 16.00 𝑔 + 3 𝑚𝑜𝑙 ( ) 𝑚𝑜𝑙 𝑚𝑜𝑙 Copyright © Cengage Learning. All rights reserved 𝑥 100% = 69.94% 3 EXERCISE! Sodium hydrogen carbonate (NaHCO3), also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent composition each element in NaHCO3 . EXERCISE! Consider separate 100.0 gram samples of each of the following: H2O, N2O, C3H6O2, CO2 – Rank them from highest to lowest percent oxygen by mass. H2O, CO2, C3H6O2, N2O Copyright © Cengage Learning. All rights reserved 5 Formulas • A molecular formula of a compound , which shows the elements symbols and numerical subscripts, tells you the type and number of each atom in a molecule. • The empirical formula is the formula that shows the smallest whole-number mole ratio of the compound’s elements. NOTE: Compound subscripts indicate the mole ratio of elements present in a particular compound. • Molecular formula (actual formula of the compound) Benzene – C6H6 = (CH)6 • Empirical formula (shows simplest whole-number mole ratio) – CH Copyright © Cengage Learning. All rights reserved Acetylene 7 Calculating Empirical Formula from Mass Percent • You can calculate the empirical formula from percent by mass by 1. First, assuming you have 100.00 g of the compound. 2. Then, convert the mass of each element to moles. 3. Finally, divide each mole value by the smallest value. • The empirical formula may or may not be the same as the molecular formula. EXERCISE! Methyl acetate is a solvent commonly used in some paints, inks, and adhesives. Determine the empirical formula for methyl acetate, which has the following chemical analysis: 48.64% carbon, 8.16% hydrogen, and 43.20% oxygen. Copyright © Cengage Learning. All rights reserved 10 EXERCISE! Succinic acid is a substance produced by lichens. Chemical analysis indicates it is composed of 40.68% carbon, 5.08% hydrogen, and 54.24% oxygen and has a molar mass of 118.1 g/mol. Determine the empirical and molecular formulas for succinic acid. Copyright © Cengage Learning. All rights reserved 12 EXERCISE! The composition of adipic acid is 49.3% C, 6.9% H, and 43.8% O (by mass). The molar mass of the compound is about 146 g/mol. – What is the empirical formula? C3H5O2 – What is the molecular formula? C6H10O4 Copyright © Cengage Learning. All rights reserved 13 EXERCISE! The mineral ilmenite is usually mined and processed for titanium, a strong, light, and flexible metal. A sample of ilmenite contains 5.41 g of iron, 4.64 g of titanium, and 4.65 g of oxygen. Determine the empirical formula for ilmenite. Calculate the simplest ratio by dividing each mole value by the smallest value. Copyright © Cengage Learning. All rights reserved 14 Hydrates • Hydrates are compounds that incorporate water molecules in their crystalline structures. • The ratio of moles of water to one mole of the compound is a small whole number. – Example: Hydrated copper(II) sulfate pentahydrate (CuSO4·5H2O), has a compound:water ratio of 5:1. CuSO4·5H2O Anhydrous forms of hydrates are often used to absorb water, particularly during shipment of electronic and optical equipment. In chemistry labs, anhydrous forms of hydrates are used to remove moisture from the air and keep other substances dry. Determining Hydrate Formula • When heated, water molecules are released from a hydrate leaving an anhydrous compound. – Weigh hydrate, then heat to drive off the water. – Change in mass = mass of water lost – Convert the known masses of H2O and now anhydrous substance to moles. – Find ratio of moles of H2O to mole of anhydrous substance. EXERCISE! A mass of 2.50 g of blue, hydrated copper sulfate (CuSO4•xH2O) is placed in a crucible and heated. After heating, 1.59 g of white anhydrous copper sulfate (CuSO4) remains. What is the formula for the hydrate? Name the hydrate. 1. Weigh hydrate, then heat to drive off the water. 2. Change in mass = mass of water lost 3. Convert the known masses of H2O and now anhydrous substance to moles. 4. Find ratio of moles of H2O to mole of anhydrous substance. Copyright © Cengage Learning. All rights reserved 18 EXERCISE! A 5.00 g sample of barium chloride hydrate was heated in a crucible. After the experiment, the mass of the solid weighed 4.26 g. Determine the number of moles of water that must be attached to BaCl2. 1. Weigh hydrate, then heat to drive off the water. 2. Change in mass = mass of water lost 3. Convert the known masses of H2O and now anhydrous substance to moles. 4. Find ratio of moles of H2O to mole of anhydrous substance. Copyright © Cengage Learning. All rights reserved 19