Physics 261 Spring06. Written HW #2 solutions. (HW was due 4/21/05). A. D. Dinsmore Phys261 written HW#2 solutions 1 Phys261 written HW#2 solutions 2 Phys261 written HW#2 solutions 3 E is the sum of p2/2m for each of the 3 directions (as stated in the problem). Each of these is given by (hn/2L)2, where n is an integer greater than zero. The key is that each of the x, y, and z directions can have different n-values. If we call them nx, ny and nz, then we find E = h2/(8mL2)(nx2 + ny2 + nz2). Phys261 written HW#2 solutions 4