Determining Empirical Formula Empirical Formulas Indicate the lowest whole number ratio of atoms of each element in a compound. The molecular formula of hydrogen peroxide is H2O2 the empirical formula would be…? HO Ho, Ho, Ho… The molecular formula of glucose is… C6H12O6, , its empirical formula is… CH2O … So what’s my point? Empirical formulas are lowest whole number ratios of atoms of each type …to determine them experimentally we need numbers of atoms! Consider the following: Analysis of a compound at CSI North Haven Labs indicates that it contains 32.38 g Na 22.65 g S 44.99 g O How can we use this data to determine the formula?...Think… Mass number of atoms! Remember doing mole conversions? Use the molar mass of element convert to moles. A mole is a number of atoms … you now have a ratio of atoms in the compound. Divide each mole amount by the smallest mole amount… whole # ratio??? Use ratio to write subscripts 1.408 mol Na : 0.7063 mol S : 2.812mol O Divide each by smallest 1.993 mol Na : 1 mol S : 3.981 mol O Na2SO4 Try this.. Analysis indicates that a compound contains 78.1% Boron and 21.9% hydrogen determine the empirical formula. Why is this one any different from the last example? Assume you have a 100 gram sample…now how many grams of boron do you have? 7.22 mol B : 21.7 mol H Divide through by smallest 1 mol B : 3.01 mol H BH3 Try this one … Analysis of a 10.150 g sample of a compound known to contain only phosphorus and oxygen indicates a phosphorus content of 4.433 g. What is the empirical formula? Grams of P = 4.433g Grams of O = ? Now try it… 0.1431 mol P : 0.3573 mol O Divide by smallest 1 mol P : 2.497 mol O … Now what?...Multiply through by two to obtain whole numbers… 2 : 5 P2O5 Find empirical formulas… 1. 36.48% Na, 25.41% S, 38.11 % O… 2. 53.70 % iron and 46.30% sulfur… 3. 4. 1.04 g K, 0.70 g Cr and 0.86 g O… 37.51% C, 4.20% H and 58.29 % O … Quantitative Analysis Various methods are used to determine the mass or percent composition of each element in a given compound…more about those later…