What’s the MATTER: Specific Heat of Matter Be Afraid… Be Very Afraid… Matter, Specific Heat of Matter At the conclusion of our time together, you should be able to: 1. Define specific heat 2. Use specific heat to determine energy changes Thermochemistry Some Definitions: Calorimeter – a device to measure the energy absorbed or released as heat in a chemical or physical change Temperature – measure of the average kinetic energy of the particles in a sample of matter Joule – the SI unit of heat Thermochemistry Some Definitions: Heat – energy transferred between samples of matter Specific Heat – the amount of energy required to raise the temperature of one gram of a substance by one Celsius degree or one Kelvin 1 Calorie/4.184 Joules – will do the above with water 15 Helpful Hints On The Lab Report from Mr. T’s Vast Lab Experience!!! Hint #9. Teamwork is essential. It allows you to blame someone else. Thermochemistry Some Definitions: Enthalpy (Heat) of Fusion – amount of energy gained or lost by a system as heat during melting or freezing Enthalpy (Heat) of Vaporization – amount of energy gained or lost by a system as heat during boiling or condensation Calvin’s Definition of a Liquid: Specific Heat Calculations: q = cp x m x t: q = energy lost or gained cp = specific heat of the substance at a specific pressure m = mass of the sample t = change in temperature (final – initial) Practice Page 12:1 q = cp x q = cp = m = t = 59.912 J m x t: 59.912 J x 36.359 g 152.0 oC = (x)(36.359 g)(152.0 oC) = 0.01084 J/g oC Practice Page 12:2 q = cp x m x t: q = -800. J cp = 0.4210 J/g oC m = 73.174 g t = (x – 102.0 oC) -800. J = 0.4210 J/goC (73.174 g)(x – 102.0 oC) -800. = 30.81x – 3142 2342 = 30.81x = 76.0 oC Matter, Specific Heat of Matter Let’s see if you can : 1. Define specific heat 2. Use specific heat to determine energy changes Maxine’s Thoughts on Intelligence!! Define Specific Heat Specific Heat – the amount of energy required to raise the temperature of one gram of a substance by one Celsius degree or one Kelvin Confucius Says: If at first you don’t succeed… Skydiving is probably not for you!!! Practice Page 12:3 q = cp q cp m t -185.4 -185.4 x m x t: = -185.4 J = 0.440 J/g oC =xg = -1475 oC J = (0.440 J/goC )(x)(-1475 oC) J = -649 Jg = 0.286 g Practice Page 12:4 q = cp x m x t: q =xJ cp = 0.0335 cal/goC (4.184 J/cal) m = 152.00 g t = -51.5oC x = (0.140164 J/goC )(152.00 g)(-51.5 oC) = -1.10 x 103 J Maxine asks: What do you get with a woman who has PMS and a GPS?? A b---- who will find you!!! Have a Great Week!!