Matter 5 Specific Heat

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What’s the MATTER:
Specific Heat of Matter
Be Afraid…
Be Very Afraid…
Matter,
Specific Heat of Matter
At the conclusion of our time
together, you should be able to:
1. Define specific heat
2. Use specific heat to determine energy
changes
Thermochemistry
 Some Definitions:
 Calorimeter – a device to measure the
energy absorbed or released as heat
in a chemical or physical change
 Temperature – measure of the
average kinetic energy of the particles
in a sample of matter
 Joule – the SI unit of heat
Thermochemistry
 Some Definitions:
 Heat – energy transferred between
samples of matter
 Specific Heat – the amount of energy
required to raise the temperature of
one gram of a substance by one
Celsius degree or one Kelvin
 1 Calorie/4.184 Joules – will do the
above with water
15 Helpful Hints On The Lab Report from
Mr. T’s Vast Lab Experience!!!
Hint #9. Teamwork is essential. It
allows you to blame someone else.
Thermochemistry
 Some Definitions:
 Enthalpy (Heat) of Fusion – amount of
energy gained or lost by a system as
heat during melting or freezing
 Enthalpy (Heat) of Vaporization –
amount of energy gained or lost by a
system as heat during boiling or
condensation
Calvin’s Definition of a Liquid:
Specific Heat Calculations:
 q = cp x m x t:
 q
= energy lost or gained
 cp
= specific heat of the substance
at a specific pressure
 m
= mass of the sample
 t = change in temperature
(final – initial)
Practice Page 12:1
 q = cp x
 q
=
 cp
=
 m
=
 t =
59.912 J
m x t:
59.912 J
x
36.359 g
152.0 oC
= (x)(36.359 g)(152.0 oC)
= 0.01084 J/g oC
Practice Page 12:2
 q = cp x m x t:
 q
= -800. J
 cp
= 0.4210 J/g oC
 m
= 73.174 g
 t = (x – 102.0 oC)
-800. J = 0.4210 J/goC (73.174 g)(x – 102.0
oC)
-800. = 30.81x – 3142
2342 = 30.81x
= 76.0 oC
Matter,
Specific Heat of Matter
Let’s see if you can :
1. Define specific heat
2. Use specific heat to determine energy
changes
Maxine’s Thoughts on Intelligence!!
Define Specific Heat
 Specific Heat – the amount of energy
required to raise the temperature of
one gram of a substance by one
Celsius degree or one Kelvin
Confucius Says:
If at first you don’t
succeed…
Skydiving is probably not for
you!!!
Practice Page 12:3
 q = cp
 q
 cp
 m
 t
-185.4
-185.4
x m x t:
= -185.4 J
= 0.440 J/g oC
=xg
= -1475 oC
J = (0.440 J/goC )(x)(-1475 oC)
J = -649 Jg
= 0.286 g
Practice Page 12:4
 q = cp x m x t:
 q
=xJ
 cp
= 0.0335 cal/goC (4.184 J/cal)
 m
= 152.00 g
 t = -51.5oC
x = (0.140164 J/goC )(152.00 g)(-51.5 oC)
= -1.10 x 103 J
Maxine asks: What do you get with a
woman who has PMS and a GPS??
A b---- who
will find you!!!
Have a
Great
Week!!
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