Fundamentals of Metal Forming

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Fundamentals of

Metal Forming

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Bulk deformation vs Sheetmetal working

Bulk deformation Aluminum extrudate – a simple angled shape.

The die shown is more complex.

* Low surface area to volume ratios

* Operations increase surface area to volume ratios

Operations are: rolling half mile long - roll the slab into sheet steel using tremendous pressure.

forging extrusion drawing

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Bulk deformation

• Rolling characteristics

* compressive deformation

* 2 or more rolls

* strong frictional relationship

• Extrusion characteristics

* compressive deformation

* force metal through die opening

* strong frictional relationship

* hot and cold working process

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Sheet metalworking

Characterized by:

* large surface area to volume ratios

* little ratio change after process

* machines called presses

* parts called stampings

* tools are punch and die

Operations: bending drawing shearing

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Material Behavior – Flow Stress

 = K e n

Concept of flow stress , Y f

– the instantaneous stress required to deform the material

Y f

= K e n

Process force considerations:

* during compression, determine instantaneous force from Y f

* max force is often all that is required, typically at end of stroke

* force analysis may be based on average stresses and strains

Average flow stress = Y f

= K e n /(1 + n)

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Temperature and Metal Forming

K and n depend on working temperature, characterized by

3 ranges:

Cold working

Warm working

Hot working

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Temperature and Metal Forming –

cold working

Advantages:

* good accuracy and tolerances

* better surface finish

* strain hardening increases strength and hardness

* directional properties

* energy economy

Disadvantages:

* higher forces/power

* strain hardening limits deformation

* may need to anneal

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Temperature and Metal Forming –

warm working

Advantages:

* above room temp., but below re-crystallization temp. (0.3 T m

* lower forces and power

)

* reduced strain hardening

* more difficult geometry

* no need for annealing

Disadvantages:

* more energy

* limited geometry

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming

Temperature and Metal Forming –

hot working

Advantages:

* above re-crystallization temp. (0.5 T m

* lower forces and power

* no strain hardening

* difficult geometry

* isotropic properties

< T < 0.75 T m

)

Disadvantages:

* more energy

* poorer surface finish

* shorter tool life

ME 482 - Manufacturing Systems

Fundamentals of Metal Forming -

Strain Rate

Room temp.

Note: Strain rate a strong function of working temperature

400º C where

    v h v = speed of testing head

(high values -> 1000 s -1 )

1200º C

Strain rate equation: strain rate is negligible at

Y f

= C e m room temperature!

Strain rate

C = strength constant m = strain-rate coefficient

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Friction and lubrication

Friction:

* undesirable

* retards metal flow (residual stresses & defects)

* increases force and power requirements

* wears tooling

* high temperature stiction

Lubricants are usually oil-based, and when used in extreme pressure situations, sulfur,

Lubricants: chlorine and phosphorus in the lubricant may chemically react with the metal surfaces (tool, chip). The reactions form a

* reduce frictional effects

* remove heat and material

* lengthen tool life surface boundary layer that is more effective than the lubricant itself in reducing friction. Lubricants are most effective at cutting speeds < 400 ft/min.

* may react chemically with tool or work

* concerns about toxicity, flammability….(mineral oils, emulsions, oils, graphite, glass..)

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Example 20.6

For a metal with K = 50,000 lb/in 2 and n = 0.27, determine the average flow stress that the metal experiences if it is subjected to a stress that is equal to its strength coefficient K.

Solution:

Y f

= K = 50,000 = 50,000 e n

Thus e = 1

Y f

= 50,000 (1) 0.27

/1.27 = 39,370 lb/in 2

ME 482 - Manufacturing Systems

What have you learned?

ME 482 - Manufacturing Systems

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