4lewis structures

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Remember back 5
rows of even side
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Lewis Structures: non-octet breaking
3+6(1)+5=14
• BH3NH3
• Any common octet breaking atoms?
H
• How many electrons are present?
• What is the central atom?
• Draw a skeletal structure
• Add electrons: do you have enough
to give all atoms octets?
• Yes? Then minimize formal charges
if needed.
• No? Then add double bonds until
you have enough electrons.
• Label each with the formal charge.
H
B N H
H
H
H
14 electrons, everything with an octet
Lewis Structures: non-octet breaking
4+1+1+6=12
• CH2O
•
•
•
•
•
Any common octet breaking atoms?
How many electrons are present?
What is the central atom?
Draw a skeletal structure
Add electrons: do you have enough to give
all atoms octets?
• Yes? Then minimize formal charges if
needed.
• No? Then add double bonds until you have
enough electrons.
• Label each with the formal charge.
H
O
O
C
C
H
H
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H
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Lewis Structures: non-octet breaking
1+5+6*2=18e• HNO2
•
•
•
•
•
Any common octet breaking atoms?
How many electrons are present?
What is the central atom?
Draw a skeletal structure
Add electrons: do you have enough to give
all atoms octets?
• Yes? Then minimize formal charges if
needed.
• No? Then add double bonds until you have
enough electrons.
• Label each with the formal charge.
We’d need 20 electrons
to give everything octets:
N
O
Add in a double bond
O
H
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Word of the day: learning
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Lewis Structures:
non-octet breaking
• N2O
•
•
•
•
•
N N O
Short 4 electrons: need
two more bonds
Where do we add them?
5(2)+6=16 electrons
Any common octet breaking atoms?
How many electrons are present?
What is the central atom?
Draw a skeletal structure
Add electrons: do you have enough
to give all atoms octets?
• Yes? Then minimize formal charges
if needed.
• No? Then add double bonds until
you have enough electrons.
• Label each with the formal charge.
5-4=1
5-6
=-1
N N O
5-4=1
6-6
=0
5-5
=0
N N O
6-7
=-1
5-7
=-2
N N O
6-5
=1
5-4=1
OCTET BREAKING EXAMPLES
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• Which of the following statements is true:
• A) Nitrogen is allowed to have five bonds because it is allowed to have eight
electrons
• B) Phosphorous is allowed to have five bonds because it is allowed to have ten
electrons
• C) Carbon can break the octet rule with greater than eight electrons.
• D) Iodine is a halogen so it can never have more than one bond.
• E) Xenon is a noble gas so it can’t form compounds
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Lewis Structures: octet breaking
• BH3
3+1(3)=6 electrons
• Any common octet breaking atoms?
• How many electrons are present?
• What is the central atom?
H
• Draw a skeletal structure
• Add electrons: do you have enough to give all
atoms octets?
• Yes? Then minimize formal charges if needed.
H
B
• No? Then add double bonds until you have
enough electrons.
• Is it one that is typically found to have
less?
• Label each with the formal charge
H
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Lewis Structures: octet breaking
• XeF4
• Any common octet breaking atoms?
• How many electrons are present?
• What is the central atom?
8+7(4)=36 electrons
F
Xe
• Draw a skeletal structure
• Add electrons: do you have enough to give all
atoms octets?
• Yes? Then minimize formal charges if needed.
• No? Then add double bonds until you have enough
electrons.
• Is it one that is typically found to have less?
• Label each with the formal charge
F
F
F
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• ClF4-
Lewis Structures: octet breaking
7+7(4)+1=36 electrons
• Any common octet breaking atoms?
• How many electrons are present?
• What is the central atom?
• Draw a skeletal structure
F
Cl
• Add electrons: do you have enough to give all
atoms octets?
• Yes? Then minimize formal charges if needed.
• No? Then add double bonds until you have enough
electrons.
• Is it one that is typically found to have less?
• Label each with the formal charge
F
F
F
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Lewis Structures: octet breaking
6(5)+2=32 electrons
• H2SO4
-1
• Any common octet breaking atoms?
• How many electrons are present?
• What is the central atom?
• Draw a skeletal structure
• Add electrons: do you have enough to give all
atoms octets?
S
O
+2
-1
S
+0
+0
O
O O O O
O
H
H
H
H
• Yes? Then minimize formal charges if needed.
• No? Then add double bonds until you have
enough electrons.
• Is it one that is typically found to have
less?
• Label each with the formal charge
O
+0
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